index.php
function delete_function(value){
alert("value is "+value);
$(document).ready(function () {
$.ajax({
url: "fields.php",
type: "POST",
datatype: "html",
data: { "delval": value},
success: function(data){
//console.log(data);
//jQuery(".res").html(data);
// var result = $(data).filter('div.dummy');
//$(".dummy").append($(data).filter('div.dummy'));
var input_value = $(data).find("#lastname").val();
alert(input_value);
//$(data) = "dfsadf";
$(".dummy").replaceWith($(data).find('#lab').val());
//$(".dummy").replaceWith($(data).val());
//$(".dummy").replaceWith($(data).find('#submit').val());
// $(".dummy").remove();
//alert(data);
$(".class"+value).remove();
}
});
alert("delete clicked ");
});
}
fields.php
" value="iamkarthik">
" value= id="firstname" placeholder="First Name">
" placeholder="Last Name">
" placeholder="Email address">
" placeholder="Department">
" placeholder="Date of joining">
" placeholder="Basic pay">
" onclick="delete_function()" id="delete" value="delete" class="input_fields" >
on delete function, please remove the $(document).ready , as this is event listener, it isn't triggered when you call the function
function delete_function(value){
alert("value is "+value);
$.ajax({
url: "fields.php",
type: "POST",
datatype: "html",
data: { "delval": value},
success: function(data){
//console.log(data);
//jQuery(".res").html(data);
// var result = $(data).filter('div.dummy');
//$(".dummy").append($(data).filter('div.dummy'));
var input_value = $(data).find("#lastname").val();
alert(input_value);
//$(data) = "dfsadf";
$(".dummy").replaceWith($(data).find('#lab').val());
//$(".dummy").replaceWith($(data).val());
//$(".dummy").replaceWith($(data).find('#submit').val());
// $(".dummy").remove();
//alert(data);
$(".class"+value).remove();
}
});
alert("delete clicked ");
}
Related
I'm looking for solution in opencart.
Need to rebuild cart.add function for adding product with option value.
By default:
'add': function(product_id, quantity) {
$.ajax({
url: 'index.php?route=checkout/cart/add',
type: 'post',
data: 'product_id=' + product_id + '&quantity=' + (typeof(quantity) != 'undefined' ? quantity : 1),
dataType: 'json',
beforeSend: function() {
$('#cart > button').button('loading');
},
success: function(json) {
$('.alert, .text-danger').remove();
$('#cart > button').button('reset');
if (json['redirect']) {
location = json['redirect'];
}
if (json['success']) {
$('#content').parent().before('<div class="alert alert-success"><i class="fa fa-check-circle"></i> ' + json['success'] + '<button type="button" class="close" data-dismiss="alert">×</button></div>');
$('#cart-total').html(json['total']);
$('html, body').animate({ scrollTop: 0 }, 'slow');
$('#cart > ul').load('index.php?route=common/cart/info ul li');
}
}
});
checkout/cart/add php side for option:
if (isset($this->request->post['option'])) {
$option = array_filter($this->request->post['option']);
} else {
$option = array();
}
Any solutions?
You can do this in the following way. Create a simple Javascript object.
var productData = {'product_id' : PRODUCT_IDS.CARD, 'quantity': 1,'option':{'229':"Some option value"}};
And send the request as follows. Converting the object to post params using the param function.
$.ajax({
url: 'index.php?route=checkout/cart/add',
type: 'post',
data: $.param(productData),
dataType: 'json',
beforeSend: function () {
},
complete: function () {
},
success: function (json) {
},
error: function (xhr, ajaxOptions, thrownError) {
}
});
Also there are some other ways to do this, you can see possible payload formats in the /controller/checkout/cart.php file.
I would like to close my modalbox, so I return to the same page, after I click the "Select" button.
I am on shuffle.php. I open the modalbox and call the code in updaterecords.php. When I click Select I should return to shuffle.php. The problem is right now that I am redirected to updaterecords.php.
I try to solve that with adding this code to my AJAX call:
$('#editBox').on('hide.bs.modal', function (data) {
$('#editBox').modal('hide')
})
But I am still redirected. Is the code I added in the wrong place?
shuffle.php
<div class="modal-footer msg">
<form action="updaterecords.php" method="post">
<input type="hidden" id="fantasy-id" value="" name="id" />
<button type="submit" name="selectStore" >Select</button>
<button type="button" data-dismiss="modal">Close</button>
</form>
</div>
updaterecords.php
$(document).ready(function() {
$(".btn-open-modal").click(function() {
var id = $(this).data("id");
$.ajax({
type: 'post',
url: 'getdata.php',
data: {
post_id: id
},
success: function(data) {
console.log(data);
var jdata = JSON.parse(data);
if (jdata) {
console.log("is json");
$("#editBox").modal().show();
$('#id').val(jdata.id);
$("#editBox .modal-title").html(jdata.headline);
$("#editBox .modal-body").html("Weekday: " + jdata.weekday + "<br><br>Description: " + jdata.description); // + " " + $query $query => query
$('#editBox').on('hide.bs.modal', function (data) {
$('#editBox').modal('hide')
})
} else {
console.log("not valid json: " + data);
}
}
});
});
});
Please try to use $('.modal').modal('hide'); on updaterecords.php.
$(document).ready(function() {
$(".btn-open-modal").click(function() {
var id = $(this).data("id");
$('.modal').modal('hide');
$.ajax({
type: 'post',
url: 'getdata.php',
data: {
post_id: id
},
success: function(data) {
console.log(data);
var jdata = JSON.parse(data);
if (jdata) {
console.log("is json");
$("#editBox").modal().show();
$('#id').val(jdata.id);
$("#editBox .modal-title").html(jdata.headline);
$("#editBox .modal-body").html("Weekday: " + jdata.weekday + "<br><br>Description: " + jdata.description); // + " " + $query $query => query
$('#editBox').on('hide.bs.modal', function (data) {
$('#editBox').modal('hide')
})
} else {
console.log("not valid json: " + data);
}
}
});
});
});
I'm trying to integrate AJAX with a mailchimp form. I’ve followed another member’s answer but still cannot get it to work. Could you guys see what's wrong with my code?
Thank you.
Here is my code:
<form id="form">
<script>
$( "button" ).click(function() {
formData = {
u: "xxxxxxxxx",
id: "xxxxxxxxx"
};
$.ajax({
url: "http://xxxxxxxxxxxxxxxxxxxxxxx/post-json?",
type: "GET",
crossDomain: true,
contentType: 'application/json',
data: formData,
dataType: "json",
success: function(data) {
//action
},
error: function() {
//action
}
});
});
</script>
<fieldset>
<label for="email_input_id"><input placeholder=
"Type Your Email" type="email" /></label>
</fieldset><button type= "submit">Submit</button>
I finally got my code working.
<form id="form" action="https://xxxxx.com/subscribe/post-json?u=xxxxx&id=xxxx&c=?" method="GET">
<input type="hidden" name="u" value="xxxx">
<input type="hidden" name="id" value="xxxx">
<input type="EMAIL" autocapitalize="off" autocorrect="off"
name="MERGE0" id="MERGE0" size="25" value=""
placeholder="Type your email and press enter">
<p id="response"> </p>
</form>
<script>
$('#form').submit(function(e) {
var $this = $(this);
var paragraph = document.getElementById('response');
$.ajax({
type: "GET",
url: "https://xxx.com/subscribe/post-json?u=xx&id=xx&c=?",
data: $this.serialize(),
dataType : 'json',
contentType: "application/json; charset=utf-8",
error : function(err) { alert("Could not connect to the registration server."); },
success : function(data) {
if (data.result != "success") {
paragraph.innerHTML = data.msg;
} else {
paragraph.innerHTML = data.msg;
}
}
});
return false;
});
</script>
I have a problem with my script. Why this AJAX don't do anything..
Thanks For help..
In body tag
<div class="share_playlist">
<a href="#" data-toggle="tooltip" title="add to playlist" class="plyshr" id="<?php echo $tracks['track_id']; ?>">
<img src="assets/img/ico/share_icon.png" width="28">
</a>
</div>
and AJAX
$(document).ready(function(){
$(".plyshr").click(function() {
var id = $(this).attr('id');
var dataString = 'id='+ id ;
var parent = $(this);
//alert (data);
$.ajax({
type: "POST",
url: "playlist.php",
success: function(html)
data: dataString,
cache: false,
success: function(html)
}).done(function( msg ) {
parent.html(html);
});
});
});
some more details
And in playlist.php
include 'connect.php';
session_start();
$ip=$_SESSION['id'];
if ($_POST['id'])
{
$id=$_POST['id'];
$ip_sql="insert into playlist (id_user, track_id) values ('$ip','$id')";
$list = mysql_query($ip_sql);
if(isset ($list)){
echo ("succes");
}
else
{
echo("failed");
}
}
you are having a syntax error in your javascript
success: function(html){
data: dataString,
there should be a brace
I have an ajax+jquery navigation system with $.ajax, and I`m trying to do a second call to $.ajax to send a contact form infos, but, when I add the second $.ajax all just stop working.
First Call -
function loadPage(url)
{
url=url.replace('#!','');
$('#loading').css('visibility','visible');
$.ajax({
type: "POST",
url: "loader.php",
data: 'page='+url,
dataType: "html",
success: function(msg){
if(parseInt(msg)!=0)
{
$('#conteudo').html(msg);
$('#loading').css('visibility','hidden');
}
}
});
}
Second Call
$("#enviar").click(function() {
var str = $("form").serializeArray();
$.ajax({
type: "POST",
url: "update.php",
data: str,
success: function(mn) {
if(parseInt(mn)!=0)
{
$("#conteudo").html(mn);
$("#enviado").css('visibility','visible');
}
}
return false;
});
#EDIT
Very good! The first ajax is not stucking anymore, but this second is not working as expected.
This is intended to parse $_POST values to a php script and if ok just turn div visible..
How I`m doing that -
<form name="formcontato" id="form">
<fieldset>
<label>Seu nome</label>
<input type="text" name="nome" class="input-block-level">
<label>Email</label>
<input type="email" name="email" placeholder="seu#email.com" class="input-block-level">
<div class="form-actions">
<input type="button" name="enviar" value="Enviar" id="enviar" class="btn btn-baixar" />
</div>
</fieldset>
</form>
This is the form.
$("#enviar").click(function () {
var str = $("#form").serialize();
$.ajax({
type: "POST",
url: "update.php",
data: str,
success: function (mn) {
alert("Ok!");
if (parseInt(mn) != 0) {
$("#conteudo").html(mn);
$("#enviado").css('visibility', 'visible');
}
}
});
return false;
});
This is the js
if($_POST) {
$nome = trim($_POST['nome']);
echo $nome;
}
This is the update.php
In what you posted, the second function does not properly close the $.ajax() function with a }); so it would generate a parse error and none of the code in this block would be available.
Try this where the $.ajax() call is succesfully closed.
$("#enviar").click(function () {
var str = $("form").serializeArray();
$.ajax({
type: "POST",
url: "update.php",
data: str,
success: function (mn) {
if (parseInt(mn) != 0) {
$("#conteudo").html(mn);
$("#enviado").css('visibility', 'visible');
}
}
});
return false;
});
FYI, proper and consistent indentation is essential to spotting these issues.