Spring Scheduler to run at different timings on a single day - spring-boot

I have a requirement where my scheduler has to run for every hour between 9 AM to 12 PM everday and then it runs once by 3PM and 5 PM respectively.
How can i make my CRON expression to work according to the requirement
So far i have tried with below cron expression
#Scheduled(cron="0 0 9-12 * * *")
But that runs for every hour from 9 AM - 12 PM
How can i modify it to make it run once by 3 PM and 5 PM also.
I have tried by combining two cron expressions like below but that dint work.
#Scheduled(cron="0 0 9-12 * * *, 0 0 3 * * *")
Can i give 2 cron expressions through 2 #Scheduled like below
#Scheduled(cron="0 0 9-12 * * *")
#Scheduled(cron="0 0 9-12 * * *")
public void myMethod() {}
Would that be a feasible solution?
Can anybody help me with this?

#Schedules annotation can be used to set multiple calendar-based timer expressions.
This annotation will get rid of the redundancy of writing the same
method multiple times.
In the following example, the first expression sets a timer to expire on the last day of every month. The second expression sets a timer to expire every Friday at 11:00 PM.
#Schedules ({
#Schedule(dayOfMonth="Last"),
#Schedule(dayOfWeek="Fri", hour="23")
})
public void doPeriodicCleanup() { ... }

Related

Spring scheduled task cron expression validation

I'm writing a scheduled task that need to run every 1st Saturday of each month.
I came up with this:
#Scheduled(cron = "0 0 23 1-7 * SAT")
// Runs on 1st Saturday of each month at 23:00
public void CleanUpScheduledTask() {
}
How did I come uo with this:
0 0 23 means at 11:00 PM everyday
1-7 * means between 1-7 every month
SAT Saturdays
How do you suggest to make sure that the above expression is valid? how I test such functionalities?
Thanks for the help.
1. Building Cron Expression
Using the Spring cron job expression
#Scheduled(cron = "[Seconds] [Minutes] [Hours] [Day of month] [Month] [Day of week] [Year]")
NB year field is optional
# used to specify day of the week and week the task should start.
eg first Saturday of every month(7#1)
? represents no specific value and can be used in either the day of month or day of week field
* represents all values
hence cron expression becomes
#Scheduled(cron = "0 0 23 ? * 7#1")
2. Testing Cron Job
use Awaitility dependency
<dependency>
<groupId>org.awaitility</groupId>
<artifactId>awaitility</artifactId>
<scope>test</scope>
</dependency>
-using Spring Integration testing
#SpringJUnitConfig(CleanScheduler.class)
public class CleanSchedulerUnitTest {
#Autowired
private CleanScheduler cleanScheduler;
#Test
void cleanUpScheduledTaskShouldReturnSuccess() {
//Act
cleanScheduler.cleanUpScheduledTask();
//Assertions
}
}
You can use an online Cron generator like https://www.freeformatter.com/cron-expression-generator-quartz.html to generate cron expressions or to describe what you posted.
0 0 0,23 ? * 7#1 * should be described and run At second:00, at minute:00, at 00 am and 23pm, on the 1st Saturday of the month, every month.

Translating and understanding the #Scheduled cron message

I have this code.
This cron message means "do this method every Sunday in 01.00 a.m." or I make a mistake translating this?
#Scheduled(cron = "0 1 0 * * ?")
private void notificationsScheduler() {
//implementation
}
you are wrong, it means every day.
Your expression
"0 1 0 * * ?"
means: At 00:01:00am every day
As per your requirement : At 01:00:00am, on every Sunday, every month
Use:
0 0 1 ? * SUN *
Follow this https://www.freeformatter.com/cron-expression-generator-quartz.html for more detail.

Spring Cron Expression to run every Tuesday night 9?

I am using Spring schedule. I configured the following Cron expression to run my task every Tuesday night at 9pm,
"0 0 21 * * TUE"
However, I am getting the following exception when am starting the application
Encountered invalid #Scheduled method 'runSchduler': Cron expression must consist of 6 fields
Is my Spring Cron expression wrong?
Is my Spring Cron expression configured, to run every Tuesday night at 9
wrong?
Yes :)
But try,
0 0 21 ? * TUE
Or with the Spring annotation:
#Scheduled(cron = "0 0 21 * * TUE")
The following is a really handy website for creating Cron expressions.
http://www.cronmaker.com/
Take note: Just remove the last element from the created expression to use it with Spring scheduling.
And a nice way to verify it in Natural Language here
Cron Expression for Everyday Tuesday Midnight 9 PM
0 0 21 ? * TUE
cleck below cron with zone example
#Component
public class SpringScheduling {
#Scheduled(cron = "0 0 21 ? * TUE",zone="Asia/Calcutta")
public void trackScheduling() {
System.out.println("Scheduled task running");
}
}
Looks like you have a field too much?
Just generated this based on your criteria of Tuesdays at 9PM
"0 21 * * 2"

Job execution in a jee environment

I am working on an application that gives its users the ability to do financial transactions. I have some operations that need some days to be executed.
So I want to know if there is a way to execute these operations in the expected day without my intervention, I mean it should be automatically done by the system.
I am actually working with spring framework and I have done some researches and find out the Task Execution and Scheduling supported by spring framework. but I don't know if this is a good choice for my case because I don't know if this job executer will work even if my application is not running and as you know the transactions execution should be done with or without running the application.
I am new to spring framework and especially to this job thing.
can anyone please explain to me this 'Job' concept and how to use it in my case.
Scheduling Tasks with spring is very reliable, however your application must be running.
You can use cron expressions to set the trigger, in this example it will run every day from Monday to Friday at 2a.m.
#Component
public class ScheduledTasks {
private static final Logger log = LoggerFactory.getLogger(ScheduledTasks.class);
private static final SimpleDateFormat dateFormat = new SimpleDateFormat("HH:mm:ss");
#Scheduled(cron="0 0 2 * * MON-FRI")
public void reportCurrentTime() {
log.info("The time is now {}", dateFormat.format(new Date()));
}
}
here how to build cron expressions spring like
Example patterns:
"0 0 * * * *" = the top of every hour of every day.
"*/10 * * * * *" = every ten seconds.
"0 0 8-10 * * *" = 8, 9 and 10 o'clock of every day.
"0 0 6,19 * * *" = 6:00 AM and 7:00 PM every day.
"0 0/30 8-10 * * *" = 8:00, 8:30, 9:00, 9:30, 10:00 and 10:30 every day.
"0 0 9-17 * * MON-FRI" = on the hour nine-to-five weekdays
"0 0 0 25 12 ?" = every Christmas Day at midnight

Spring cron expression for every day two times

I have following spring job to run every day two times please check my following cron express is that correct to trigger every day two times.
#Scheduled(cron = "0 0 24/12 * ? *")
public void demoService()
{
}
I tried the above expression, but this didn't work. What's wrong here?
You could use
0 0 0/12 * * ?
which means every 12 hours.
#Scheduled(cron = "0 0 0/12 * * ?")
public void demoService()
{
}
Hope it could help.

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