I just noticed, that when I'm trying to execute a single UserLog::create($data_array) query.
Laravel executes 2 queries instead.
This isn't causing any problems, I'm just trying to understand why? (as I'm already telling it which columns to set data for in the $data_array)
Is there any way to reduce it to a single query?
Here are the 2 queries executed for UserLog::create($data_array):
1. select column_name as `column_name` from information_schema.columns where table_schema = 'database_name' and table_name = 'user_logs'
2. insert into `user_logs` (...) values (...)
Edit: I'm only doing a single create() in the page I'm experiencing this, and when I comment out the line, no queries are executed.
Related
I have the function below
CREATE OR REPLACE FUNCTION BUTCE_REPORT_Fun (birim_id IN VARCHAR2)
RETURN sys_refcursor
IS
retval sys_refcursor;
BEGIN
OPEN retval FOR
select *
from ifsapp.butce_gerceklesme
WHERE budget_year = '2018'
AND USER_GROUP = birim_id ;
RETURN retval;
END BUTCE_REPORT_Fun;
and am trying to execute the function this way
SELECT * from table(IFSAPP.BUTCE_REPORT_FUN('3008'))
the line above generates this exception
ora-22905 cannot access rows from a non-nested table item
to keep in mind that ifsapp.butce_gerceklesme is a view (which I do not think that it matters).
So how I can solve this. any help is appreciated.
Actually, am trying to create a function that returns rows from the view above according to the parameters provided. so if I can achieve that in another way that would be better.
Ref Cursors are for use in program calls: they map to JDBC or ODBC ResultSet classes. They can't be used as an input to a table() call. Besides, there is no value in calling your function in SQL because you can simply execute the embedded query in SQL.
the main table is huge and the inner query assigned to USER_GROUP is selected every time
So maybe what you want is subquery factoring AKA the WITH clause?
with ug as (
select con2.CODE_PART_VALUE
from IFSAPP.ACCOUNTING_ATTRIBUTE_CON2 con2
where COMPANY = 'XYZ'
and ATTRIBUTE = 'ABC'
and CODE_PART = 'J'
and con2.ATTRIBUTE_VALUE=407
AND rownum = 1
)
select *
from ifsapp.butce_gerceklesme t
join ug on t.USER_GROUP = ug.CODE_PART_VALUE
WHERE t.budget_year = '2018'
Tuning queries on StackOverflow is a mug's game, because there are so many things which might be responsible for sub-optimal performance. But as a rule of thumb you should try to tune the whole query. Encapsulating a part of it in PL/SQL is unlikely to improve response times, and indeed may degrade them.
I need to update a column in one table with the results from a select sub-query (and they should ultimately be different). But When I do this, I get the 'ORA-01427: single row sub-query returns more than one row query' error.
Can you please take a look and see what it is that I am overlooking? (I could just be overlooking something simple for all I know)
UPDATE AIRMODEL_NETWORK_SUMMARY ans
SET ANS.NBR_RETURNS = (
SELECT SUM(RQ.RETURN_QTY)
FROM RETURN_QTY RQ JOIN AIRMODEL_NETWORK_SUMMARY ANS ON RQ.LOC_ID = ANS.LOC_ID
WHERE RQ.FSCL_YR_NUM = ans.FSCL_YR_NUM
AND RQ.FSCL_WK_IN_YR_NUM =
ans.FSCL_WK_IN_YR_NUM
GROUP BY ANS.LOC_ID,
ans.FSCL_WK_IN_YR_NUM,
ANS.FSCL_YR_NUM
);
I think that your inner query is not well correlated to the table that you're trying to update. Please look here Oracle SQL: Update a table with data from another table. You should add some kind of a where condition that ties the rows you're trying to update with the values calculated by the inner statement.
I'm using MySQL and have a table of 9 million rows and would like to quickly check if a record (id) exists or not.
Based on some research it seems the fastest way is the following sql:
SELECT EXISTS(SELECT 1 FROM table1 WHERE id = 100)
Source: Best way to test if a row exists in a MySQL table
How can I write this using Laravel's query builder?
Use selectOne method of the Connection class:
$resultObj = DB::selectOne('select exists(select 1 from your_table where id=some_id) as `exists`');
$resultObj->exists; // 0 / 1;
see here http://laravel.com/docs/4.2/queries
Scroll down to Exists Statements, you will get what you need
DB::table('users')
->whereExists(function($query)
{
$query->select(DB::raw(1))
->from('table1')
->whereRaw("id = '100'");
})
->get();
This is an old question that was already answered, but I'll post my opinion - maybe it'll help someone down the road.
As mysql documentation suggests, EXISTS will still execute provided subquery. Using EXISTS is helpful when you need to have it as a part of a bigger query. But if you just want to check from your Laravel app if record exists, Eloquent provides simpler way to do this:
DB::table('table_name')->where('field_name', 'value')->exists();
this will execute query like
select count(*) as aggregate from `table_name` where `field_name` = 'value' limit 1
// this is kinda the same as your subquery for EXISTS
and will evaluate the result and return a true/false depending if record exists.
For me this way is also cleaner then the accepted answer, because it's not using raw queries.
Update
In laravel 5 the same statement will now execute
select exists(select * from `table_name` where `field_name` = 'value')
Which is exactly, what was asked for.
I have created a view in oracle. Now i would like to fetch data from that view. So i have written a SQL Query. But the query is not working for not having a specific condition. But if I give that condition the query executes. But the problem is not occurring if i joined the same number of tables (that were used to create view) instead of using view. In the following I am giving the oracle query.
SELECT *
FROM "920_search_report"
WHERE lm_culture = '7aacb509-271d-4aca-e040-e00adea40aae'
AND hand_person_info_guid = 'eebd4257-7856-4c6e-b6b8-9b886e89e397'
AND ( Lower(handicap_type) LIKE Lower('%DQ871J%')
OR Lower(skskodenr) LIKE Lower('%DQ871J%') );
The above query executes and returns one record but if I omit or comment the third line then the query does not return any records, but it should return one or two. the query is given below:
SELECT *
FROM "920_search_report"
WHERE lm_culture = '7aacb509-271d-4aca-e040-e00adea40aae'
--AND HAND_PERSON_INFO_GUID='eebd4257-7856-4c6e-b6b8-9b886e89e397'
AND ( Lower(handicap_type) LIKE Lower('%DQ871J%')
OR Lower(skskodenr) LIKE Lower('%DQ871J%') );
Can anyone help me to solve the problem.
I have one complex SQL queries. One of the simple part of the queries looks like:
Query 1:
SELECT *
FROM table1 t1, table2 t2
WHERE t1.number = t2.number
AND UPPER(t1.name) = UPPER(t2.name)
AND t1.prefix = p_in_prefix;
Query 2:
SELECT *
FROM table1 t1, table2 t2
WHERE t1.number = t2.number
AND UPPER(t1.name) = UPPER(p_in_prefix || t2.name)
AND t1.prefix = p_in_prefix;
I have function based index on table1 as (number, UPPER(name)). I have function based index on my table2 as (number, UPPER(NAME)). p_in_prefix is a input parameter (basically a number).
Because of these indexes my Query 1 runs efficiently. But Query 2 has a performance issue, as in Query 2, 't2.name' is prefixed with p_in_prefix.
I can not create function based index for Query 2 because p_in_prefix is a input parameter and I don't know while creating index, what values it might hold. How to resolve performace issue in this scenario? Any hint/idea would be appreciated. If you require more information, please let me know.
Thanks.
Use AND UPPER(t1.name) = UPPER(p_in_prefix) || UPPER(t2.name).
As you have a function based index as UPPER(NAME) of table2, you should have an operand with the same expression in the query in order to make use of the function based index.
Using UPPER(p_in_prefix || t2.name) will not use the function based index as this does not match the function expression UPPER(NAME). Note here that using UPPER(t2.name) does not cause any problems as t2 is just a column alias.
Along with this, you can also pass an optimizer hint in your query in order to instruct the optimizer to use the index.
For more information read "Oracle Database 11g SQL" by Jason Price.
Also read Oracle Docs here and here and for optimizer hints here.