How can I compare elements from two different arrays? Ruby - ruby

I am trying to make a ruby def that looks like this:
def title_case(title, minor_words)
end
It's supposed to title case the string variable "title", any word in the minor_words variable is to be downcased and any word not it the minor_words variable is to be capitalized.
Example:
title_case("The King is a Good man", "a and the an at")
-> "the King Is a Good Man"
And the code I am attempting to write looks like this:
def title_case(title, minor_words)
title = title.downcase.split
minor_words = minor_words.downcase.split
title.map {|word| if word == (any word from minor_words)
word.downcase
else
word.capitalize
end}.join(" ")
end
If minor_words is empty it returns title with all letters capitalized. Like so:
-> "The King Is A Good Man"
If title is empty, or both are empty it returns an empty string:
-> ""
Hope I made things clear! Thanks!

You could use a ternary statement:
ary1.map { |e| ary2.include?(e.downcase) ? e.downcase : e }
# => ["the", "man", "is", "not", "nice"]
To mutate the array in place use Array#map! instead of Array#map.

Related

How do I use regular expression to select from an array?

I have a code that asks for the user to either type Cats or Dogs then it'll search an array for everything that contains the word Cats or Dogs then puts them all out.
print "Cats or Dogs? "
userinput = gets.chomp
lines = [["Cats are smarter than dogs"],["Dogs also like meat"], ["Cats are nice"]]
lines.each do |line|
if line =~ /(.*?)#{userinput}(.*)/
puts line
end
end
So If I were to input Cats. I should get two sentences:
Cats are smarter than dogs
Cats are nice
You could even input smarter and I'll get
Cats are smarter than dogs
I'm strictly looking for ways to use an regular expression to search through an array or string and take out the lines/sentences that match the expression.
If anyone is wondering, the lines array was originally from an file and I turned each line into an array part.
EDIT:
Wow, how far I came in the coding world.
print "Cats or Dogs? "
userinput = gets.chomp
lines = [["Cats are smarter than dogs"],["Dogs also like meat"], ["Cats are nice"]]
lines.each do |linesInside|
linesInside.each do |line|
if line =~ /(.*?)#{userinput}(.*)/
puts line
end
end
end
Took literally 5 seconds to solve what took me ages to give up on at the time.
Try this
...
lines = ["Cats are smarter than dogs", "Dogs also like meat", "Cats are nice"]
regexp = Regexp.new(userinput)
selected_lines = lines.grep(regexp)
puts selected_lines
How does this work?
grep filters an array using pattern matching
Notice that I am using an array of strings. Your example code uses an array of single-element arrays, I assume you mean to just use an array of strings.
You can, of course, do that without a regex.
lines = ["Dogs are smarter than cats", "Cats also like meat", "Dogs are nice"]
print "Cats or Dogs? "
input = gets.chomp.downcase
If input #=> "dogs",
lines.select { |line| line.downcase.split.include?(input) }
#=> ["Dogs are smarter than cats", "Dogs are nice"]
If input #=> "cats",
lines.select { |line| line.downcase.split.include?(input) }
#=> ["Dogs are smarter than cats", "Cats also like meat"]
Since your array is an array of arrays, you could call flatten first :
lines.flatten.grep(/#{userinput}/i)
i is for case insensitive search, so that 'Dogs' matches 'Dogs' and 'dogs'.
If you want whole-word search :
lines.flatten.grep(/\b#{userinput}\b/i)
Finally, if you don't really need an array of arrays, just read an array from your file directly, either with File.readlines(f) or File.foreach(f).

Find a keyword in text and then print words leading up to a separate keyword

I am trying to write a program that looks at text provided by a user, searches for a keyword, and if it finds that keyword, will print it as well as any words that follow it until it encounters a separate keyword. For example:
Search for "I", print until "and"
User text: "I like fishing and running"
Returns: "I like fishing"
I have tried to loop through an array of the user's text using each_with_index, but could not access the index of words ahead of the word my loop is currently on. Any attempt to access other indices returns nil.
def search()
#text.each_with_index do |word, index|
if word == "I"
puts word + word[1]
end
end
end
Once I can print words of future indices, my next problem would be to print all words leading up to a key word that tells it to stop, which I imagine I could probably do with an if statement and break, but I'd be grateful for any ideas for this as well.
If you have any suggestions on how to make the above work, or any other solutions I would appreciate it.
str = "The quickest of the quick brown dogs jumped over the lazy fox"
word_include = "quick"
word_exclude = "lazy"
r = /
\b#{word_include}\b # match value of word_include between word boundaries
.*? # match any number of any character, lazily
(?=\b#{word_exclude}\b) # match value of word_exclude with word breaks
# in positive lookahead
/x # extended mode for regex def
#=> /\bquick\b.*?(?=\blazy\b)/
str[r]
#=>"quick brown dogs jumped over the "
Note that if:
str = "The quick brown lazy dog jumped over the lazy fox"
we would obtain:
str[r]
#=> "quick brown "
which is what we want. If however, we changed .*? in the regex to .*, making it non-lazy, we would obtain:
str[r]
#=> "quick brown lazy dog jumped over the "
Using an index here does not seem to be the right way.
_, key, post = "I like fishing and running".partition(/\bI\b/)
pre, key, _ = (key + post).partition(/\band\b/)
pre # => "I like fishing"
def enclosed_words(sentence, start_word, end_word)
words = sentence.split
return [] unless words.include?(start_word) and words.include?(end_word)
words[words.index(start_word)...words.index(end_word)].join(' ')
end
enclosed_words('I like fishing and running', 'I', 'and') # => "I like fishing"

Counting words in Ruby with some exceptions

Say that we want to count the number of words in a document. I know we can do the following:
text.each_line(){ |line| totalWords = totalWords + line.split.size }
Say, that I just want to add some exceptions, such that, I don't want to count the following as words:
(1) numbers
(2) standalone letters
(3) email addresses
How can we do that?
Thanks.
You can wrap this up pretty neatly:
text.each_line do |line|
total_words += line.split.reject do |word|
word.match(/\A(\d+|\w|\S*\#\S+\.\S+)\z/)
end.length
end
Roughly speaking that defines an approximate email address.
Remember Ruby strongly encourages the use of variables with names like total_words and not totalWords.
assuming you can represent all the exceptions in a single regular expression regex_variable, you could do:
text.each_line(){ |line| totalWords = totalWords + line.split.count {|wrd| wrd !~ regex_variable }
your regular expression could look something like:
regex_variable = /\d.|^[a-z]{1}$|\A([^#\s]+)#((?:[-a-z0-9]+\.)+[a-z]{2,})\Z/i
I don't claim to be a regex expert, so you may want to double check that, particularly the email validation part
In addition to the other answers, a little gem hunting came up with this:
WordsCounted Gem
Get the following data from any string or readable file:
Word count
Unique word count
Word density
Character count
Average characters per word
A hash map of words and the number of times they occur
A hash map of words and their lengths
The longest word(s) and its length
The most occurring word(s) and its number of occurrences.
Count invividual strings for occurrences.
A flexible way to exclude words (or anything) from the count. You can pass a string, a regexp, an array, or a lambda.
Customisable criteria. Pass your own regexp rules to split strings if you prefer. The default regexp has two features:
Filters special characters but respects hyphens and apostrophes.
Plays nicely with diacritics (UTF and unicode characters): "São Paulo" is treated as ["São", "Paulo"] and not ["S", "", "o", "Paulo"].
Opens and reads files. Pass in a file path or a url instead of a string.
Have you ever started answering a question and found yourself wandering, exploring interesting, but tangential issues, or concepts you didn't fully understand? That's what happened to me here. Perhaps some of the ideas might prove useful in other settings, if not for the problem at hand.
For readability, we might define some helpers in the class String, but to avoid contamination, I'll use Refinements.
Code
module StringHelpers
refine String do
def count_words
remove_punctuation.split.count { |w|
!(w.is_number? || w.size == 1 || w.is_email_address?) }
end
def remove_punctuation
gsub(/[.!?,;:)](?:\s|$)|(?:^|\s)\(|\-|\n/,' ')
end
def is_number?
self =~ /\A-?\d+(?:\.\d+)?\z/
end
def is_email_address?
include?('#') # for testing only
end
end
end
module CountWords
using StringHelpers
def self.count_words_in_file(fname)
IO.foreach(fname).reduce(0) { |t,l| t+l.count_words }
end
end
Note that using must be in a module (possibly a class). It does not work in main, presumably because that would make the methods available in the class self.class #=> Object, which would defeat the purpose of Refinements. (Readers: please correct me if I'm wrong about the reason using must be in a module.)
Example
Let's first informally check that the helpers are working correctly:
module CheckHelpers
using StringHelpers
s = "You can reach my dog, a 10-year-old golden, at fido#dogs.org."
p s = s.remove_punctuation
#=> "You can reach my dog a 10 year old golden at fido#dogs.org."
p words = s.split
#=> ["You", "can", "reach", "my", "dog", "a", "10",
# "year", "old", "golden", "at", "fido#dogs.org."]
p '123'.is_number? #=> 0
p '-123'.is_number? #=> 0
p '1.23'.is_number? #=> 0
p '123.'.is_number? #=> nil
p "fido#dogs.org".is_email_address? #=> true
p "fido(at)dogs.org".is_email_address? #=> false
p s.count_words #=> 9 (`'a'`, `'10'` and "fido#dogs.org" excluded)
s = "My cat, who has 4 lives remaining, is at abbie(at)felines.org."
p s = s.remove_punctuation
p s.count_words
end
All looks OK. Next, put I'll put some text in a file:
FName = "pets"
text =<<_
My cat, who has 4 lives remaining, is at abbie(at)felines.org.
You can reach my dog, a 10-year-old golden, at fido#dogs.org.
_
File.write(FName, text)
#=> 125
and confirm the file contents:
File.read(FName)
#=> "My cat, who has 4 lives remaining, is at abbie(at)felines.org.\n
# You can reach my dog, a 10-year-old golden, at fido#dogs.org.\n"
Now, count the words:
CountWords.count_words_in_file(FName)
#=> 18 (9 in ech line)
Note that there is at least one problem with the removal of punctuation. It has to do with the hyphen. Any idea what that might be?
Something like...?
def is_countable(word)
return false if word.size < 2
return false if word ~= /^[0-9]+$/
return false if is_an_email_address(word) # you need a gem for this...
return true
end
wordCount = text.split().inject(0) {|count,word| count += 1 if is_countable(word) }
Or, since I am jumping to the conclusion that you can just split your entire text into an array with split(), you might need:
wordCount = 0
text.each_line do |line|
line.split.each{|word| wordCount += 1 if is_countable(word) }
end

Regex to match exact word in string

I've looked around but haven't been able to find a working solution to my problem.
I have an array of two strings input and want to test which element of the array contains an exact substring Test.
One thing I have tried (among numerous other attempts):
input = ["Test's string", "Test string"]
# Alternative input array that it needs to work on:
# ["Testing string", "some Test string"]
substring = "Test"
if (input[0].match(/\b#{substring}\b/))
puts "Test 0 "
# Do something...
elsif (input[1].match(/\b#{substring}\b/))
puts "Test 1"
# Do something different...
end
The desired result is a print of "Test 1". The input can be more complex but overall I am looking for a way to find an exact match of a substring in a longer string.
I feel like this should be a rather trivial regex but I haven't been able to come up with the correct pattern. Any help would be greatly appreciated!
Following code may be what you are looking for.
input = ["Testing string", "Test string"]
substring = "Test"
if (input[0].match(/[^|\s]#{substring}[\s|$]/)
puts "Test 0 "
elsif (input[1].match(/[^|\s]#{substring}[\s|$]/)
puts "Test 1"
end
The meaning of the pattern /[^|\s]#{substring}[\s|$]/ is
[^|\s] : left side of the substring is begining of string(^) or white space,
{substring} : subsring is matched exactly,
[\s|$] : right side of the substring is white space or end of string($).
One way to that is as follows:
input = ["Testing string", "Test"]
"Test #{ input.index { |s| s[/\bTest\b/] } }"
#=> "Test 1"
input = ["Test", "Testing string"]
"Test #{ input.index { |s| s[/\bTest\b/] } }"
#=> "Test 0"
\b is the regex denotes a word boundary.
Maybe you want a method to return the index of the first element of input that contains the word? That could be:
def matching_index(input, word)
input.index { |s| s[/\b#{word}\b/i] }
end
input = ["Testing string", "Test"]
matching_index(input, "Test") #=> 1
matching_index(input, "test") #=> 1
matching_index(input, "Testing") #=> 0
matching_index(input, "Testy") #=> nil
Then you could use it like this, for example:
word = 'Test'
puts "The matching element for '#{word}' is at index #{ matching_index(input, word) }"
#=> The matching element for 'Test' is at index 1
word = "Testing"
puts "The matching element for '#{word}' is '#{ input[matching_index(input, word)] }'"
#The matching element for 'Testing' is 'Testing string'
The problem is with your bounding. In your original question, the word Test will match the first string because the ' is will match the \b word boundary. It's a perfect match and is responding with "Test 0" correctly. You need to determine how you'll terminate your search. If your input contains special characters, I don't think the regex will work properly. /\bTest my $money.*/ will never match because the of the $ in your substring.
What happens if you have multiple matches in your input array? Do you want to do something to all of them or just the first one?

Regex with named capture groups getting all matches in Ruby

I have a string:
s="123--abc,123--abc,123--abc"
I tried using Ruby 1.9's new feature "named groups" to fetch all named group info:
/(?<number>\d*)--(?<chars>\s*)/
Is there an API like Python's findall which returns a matchdata collection? In this case I need to return two matches, because 123 and abc repeat twice. Each match data contains of detail of each named capture info so I can use m['number'] to get the match value.
Named captures are suitable only for one matching result.
Ruby's analogue of findall is String#scan. You can either use scan result as an array, or pass a block to it:
irb> s = "123--abc,123--abc,123--abc"
=> "123--abc,123--abc,123--abc"
irb> s.scan(/(\d*)--([a-z]*)/)
=> [["123", "abc"], ["123", "abc"], ["123", "abc"]]
irb> s.scan(/(\d*)--([a-z]*)/) do |number, chars|
irb* p [number,chars]
irb> end
["123", "abc"]
["123", "abc"]
["123", "abc"]
=> "123--abc,123--abc,123--abc"
Chiming in super-late, but here's a simple way of replicating String#scan but getting the matchdata instead:
matches = []
foo.scan(regex){ matches << $~ }
matches now contains the MatchData objects that correspond to scanning the string.
You can extract the used variables from the regexp using names method. So what I did is, I used regular scan method to get the matches, then zipped names and every match to create a Hash.
class String
def scan2(regexp)
names = regexp.names
scan(regexp).collect do |match|
Hash[names.zip(match)]
end
end
end
Usage:
>> "aaa http://www.google.com.tr aaa https://www.yahoo.com.tr ddd".scan2 /(?<url>(?<protocol>https?):\/\/[\S]+)/
=> [{"url"=>"http://www.google.com.tr", "protocol"=>"http"}, {"url"=>"https://www.yahoo.com.tr", "protocol"=>"https"}]
#Nakilon is correct showing scan with a regex, however you don't even need to venture into regex land if you don't want to:
s = "123--abc,123--abc,123--abc"
s.split(',')
#=> ["123--abc", "123--abc", "123--abc"]
s.split(',').inject([]) { |a,s| a << s.split('--'); a }
#=> [["123", "abc"], ["123", "abc"], ["123", "abc"]]
This returns an array of arrays, which is convenient if you have multiple occurrences and need to see/process them all.
s.split(',').inject({}) { |h,s| n,v = s.split('--'); h[n] = v; h }
#=> {"123"=>"abc"}
This returns a hash, which, because the elements have the same key, has only the unique key value. This is good when you have a bunch of duplicate keys but want the unique ones. Its downside occurs if you need the unique values associated with the keys, but that appears to be a different question.
If using ruby >=1.9 and the named captures, you could:
class String
def scan2(regexp2_str, placeholders = {})
return regexp2_str.to_re(placeholders).match(self)
end
def to_re(placeholders = {})
re2 = self.dup
separator = placeholders.delete(:SEPARATOR) || '' #Returns and removes separator if :SEPARATOR is set.
#Search for the pattern placeholders and replace them with the regex
placeholders.each do |placeholder, regex|
re2.sub!(separator + placeholder.to_s + separator, "(?<#{placeholder}>#{regex})")
end
return Regexp.new(re2, Regexp::MULTILINE) #Returns regex using named captures.
end
end
Usage (ruby >=1.9):
> "1234:Kalle".scan2("num4:name", num4:'\d{4}', name:'\w+')
=> #<MatchData "1234:Kalle" num4:"1234" name:"Kalle">
or
> re="num4:name".to_re(num4:'\d{4}', name:'\w+')
=> /(?<num4>\d{4}):(?<name>\w+)/m
> m=re.match("1234:Kalle")
=> #<MatchData "1234:Kalle" num4:"1234" name:"Kalle">
> m[:num4]
=> "1234"
> m[:name]
=> "Kalle"
Using the separator option:
> "1234:Kalle".scan2("#num4#:#name#", SEPARATOR:'#', num4:'\d{4}', name:'\w+')
=> #<MatchData "1234:Kalle" num4:"1234" name:"Kalle">
I needed something similar recently. This should work like String#scan, but return an array of MatchData objects instead.
class String
# This method will return an array of MatchData's rather than the
# array of strings returned by the vanilla `scan`.
def match_all(regex)
match_str = self
match_datas = []
while match_str.length > 0 do
md = match_str.match(regex)
break unless md
match_datas << md
match_str = md.post_match
end
return match_datas
end
end
Running your sample data in the REPL results in the following:
> "123--abc,123--abc,123--abc".match_all(/(?<number>\d*)--(?<chars>[a-z]*)/)
=> [#<MatchData "123--abc" number:"123" chars:"abc">,
#<MatchData "123--abc" number:"123" chars:"abc">,
#<MatchData "123--abc" number:"123" chars:"abc">]
You may also find my test code useful:
describe String do
describe :match_all do
it "it works like scan, but uses MatchData objects instead of arrays and strings" do
mds = "ABC-123, DEF-456, GHI-098".match_all(/(?<word>[A-Z]+)-(?<number>[0-9]+)/)
mds[0][:word].should == "ABC"
mds[0][:number].should == "123"
mds[1][:word].should == "DEF"
mds[1][:number].should == "456"
mds[2][:word].should == "GHI"
mds[2][:number].should == "098"
end
end
end
I really liked #Umut-Utkan's solution, but it didn't quite do what I wanted so I rewrote it a bit (note, the below might not be beautiful code, but it seems to work)
class String
def scan2(regexp)
names = regexp.names
captures = Hash.new
scan(regexp).collect do |match|
nzip = names.zip(match)
nzip.each do |m|
captgrp = m[0].to_sym
captures.add(captgrp, m[1])
end
end
return captures
end
end
Now, if you do
p '12f3g4g5h5h6j7j7j'.scan2(/(?<alpha>[a-zA-Z])(?<digit>[0-9])/)
You get
{:alpha=>["f", "g", "g", "h", "h", "j", "j"], :digit=>["3", "4", "5", "5", "6", "7", "7"]}
(ie. all the alpha characters found in one array, and all the digits found in another array). Depending on your purpose for scanning, this might be useful. Anyway, I love seeing examples of how easy it is to rewrite or extend core Ruby functionality with just a few lines!
A year ago I wanted regular expressions that were more easy to read and named the captures, so I made the following addition to String (should maybe not be there, but it was convenient at the time):
scan2.rb:
class String
#Works as scan but stores the result in a hash indexed by variable/constant names (regexp PLACEHOLDERS) within parantheses.
#Example: Given the (constant) strings BTF, RCVR and SNDR and the regexp /#BTF# (#RCVR#) (#SNDR#)/
#the matches will be returned in a hash like: match[:RCVR] = <the match> and match[:SNDR] = <the match>
#Note: The #STRING_VARIABLE_OR_CONST# syntax has to be used. All occurences of #STRING# will work as #{STRING}
#but is needed for the method to see the names to be used as indices.
def scan2(regexp2_str, mark='#')
regexp = regexp2_str.to_re(mark) #Evaluates the strings. Note: Must be reachable from here!
hash_indices_array = regexp2_str.scan(/\(#{mark}(.*?)#{mark}\)/).flatten #Look for string variable names within (#VAR#) or # replaced by <mark>
match_array = self.scan(regexp)
#Save matches in hash indexed by string variable names:
match_hash = Hash.new
match_array.flatten.each_with_index do |m, i|
match_hash[hash_indices_array[i].to_sym] = m
end
return match_hash
end
def to_re(mark='#')
re = /#{mark}(.*?)#{mark}/
return Regexp.new(self.gsub(re){eval $1}, Regexp::MULTILINE) #Evaluates the strings, creates RE. Note: Variables must be reachable from here!
end
end
Example usage (irb1.9):
> load 'scan2.rb'
> AREA = '\d+'
> PHONE = '\d+'
> NAME = '\w+'
> "1234-567890 Glenn".scan2('(#AREA#)-(#PHONE#) (#NAME#)')
=> {:AREA=>"1234", :PHONE=>"567890", :NAME=>"Glenn"}
Notes:
Of course it would have been more elegant to put the patterns (e.g. AREA, PHONE...) in a hash and add this hash with patterns to the arguments of scan2.
Piggybacking off of Mark Hubbart's answer, I added the following monkey-patch:
class ::Regexp
def match_all(str)
matches = []
str.scan(self) { matches << $~ }
matches
end
end
which can be used as /(?<letter>\w)/.match_all('word'), and returns:
[#<MatchData "w" letter:"w">, #<MatchData "o" letter:"o">, #<MatchData "r" letter:"r">, #<MatchData "d" letter:"d">]
This relies on, as others have said, the use of $~ in the scan block for the match data.
I like the match_all given by John, but I think it has an error.
The line:
match_datas << md
works if there are no captures () in the regex.
This code gives the whole line up to and including the pattern matched/captured by the regex. (The [0] part of MatchData) If the regex has capture (), then this result is probably not what the user (me) wants in the eventual output.
I think in the case where there are captures () in regex, the correct code should be:
match_datas << md[1]
The eventual output of match_datas will be an array of pattern capture matches starting from match_datas[0]. This is not quite what may be expected if a normal MatchData is wanted which includes a match_datas[0] value which is the whole matched substring followed by match_datas[1], match_datas[[2],.. which are the captures (if any) in the regex pattern.
Things are complex - which may be why match_all was not included in native MatchData.

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