I'm creating an ssrs form in oracle sql on which I need to list an address. New lines have to remain in the address however I can't find the way of removing new lines at the end of the address.
Example of what I have:
10 Donkey Kong,
London,
XX1 1XX
new line
new line
Example of what I want:
10 Donkey Kong,
London,
XX1 1XX
Oracle version: 11g - release 11.2
I tried already:
trim(both chr(10) from (trim(both chr(13) from a.address)) - it doesnt make any difference
substr(a.address,1,length(translate(a.address,'d'||chr(10)||chr(13),'d'))) - translate checks how many spaces is in the whole address and substring only returns part of the address because it cuts more than it should
Thanks
Found an answer :D
Regex to the rescue.
regexp_replace(a.address,'[' || chr(10) || chr(13) || ' ]+$', '')
I would still like to know why trim didn't work. Any idea ?
You might be able to use REGEXP_REPLACE here with the pattern \s+$ here:
UPDATE yourTable
SET address = REGEXP_REPLACE(address, '\s+$', '');
I can speculate a few reasons why your trim approach is failing. First of all, perhaps not every column value has CRLF (CHR(10) || CHR(13)). Instead, it could have a Linux line ending, which is just CHR(13). Or, there could be other types of whitespace present at the end. The answer I gave is simpler and should cover you in all edge cases.
Related
I am trying to insert a space before the capital letters in oracle. I thought it would be easy using a regexp_replace, but I can't seem to get a proper back reference to the character I am replacing.
select trim(regexp_replace ('FreddyFox', '[A-Z]', ' \1' )) from dual;
Result: '\1reddy \1ox'
I have tried multiple variants of a back reference but I can't seem to find something that satisfies Oracle.
I did look at multiple SO answers but I could not figure out what is wrong.
e.g. regexp_replace: insert a space in a string if not already present
TRIM(regexp_replace ('FreddyFox', '([A-Z])', ' \1' ))
TRIM enables you to trim leading or trailing characters (or both) from a character string. If trim_character or trim_source is a character literal, then you must enclose it in single quotes. Default is both.
regexp_replace ('FreddyFox', '^([A-Z])', ' \1')
I hope there is no post limit since I have posted more than once today. :-P
Now I have a table in OracleSQL. I noticed there are some useless signs and want to delete them. The way I do it is to replace all of them. Below is my table and my query.
Here is my query:
SELECT
CASE WHEN WORD IN ('!', '"', '#','""') Then ''
ELSE WORD END
FROM TERM_FREQUENCY;
It is not giving me an error, but these special characters are not going away either... Any thoughts?
A little typo of yours: you use - instead of _
SELECT
CASE WHEN WORD IN ('!', '"', '#','""') Then ''
ELSE WORD END
-- FROM TERM-FREQUENCY; --This is where the problem is.
FROM TERM_FREQUENCY; -- Because your table is named TERM _ FREQUENCY
You originally tagged your question with 'replace' but then didn't use that function in your code. You're comparing each whole word to those fixed strings, not seeing if it contains any of them.
You can either use nested replace calls to remove one character at a time:
select replace(replace(word, '!', null), '"', null) from ...
... which would be tedious and rely on you identifying every character you didn't want; or you could use a regular expression only keep alphabetic characters, which I suspect is what you're really after:
select regexp_replace(word, '[^[:alpha:]]', null) from ...
Quick demo.
You might also want to use lower or upper to get everything into the same case, as you probably don't really want to count different capitalisation differently either.
Is there any way to use ascii code for value separator in SYS_CONNECT_BY_PATH.
For example in SYS_CONNECT_BY_PATH(columnname,'!'),
I want to use the ASCII value of !(33) instead of actual symbol. Also, can i use the ascii value of ENTER (13) as value separator?
Thank you.
You can use the chr function to replace a character with it's numeric equivalent.
SYS_CONNECT_BY_PATH(column name, chr(33))
Or to use a line feed, which should also be fine:
SYS_CONNECT_BY_PATH(column name, chr(13))
It's not strictly ASCII as it depends on your character set, but it will probably work for you. You can see the numeric values using the reverse ascii function, which also isn't really quite ASCII, but again close enough especially if you're always using the same character set. So ascii('!') would give you 33.
As you've discovered, giving anything except a fixed string literal gives:
SQL Error: ORA-30003: illegal parameter in SYS_CONNECT_BY_PATH
function
30003. 00000 - "illegal parameter in SYS_CONNECT_BY_PATH function"
*Cause:
*Action: use a non-empty constant string as the second argument,
then retry the operation.
This is why I usually test things before posting, but this seemed so simple... You can get around that with replace:
REPLACE(SYS_CONNECT_BY_PATH(column name, '/'), '/', chr(33))
Borrowing an example from the manual:
SELECT LPAD(' ', 2*level-1)
||replace(SYS_CONNECT_BY_PATH(last_name, '/'),'/',chr(33)) "Path"
FROM employees
START WITH last_name = 'Kochhar'
CONNECT BY PRIOR employee_id = manager_id;
Path
--------------------------------------------------
!Kochhar
!Kochhar!Greenberg
!Kochhar!Greenberg!Faviet
!Kochhar!Greenberg!Chen
!Kochhar!Greenberg!Sciarra
!Kochhar!Greenberg!Urman
!Kochhar!Greenberg!Popp
!Kochhar!Whalen
!Kochhar!Mavris
!Kochhar!Baer
!Kochhar!Higgins
!Kochhar!Higgins!Gietz
All the credit goes to Sanjeev Chauhan. Update 7/25/2017: This turned out to be a SQL Developer 4.2.0 and 17.2.0 bug. In SQLPlus and SQL Developer 3.2.2 the statement works fine.
Fix: set secureliterals off;
The source is https://community.oracle.com/thread/4065282
I had changed the version from 4.2.0 to 4.1.1.19 and my piece of code worked. Also be aware that I couldn't find "secureliterals" in version 4.2.0
How would I go about counting the characters after a certain character. I'm new to Oracle, and I've learned quite a bit however I'm stumped at this point. I found a couple functions that will get you a substring and I found a function that will give you the length of a string. I am examining an email address, myemail#thedomain.com. I want to check the length after the '.' in the email.
SELECT email
FROM user_table
WHERE length(substr(email, /*what values*/, /*to put here*/))
I don't know if it's actually possible to find the location of the final '.' in the email string?
I'm not sure I would use substr. You can try something like this :
select length('abcd#efgh.123.4567') - instr('abcd#efgh.123.4567', '.', -1) from dual
Using instr(..,..,-1) searches backwards from the last character to find the position.
Since you're doing checks, I suggest you validate the format with regular expressions using REGEXP_INSTR. For instance, an email validation I found on this site is REGEXP_INSTR(email, '\w+#\w+(\.\w+)+') > 0
I didn't check it myself, but it looks quite ok.
Cheers.
I know line feeds in Foxpro are CHR(10) + CHR(13), but when creating an import record comma delimited, I need to imbed the line feed into the field, when I add the CHR(10) + CHR(13) into the .txt file it puts an actual line feed into the import record rather than being embeded.
Any examples of syntax you can give me:
** This example does not work! can I get an example of how to embed these line feeds correctly?
Sam Jenkins + CHR(13) + CHR(10) + Address1 + CHR(13) + CHR(10) + Address2
Thanks - Evan
Maybe I don't understand the ops question but....
ASCII encoding:
CHR(10) = Newline/Linefeed
CHR(13) = Carriage return
Most text file viewers will will move the cursor down one line and to the left margin when they encounter a CHR(13)CHR(10). Your file may be correct, it's just that whatever you are using to view it is respecting the characters. If the text was quote enclosed and the viewer respected that, you might get the display you want otherwise the viewer wouldn't know when a CrLf is embedded or the real end of line.
Sorry, you're not going to get around text files representing linefeed+carriage return as anything other than what they are. I'd suggest some sort of workaround. Maybe you can encode them like C does, "\n" would work fine in VFP and a text file. You'd have to decode it in the consuming application though.
Your specific example seems very strange. If I was writing a comma delimited file, I'd seperate the fields with commas "Name, Addr1, Addr2" instead of lfcr. Then VFP would import that with a simple append from x type csv.
If you're trying to read from a file where the fields are seperated onto different lines, you're going to have to do more work. If you're lucky, the file always uses the same number of fields and you can just count line numbers to know which field you're on. (line 1 is name, line 2 is addr1, line3 addr2, line4 city-state-zip, line5 next name...) If that was the case, I'd use a loop and some local variables and then gather them into a blank table row.