return $data =InteractiveSession::with('messages.user')->where('exercise_id',$exercise->id)->first();
This code will return data like below
{
"id": 1,
"exercise_id": 48,
"messages": [
{
"id": 1,
"from_user": 69,
"message": "Hi",
"interactive_session_id": 1,
"user": {
"id": 69,
"first_name": "Jobin"
}
}
]}
how can i return data like below??
{
"id": 1,
"exercise_id": 48,
"messages": [
{
"id": 1,
"from_user":{
"id": 69,
"first_name": "Jobin"
},
"message": "Hi",
"interactive_session_id": 1,
}
]}
i have tables interactivesession,message,users, using hasmany relation
You can create a relation for from_user to the user model, and then do return $data = InteractiveSession::with(['messages.user', 'fromUser'])->where('exercise_id',$exercise->id)->first(); (remember fromUser should be your relation name)
Try this:
$data = InteractiveSession::with('messages.user')->where('exercise_id',$exercise->id)->first();
$data->transform(function($record) {
$messages = $record->messages->transform(function($message) {
'id' => $message->id,
'from_user' => [
'id' => $message->user->id,
'first_name' => $message->user->first_name
],
'message' => $message->message,
'interactive_session_id' => $message->interactive_session_id
});
return [
'id' => $record->id,
'exercise_id' => $record->exercise_id,
'messages' => $messages
];
});
Related
I am making an e-commerce site where the person can make an offer for the product. And I want to display all the offers on product at a place where I get the product.After that want to get the information about the user who made the offer and the parent offer in the same query.
I am getting the product like this
`public function show(Product $product)
{
// return response()->json($product);
return new SingleProductResource($product);
}`
The SingleProductResource returns the following
`public function toArray($request)
{
return [
'id' => $this->id,
'title' => $this->title,
'description' => $this->description,
'type' => $this->type,
'images' => $this->images,
'status' => $this->status,
'owner' => $this->user,
'offers' => $this->offers,
];
}`
Offers returns an array like this
`"offers": [
{
"id": 2,
"user_id": null,
"product_id": 1,
"offer_amount": "3",
"parent_id": 2,
"created_at": "2022-11-12T07:54:10.000000Z",
"updated_at": "2022-11-12T07:54:10.000000Z"
},
{
"id": 4,
"user_id": 1,
"product_id": 1,
"offer_amount": "3",
"parent_id": 2,
"created_at": "2022-11-12T08:01:29.000000Z",
"updated_at": "2022-11-12T08:01:29.000000Z"
},
{
"id": 5,
"user_id": null,
"product_id": 1,
"offer_amount": "3",
"parent_id": null,
"created_at": "2022-11-12T08:01:56.000000Z",
"updated_at": "2022-11-12T08:01:56.000000Z"
}
]`
But I want to get the user information directly in this query.
I cannot do this(see comment below) inside the resource as $this->offers returns an array.
`return [
'id' => $this->id,
'title' => $this->title,
'description' => $this->description,
'type' => $this->type,
'images' => $this->images,
'status' => $this->status,
'creator' => $this->user,
'offers' => $this->offers->user, //this
];`
You will need to trim your $product in some way. For example
$products = Product::leftJoin('offers', 'products.id', 'offers.product_id')
->where('user_id')
->where('products.id', $product['id'])
->get();
return new SingleProductResource::collection($products);
I am using Lumen to create api where I integrate collection. All code details are given below. I want to add pagination according to my code. How I add paginator in my code?
In Controller:
//To get all Employee Type
public function getAllEmployeeTypes(){
$employeeType = OsEmployeeType::where('status',1)->orderBy('priority', 'DESC')->get();
return new OsEmployeeTypeCollection($employeeType);
}
In Collection it looks like
public function toArray($request)
{
return [
'data' => $this->collection->map(function($data) {
return [
'id' => $data->id,
'name' => $data->name,
'priority' => $data->priority,
'status' => $data->status,
];
})
];
}
public function with($request)
{
return [
'success' => true,
'status' => 200
];
}
and the response that I got
{
"data": [
{
"id": 3,
"name": "Type 3",
"priority": 3,
"status": 1
},
{
"id": 2,
"name": "Type 2",
"priority": 2,
"status": 1
},
{
"id": 1,
"name": "Type 1",
"priority": 1,
"status": 1
}
],
"success": true,
"status": 200
}
How can I paginate my API response?
Paginate is the same as Laravel in Lumen. You will do just the same as in Laravel.
$employeeType = OsEmployeeType::where('status',1)->orderBy('priority', 'DESC')->skip(10)->take(5)->get();
Below is the code inside my CategoryResource.php
[
'id' => $this->id,
'name' => $this->name,
'categories' => CategoryResource::collection($this->children),
'items' => ItemListResource::collection($this->items)
];
and by this i am getting response like:
{
"status": true,
"data": {
"categories": [
{
"id": 10,
"name": "Fast Food",
"categories": [
{
"id": 11,
"name": "Pizza",
"categories": [],
"items": [
{
"id": 9,
"name": "Ham \u0026 Crab Stick",
"price": "20.00",
"image": "up/products/c11/Mrn4OpjngYRCkRJ28rJ1LbXUOXy0XjTRyXU7eFoi.jpg"
}
]
}
],
"items": []
}
]
}
}
i dont want "categories" : [] when category does not exist for a category.
please suggest some ideas or ways i can deal with this issue.
I assume that CategoryResource::collection($this->children) returns an array, maybe empty or not.
If that's true, then:
$dataArray = [
'id' => $this->id,
'name' => $this->name,
'items' => ItemListResource::collection($this->items)
];
$categories = CategoryResource::collection($this->children);
if (count(categories) > 0) $dataArray['categories'] = $categories;
In my DoctorController, I have show method like below -
public function show(Doctor $doctor){
DoctorResource::withoutWrapping();
return new DoctorResource($doctor->load('expertises'));
}
In my DoctorResource, if I do
public function toArray($request){
return parent::toArray($request);
}
It returns -
{
"id": 1,
"name": "John Doe",
"mobile": "1234567890",
"email": null,
"avatar": null,
"bio": "Lorem Ipsum 2",
"email_verified_at": null,
"mobile_verified_at": null,
"is_account_verified": 0,
"account_status": "Active",
"created_at": "2020-12-03T07:45:07.000000Z",
"updated_at": "2020-12-03T10:49:30.000000Z",
"expertises": [
{
"id": 1,
"expertise": "ABC",
"created_at": null,
"updated_at": null,
"pivot": {
"doctor_id": 1,
"expertise_id": 1,
"created_at": "2020-12-03T10:49:29.000000Z",
"updated_at": "2020-12-03T10:49:29.000000Z"
}
},
{
"id": 2,
"expertise": "XYZ",
"created_at": null,
"updated_at": null,
"pivot": {
"doctor_id": 1,
"expertise_id": 2,
"created_at": "2020-12-03T10:49:29.000000Z",
"updated_at": "2020-12-03T10:49:29.000000Z"
}
}
]
}
But I want to return certain fields from my DoctorResource, So I did this but it is giving me an error. Exception: Property [expertise] does not exist on this collection instance.
public function toArray($request){
return [
'id' => $this->id,
'name' => $this->name,
'mobile' => $this->mobile,
'email' => $this->email,
'avatar' => $this->avatar,
'bio' => $this->bio,
'expertises' => [
'name' => $this->expertises->expertise
]
];
}
you have define another Json Resource to do that:
first you can retrive the model and add keys and values based on each model properties like :
public function toArray($request){
return [
'id' => $this->id,
'name' => $this->name,
'mobile' => $this->mobile,
'email' => $this->email,
'avatar' => $this->avatar,
'bio' => $this->bio,
'expertises' => ExpertiesResource::collection($this->experties);
];
}
and you have to define Resource Collection as Follow:
class ExpertiesResource extends JsonResource
{
/**
* Transform the resource into an array.
*
* #param \Illuminate\Http\Request $request
* #return array
*/
public function toArray($request)
{
return [
"id" => $this->id,
"exp" => $this->exp,
.....
];
}
}
when your JsonResource has an Array of Object(Resource), you have to Define That Resource and make use of it like use App\Http\Resources\ExpertiesResource
I am trying to iterate my collection, which has nested collections, with the collection reject() function and return the original collection with the updated nested data.
So this is my quiz collection
{
"id": 1,
"title": "quiz 1",
"questions": [
{
"id": 1,
"quiz_id": 1,
"question": "q1 - q1",
"answers": [
{
"id": 1,
"question_id": 1,
"answer": "answer to question 1"
},
{
"id": 2,
"question_id": 1,
"answer": "answer to question 1"
}
]
},
{
"id": 2,
"quiz_id": 1,
"question": "q1 - q2",
"answers": [
{
"id": 3,
"question_id": 2,
"answer": "answer to question 1"
}
]
}
]
}
Now I want to iterate through the questions and reject those that were already answered and exist in the result collection. I do so by using the reject() function
$quizResults = [
{
"id": 1,
"user_id": 1,
"quiz_id": 1,
"question_id": 1,
"answer_id": 1,
"correct": 1,
"created_at": null,
"updated_at": null
}
];
$filtered = $quiz->questions->reject(function ($value, $key) use ($quizResult) {
return $quizResult->contains('question_id', $value->id);
});
I want to return the quiz collection with the updated questions (without the rejected questions), but I can't seem to figure out the correct way to accomplish this. (if i return just the $filtered variable i get the correct filtered results, however if i try putting it back in to the $quiz var it won't apply the rejected filter). If I just do
return $quiz
I will get the same original collection with all the questions as if I never ran the reject() function.
How do I make the $quiz->questions = $filtered; ?
Pass it by reference
$filtered = $quiz->questions->reject(function ($value, $key) use (&$quizResult) {
return $quizResult->contains('question_id', $value->id);
});
This is the min steps to reproduce your problem,
$quizResult = [
0 => [
'id' => 1,
'user_id' => 1,
'quiz_id' => 1,
'question_id' => 1,
'answer_id' => 1,
'correct' => 1,
'created_at' => null,
'updated_at' => null,
],
];
$quiz = [
'id' => 1,
'title' => 'quiz 1',
'questions' => [
0 => [
'id' => 1,
'quiz_id' => 1,
'question' => 'q1 - q1',
'answers' => [
0 => [
'id' => 1,
'question_id' => 1,
'answer' => 'answer to question 1',
],
1 => [
'id' => 2,
'question_id' => 1,
'answer' => 'answer to question 1',
],
],
],
1 => [
'id' => 2,
'quiz_id' => 1,
'question' => 'q1 - q2',
'answers' => [
0 => [
'id' => 3,
'question_id' => 2,
'answer' => 'answer to question 1',
],
],
],
],
];
$filtered = collect($quiz['questions'])->reject(function ($value) use ($quizResult) {
return collect($quizResult)->contains('question_id', $value['id']);
});
$quiz['questions'] = $filtered;
return $quiz;
And this the result,
{
"id": 1,
"title": "quiz 1",
"questions": {
"1": {
"id": 2,
"quiz_id": 1,
"question": "q1 - q2",
"answers": [
{
"id": 3,
"question_id": 2,
"answer": "answer to question 1"
}
]
}
}
}
I do not understand why you said it's returning original one.
I had to unset the $quiz['questions'] first so it was like this
unset($quiz['questions']);
$quiz['questions'] = $filtered->flatten();
return $quiz;
and the result was as intended:
{
"id": 1,
"title": "quiz 1",
"questions": [
{
"id": 2,
"quiz_id": 1,
"question": "q1 - q2",
"answers": [
{
"id": 3,
"question_id": 2,
"answer": "answer to question 1"
}
]
}
]
}