How do you get items from txt into presentable table in bash? - bash

Question

I'm trying to retrieve items from Node01.pc and put it within a table.
Example:
echo ${NodeCPU[0]} is able to print the item from the line.
But when I use printf or echo it either breaks or does not display the output from the array item.
The formating of the table seems work and it displays only if it's not the arrays. Could it be that there's more than to the file that I can see?
Node01.pc contains
192.168.0.99
2
70
16
80
4
4
100
4
VS122:NMAD:20:20:1:1
VS122:NAMD:20:20:1:1
RS123:FEM:10:20:1:1
QV999:BEM:20:20:1:1
But I only need lines 3,5,7,9
I'm not sure if what is the best way to do this, or if I even need to store items into arrays.
I thought about retrieving all text from the texts files and making a new file which will contain all the data, but I'm not sure how to do that.
This is the code that I have right now.
#!/bin/bash
Node01=($(cat Node01.pc))
Node02=($(cat Node02.pc))
Node03=($(cat Node03.pc))
Node04=($(cat Node04.pc))
Node05=($(cat Node05.pc))
NodeCPU=("${Node01[2]}" "${Node02[2]}" "${Node03[2]}" "${Node04[2]}" "${Node05[2]}")
NodeMEM=("${Node01[4]}" "${Node02[4]}" "${Node03[4]}" "${Node04[4]}" "${Node05[4]}")
NodeHDD=("${Node01[6]}" "${Node02[6]}" "${Node03[6]}" "${Node04[6]}" "${Node05[6]}")
NodeNET=("${Node01[8]}" "${Node02[8]}" "${Node03[8]}" "${Node04[8]}" "${Node05[8]}")
seperator=----------------------
seperator=$seperator$seperator
rows="%-10s| %-7s| %-7s| %-7s| %-7s\n"
TableWidth=140
printf "%-10s| %-7s| %-7s| %-7s| %-7s\n" NodeNumber CPU MEM HDD NET
printf "%.${TableWidth}s\n" "$seperator"
for((i=0;i<=4;i++))
do
printf "$rows" "$(( $i+1 ))" "${NodeCPU[i]}" "${NodeMEM[i]}" "${NodeHDD[i]}" "${NodeNET[i]}"
done
read
This is an example of what I want to display
NodeNumber | CPU | MEM | HDD | NET
----------------------------------
1 | 10 | 20 | 20 | 40
2 | 10 | 20 | 20 | 40
3 | 10 | 20 | 20 | 40
4 | 10 | 20 | 20 | 40
5 | 10 | 20 | 20 | 40
EDIT This is what I'm currently getting:
NodeNumber| CPU | MEM | HDD | NET
--------------------------------------------
| 4 | 70
| 5 | 90
| 6 | 100
| 6 | 70
| 40 | 40
Issue I'm having is with
printf "$rows" "$(( $i+1 ))" "${NodeCPU[i]}" "${NodeMEM[i]}" "${NodeHDD[i]}" "${NodeNET[i]}"

Answer 1

Why worry about all the separate array? Simply loop over all "Node*.pc" files in the current directory and read the contents of each file into an array with readarray and then output the file count and elements nos. 2, 4, 6, 8 of the array in the proper format (adjust elements output as needed), e.g.
#!/bin/bash
cnt=1 ## file counter
## print heading
printf "NodeNumber | CPU | MEM | HDD | NET\n----------------------------------\n"
for i in Node*.pc; do ## loop over all Node*.pc files in directory
readarray -t node < "$i" ## read contents into array
## output count and elements 2, 4, 6, 8 in proper format
printf "%-11s| %-4s| %-4s| %-4s| %s\n" $((cnt++)) \
"${node[2]}" "${node[4]}" "${node[6]}" "${node[8]}"
done
Example Use/Output
With the example data shown copied to the file Node01.pc in the current directory, you would get:
$ bash node.sh
NodeNumber | CPU | MEM | HDD | NET
----------------------------------
1 | 70 | 80 | 4 | 4
(I called the script node.sh)
It would output the information from each file as separate lines numbered 1, 2, ... Look things over an let me know if this is what you intended. (you can also do the same thing with awk faster by setting FS=\n and treating the lines as columns in a single record)
You can do the same thing in awk with:
awk '
BEGIN {
RS=""; FS="\n"
printf "NodeNumber | CPU | MEM | HDD | NET\n----------------------------------\n"
}
NF >= 9 {
printf "%-11s| %-4s| %-4s| %-4s| %s\n",++cnt,$3,$5,$7,$9
}
' Node*.pc
(note: in awk the field numbers are 1-based, while in bash the array indexes are 0-based)
Output is the same.