I understood that casting is being implemented in go using type assertion.
I'm trying to cast an object which is an instance of a struct that implements an interface.
My Code:
package main
import "fmt"
type Base interface {
Merge(o Base)
}
type Impl struct {
Names []string
}
func (i Impl) Merge (o Base) {
other, _ := o.(Impl)
i.Names = append(i.Names, other.Names...)
}
func main() {
impl1 := &Impl{
Names: []string{"name1"},
}
impl2 := &Impl{
Names: []string{"name2"},
}
impl1.Merge(impl2)
fmt.Println(impl1.Names)
}
Which outputs this:
[name1]
I expect the output to be:
[name1, name2]
Why this casting doesn't work? After debugging this it seems like that the other variable is empty.
You need to use a pointer method to modify the receiver's build.
func (i *Impl) Merge (o Base) {
other, _ := o.(*Impl)
i.Names = append(i.Names, other.Names...)
}
Playground: https://play.golang.org/p/7NQQnfJ_G6A
Related
I am really new to golang and I am trying to see how encapsulation really works in go.
I have the following structure
-- package a
-a_core.go
-a.go
-models.go
-- main.go
In models.go I have structs for request and responses for an api call,
a.go has an empty struct, which is private and a public interface, which I want to expose with various methods
a_core.go just has some business logic which would be called in my interface implementation
Then, I have a main.go where I just call the public interface.
code in a.go
package a
type myFunction struct{}
type MyFunc interface {
Create(myData *MyData) (*MyData, error)
Fetch(test string)
Delete(test string)
}
//Concrete implementations that can be accessed publicly
func (a *myFunction) Create(data *MyData) (*MyData, error) {
return nil, nil
}
func (a *myFunction) Fetch(test string) {
}
func (a *myFunction) Delete(test string) {
}
In main.go, I call the interface my first create the MyData pointer with values
data := &a.MyData{
/////
}
result, err := a.MyFunc.Create(data)
I get the following error when I do this,
too few arguments in call to a.MyFunc.Create
cannot use data (variable of type *a.MyData) as a.MyFunc value in argument to a.MyFunc.Create: missing method CreatecompilerInvalidIfaceAssign
Please what am I doing wrong?
Here is an example
Note that names in uppercase are public, in lowercase private (see https://tour.golang.org/basics/3 )
./go-example/main.go
package main
import "go-example/animal"
func main() {
var a animal.Animal
a = animal.Lion{Age: 10}
a.Breathe()
a.Walk()
}
./go-example/animal/animal.go
package animal
import "fmt"
type Animal interface {
Breathe()
Walk()
}
type Lion struct {
Age int
}
func (l Lion) Breathe() {
fmt.Println("Lion breathes")
}
func (l Lion) Walk() {
fmt.Println("Lion walk")
}
I'm trying to convert an interface dynamically back to it's original struct but I am having issues accessing attributes of the struct after the conversion.
Take this code for example.
package main
import (
"fmt"
"log"
)
type struct1 struct {
A string
B string
}
type struct2 struct {
A string
C string
}
type struct3 struct {
A string
D string
}
func main() {
s1 := struct1{}
s1.A = "A"
structTest(s1)
s2 := struct2{}
s2.A = "A"
structTest(s2)
s3 := struct3{}
s3.A = "A"
structTest(s3)
}
func structTest(val interface{}) {
var typedVal interface{}
switch v := val.(type) {
case struct1:
fmt.Println("val is struct1")
case struct2:
fmt.Println("val is struct2")
case struct3:
fmt.Println("val is struct3")
default:
log.Panic("not sure what val is.")
}
fmt.Println(typedVal.A)
}
I would like to be able to pass in one of 3 known struct types into my function. Then figure out which struct type was passed in to type assert it. Finally I want to be able to access like attributes.
Basically I want to have some basic inheritance in my structs, but so far it seems that it is not possible to do this in go. I saw some posts mentioning inheritance using an interface, but my structs have no methods so I'm not sure how I would use an interface.
Is something like this possible in go?
I would like to be able to pass in one of 3 known struct types into my function. Then figure out which struct type was passed in to type assert it. Finally I want to be able to access like attributes.
You can use type assertions to do exactly that. Basic idea is, in any case of the type switch just use type assertion to get a concrete instance of the corresponding type and then you can call whatever properties that you wish.
Take a look at the following example
package main
import (
"fmt"
)
type test1 struct {
A, B string
}
type test2 struct {
A, C string
}
func testType(val interface{}) {
switch val.(type) {
case test1:
t := val.(test1)
fmt.Println(t.B)
break
case test2:
t := val.(test2)
fmt.Println(t.C)
break
}
}
func main() {
t1, t2 := test1{B: "hello"}, test2{C: "world"}
testType(t1)
testType(t2)
}
Playground
Function structTest(val interface{}) in your code seems to be loosely typed. You pass it an untyped argument and expect it will satisfy some condition (will have field A), it looks strange in any typed language.
Using an interface this kind of polymorphism, in Go, to my mind, can be expressed something like
package main
import (
"fmt"
"log"
)
type A string
type HasA interface {
PrintA()
}
func (a A) PrintA() { fmt.Println(a) }
type struct1 struct {
A
B string
}
type struct2 struct {
A
C string
}
type struct3 struct {
A
D string
}
func main() {
s1 := struct1{}
s1.A = "A"
structTest(s1)
s2 := struct2{}
s2.A = "A"
structTest(s2)
s3 := struct3{}
s3.A = "A"
structTest(s3)
}
func structTest(val HasA) {
switch val.(type) {
case struct1:
fmt.Println("val is struct1")
case struct2:
fmt.Println("val is struct2")
case struct3:
fmt.Println("val is struct3")
default:
log.Panic("not sure what val is.")
}
val.PrintA()
}
Playground
I have a function that has a parameter with the type interface{}, something like:
func LoadTemplate(templateData interface{}) {
In my case, templateData is a struct, but each time it has a different structure. I used the type "interface{}" because it allows me to send all kind of data.
I'm using this templateData to send the data to the template:
err := tmpl.ExecuteTemplate(w, baseTemplateName, templateData)
But now I want to append some new data and I don't know how to do it because the "interface" type doesn't allow me to add/append anything.
I tried to convert the interface to a struct, but I don't know how to append data to a struct with an unknown structure.
If I use the following function I can see the interface's data:
templateData = appendAssetsToTemplateData(templateData)
func appendAssetsToTemplateData(t interface{}) interface{} {
switch reflect.TypeOf(t).Kind() {
case reflect.Struct:
fmt.Println("struct")
s := reflect.ValueOf(t)
fmt.Println(s)
//create a new struct based on current interface data
}
return t
}
Any idea how can I append a child to the initial interface parameter (templateData)? Or how can I transform it to a struct or something else in order to append the new child/data?
Adrian is correct. To take it a step further, you can only do anything with interfaces if you know the type that implements that interface. The empty interface, interface{} isn't really an "anything" value like is commonly misunderstood; it is just an interface that is immediately satisfied by all types.
Therefore, you can only get values from it or create a new "interface" with added values by knowing the type satisfying the empty interface before and after the addition.
The closest you can come to doing what you want, given the static typing, is by embedding the before type in the after type, so that everything can still be accessed at the root of the after type. The following illustrates this.
https://play.golang.org/p/JdF7Uevlqp
package main
import (
"fmt"
)
type Before struct {
m map[string]string
}
type After struct {
Before
s []string
}
func contrivedAfter(b interface{}) interface{} {
return After{b.(Before), []string{"new value"}}
}
func main() {
b := Before{map[string]string{"some": "value"}}
a := contrivedAfter(b).(After)
fmt.Println(a.m)
fmt.Println(a.s)
}
Additionally, since the data you are passing to the template does not require you to specify the type, you could use an anonymous struct to accomplish something very similar.
https://play.golang.org/p/3KUfHULR84
package main
import (
"fmt"
)
type Before struct {
m map[string]string
}
func contrivedAfter(b interface{}) interface{} {
return struct{
Before
s []string
}{b.(Before), []string{"new value"}}
}
func main() {
b := Before{map[string]string{"some": "value"}}
a := contrivedAfter(b)
fmt.Println(a)
}
You can't append data arbitrarily to a struct; they're statically typed. You can only assign values to the fields defined for that specific struct type. Your best bet is probably to use a map instead of structs for this.
Not recommended, but you can create structs dynamically using the reflect package.
Here is an example:
package main
import (
"encoding/json"
"os"
"reflect"
)
type S struct {
Name string
}
type D struct {
Pants bool
}
func main() {
a := Combine(&S{"Bob"}, &D{true})
json.NewEncoder(os.Stderr).Encode(a)
}
func Combine(v ...interface{}) interface{} {
f := make([]reflect.StructField, len(v))
for i, u := range v {
f[i].Type = reflect.TypeOf(u)
f[i].Anonymous = true
}
r := reflect.New(reflect.StructOf(f)).Elem()
for i, u := range v {
r.Field(i).Set(reflect.ValueOf(u))
}
return r.Addr().Interface()
}
You could use something like the Combine function above to shmush any number of structs together. Unfortunately, from the documentation:
StructOf currently does not generate wrapper methods for embedded fields. This limitation may be lifted in a future version.
So your created struct won't inherit methods from the embedded types. Still, maybe it does what you need.
If you are just looking to convert your interface to struct, use this method.
type Customer struct {
Name string `json:"name"`
}
func main() {
// create a customer, add it to DTO object and marshal it
receivedData := somefunc() //returns interface
//Attempt to unmarshall our customer
receivedCustomer := getCustomerFromDTO(receivedData)
fmt.Println(receivedCustomer)
}
func getCustomerFromDTO(data interface{}) Customer {
m := data.(map[string]interface{})
customer := Customer{}
if name, ok := m["name"].(string); ok {
customer.Name = name
}
return customer
}
I've seen a very similar question to this one but it doesn't address one important detail. How do you do this entirely through variables and without directly referencing the struct.
For instance, given the following, I've tried a few variants of main() methods to test this out:
package main
import (
"reflect"
"fmt"
)
type Operable interface {
compute() string
}
type Operator struct {
Operable
Name string
Type string
}
func (o Operator) compute() string {
return "operating"
}
type Read struct {
Operator
}
func (r Read) compute() string {
return "reading"
}
var Operators = make(map[string]reflect.Type)
func init() {
Operators[reflect.TypeOf(Read{}).Name()] = reflect.TypeOf(Read{})
}
I want to instantiate a new Read struct (Operator) from a string.
In the following, I get the error theOp.Name undefined (type interface {} is interface with no methods). Which is expected.
func main() {
nameOfOp := "Read"
typeOfOp := Operators[nameOfOp]
theOp := reflect.New(typeOfOp).Elem().Interface()
fmt.Println(theOp.Name)
}
If I do the following, I get the error typeOfOp is not a type.
func main() {
nameOfOp := "Read"
typeOfOp := Operators[nameOfOp]
theOp := reflect.New(typeOfOp).Elem().Interface().(typeOfOp)
fmt.Println(theOp.Name)
}
The only thing I have found to compile is to explicitly enter the struct type. But I want this to be dynamic, any thoughts?
func main() {
nameOfOp := "Read"
typeOfOp := Operators[nameOfOp]
theOp := reflect.New(typeOfOp).Elem().Interface().(Read)
fmt.Println(theOp.Name)
}
Thanks in advance.
I began to learn Go and have trouble understanding the following:
package main
import "fmt"
type I interface {
foo(interface {})
}
type S struct {}
func (s S) foo(i int) {
fmt.Println(i)
}
func main() {
var i I = S{}
i.foo(2)
}
This fails with:
cannot use S literal (type S) as type I in assignment:
S does not implement I (wrong type for foo method)
have foo(int)
want foo(interface {})
I don't understand why Go doesn't accept the foo(int) signature given the fact that int implements interface {}. Can anyone help with an explanation?
I think your understanding of interface isn't sound. Interface{} itself is a type. It consists of two things : underlying type and underlying value.
Golang doesn't have overloading. Golang type system matches by name and requires consistency in the types
So, when you are defining a function taking a interface type as a parameter:
foo(interface {})
This is a different function from a function taking int type:
foo(int)
So you should change the following line to
func (s S) foo(i interface{}) {
fmt.Println(i)
}
Or better yet to this:
type I interface {
foo()
}
type S struct {
I int
}
func (s S) foo() {
fmt.Println(s.I)
}
func main() {
var i I = S{2}
i.foo()
}
The error message itself is self-explaining:
"S does not implement I (wrong type for foo method)"
so S{} which is of S type cannot be used on the RHS of type I variable assignment.
To implement I interface, type S needs to define foo function with the exact same signature.
To achieve what you wanted, you can use empty interface as input parameter for your foo function in S and do type assertion
package main
import "fmt"
type I interface {
foo(interface {})
}
type S struct {}
func (s S) foo(i interface{}) {
if i, ok := i.(int); ok{
fmt.Println(i)
}
}
func main() {
var i I = S{}
i.foo(2)
i.foo("2")
}
Try it in go playground