I am implementing page cache for one of my page. For depenedency, I have to check an array, which can be either exist or not. Possible array keys cane ,
usersearch['id'], usersearch['name'], usersearch['phone]. I have to add dependency for any change in these values as well.
Also, I have to clear cache for any update or add in user table.
Is there any possible solution for this.?
Thanks in advance
You can use variations
public function behaviors(){
$usersearch = Yii::$app->requst->get('usersearch');
return [
[
'class' => 'yii\filters\PageCache',
'only' => ['index'],
'duration' => 60,
'variations' => [
'YOUR_DYNAMIC_VALUE1','YOUR_DYNAMIC_VALUE2'
],
'dependency' => [
'class' => 'yii\caching\DbDependency',
'sql' => 'SELECT COUNT(*) FROM post',
],
],
];
}
Ref link
IN YOUR CASE ,you can use
'variations' => \Yii::$app->requst->get('usersearch')??[],
or
'variations' => [
\/Yii::$app->requst->get('usersearch')['id'] ?? '',
\Yii::$app->requst->get('usersearch')['name'] ?? '',
\Yii::$app->requst->get('usersearch')['phone'] ?? '',
]
You could use a yii\caching\FileCache component with the following configuration.
Firstly, you set the cache in the init function of your controller:
Yii::$app->setComponents([
'yourCacheName' => [
'class' => \yii\caching\FileCache::class,
'defaultDuration' => 1800, //cache duration in seconds
'keyPrefix' => Yii::$app->getSession()->getId(). '_'
]
]);
Here, the parameter keyPrefix is set so that it is linked to the session ID. Thus, the visitors do not see each other's cached page. If the content is static and equal, regardless of the user or the session, this parameter can be removed.
In the view that must be cached you can call the beginCache function and the dependency as follows:
$this->beginCache('cache-id', [
'cache' => Yii::$app->yourCacheName, // the name of the component as set before
'variations' => [
$usersearch['id'] ?? '',
$usersearch['name'] ?? '',
$usersearch['phone'] ?? '',
],
'dependency' => [
'class' => \yii\caching\DbDependency::class,
'sql' => 'SELECT count(*) FROM your_user_table'
]
]);
// your view
$this->endCache();
Related
We're having a problem with our test suite.
When we run this using the test suite we get a 'The table is empty...' response from PHPUnit.
We know it works as we've also tested using Stripe's 'Send a web hook' test function which works, and the response is stored as expected.
Our code is here:
public function test_webhook_received()
{
$this->expectsJobs([StoreStripeWebHookJob::class]);
$this->postJson('/stripeHook', [
'created' => 1326853478,
'livemode' => false,
'id' => 'evt_00000000000000',
'type' => 'account.external_account.created',
'object' => 'event',
'request' => NULL,
'pending_webhooks' => 1,
'api_version' => '2019-12-03',
'data' => [
'object' => [
'id' => 'ba_00000000000000',
'object' => 'bank_account',
'account' => 'acct_00000000000000',
'account_holder_name' => 'Jane Austin',
'account_holder_type' => 'individual',
'bank_name' => 'STRIPE TEST BANK',
'country' => 'US',
'currency' => 'gbp',
'fingerprint' => '8JXtPxqbdX5GnmYz',
'last4' => '6789',
'metadata' => [],
'routing_number' => '110000000',
'status' => 'new',
],
],
]);
$this->assertDatabaseHas('stripe_webhooks', [
'stripe_created_at' => 1326853478,
'type' => 'account.external_account.created',
]);
}
The response received is:
Failed asserting that a row in the table [stripe_webhooks] matches the
attributes {
"stripe_created_at": 1326853478,
"type": "account.external_account.created" }.
The table is empty..
If we remove the
$this->expectsJobs([StoreStripeWebHookJob::class]);
tests succeed. Obviously the expectsJob() call should be where it is though.
ExpectsJob also intercepts the job. Much like expectsException. Judging from your clean naming convention "StoreStripe..." - I'd say it's really not storing under these test circumstances.
You'll need to test separately that your endpoint/controller is queuing a job... and that the job is storing the data. 2 tests.
I've been trying to work with Guzzle and learn my way around it, but I'm a bit confused about using a request in conjunction with empty or null values.
For example:
$response = $client->request('POST',
'https://www.testsite.com/coep/public/api/donations', [
'form_params' => [
'client' => [
'web_id' => NULL,
'name' => 'Test Name',
'address1' => '123 E 45th Avenue',
'address2' => 'Ste. 1',
'city' => 'Nowhere',
'state' => 'CO',
'zip' => '80002'
],
'contact' => [],
'donation' => [
'status_id' => 1,
'amount' => $donation->amount,
'balance' => $donation->balance,
'date' => $donation->date,
'group_id' => $group->id,
],
]
]);
After running a test, I found out that 'web_id' completely disappears from my request if set to NULL. My question is how do I ensure that it is kept around on the request to work with my conditionals?
At this point, if I dd the $request->client, all I get back is everything but the web_id. Thanks!
I ran into this issue yesterday and your question is very well ranked on Google. Shame that it has no answer.
The problem here is that form_params uses http_build_query() under the hood and as stated in this user contributed note, null params are not present in the function's output.
I suggest that you pass this information via a JSON body (by using json as key instead of form_params) or via multipart (by using multipart instead of form_params).
Note: those 2 keys are available as constants, respectively GuzzleHttp\RequestOptions::JSON and GuzzleHttp\RequestOptions::MULTIPART
Try to define anything like form_params, headers or base_uri before creating a client, so:
// set options, data, params BEFORE...
$settings = [
'base_uri' => 'api.test',
'headers' => [
'Accept' => 'application/json',
'Authorization' => 'ajustneedatokenheredontworry'
],
'form_params' => [
'cash' => $request->cash,
'reason' => 'I have a good soul'
]
];
// ...THEN create your client,
$client = new GuzzleClient($settings);
// ...and finally check your response.
$response = $client->request('POST', 'donations');
If you check $request->all() at the controller function that you are calling, you should see that were sent successfully.
For those using laravel, use this:
Http::asJson()
In my CakePHP application, I have applied Url validations so that admin can access only those actions which are defined for admin and same as with users.
In my application, "surveylist" is the action of admin and when any user directly access that action(surveylist), URL validations work(Unauthorized access msg is displayed).
But below that message ctp file of surveylist executes forcefully and show errors because I have validated URL through the try-catch block and it cannot get the set variables of action.
I want that ctp file should not execute if unauthorize error comes.
My code for surveylist is:-
public function surveylist($pg=null){
try{
if($this->checkPageAccess($this->params['controller'] . '/' . $this->params['action'])){
$this->Paginator->settings = array(
'Survey' => array(
'limit' => 5,
'order' => 'created desc',
'conditions'=>array('is_deleted'=> 0),
'page' => $pg
)
);
$numbers = $this->Paginator->paginate('Survey');
$this->set(compact('numbers'));
}else{
$this->Flash->set(__('Unauthorised access'));
}
}catch(Exception $e){
$this->Flash->set(__($e->getMessage()));
}
}
I don't want the ctp file of surveylist to execute if control comes to else.
Plz, help me out......
Thanx in advance...
I suppose you are using prefix to separate admin and users, if not please do that it is great way to handle and restrict methods.
After doing that you have to make condition to check which prefix(admin, user) is currently active and according that load Auth component and allow action in allow() method of Auth.
Example:
$this->loadComponent('Auth',[
/*'authorize' => [
'Acl.Actions' => ['actionPath' => 'controllers/']
],*/
'loginRedirect' => [
'controller' => 'Users',
'action' => 'index'
],
'authenticate' => [
'Form' => [
'fields' => [
'username' => 'email',
'password' => 'password'
]
]
],
'loginAction' => [
'controller' => 'Users',
'action' => 'login'
],
'unauthorizedRedirect' => [
'controller' => 'Users',
'action' => 'login',
'prefix' => false
],
'authError' => 'You are not authorized to access that location.',
]);
if ($this->request->params['prefix']=='admin') {
// Put actions you want to access to admin in allow method's array
$this->Auth->allow(array('add', 'edit', etc...));
} else if ($this->request->params['prefix']=='user') {
// Put actions you want to access to user in allow method's array
$this->Auth->allow(array('login', 'view', etc...));
}
This way you can restrict actions for particular role.
Hope this helps!
I have a field that is a Select2 widget field and it's usually used in many forms, but copy pasting the same code after a while gets really annoying. Therefore I decided perhaps its best to create a widget just for this field.
The field is as follows
<?= $form->field($model, 'contact_id')->widget(Select2::className(), [
'initValueText' => empty($model->contact_id) ? '' : $model->contact->contact_id . ' ' . $model->contact->fullname,
'options' => [
'class' => 'input-sm',
'id' => 'contact_id',
'placeholder' => '-- Search --',
'disabled' => $disabled,
'onchange' => new JsExpression("get_contact_info($(this).val())"),
],
'pluginOptions' => [
'allowClear' => true,
'language' => [
'errorLoading' => new JsExpression("function () { return 'Waiting for results...'; }"),
],
'ajax' => [
'url' => $fetch_url,
'dataType' => 'json',
'data' => new JsExpression('function(params) { return {q:params.term}; }'),
'results' => new JsExpression('function(data,page) { return {results:data.results.text}; }'),
],
'escapeMarkup' => new JsExpression('function (markup) { return markup; }'),
'templateResult' => new JsExpression('function(contact) { return contact.text; }'),
'templateSelection' => new JsExpression('function (contact) { return contact.text; }'),
],
]); ?>
This field utilizes Ajax Fetching, and must allow to be used in create and update forms.
Can anyone please point me to the right direction.
I see two solution:
a) create widget - more work, but flexible using by adding additional settings
b) create separate view and render it - faster, but no so flexible
I've been trying to install user-management for Yii2.0, but getting ReflectionException while loading the page. I have attached the error page and directory structure below.
and the file path is as shown below.
I've searched a lot to find out the reason for this, but nothing worked out. can someone tell me what am I missing here to get it work. looks like the user-management installation documentation has some flaws. It is not clear enough to understand. Hope to get the steps to install. Thanks
Here is my console/web.php
<?php
$params = require(__DIR__ . '/params.php');
$config = [
'id' => 'basic',
'basePath' => dirname(__DIR__),
'bootstrap' => ['log'],
'components' => [
'request' => [
// !!! insert a secret key in the following (if it is empty) - this is required by cookie validation
'cookieValidationKey' => 'gAry7SfUr0oOjNQDqItsobmGBcJajQoW',
],
'cache' => [
'class' => 'yii\caching\FileCache',
],
'user' => [
//'identityClass' => 'app\models\User',
'enableAutoLogin' => true,
'class' => 'app\webvimark\modules\user-management\components\UserConfig',
// Comment this if you don't want to record user logins
'on afterLogin' => function($event) {
\webvimark\modules\user-management\models\UserVisitLog::newVisitor($event->identity->id);
}
],
'errorHandler' => [
'errorAction' => 'site/error',
],
'mailer' => [
'class' => 'yii\swiftmailer\Mailer',
// send all mails to a file by default. You have to set
// 'useFileTransport' to false and configure a transport
// for the mailer to send real emails.
'useFileTransport' => true,
],
'log' => [
'traceLevel' => YII_DEBUG ? 3 : 0,
'targets' => [
[
'class' => 'yii\log\FileTarget',
'levels' => ['error', 'warning'],
],
],
],
'db' => require(__DIR__ . '/db.php'),
],
'modules'=>[
'user-management' => [
'class' => 'webvimark\modules\user-management\UserManagementModule',
// 'enableRegistration' => true,
// Here you can set your handler to change layout for any controller or action
// Tip: you can use this event in any module
'on beforeAction'=>function(yii\base\ActionEvent $event) {
if ( $event->action->uniqueId == 'user-management/auth/login' )
{
$event->action->controller->layout = 'loginLayout.php';
};
},
],
],
'params' => $params,
];
if (YII_ENV_DEV) {
// configuration adjustments for 'dev' environment
$config['bootstrap'][] = 'debug';
$config['modules']['debug'] = [
'class' => 'yii\debug\Module',
];
$config['bootstrap'][] = 'gii';
$config['modules']['gii'] = [
'class' => 'yii\gii\Module',
];
}
return $config;
It seems to have a slight difference with the expected configuration for this extension.
Use this
'class' => 'webvimark\modules\UserManagement\components\UserConfig',
ie UserManagement instead of user-management is a configuration path and not a route