OneToOne CascadeType in spring data jpa - spring

I use OneToOne in the spring data JPA and I want to delete a record from the Address table without touching the user. But I can't.
If I remove User, in this case Address is removed, that's good.
But how can you delete an Address without touching the User?
https://github.com/myTestPercon/TestCascade
User.Java
#Entity
#Table(name = "user", schema = "testCascade")
public class User implements Serializable {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Column(name = "id")
private Long id;
#Column(name = "name")
private String name;
#OneToOne(mappedBy = "user", cascade = CascadeType.ALL)
private Address address;
// Getter and Setter ...
}
Address.java
#Entity
#Table(name = "address", schema = "testCascade")
public class Address implements Serializable {
#Id
private Long id;
#Column(name = "city")
private String city;
#OneToOne
#MapsId
#JoinColumn(name = "id")
private User user;
// Getter and Setter ...
}
DeleteController.java
#Controller
public class DeleteController {
#Autowired
ServiceJpa serviceJpa;
#GetMapping(value = "/deleteAddressById")
public String deleteAddressById () {
serviceJpa.deleteAddressById(4L);
return "redirect:/home";
}
}

You got your mapping wrong thats all is the problem .
try the below and see
User.java
#Entity
#Table(name = "user", schema = "testCascade")
public class User implements Serializable {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Column(name = "id")
private Long id;
#Column(name = "name")
private String name;
#OneToOne(cascade=CascadeType.ALL)
#JoinColumn(name="foriegn key column in user table for address example.. address_id")
private Address address;
// Getter and Setter ...
}
Address.java
#Entity
#Table(name = "address", schema = "testCascade")
public class Address implements Serializable {
#Id
private Long id;
#Column(name = "city")
private String city;
//name of the address variable in your user class
#OneToOne(mappedBy="address",
cascade={CascadeType.DETACH, CascadeType.MERGE, CascadeType.PERSIST,
CascadeType.REFRESH})
private User user;
// Getter and Setter ...
}

In order to solve this problem, you need to read the hibernate Documentation Hibernate Example 162, Example 163, Example 164.
And also I recommend to look at this is Using #PrimaryKeyJoinColumn annotation in spring data jpa
This helped me in solving this problem.
And also you need to specify the parameter orphanRemoval = true
User.java
#Entity(name = "User")
#Table(name = "user", schema = "testother")
public class User implements Serializable {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Column(name = "id")
private Long id;
#Column(name = "name")
private String name;
#OneToOne(mappedBy = "user", cascade = CascadeType.ALL, orphanRemoval = true)
private Address address;
public void addAddress(Address address) {
address.setUser( this );
this.address = address;
}
public void removeAddress() {
if ( address != null ) {
address.setUser( null );
this.address = null;
}
}
// Getter and Setter
}
Address.java
#Entity(name = "Address")
#Table(name = "address", schema = "testother")
public class Address implements Serializable {
#Id
private Long id;
#Column(name = "city")
private String city;
#OneToOne
#MapsId
#JoinColumn(name = "id")
private User user;
// Getter and Setter
}
DeleteController .java
#Controller
public class DeleteController {
#Autowired
ServiceJpa serviceJpa;
#GetMapping(value = "/deleteUser")
public String deleteUser () {
User user = serviceJpa.findUserById(2L).get();
user.removeAddress();
serviceJpa.saveUser(user);
return "/deleteUser";
}
}
Or make a custom SQL query.
#Repository
public interface DeleteAddress extends JpaRepository<Address, Long> {
#Modifying
#Query("delete from Address b where b.id=:id")
void deleteBooks(#Param("id") Long id);
}

public class Address {
#Id
private Long id;
#MapsId
#JoinColumn(name = "id")
private User user;
}
Rename #JoinColumn(name = "id") to #JoinColumn(name = "user_id")
You can't say that the column that will point to user will be the id of the Address

Related

Rest api creation for multiple path variables

I need to fetch names of all students who have enrolled for the courses.
Url:-/students/{course1}/{course2}
Eg /students/java/oracle
How to write controller, service and repository in rest api.
Entity:-
Student
Integer Id,String name and list coursenames
What about?
#Controller
#RequestMapping("/students")
public class StudentController {
#Autowired
private StudentService studentService;
// /students/java,oracle
#GetMapping(value="/{courses}")
#ResponseBody
public String getStudents(#PathVariable String[] courses) {
return studentService.getStudents(courses);
}
}
Student
#Entity
#Table(name = "student")
public class StudentDao {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Column(name = "id")
private Long id;
#Column(name = "name")
private String name;
#OneToMany(fetch = FetchType.EAGER)
#Fetch(value = FetchMode.SUBSELECT)
#JoinColumn(name = "id", referencedColumnName = "id")
private List<CourseDao> course;
}
Course
#Entity
#Table(name = "course")
public class CourseDao {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Column(name = "id")
private Long id;
#Column(name = "name")
private String name;
}
In my opinion it is bad rest design. I'll create POST endpoint with body, which contains array with course Id's and find students by course id's.
If the parameters are optional or an array you shouldn't use a path variable but use a request parameter.

Add extra custom column to auto mapped Table in Spring JPA ManyToMany

#Getter #Setter #NoArgsConstructor #AllArgsConstructor
#Table(name = "my_users")
public class MyUsers {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(nullable = false)
private Long id;
#Column(nullable = false, unique = true)
private String userName;
private String password;
#ManyToMany
private List<MyUsers> connections;
}
This is my MyUsers Model Class. I am using Hibernate and MySQL.
#ManyToMany
private List<MyUsers> connections;
This ManyToMany relationship is automatically creating the table 'my_users_connections' with 'my_users_id' and 'connections_id' colums. How can I add extra columns to this auto mapped table?
It's not ideal solution...
#Getter
#Setter
#NoArgsConstructor
#AllArgsConstructor
#Entity
#Table(name = "my_users")
public class MyUsers implements Serializable {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(nullable = false)
private Long myUsersId;
#Column(nullable = false, unique = false)
private String userName;
private String password;
#ManyToMany(cascade = CascadeType.ALL)
#JoinTable(name = "my_users_connections",
joinColumns = { #JoinColumn(name = "my_users_id") },
inverseJoinColumns = { #JoinColumn(name = "connections_id") })
private List<MyUsers> connections;
}
Create embedded id MyUsersConnectionsPK:
#Data
#Embeddable
public class MyUsersConnectionsPK implements Serializable {
#Column(name = "my_users_id")
private Long myUsersId;
#Column(name = "connections_id")
private Long connectionsId;
}
Create MyUsersConnections, which represent ManyToMany
#Data
#Entity
#Table(name = "my_users_connections")
public class MyUsersConnections implements Serializable {
#EmbeddedId
private MyUsersConnectionsPK id;
#ManyToOne
#MapsId("my_users_id")
#JoinColumn(name = "my_users_id")
private MyUsers myUsersId;
#ManyToOne
#MapsId("connections_id")
#JoinColumn(name = "connections_id")
private MyUsers connectionsId;
#Column(name = "extra_column")
private String extraColumn;
}
Create JPA repository
#Repository
public interface MyUsersConnectionsRepository extends JpaRepository<MyUsersConnections, MyUsersConnectionsPK> {
List<MyUsersConnections> findMyUsersConnectionsByMyUsersIdMyUsersId(Long id);
}
And simple sample for using:
#Service
public class Test {
#Autowired
private MyUsersConnectionsRepository myUsersConnectionsRepository;
#Autowired
private MyUsersRepository myUsersRepository;
public void test() {
MyUsers myUsers = new MyUsers();
myUsers.setUserName("user name");
myUsers.setPassword("password");
MyUsers myUsers2 = new MyUsers();
myUsers2.setUserName("user name 2");
myUsers2.setPassword("password 2");
myUsers.setConnections(Collections.singletonList(myUsers2));
myUsers = myUsersRepository.saveAndFlush(myUsers);
List<MyUsersConnections> myUsersConnections = myUsersConnectionsRepository.findMyUsersConnectionsByMyUsersIdMyUsersId(myUsers.getMyUsersId());
MyUsersConnections item = myUsersConnections.get(0);
item.setExtraColumn("Extra column");
myUsersConnectionsRepository.saveAndFlush(item);
}
}

(Do not display relationship values)

I have two entity with name of the article and article Category.
and they have one-to-many relationships.
I use #JsonIdentityInfo(generator=ObjectIdGenerators.PropertyGenerator.class,property = "id")
but I cant see data of article category(category_id) in spring data rest.
ArticleCategory.class
#Entity
#Table(name = "article_category")
#Getter
#Setter
public class ArticleCategory implements Serializable {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
#Column(name = "category_name")
private String categoryName;
#OneToMany(cascade = CascadeType.ALL, mappedBy = "articleCategory", fetch = FetchType.LAZY)
private Set<Article> articles = new HashSet<>();
}
Article.class
#Entity
#Table(name = "article")
#Getter
#Setter
#JsonIdentityInfo(generator = ObjectIdGenerators.PropertyGenerator.class,
property = "id")
public class Article implements Serializable {
public Article() {
}
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
#ManyToOne(fetch = FetchType.LAZY)
#JoinColumn(name = "category_id", nullable = false)
private ArticleCategory articleCategory;
#Column(name = "title")
private String title;
#Column(name = "image_url")
private String image_url;
#Column(name = "short_description")
private String short_description;
#Column(name = "text")
private String text;
#Column(name = "keywords", nullable = true)
private String keywords;
#Column(name = "visit", nullable = false)
private int visit;
#Column(name = "code", nullable = false)
private UUID code;
#Column(name = "date_created")
#CreationTimestamp
private Date dateCreated;
#Column(name = "date_updated", nullable = false)
#UpdateTimestamp
private Date dateUpdated;
#ManyToOne(fetch = FetchType.LAZY)
#JoinColumn(name = "user_id")
private User user;
public Article(String title, String image_url, String short_description, String text, String keywords, int visit, UUID code) {
this.title = title;
this.image_url = image_url;
this.short_description = short_description;
this.text = text;
this.keywords = keywords;
this.visit = visit;
this.code = code;
}
}
Article Repository
#CrossOrigin("http://localhost:4200")
#RepositoryRestResource(collectionResourceRel = "article", path = "article")
public interface ArticleRepository extends JpaRepository<Article,Long> {
Article findByCode(UUID uuid);
}
And this is output of spring data rest
enter image description here
That is exactly because you used #JsonManagedReference and #JsonBackReference. Keep in mind the following when using them:
#JsonManagedReference is the forward part of the relationship and is the one that gets serialized normally.
#JsonBackReference is the back part of the relationship and it will be omitted from serialization.
The serialized Article object does not contain a reference to the ArticleCategory object.
If you want to have any ArticleCategory data when serializing Article you can either use #JsonIdentityInfo so that one of the properties is serialized (in this case I've chosen id for both):
#Entity
#Table(name = "article")
#Getter
#Setter
#JsonIdentityInfo(
generator = ObjectIdGenerators.PropertyGenerator.class,
property = "id")
public class Article implements Serializable{
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
#ManyToOne(fetch = FetchType.LAZY)
#JoinColumn(name = "category_id", nullable = false)
private ArticleCategory articleCategory;
}
#Entity
#Table(name = "article_category")
#Getter
#Setter
#JsonIdentityInfo(
generator = ObjectIdGenerators.PropertyGenerator.class,
property = "id")
public class ArticleCategory implements Serializable {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
#Column(name = "category_name")
private String categoryName;
#OneToMany(cascade = CascadeType.ALL,mappedBy = "articleCategory" ,fetch = FetchType.LAZY)
private Set<Article> articles=new HashSet<>();
}
If you are only interested in categoryId another possibility would be to use #JsonIgnore on private Set<Article> articles property so that it is not serialized:
#Entity
#Table(name = "article_category")
#Getter
#Setter
public class ArticleCategory implements Serializable {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
#Column(name = "category_name")
private String categoryName;
#JsonIgnore
#OneToMany(cascade = CascadeType.ALL,mappedBy = "articleCategory" ,fetch = FetchType.LAZY)
private Set<Article> articles=new HashSet<>();
}
If none of those suits your needs you might need to implement your own custom serializer. You can read more about all those options at https://www.baeldung.com/jackson-bidirectional-relationships-and-infinite-recursion.
I solved the problem using the controller
And that's why #JsonManageRefrence and #JsonBackRefrence do not work
I replaced the lazy load with the eager load in both entity
#ManyToOne(fetch = FetchType.Eager)
#JoinColumn(name = "user_id")
#JsonManageRefrence
private User user;
#OneToMany(cascade = CascadeType.ALL, mappedBy = "articleCategory",
fetch = FetchType.Eager)
#JsonBackRefrence
private Set<Article> articles = new HashSet<>();
and then add a controller
package com.example.demo;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.web.bind.annotation.GetMapping;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RestController;
import java.util.List;
#RestController
#RequestMapping("/getAllArticle")
public class MyController {
private ArticleRepository articleRepository;
// you must do constructor injection
#GetMapping("/getAllArticle")
public List<Article> allArticle()
{
return articleRepository.findAll();
}
}

Spring JPA: How to insert data to join many tables with #ManytoMany relationship

I'm starting to learn Spring Java Framework . I created some Enity to join 2 Model like my Database. And now I want to insert to Join Table by JpaRepository. What i have to do?
This is my Code (Please fix help me me if something is not right)
Model Users_RoomId to define Composite Primary Key
#Embeddable
public class Users_RoomId implements Serializable {
private static final long serialVersionUID = 1L;
#Column(name = "ID_room", nullable = false)
private String idRoom;
#Column(name = "user_id", nullable = false)
private int idUser;
}
Model Users_Room to join 2 Model Users and Room
#Entity
#Table(name ="bookroom")
public class Users_Room {
#EmbeddedId
private Users_RoomId usersroomId;
#ManyToOne
#MapsId("idRoom")
private Room room;
#ManyToOne
#MapsId("idUser")
private Users users;
#Column(name = "Bookday")
private String bookday;
Model Users and Room I used annotation #OneToMany
Model Users
#Entity
#Table(name = "users")
public class Users implements Serializable{
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "user_id", nullable = false)
private int id;
#Column(name = "name", nullable = false)
private String name;
#Column(name = "email")
private String email;
#Column(name = "pass")
private String pass;
#Column(name = "role")
private int role;
#OneToMany(mappedBy = "users")
private List<Users_Room> user;
Model Room
#Entity
#Table(name ="room")
public class Room implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "ID_room", nullable = false)
private String id;
#Column(name = "name_room", nullable = false)
private String name;
#Column(name = "Description")
private String describe;
#ManyToOne
#JoinColumn(name = "ID_status")
private Status status;
#Column(name = "room_image")
private String image;
public Room() {
super();
}
#ManyToOne
#JoinColumn(name = "ID_kind")
private KindRoom kind;
#OneToMany(mappedBy = "room")
private List<Users_Room> rooms;
This is my database
So I don't know how to insert a new bookroom with iduser,idroom and bookday with JPA repository.. It'necessary to write Query in JPARepository or We just need to use method save() to insert data
Thanks everyone
I had same problem and solved with following code. I used method save() to insert data. Following code is 'createRoom' method in 'RoomService.java'.
RoomService.java
private final RoomRepository roomRepository;
private final UserRoomRepository userRoomRepository;
private final UserRepository userRepository;
public RoomService(RoomRepository roomRepository, UserRoomRepository userRoomRepository, UserRepository userRepository) {
this.roomRepository = roomRepository;
this.userRoomRepository = userRoomRepository;
this.userRepository = userRepository;
}
#Transactional
public RoomDto createRoom(Long userId, Long chattingUserId) {
Room room = roomRepository.save(new Room());
room.addUserRoom(userRepository.findById(userId).orElseThrow(()->new NoSuchElementException("No User")));
room.addUserRoom(userRepository.findById(chattingUserId).orElseThrow(()->new NoSuchElementException("No User")));
userRoomRepository.save(new UserRoom(userRepository.findById(userId).orElseThrow(()->new NoSuchElementException("No User")),room));
userRoomRepository.save(new UserRoom(userRepository.findById(chattingUserId).orElseThrow(()->new NoSuchElementException("No User")),room));
RoomDto roomDto = RoomDto.of(room);
return roomDto;
}

How to get an Authenticated User's Details in Spring Security OAuth2

I am unable to extract the current logged in user in Spring Security OAuth2. My goal is to extract the user when the create event on ClientSuggestion entity is triggered and persist it to the database.
Employee.java
#Entity
#Table(name = "er_employee")
public class Employee implements Serializable {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Column(name = "id")
private Long id;
#Column(name = "username", unique = true)
#NotNull
#Size(max = 10)
private String username;
#Column(name = "password_hash")
#NotNull
#Size(min = 8, max = 512)
private String password;
#Column(name = "email_verification_token")
#Size(max = 512)
private String emailVerificationToken;
#Column(name = "password_reset_token")
#Size(max = 512)
private String passwordResetToken;
#Column(name = "active")
#NotNull
private boolean active;
#Column(name = "is_deleted")
#NotNull
private boolean deleted;
#Column(name = "date_of_creation")
#Temporal(TemporalType.TIMESTAMP)
#NotNull
private Date dateOfCreation;
#OneToMany(mappedBy = "employee")
private List<ClientSuggestion> clientSuggestions;
//Constructors
//Getters ans setters
}
ClientSuggestion.java
#Entity
#Table(name = "er_suggestion")
public class ClientSuggestion implements Serializable {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Column(name = "id")
private Long id;
#Column(name = "content", unique = true)
#NotNull
#Size(max = 200)
private String suggestion;
#ManyToOne
#JoinColumn(name = "employee_id")
private Employee employee;
//Constructors
//Getters ans setters
}
EmployeeRepository.java
public interface EmployeeRepository extends CrudRepository<Employee, Long> {
ClientSuggestionRepository .java
public interface ClientSuggestionRepository extends CrudRepository<ClientSuggestion, Long> {
}
The event handler
#Component
#RepositoryEventHandler(ClientSuggestion.class)
public class ClientSuggestionEventHandler {
Employee employee= (Employee ) SecurityContextHolder.getContext().getAuthentication().getPrincipal();
#HandleBeforeCreate
public void handleClientSuggestionBeforeCreate(ClientSuggestion cs) {
cs.setDeleted(false);
cs.setActive(true);
cs.setPasswordResetToken(Encryptor.generateHash(cs.getPassword, 512));
cs.setEmployee(employee);
}
}
The bean, ClientSuggestionEventHandler, is registered in a configuration class. When I tried running the project, NullPointerException exception is thrown. I wish to find out how to get the current logged employee.
I'm new to Spring Security OAuth2. Thanks.
In Employee.java implement org.springframework.security.core.userdetails.UserDetails class
Employee.java
#Entity
#Table(name = "er_employee")
public class Employee implements Serializable, UserDetails {
And then use Employee employee= (Employee) SecurityContextHolder.getContext().getAuthentication().getPrincipal();

Resources