Complex sorting in Spring Data JPA Sort object - spring-boot

Question

I want to do this query
select * from order_config
where group_id like '%PATH%'
order by (group_id = 'PATH') desc
and I have this JpaRepository that I want to pass a Pageable object with this complex sorting
val sort = Sort.by(Sort.Direction.DESC, "group_id")
val pageable = PageRequest.of(pageNumber, pageSize, sort)
this.findAll(pageable)
I have already tried this but it doesn't work
val sort = JpaSort.unsafe(Sort.Direction.DESC, "(group_id = 'PATH')")
val pageable = PageRequest.of(pageNumber, pageSize, sort)
this.findAll(pageable)
How do I build this Sort object with this expression instead of a model property?

Answer 1

You can use specification API for generating more complex Query. I my code I used this code for creating specification object.
// Instead of Post class pass your own entity class.
public static Specification<Post> search(String keyword) {
return ((root, criteriaQuery, criteriaBuilder) -> {
if (keyword == null) {
return null;
}
return criteriaBuilder.like(root.get("title"), "%" + keyword + "%"));
});
}
findAll() accept specification object too you can pass both specification and pageable object like:
this.findAll(search("PATH"), pageable);