How to find channel information from channel name? - youtube-data-api

I am facing problem of fetching channel information by using channel name.
For example, https://www.youtube.com/c/mkbhd/videos is the url. here mkbhd is channel name. Is the any API endpoint which gives information by using channel name?
I tried with channel list(by YoutTube username) but received different channel information
Channel 1 - https://www.youtube.com/channel/UCBJycsmduvYEL83R_U4JriQ
Channel 2 - https://www.youtube.com/channel/UCmf_VrB73I-eJ3fq0adaOkg
I tried getting information of channel 1 with its channel name (above url - mkbhd), but got information of channel 2
Attaching screentshots
Thanks in advance.

Related

Can you give an example of comment channel message?

I don't understand how to comment on channels in Pyrogram
I hope you can give me an example of the comment channel. Thank you very much
Commenting on channels is the same as sending message because comments are basically replies to the auto-forwarded message (every channel message is auto forwarded to the linked group). The only difference is users can reply to the message without really being in the group.
If you already have the message (the group message):
await message.reply("See my comment")
Or you can get the message using id of the message in linked group. Look at the documentation of get_discussion_message for further.
You should have access to post on the associated discussion group.
Then you can use the below script to send a message as a comment on Pyrogram 2.0+.
from pyrogram import Client
Credentials = Client(
name="comment_on_channel",
api_id=---,
api_hash="---",
device_model="Comment On Channel",
app_version="CoCh v1.0",
)
with Credentials as app:
# Group's Numeric ID with corresponding -100 [integer]
group_ID = -1001234567890
# ID of the message that you want to reply to (ID of a post in the discussion group) [integer]
msg_ID = 165
app.send_message(
chat_id=group_ID,
reply_to_message_id=msg_ID,
text="My Comment"
)

Getting the discord voice channel using its id

I had a necessity to connect to a voice channel using its id. After some research, I came across something like this:-
channel: discord.channel.VoiceChannel = ctx.message.author.voice.channel
But I am unable to find a way of getting the channel using its id.
Thanks
You can use the guild.get_channel method to get a voice channel by id.
voicechannel = guild.get_channel(123456789012345678)
If you don't already have the guild, you can get it from the message.
voicechannel = message.guild.get_channel(123456789012345678)

How to determine a channel is a DM or a normal channel

I got a bot which may:
start talk when user say somethibng in DM with the bot.
start talk only when user mentioned the bot in some channel.
Question:
How can I know it's a DM channel or a normal channel?
I guess https://api.slack.com/methods/channels.info might help, but I'm not sure which property indicates it.
Your best approach is to use the conversations.info API method. It will tell you exactly what kind of channel it is. It actually replaces the older channels.info method (which only works for public channels anyways).
Among other you get:
"is_channel": true
"is_group": false
"is_im": false
Here is how those terms are used in the API and (mostly) in the documentation:
channel = public channel
group = private channel
im = direct message.
conversation = any kind of channel
Alternatively you can also guess the channel type based on the first letter of it's ID. That is not 100% though, because channels can be converted from one type to another while keeping their ID.
C: public channel
G: private chanel / MPIM
D: Direct Message / IM

Is there any way for broadcast to every channel in redis?

I am trying to broadcast the message to channel in redis, but every user have they'r own channel with their user_id.
the way i think can be use is get all active channel and then publish it one by one. because what i know redis can't publish if diferent channel.
but the problem is, in lib go-redis i am using when the user subribe and check the redis with command PUBSUB CAHNNELS there is no channel result. i read on documentation the subribe function not gonna actived thhe channel immidietly. so how can i get the subribe channel ?
is there any solution to solve this ?
i am using golang-redis https://godoc.org/github.com/go-redis/redis
Subscribe each connection to the per user channel and and a channel for broadcasts. To send to all users, publish to the broadcast channel. The subscriber code will look something like this with the go-redis client:
sub := client.Subscribe(userChannel, broadcastChannel)
defer sub.Close()
for {
m, err := sub.ReceiveMessage()
... do something with m
}
where userChannel and broadcastChannel are the names of Redis channels. Use code like this to broadcast:
cmd := client.Publish(broadcastChannel, message)
if cmd.Err() != nil {
// handle error
}

WebSphere MQ Receiver Channel Paused

I think I tried to start a channel that is already running or whatever. Whenever I start the sender channel, the receiver channel goes to a PAUSED state. I looked it up and found something about AdoptNewMCA configuration, not sure how to set it at the queue manager level. How do I fix this smoothly. Merely stopping and restarting the channels does not do it.
Error log says:
/02/2012 12:38:41 PM - Process(19161.269) User(mqm) Program(amqrmppa)
Host() Installation(Installation1)
VRMF(7.1.0.0) QMgr(QM_TEST2)
AMQ9514: Channel 'QM_TEST1.TO.QM_TEST2' is in use.
EXPLANATION: The requested operation failed because channel
''QM_TEST1.TO.QM_TEST2' is currently active. ACTION: Either end the channel
manually, or wait for it to close, and retry the operation.
----- amqrcsia.c : 1042 -------------------------------------------------------
08/02/2012 12:38:41 PM - Process(19161.269) User(mqm) Program(amqrmppa)
Host(...) Installation(Installation1)
VRMF(7.1.0.0) QMgr(QM_TEST2)
AMQ9999: Channel ''QM_TEST1.TO.QM_TEST2' to host '17.2.33.44' ended abnormally.
EXPLANATION: The channel program running under process ID 19161 for
channel ''QM_TEST1.TO.QM_TEST2' ended abnormally. The host name is
'17.2.33.44'; in some cases the host name cannot be
determined and so is shown as '????'. ACTION: Look at previous error
messages for the channel program in the error logs to determine the
cause of the failure. Note that this message can be excluded
completely or suppressed by tuning the "ExcludeMessage" or
"SuppressMessage" attributes under the "QMErrorLog" stanza in qm.ini.
Further information can be found in the System Administration Guide.
----- amqrmrsa.c : 887 --------------------------------------------------------
When looking these things up, I'd start first with the product manuals. In this case, the Infocenter topic on channel states says that a channel in PAUSED state is waiting on a retry interval. The sub-topic on channel errors explains why sending or receiving channels can be in retry:
If a channel is unable to put a message to the target queue because
that queue is full or put inhibited, the channel can retry the
operation a number of times (specified in the message-retry count
attribute) at a time interval (specified in the message-retry interval
attribute). Alternatively, you can write your own message-retry exit
that determines which circumstances cause a retry, and the number of
attempts made. The channel goes to PAUSED state while waiting for the
message-retry interval to finish.
So if you stop your channels, you should see a message in the XMitQ on the sending side. If you GET-enable that queue you can browse the message, look at the header and see which queue it is destined for. On the receiving side, look to see if that queue is full.
Classic fast-sender, slow-consumer problem here. If the consumer can't keep up, the messages back up on the receiving QMgr, then the channel goes to retry and they begin to back up on the sending QMgr. Got to monitor depth and input handles on request queues.
Make sure a DLQ is set.
Try reducing the message retry count to 1 to speed up use of the DLQ.

Resources