Related
I have created my fiddle example here: FIDDLE
Here is also athe code from the fiddle:
CREATE TABLE T1(ID INT, CODE INT, CODE_NAME VARCHAR(100), PARENT_ID INT);
INSERT INTO T1 VALUES(100,1,'LEVEL 1', NULL);
INSERT INTO T1 VALUES(110,11,'LEVEL 2', 100);
INSERT INTO T1 VALUES(120,111,'LEVEL 3', 110);
INSERT INTO T1 VALUES(125,112,'LEVEL 3', 110);
INSERT INTO T1 VALUES(130,1111,'LEVEL 4', 120);
INSERT INTO T1 VALUES(200,2,'LEVEL 1', NULL);
INSERT INTO T1 VALUES(210,21,'LEVEL 2', 200);
INSERT INTO T1 VALUES(300,3,'LEVEL 1', NULL);
I have trouble finding the soultuin how to get from that table this result:
| CODE | CODE NAME | CODE 1 |CODE NAME 1| CODE 2 | CODE NAME 2| CODE 3 | CODE NAME 3 |
+--------+------------+--------+-----------+--------+------------+--------+-------------+
| 1 | LEVEL 1 | 11 | LEVEL 2 | 111 | LEVEL 3 | 1111 | LEVEL 4 |
| 1 | LEVEL 1 | 11 | LEVEL 2 | 112 | LEVEL 3 | 112 | LEVEL 3 |
| 2 | LEVEL 1 | 21 | LEVEL 2 | 21 | LEVEL 2 | 21 | LEVEL 2 |
| 3 | LEVEL 1 | 3 | LEVEL 1 | 3 | LEVEL 1 | 3 | LEVEL 1 |
I have tried something with connect by but that is not what I need(I think)...
The max I will ever have is 4 levels and if there are only two levels in the data then the 3rd and the 4th level should be filled wiht the values of the last existing value. The same rule is valid if there are 3 levels or 1 level.
You can use a recursive sub-query:
WITH hierarchy (
code, code_name,
code1, code_name1,
code2, code_name2,
code3, code_name3,
id, depth
) AS (
SELECT code,
code_name,
CAST(NULL AS INT),
CAST(NULL AS VARCHAR2(100)),
CAST(NULL AS INT),
CAST(NULL AS VARCHAR2(100)),
CAST(NULL AS INT),
CAST(NULL AS VARCHAR2(100)),
id,
1
FROM t1
WHERE parent_id IS NULL
UNION ALL
SELECT h.code,
h.code_name,
CASE depth WHEN 1 THEN COALESCE(t1.code, h.code) ELSE h.code1 END,
CASE depth WHEN 1 THEN COALESCE(t1.code_name, h.code_name) ELSE h.code_name1 END,
CASE depth WHEN 2 THEN COALESCE(t1.code, h.code1) ELSE h.code2 END,
CASE depth WHEN 2 THEN COALESCE(t1.code_name, h.code_name1) ELSE h.code_name2 END,
CASE depth WHEN 3 THEN COALESCE(t1.code, h.code2) ELSE h.code3 END,
CASE depth WHEN 3 THEN COALESCE(t1.code_name, h.code_name2) ELSE h.code_name3 END,
t1.id,
h.depth + 1
FROM hierarchy h
LEFT OUTER JOIN t1
ON (h.id = t1.parent_id)
WHERE depth < 4
)
CYCLE code, depth SET is_cycle TO 1 DEFAULT 0
SELECT code, code_name,
code1, code_name1,
code2, code_name2,
code3, code_name3
FROM hierarchy
WHERE depth = 4;
Which, for the sample data:
CREATE TABLE T1(ID, CODE, CODE_NAME, PARENT_ID) AS
SELECT 100, 1, 'LEVEL 1', NULL FROM DUAL UNION ALL
SELECT 110, 11, 'LEVEL 2', 100 FROM DUAL UNION ALL
SELECT 120, 111, 'LEVEL 3', 110 FROM DUAL UNION ALL
SELECT 130, 1111, 'LEVEL 4', 120 FROM DUAL UNION ALL
SELECT 200, 2, 'LEVEL 1', NULL FROM DUAL UNION ALL
SELECT 210, 21, 'LEVEL 2a', 200 FROM DUAL UNION ALL
SELECT 220, 22, 'LEVEL 2b', 200 FROM DUAL UNION ALL
SELECT 230, 221, 'LEVEL 3', 220 FROM DUAL UNION ALL
SELECT 300, 3, 'LEVEL 1', NULL FROM DUAL;
Outputs:
CODE
CODE_NAME
CODE1
CODE_NAME1
CODE2
CODE_NAME2
CODE3
CODE_NAME3
1
LEVEL 1
11
LEVEL 2
111
LEVEL 3
1111
LEVEL 4
3
LEVEL 1
3
LEVEL 1
3
LEVEL 1
3
LEVEL 1
2
LEVEL 1
21
LEVEL 2a
21
LEVEL 2a
21
LEVEL 2a
2
LEVEL 1
22
LEVEL 2b
221
LEVEL 3
221
LEVEL 3
db<>fiddle here
For sample data you posted:
SQL> select * from t1;
ID CODE CODE_NAME PARENT_ID
---------- ---------- ---------- ----------
100 1 LEVEL 1
110 11 LEVEL 2 100
120 111 LEVEL 3 110
130 1111 LEVEL 4 120
200 2 LEVEL 1
210 21 LEVEL 2 200
6 rows selected.
SQL>
an ugly (and who-knows-how-performant) query that, though, returns desired result is
with temp as
(select id, code, code_name, parent_id, level lvl,
row_number() over (partition by level order by id) rn
from t1
start with parent_id is null
connect by prior id = parent_id
),
a as
(select * from temp where lvl = 1),
b as
(select * from temp where lvl = 2),
c as
(select * from temp where lvl = 3),
d as
(select * from temp where lvl = 4)
select
a.code code1, a.code_name code_name1,
coalesce(b.code, a.code) code2, coalesce(b.code_name, a.code_name) code_name2,
coalesce(c.code, b.code, a.code) code3, coalesce(c.code_name, b.code_name, a.code_name) code_name3,
coalesce(d.code, c.code, b.code, a.code) code4, coalesce(d.code_name, c.code_name, b.code_name, a.code_name) code_name4
from a join b on b.rn = a.rn
left join c on c.rn = b.rn
left join d on d.rn = c.rn;
which results in
CODE1 CODE_NAME1 CODE2 CODE_NAME2 CODE3 CODE_NAME3 CODE4 CODE_NAME4
---------- ---------- ---------- ---------- ---------- ---------- ---------- ----------
1 LEVEL 1 11 LEVEL 2 111 LEVEL 3 1111 LEVEL 4
2 LEVEL 1 21 LEVEL 2 21 LEVEL 2 21 LEVEL 2
What does it do?
temp CTE creates a hierarchy; additionally, row_number function numbers each row within the same level
a, b, c, d CTEs extract values belonging to their own level value (you said there can be up to 4 levels)
finally, coalesce on column names along with outer join do the job
From your example I assume you want to see one row per root key as your example is not realy a tree but a bamboo
If so this is a trivial PIVOT query - unfortunately limited to some level deep (here example for your 4 levels)
with p (ROOT_CODE, CODE, CODE_NAME, ID, PARENT_ID, LVL) as (
select CODE, CODE, CODE_NAME, ID, PARENT_ID, 1 LVL from t1 where PARENT_ID is NULL
union all
select p.ROOT_CODE, c.CODE, c.CODE_NAME, c.ID, c.PARENT_ID, p.LVL+1 from t1 c
join p on c.PARENT_ID = p.ID),
t2 as (
select ROOT_CODE, CODE,CODE_NAME,LVL from p)
select * from t2
PIVOT
(max(CODE) code, max(CODE_NAME) code_name
for LVL in (1 as "LEV1",2 as "LEV2",3 as "LEV3",4 as "LEV4")
);
ROOT_CODE LEV1_CODE LEV1_CODE_ LEV2_CODE LEV2_CODE_ LEV3_CODE LEV3_CODE_ LEV4_CODE LEV4_CODE_
---------- ---------- ---------- ---------- ---------- ---------- ---------- ---------- ----------
1 1 LEVEL 1 11 LEVEL 2 111 LEVEL 3 1111 LEVEL 4
2 2 LEVEL 1 21 LEVEL 2
The recursive CTE calculates the ROOT_CODE required for the pivot.
I' leaving as an exercise to fill the not defined levels (with COALESCE) with the previous values as in your example.
In case (as commented) you nedd oner row for each leave key a simple solution based on CONNECT_BY_PATHis possible.
I'm using again *recursive CTEcalculating the path from *root* to the *current node* and finaly filtering in the result the *leaves* (IDthat are notPARENT_ID`)
with p ( CODE, CODE_NAME, ID, PARENT_ID, PATH) as (
select CODE, CODE_NAME, ID, PARENT_ID, to_char(CODE)||'|'||CODE_NAME PATH from t1 where PARENT_ID is NULL
union all
select c.CODE, c.CODE_NAME, c.ID, c.PARENT_ID, p.PATH ||'|'||to_char(c.CODE)||'|'||c.CODE_NAME from t1 c
join p on c.PARENT_ID = p.ID)
select PATH from p
where ID in (select ID from T1 MINUS select PARENT_ID from T1)
order by 1;
The result holds for any level deepness and is concatenated string with delimiter
PATH
----------------------------------------------
1|LEVEL 1|11|LEVEL 2|111|LEVEL 3|1111|LEVEL 4
1|LEVEL 1|11|LEVEL 2|112|LEVEL 3
2|LEVEL 1|21|LEVEL 2
3|LEVEL 1
Use substr instr to extract and coalesce for the default values.
Solution using a hierarchical query - we record the code and code_name paths, then we break them apart. Level is used to decide whether we populate data from the paths or from the leaf node. The solution assumes the codes and code names do not contain the forward-slash character (if they may, use another separator in the paths - perhaps some control character like chr(31), the unit separator character in ASCII and Unicode).
To break apart the paths, I used regexp_substr as it's easier to work with (and, moreover, I assumed all codes and code names are non-null - if they may be null, the solution can be adapted easily). If this proves to be slow, that can be changed to use standard string functions.
with
p (code, code_name, parent_id, lvl, code_pth, code_name_pth) as (
select code, code_name, parent_id, level,
sys_connect_by_path(code, '/') || ',' ,
sys_connect_by_path(code_name, '/') || ','
from t1
where connect_by_isleaf = 1
start with parent_id is null
connect by parent_id = prior id
)
select case when lvl = 1 then code
else to_number(regexp_substr(code_pth, '[^/]+', 1, 1)) end as code,
case when lvl =1 then code_name
else regexp_substr(code_name_pth, '[^/]+', 1, 1) end as code_name,
case when lvl <= 2 then code
else to_number(regexp_substr(code_pth, '[^/]+', 1, 2)) end as code_1,
case when lvl <= 2 then code_name
else regexp_substr(code_name_pth, '[^/]+', 1, 2) end as code_name_1,
case when lvl <= 3 then code
else to_number(regexp_substr(code_pth, '[^/]+', 1, 3)) end as code_2,
case when lvl <= 3 then code_name
else regexp_substr(code_name_pth, '[^/]+', 1, 3) end as code_name_2,
code as code_3,
code_name as code_name_3
from p;
I got a single string row split into rows
For example,
A,B,C,D,E
into
A
B
C
D
E
but what I would like to is multiple columns' single row
| A,B,C | H,I,J,K,L | Q,R,X,Y,Z |
into
A | H | Q
B | I | R
C | J | X
| K | Y
| L |
How can I do this in oracle?
You can use hiearchy query as follows:
SQL> WITH DATAA ( D ) AS (
2 SELECT '| A,B,C | H,I,J,K,L | Q,R,X,Y,Z |'
3 FROM DUAL
4 )
5 -- your query starts from here
6 SELECT TRIM(REGEXP_SUBSTR(REGEXP_SUBSTR(D.D, '[^|]+', 1, 1), '[^,]+', 1, LEVEL)) AS COL1,
7 TRIM(REGEXP_SUBSTR(REGEXP_SUBSTR(D.D, '[^|]+', 1, 2), '[^,]+', 1, LEVEL)) AS COL2,
8 TRIM(REGEXP_SUBSTR(REGEXP_SUBSTR(D.D, '[^|]+', 1, 3), '[^,]+', 1, LEVEL)) AS COL3
9 FROM DATAA D
10 CONNECT BY LEVEL <= (
11 SELECT MAX(REGEXP_COUNT((REGEXP_SUBSTR(D.D, '[^|]+', 1, COLUMN_VALUE)), ',')) + 1
12 FROM DATAA D
13 CROSS JOIN TABLE ( CAST(MULTISET(
14 SELECT LEVEL LVL
15 FROM DUAL
16 CONNECT BY LEVEL <= REGEXP_COUNT(D.D, '[^|]+')
17 ) AS SYS.ODCIVARCHAR2LIST) ) LVLS
18 );
COL1 COL2 COL3
------- ----------- -----------
A H Q
B I R
C J X
K Y
L Z
SQL>
I am creating a function that returns a table type object based on the split of the chain, the query is the following:
WITH COLUMNA AS (
SELECT ROWNUM COL_ID, REGEXP_SUBSTR ('A,B,C:D,E,F:','[^:]+',1,LEVEL) COL FROM DUAL
CONNECT BY REGEXP_SUBSTR ('A,B,C:D,E,F:','[^:]+',1,LEVEL) IS NOT NULL
ORDER BY COL_ID
)
SELECT * FROM (SELECT COL_ID, ROWNUM FIL_ID, SUBSTR(COL, INSTR(COL, ',', 1, LVL) + 1, INSTR(COL, ',', 1, LVL + 1) - INSTR(COL, ',', 1, LVL) - 1) NAME
FROM
( SELECT ',' || COL || ',' AS COL, COL_ID FROM COLUMNA ),
( SELECT LEVEL AS LVL FROM DUAL CONNECT BY LEVEL <= 100 )
WHERE LVL <= LENGTH(COL) - LENGTH(REPLACE(COL, ',')) - 1
ORDER BY COL_ID, NAME
) FILA
The result is as follows:
COL_ID FIL_ID NAME
1 1 A
1 2 B
1 3 C
2 4 D
2 5 E
2 6 F
And I Need To Get The Following Result
COL_ID VAL1 VAL2 VAL3 VALN
1 A B C X
2 D E F Y
I hope your valuable help!!!
You need to have a fixed number of columns in your object:
CREATE TYPE values_obj AS OBJECT(
COL_id INTEGER,
VAL1 VARCHAR2(10),
VAL2 VARCHAR2(10),
VAL3 VARCHAR2(10),
VAL4 VARCHAR2(10),
VAL5 VARCHAR2(10)
)
/
CREATE TYPE values_tab AS TABLE OF values_obj
/
CREATE OR REPLACE FUNCTION split_values(
in_list VARCHAR2
) RETURN values_tab
IS
vals VALUES_TAB;
BEGIN
SELECT values_obj(
LEVEL,
REGEXP_SUBSTR( in_list, '([^:,]*),?([^:,]*),?([^:,]*),?([^:,]*),?([^:,]*).*?(:|$)', 1, LEVEL, NULL, 1 ),
REGEXP_SUBSTR( in_list, '([^:,]*),?([^:,]*),?([^:,]*),?([^:,]*),?([^:,]*).*?(:|$)', 1, LEVEL, NULL, 2 ),
REGEXP_SUBSTR( in_list, '([^:,]*),?([^:,]*),?([^:,]*),?([^:,]*),?([^:,]*).*?(:|$)', 1, LEVEL, NULL, 3 ),
REGEXP_SUBSTR( in_list, '([^:,]*),?([^:,]*),?([^:,]*),?([^:,]*),?([^:,]*).*?(:|$)', 1, LEVEL, NULL, 4 ),
REGEXP_SUBSTR( in_list, '([^:,]*),?([^:,]*),?([^:,]*),?([^:,]*),?([^:,]*).*?(:|$)', 1, LEVEL, NULL, 5 )
)
BULK COLLECT INTO vals
FROM DUAL
CONNECT BY LEVEL < REGEXP_COUNT( in_list, '([^:,]*),?([^:,]*),?([^:,]*),?([^:,]*),?([^:,]*).*?(:|$)' );
RETURN vals;
END;
/
Then you can do:
SELECT *
FROM TABLE( split_values( 'A,B,C:D,E,F,G:H,I,J,K,L,M::N' ) );
Which outputs:
COL_ID VAL1 VAL2 VAL3 VAL4 VAL5
------ ---- ---- ---- ---- ----
1 A B C - -
2 D E F G -
3 H I J K L
4 - - - - -
5 N - - - -
I've source data Like this
Childid | Parent ID
------- | ---------
1 | NULL
2 | 1
3 | 1
4 | 2
5 | 4
6 | 5
7 | 6
I need an oracle query to show the out put like this.
Child | L1Parent | l2Parent | L3Parent | L4Parent | L5Parent
----- | -------- | -------- | -------- | -------- | --------
1 | NULL
2 | 1
3 | 1
4 | 1 | 2
5 | 1 | 2 | 4
6 | 1 | 2 | 4 | 5
7 | 1 | 2 | 4 | 5 | 6
This seems to me easier:
SELECT childId,
trim(SYS_CONNECT_BY_PATH(decode(level,2,parentId,''), ' ')) AS L1,
trim(SYS_CONNECT_BY_PATH(decode(level,3,parentId,''), ' ')) AS L2,
trim(SYS_CONNECT_BY_PATH(decode(level,4,parentId,''), ' ')) AS L3,
trim(SYS_CONNECT_BY_PATH(decode(level,5,parentId,''), ' ')) AS L4,
trim(SYS_CONNECT_BY_PATH(decode(level,6,parentId,''), ' ')) AS L5,
trim(SYS_CONNECT_BY_PATH(decode(level,7,parentId,''), ' ')) AS L6,
trim(SYS_CONNECT_BY_PATH(decode(level,8,parentId,''), ' ')) AS L7
FROM table_name
START WITH parentId is null
CONNECT BY PRIOR childId = parentId;
Oracle Setup:
CREATE TABLE table_name ( childId, parentId ) AS
SELECT 1, NULL FROM DUAL UNION ALL
SELECT 2, 1 FROM DUAL UNION ALL
SELECT 3, 1 FROM DUAL UNION ALL
SELECT 4, 2 FROM DUAL UNION ALL
SELECT 5, 4 FROM DUAL UNION ALL
SELECT 6, 5 FROM DUAL UNION ALL
SELECT 7, 6 FROM DUAL;
Query:
SELECT childId,
CASE WHEN p02 = 1 THEN NULL WHEN p03 = 1 THEN SUBSTR( path, p02 ) ELSE SUBSTR( path, p02, p03 - p02 - 1 ) END AS Lp1,
CASE WHEN p03 = 1 THEN NULL WHEN p04 = 1 THEN SUBSTR( path, p03 ) ELSE SUBSTR( path, p03, p04 - p03 - 1 ) END AS lp2,
CASE WHEN p04 = 1 THEN NULL WHEN p05 = 1 THEN SUBSTR( path, p04 ) ELSE SUBSTR( path, p04, p05 - p04 - 1 ) END AS lp3,
CASE WHEN p05 = 1 THEN NULL WHEN p06 = 1 THEN SUBSTR( path, p05 ) ELSE SUBSTR( path, p05, p06 - p05 - 1 ) END AS lp4,
CASE WHEN p06 = 1 THEN NULL WHEN p07 = 1 THEN SUBSTR( path, p06 ) ELSE SUBSTR( path, p06, p07 - p06 - 1 ) END AS lp5,
CASE WHEN p07 = 1 THEN NULL WHEN p08 = 1 THEN SUBSTR( path, p07 ) ELSE SUBSTR( path, p07, p08 - p07 - 1 ) END AS lp6
FROM (
SELECT childId,
path,
INSTR( path, '/', 1, 2 ) + 1 AS p02,
INSTR( path, '/', 1, 3 ) + 1 AS p03,
INSTR( path, '/', 1, 4 ) + 1 AS p04,
INSTR( path, '/', 1, 5 ) + 1 AS p05,
INSTR( path, '/', 1, 6 ) + 1 AS p06,
INSTR( path, '/', 1, 7 ) + 1 AS p07,
INSTR( path, '/', 1, 8 ) + 1 AS p08
FROM (
SELECT childId,
SYS_CONNECT_BY_PATH( parentId, '/') AS path
FROM table_name
START WITH parentId IS NULL
CONNECT BY PRIOR childId = parentId
)
);
Output:
CHILDID LP1 LP2 LP3 LP4 LP5 LP6
---------- --- --- --- --- --- ---
1
2 1
4 1 2
5 1 2 4
6 1 2 4 5
7 1 2 4 5 6
3 1
Query 2 - Regular Expressions:
SELECT childId,
TO_NUMBER( REGEXP_SUBSTR( path, '/([^/]*)', 1, 2, NULL, 1 ) ) AS lp1,
TO_NUMBER( REGEXP_SUBSTR( path, '/([^/]*)', 1, 3, NULL, 1 ) ) AS lp2,
TO_NUMBER( REGEXP_SUBSTR( path, '/([^/]*)', 1, 4, NULL, 1 ) ) AS lp3,
TO_NUMBER( REGEXP_SUBSTR( path, '/([^/]*)', 1, 5, NULL, 1 ) ) AS lp4,
TO_NUMBER( REGEXP_SUBSTR( path, '/([^/]*)', 1, 6, NULL, 1 ) ) AS lp5,
TO_NUMBER( REGEXP_SUBSTR( path, '/([^/]*)', 1, 7, NULL, 1 ) ) AS lp6,
TO_NUMBER( REGEXP_SUBSTR( path, '/([^/]*)', 1, 8, NULL, 1 ) ) AS lp7
FROM (
SELECT childId,
SYS_CONNECT_BY_PATH( parentId, '/') AS path
FROM table_name
START WITH parentId IS NULL
CONNECT BY PRIOR childId = parentId
);
I have a problem in converting a date value stored in a blob field in Oracle 11g sql command. When i execute the sql:
select dump(HIGH_VALUE) from all_tab_columns where COLUMN_NAME='TARIH'
i receive the following result;
Typ=23 Len=7: 120,116,3,6,1,1,1
I know that these numbers represent a date (not datetime), but i don't know how to extract the date from this result.
Thanks in advance,
Alper
Oracle stores dates in tables as 7-bytes
byte 1 - century + 100
byte 2 - (year MOD 100 ) + 100
byte 3 - month
byte 4 - day
byte 5 - hour + 1
byte 6 - minute + 1
byte 7 - seconds+ 1
So 120,116,3,6,1,1,1 converts to:
byte 1 - century = 120 - 100 = 20
byte 2 - year = 116 - 100 = 16
byte 3 - month = 3
byte 4 - day = 6
byte 5 - hour = 1 - 1 = 0
byte 6 - minute = 1 - 1 = 0
byte 7 - seconds = 1 - 1 = 0
So 2016-03-06T00:00:00
Oracle Setup:
CREATE TABLE file_upload ( file_blob BLOB );
INSERT INTO file_upload VALUES (
utl_raw.cast_to_raw(
CHR(120) || CHR(116) || CHR(3) || CHR(6) || CHR(1) || CHR(1) || CHR(1)
)
);
Query:
SELECT DUMP( DBMS_LOB.SUBSTR( file_blob, 7, 1 ) ) AS dmp,
TO_DATE(
TO_CHAR(
( ASCII( SUBSTR( chars, 1, 1 ) ) - 100 ) * 100
+ ASCII( SUBSTR( chars, 2, 1 ) ) - 100,
'0000'
)
|| TO_CHAR( ASCII( SUBSTR( chars, 3, 1 ) ), '00' )
|| TO_CHAR( ASCII( SUBSTR( chars, 4, 1 ) ), '00' )
|| TO_CHAR( ASCII( SUBSTR( chars, 5, 1 ) ) - 1, '00' )
|| TO_CHAR( ASCII( SUBSTR( chars, 6, 1 ) ) - 1, '00' )
|| TO_CHAR( ASCII( SUBSTR( chars, 7, 1 ) ) - 1, '00' ),
'YYYYMMDDHH24MISS'
) AS converted_date
FROM (
SELECT file_blob,
UTL_RAW.CAST_TO_VARCHAR2(DBMS_LOB.SUBSTR( file_blob, 7, 1 ) ) AS chars
FROM file_upload
);
Output:
DMP CONVERTED_DATE
------------------------------- -------------------
Typ=23 Len=7: 120,116,3,6,1,1,1 2016-03-06 00:00:00