I have a scenario, where the time needs to be shifted by 12 months.
${__timeShift(dd/MM/YYYY,,P365D,,)} doesn't helps. It isn't flexible. Depending on leap years, the number of days could change.
Could someone help me with an accurate solution.
Regards,
Ajith
You can consider using __groovy() function and use Groovy's TimeCategory class like:
${__groovy(import groovy.time.TimeCategory; def now = new Date(); use(TimeCategory) { def nowPlusOneYear = now + 1.year; return nowPlusOneYear.format('dd/MM/YYYY')},)}
More information: Creating and Testing Dates in JMeter - Learn How
Related
I have a requirement to book an appointment, The value should not overlap.So I have to increment start time and end time for every thread and it should consider time from 9:00 am to 6:00 pm.I have written below Groovy code to increment the date. But for every thread I am getting the same value.Below is the log viewer ,where we can see that ,for all 4 threads the value didnt change. Any help would be appreciated.
def now = new Date()
log.info('Before: ' + now.format('HH:mm'))
use(groovy.time.TimeCategory) {
def nowPlus60Mins = now + 60.minutes
def nowPlus15Mins = nowPlus60Mins + 15.minutes
props.put('After',nowPlus60Mins.format('HH:mm'));
props.put('End',nowPlus15Mins.format('HH:mm'));
log.info('After: ' + props.get('After'))
log.info('End: ' + props.get('End'))
}
As per JMeter Documentation:
Properties are not the same as variables. Variables are local to a thread; properties are common to all threads
So what you're doing is overwriting the value hence all the threads are using the same (last) one.
Consider switching from props to vars and you should get expected result.
Moreover, JMeter provides __timeShift() function so you don't even need any custom Groovy scripting
Objective
I am trying to calculate the distance in weeks since a given date without jumping through hoops. I'd prefer to do it in plain Ruby, but ActiveSupport is certainly an acceptable alternative.
My Code
I wrote the following, which seems to work but looks like the long way around to me.
require 'date'
DAYS_IN_WEEK = 7.0
def weeks_since date_string
date = Date.parse date_string
days = Date.today - date
weeks = days / DAYS_IN_WEEK
weeks.round 2
end
weeks_since '2015-06-15'
#=> 32.57
ActiveSupport's #weeks_since takes a number of weeks as its argument, so it doesn't fit this use case. Ruby's Date class doesn't seem to have anything relevant, either.
Alternatives?
Is there a better built-in solution or well-known algorithm for calculating the number of weeks separating a pair of dates? I'm not trying to code-golf this, as readability trumps brevity, but simply to learn whether Ruby natively supports the type of date arithmetic I've coded by hand.
require 'date'
str = '2015-06-15'
Date.parse(str).step(Date.today, 7).count # => 33
Date.parse(str).upto(Date.today).count.fdiv(7).round(2) # => 32.71
Might be easier to convert the dates to time and then divide the time difference by a week. You can round it however you want or ceil.
def weeks_since(date_string)
time_in_past = Date.parse(date_string).to_time
now = Time.now
time_difference = now - time_in_past
(time_difference / 1.week).round(2)
end
in_weeks (Rails 6.1+)
Rails 6.1 introduces new ActiveSupport::Duration conversion methods like in_seconds, in_minutes, in_hours, in_days, in_weeks, in_months, and in_years.
As a result, now, your problem can be solved as:
date_1 = Time.parse('2020-10-18 00:00:00 UTC')
date_2 = Time.parse('2020-08-13 03:35:38 UTC')
(date_2 - date_1).seconds.in_weeks.to_i.abs
# => 9
Here is a link to the corresponding PR.
I am working with an API that requires me to pass in numbers as strings. I need to increment the counter on each call.
I am using the following code:
days = days.to_i
days += 1
days = days.to_s
This works, but seems kind of sloppy. Is there a more way to do this in Ruby?
Yes, there is. You can do:
days = days.next
or
days = days.succ
Or, you can use the bang (!) methods:
days.next!
or
days.succ!
This question arose when I was trying to understand Sakamoto's algorithm for finding the day of a given date.
I found the working of the algorithm to be difficult to comprehend even after reading the following Stackoverflow answer
So, I decided to first solve a specific problem of finding the day in which a given year begins( Jan-1).
From the Sakamoto's algorithm, I just took the part of adding the additional days contributed by the leap and non-leap years.
My code is as follows:
public String getDay(String date)
{
String[] days = { "Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday" };
int day = Integer.parseInt(date.split("/")[0]);
int month = Integer.parseInt(date.split("/")[1]);
int year = Integer.parseInt(date.split("/")[2]);
year--; // to calculate the additional days till the previous year
int dayOfTheWeek = (year + year/4 - year/100 + year/400) % 7;
return days[dayOfTheWeek];
}
Thus, for the date "1/1/0001", it returns Sunday.
To verify its correctness, I implemented Sakamoto's algorithm and compared the results and my program's result always seems to be one day before the day returned by the Sakamoto's algorithm.
For the date "1/1/0001" my program returns Sunday, while Sakamoto's returns Monday.
So,
1) Does it mean that the Gregorian calendar started on Monday instead of Sunday??
2) If yes, does it mean I should add 1 to the result to get the right day or is my program logically incorrect?
Finally, I used TimeAndDate site's day calculator tool and "1/1/0001" starts on Saturday.
My final question is
3) On what day does the Gregorian calendar start?
Any light on the these questions is much appreciated.
Thanks,
What exactly is the point of reinventing the wheel?
Joda-Time is a de facto standard for date-time operations in Java, and it provides dayOfWeek method for its DateTime objects. See e.g. http://joda-time.sourceforge.net/userguide.html#Querying_DateTimes
If you are then still interested in details how to get the computation right, see https://github.com/JodaOrg/joda-time/blob/master/src/main/java/org/joda/time/chrono/BasicChronology.java#L538
I have 2 independent but contiguous date ranges. The first range is the start and end date for a project. Lets say start = 3/21/10 and end = 5/16/10. The second range is a month boundary (say 3/1/10 to 3/31/10, 4/1/10 to 4/30/10, etc.) I need to figure out how many days in each month fall into the first range.
The answer to my example above is March = 10, April = 30, May = 16.
I am trying to figure out an excel formula or VBA function that will give me this value.
Any thoughts on an algorithm for this? I feel it should be rather easy but I can't seem to figure it out.
I have a formula which will return TRUE/FALSE if ANY part of the month range is within the project start/end but not the number of days. That function is below.
return month_start <= project_end And month_end >= project_start
Think it figured it out.
=MAX( MIN(project_end, month_end) - MAX(project_start,month_start) + 1 , 0 )