Bash scripts return a substring not whole value in column for psql - bash

Question

I want to get the value of message in db, which for example is "the error is missing index " but when I run the code belong, it only return me 'the' for error_type. How could this happen that only return me the first word but not the whole value of the query result? How can I get the query results with the whole value?
declare -a ROW=($(psql \
-X \
-U $DB_USER \
-h $DB_HOST \
-d $DB_NAME \
-p $DB_PORT \
--single-transaction \
--set AUTOCOMMIT=off \
--set ON_ERROR_STOP=on \
--no-align \
-t \
--field-separator ' ' \
--quiet \
-c "SELECT message
FROM error_message
WHERE created_at > '$t1' and created_at < '$t'")
)
error_type=${ROW[0]}
echo $error_type

Answer 1

Don't use an array, use an ordinary string variable to contain the whole result.
error_type=$(psql \
-X \
-U $DB_USER \
-h $DB_HOST \
-d $DB_NAME \
-p $DB_PORT \
--single-transaction \
--set AUTOCOMMIT=off \
--set ON_ERROR_STOP=on \
--no-align \
-t \
--field-separator ' ' \
--quiet \
-c "SELECT message
FROM error_message
WHERE created_at > '$t1' and created_at < '$t'")
echo "$error_type"
Remember to quote variables unless you need word splitting and wildcard expansion to be done.