I'm struggling with Eloquent with query on relation.
For example, I'm looking for only the client John who doesn't have transaction.
How can I do this with Eloquent?
Client model relation
public function transactions()
{
return $this->hasMany(Transaction::class);
}
$results = Client::whereDoesntHave('transactions', function ($query) use ($inputFirst, $period) {
$query->where('transactions.period_id', '=', $period->id)
->where('firstname', '=', $inputFirst);
})
->orderBy('id', 'desc')
->get();
A little help would be great.
Thanks
The issue with your code is that you are nesting the statements. The way you are doing Laravel is generating a SQL like this:
select * from `clients` where not exists
(select * from `transactions`
where `clients`.`id` = `transactions`.`client_id`
and `name` = John)
But the actual SQL code you're looking for is:
select * from `clients` where not exists
(select * from `transactions`
where `clients`.`id` = `transactions`.`client_id`)
and `name` = John)
For that your code should be:
$results = Client::whereDoesntHave('transactions')
->where('firstname', '=', $inputFirst)
->orderBy('id', 'desc')
->get();
*I didn't include the transactions.period_id, coz I wasn't sure if where you're looking to have it. But if it's meant to be inside the second select, leave in the nested statement, if not leave outside.
Related
I am trying to search with a column on a connected table using with. According to laravel the following should work.
$lineItems = Invoice::with(['invoiceHeader' => function ($query) {
$query->where('community_id', '=', 1);
}, 'invoiceLineItems'])
->limit(10)
->get()
->toArray();
However, I don't get anything from the invoiceHeader table and I get all the invoices available. If I take out the function I get the same but with invoiceHeader's table values showing up.
$lineItems = Invoice::with(['invoiceHeader', 'invoiceLineItems'])
->limit(10)
->get()
->toArray();
It seems I might be doing something of a right join where I get all the Invoices but then only the invoiceHeader values when applicable to the foreign key.
Edit:
I put ->toSql(); after the limit() and it shows I only get the following.
"select * from `invoice` limit 10"
You should use whereHas mixing with with:
$lineItems = Invoice::with(['invoiceHeader', 'invoiceLineItems'])
->whereHas('invoiceHeader', function ($query) {
return $query->where('community_id', 1);
})
->limit(10)
->get()
->toArray();
I have a function to get a pass a language number to get language categories record for API purpose. I use a database query statement to select categories table and join the category language table to get category id, parent_id and name (specified language). When execute return error and select the underlying SQL converted the language value to string (e.g. languages_id = 1). I google a lot and no ideas what's wrong. Can anyone advise how to resolve. Thanks a lot.
I tried to copy the underlying SQL to MySQL Workbench and remove the languages_id = 1 --> languages_id = 1 can working properly. I guess the 1 caused error.
Code Sample:
private function getCategories($language) {
$categories = DB::table('categories')
->select(DB::raw('categories.id, categories.parent_id, categories_translation.name'))
->join('categories_translation', function($join) use ($language) {
$join->on('categories_translation.categories_id', '=', 'categories.id');
$join->on('categories_translation.languages_id', '=', $language);
})
->where([
['parent_id' ,'=', '0'],
['categories.id', '=', $id]
])
->get();
return $categories;
}
Error return the converted SQL:
"SQLSTATE[42S22]: Column not found: 1054 Unknown column '1' in 'on
clause' (SQL: select categories.id, categories.parent_id,
categories_translation.name from categories inner join
categories_translation on categories_translation.categories_id =
categories.id and categories_translation.languages_id = 1
where (parent_id = 0 and categories.id = 1))"
You are trying to join using a comparison to an scalar value, instead of a column. I think you actually want to put that comparison as a "where" condition, rather than a "join on"
->where([
['parent_id' ,'=', '0'],
['categories.id', '=', $id],
['categories_translation.languages_id', '=', $language]
])
there is another thing i just discover with your code. when joining table, you are suppose to be joining 'categories_translation.languages_id' with another table id field. in your case, it is not so. you are not joining 'categories_translation.languages_id' with any table field. so ideally, what you are going to do is this
private function getCategories($language) {
$categories = DB::table('categories')
->select(DB::raw('categories.id, categories.parent_id, categories_translation.name'))
->join('categories_translation', function($join) use ($language) {
$join->on('categories_translation.categories_id', '=', 'categories.id');
})
->where([
['parent_id' ,'=', '0'],
['categories.id', '=', $id]
['categories_translation.languages_id', '=', $language]
])
->get();
return $categories;
}
hope this helps
I am trying to do this query in Laravel 5.4 with Eloquent and I do not get the subquery to function as it should. This is the original SQL query:
select * from projects p
inner join projects_categories pc on p.id = pc.project_id
where pc.name in (select pc.name from projects p
inner join projects_categories pc on p.id = pc.project_id
where p.id = $project->id) and p.id <> $project->id;
This is what I'm trying to do:
Project::join('projects_categories', 'projects.id', '=', 'projects_categories.project_id')
->whereIn([
['projects_categories.name', function ($query) {
$query->select('projects_categories.name')
->from('projects')
->join('projects_categories', 'projects.id', '=', 'projects_categories.project_id')
->where('project.id', '=', $project->id);
}],
['projects.id', '<>', $project->id]
])
->get();
But all the time I get the error back:
Missing argument 2 for Illuminate\Database\Query\Builder::whereIn().
Could anyone help me with this? Thank you very much for your time and help.
Try this:
Project::join('projects_categories', 'projects.id', '=', 'projects_categories.project_id')
->whereIn('projects_categories.name', function($query) use($project) {
$query->select('projects_categories.name')->from('projects')
->join('projects_categories', 'projects.id', '=', 'projects_categories.project_id')
->where('projects.id', '=', $project->id);
})->where('projects.id', '<>', $project->id)->get();
If in Project.php you have a hasMany relationship for categories i.e
public function categories()
{
return $this->hasMany(Category::class);
}
Then you should be able to return the relationship eloquently like so:
Project::find($id)->with('categories');
Or if you already have a project object loaded
$project->load('categories');
I would checkout the Laravel documentation as the join you posted looks overly complicated!
I have a code:
$response = $this->posts
->where('author_id', '=', 1)
->with(array('postComments' => function($query) {
$query->where('comment_type', '=', 1);
}))
->orderBy('created_at', 'DESC')
->limit($itemno)
->get();
And when I logged this query with:
$queries = \DB::getQueryLog();
$last_query = end($queries);
\Log::info($last_query);
In log file I see follow:
"select * from `post_comments` where `post_comments`.`post_id` in (?, ?, ?, ?) and `comment_type` <> ?"
Why is the question mark for comment_type in the query?
Update #1:
I replaced current code with following and I get what I want. But I'm not sure it is OK. Maybe exists many better, nicer solution.
$response = $this->posts
->where('author_id', '=', 1)
->join('post_comments', 'post_comments.post_id', '=', 'posts.id')
->where('comment_type', '=', 1)
->orderBy('created_at', 'DESC')
->limit($itemno)
->get();
Behind the scene the PDO is being used and it's the way that PDO does as a prepared query, for example check this:
$title = 'Laravel%';
$author = 'John%';
$sql = "SELECT * FROM books WHERE title like ? AND author like ? ";
$q = $conn->prepare($sql);
$q->execute(array($title,$author));
In the run time during the execution of the query by execute() the ? marks will be replaced with value passed execute(array(...)). Laravel/Eloquent uses PDO and it's normal behavior in PDO (PHP Data Objects). There is another way that used in PDO, which is named parameter/placeholder like :totle is used instead of ?. Read more about it in the given link, it's another topic. Also check this answer.
Update: On the run time the ? marks will be replaced with value you supplied, so ? will be replaced with 1. Also this query is the relational query, the second part after the first query has done loading the ids from the posts table. To see all the query logs, try this instead:
$queries = \DB::getQueryLog();
dd($queries);
You may check the last two queries to debug the queries for the following call:
$response = $this->posts
->where('author_id', '=', 1)
->with(array('postComments' => function($query) {
$query->where('comment_type', '=', 1);
}))
->orderBy('created_at', 'DESC')
->limit($itemno)
->get();
Update after clarification:
You may use something like this if you have setup relation in your Posts model:
// $this->posts->with(...) is similar to Posts::with(...)
// if you are calling it directly without repository class
$this->posts->with(array('comments' =. function($q) {
$q->where('comment_type', 1);
}))
->orderBy('created_at', 'DESC')->limit($itemno)->get();
To make it working you need to declare the relationship in your Posts (Try to use singular name Post if possible) model:
public function comments()
{
return $this->hasmany('Comment');
}
Your Comment model should be like this:
class Comment extends Eloquent {
protected $table = 'post_comments';
}
I'm trying to add a condition using a JOIN query with Laravel Query Builder.
<?php
$results = DB::select('
SELECT DISTINCT
*
FROM
rooms
LEFT JOIN bookings
ON rooms.id = bookings.room_type_id
AND ( bookings.arrival between ? and ?
OR bookings.departure between ? and ? )
WHERE
bookings.room_type_id IS NULL
LIMIT 20',
array('2012-05-01', '2012-05-10', '2012-05-01', '2012-05-10')
);
I know I can use Raw Expressions but then there will be SQL injection points. I've tried the following with Query Builder but the generated query (and obviously, query results) aren't what I intended:
$results = DB::table('rooms')
->distinct()
->leftJoin('bookings', function ($join) {
$join->on('rooms.id', '=', 'bookings.room_type_id');
})
->whereBetween('arrival', array('2012-05-01', '2012-05-10'))
->whereBetween('departure', array('2012-05-01', '2012-05-10'))
->where('bookings.room_type_id', '=', null)
->get();
This is the generated query by Laravel:
select distinct * from `room_type_info`
left join `bookings`
on `room_type_info`.`id` = `bookings`.`room_type_id`
where `arrival` between ? and ?
and `departure` between ? and ?
and `bookings`.`room_type_id` is null
As you can see, the query output doesn't have the structure (especially under JOIN scope). Is it possible to add additional conditions under the JOIN?
How can I build the same query using Laravel's Query Builder (if possible) Is it better to use Eloquent, or should stay with DB::select?
$results = DB::table('rooms')
->distinct()
->leftJoin('bookings', function($join)
{
$join->on('rooms.id', '=', 'bookings.room_type_id');
$join->on('arrival','>=',DB::raw("'2012-05-01'"));
$join->on('arrival','<=',DB::raw("'2012-05-10'"));
$join->on('departure','>=',DB::raw("'2012-05-01'"));
$join->on('departure','<=',DB::raw("'2012-05-10'"));
})
->where('bookings.room_type_id', '=', NULL)
->get();
Not quite sure if the between clause can be added to the join in laravel.
Notes:
DB::raw() instructs Laravel not to put back quotes.
By passing a closure to join methods you can add more join conditions to it, on() will add AND condition and orOn() will add OR condition.
If you have some params, you can do this.
$results = DB::table('rooms')
->distinct()
->leftJoin('bookings', function($join) use ($param1, $param2)
{
$join->on('rooms.id', '=', 'bookings.room_type_id');
$join->on('arrival','=',DB::raw("'".$param1."'"));
$join->on('arrival','=',DB::raw("'".$param2."'"));
})
->where('bookings.room_type_id', '=', NULL)
->get();
and then return your query
return $results;
You can replicate those brackets in the left join:
LEFT JOIN bookings
ON rooms.id = bookings.room_type_id
AND ( bookings.arrival between ? and ?
OR bookings.departure between ? and ? )
is
->leftJoin('bookings', function($join){
$join->on('rooms.id', '=', 'bookings.room_type_id');
$join->on(DB::raw('( bookings.arrival between ? and ? OR bookings.departure between ? and ? )'), DB::raw(''), DB::raw(''));
})
You'll then have to set the bindings later using "setBindings" as described in this SO post:
How to bind parameters to a raw DB query in Laravel that's used on a model?
It's not pretty but it works.
The sql query sample like this
LEFT JOIN bookings
ON rooms.id = bookings.room_type_id
AND (bookings.arrival = ?
OR bookings.departure = ?)
Laravel join with multiple conditions
->leftJoin('bookings', function($join) use ($param1, $param2) {
$join->on('rooms.id', '=', 'bookings.room_type_id');
$join->on(function($query) use ($param1, $param2) {
$query->on('bookings.arrival', '=', $param1);
$query->orOn('departure', '=',$param2);
});
})
I am using laravel5.2 and we can add joins with different options, you can modify as per your requirement.
Option 1:
DB::table('users')
->join('contacts', function ($join) {
$join->on('users.id', '=', 'contacts.user_id')->orOn(...);//you add more joins here
})// and you add more joins here
->get();
Option 2:
$users = DB::table('users')
->join('contacts', 'users.id', '=', 'contacts.user_id')
->join('orders', 'users.id', '=', 'orders.user_id')// you may add more joins
->select('users.*', 'contacts.phone', 'orders.price')
->get();
option 3:
$users = DB::table('users')
->leftJoin('posts', 'users.id', '=', 'posts.user_id')
->leftJoin('...', '...', '...', '...')// you may add more joins
->get();
For conditional params we can use where,
$results = DB::table('rooms')
->distinct()
->leftJoin('bookings', function($join) use ($param)
{
$join->on('rooms.id', '=', 'bookings.room_type_id')
->where('arrival','=', $param);
})
->where('bookings.room_type_id', '=', NULL)
->get();
There's a difference between the raw queries and standard selects (between the DB::raw and DB::select methods).
You can do what you want using a DB::select and simply dropping in the ? placeholder much like you do with prepared statements (it's actually what it's doing).
A small example:
$results = DB::select('SELECT * FROM user WHERE username=?', ['jason']);
The second parameter is an array of values that will be used to replace the placeholders in the query from left to right.
My five cents for scheme LEFT JOIN ON (.. or ..) and (.. or ..) and ..
->join('checks','checks.id','check_id')
->leftJoin('schema_risks', function (JoinClause $join) use($order_type_id, $check_group_id, $filial_id){
$join->on(function($join){
$join->on('schema_risks.check_method_id','=', 'check_id')
->orWhereNull('schema_risks.check_method_id')
;
})
->on(function($join) use ($order_type_id) {
$join->where('schema_risks.order_type_id', $order_type_id)
->orWhereNull('schema_risks.order_type_id')
;
})
->on(function($join) use ($check_group_id) {
$join->where('schema_risks.check_group_id', $check_group_id)
->orWhereNull('schema_risks.check_group_id')
;
})
->on(function($join) use($filial_id){
$join->whereNull('schema_risks.filial_id');
if ($filial_id){
$join->orWhere('schema_risks.filial_id', $filial_id);
}
})
->on(function($join){
$join->whereNull('schema_risks.check_risk_level_id')
->orWhere('schema_risks.check_risk_level_id', '>' , CheckRiskLevel::CRL_NORMALLLY );
})
;
})