Related
So I have this working SQL script that take a date and returns the age from current time to the given date excluding dates defined in a table called exclude dates
SELECT
COUNT(*)
FROM
(
SELECT
ROWNUM rnum
FROM
all_objects
WHERE
ROWNUM <= CAST(current_timestamp AS DATE) - to_date('&2') + 1
)
WHERE
to_char(to_date('&2') + rnum - 1, 'DY') NOT IN ( 'SAT', 'SUN' )
AND NOT EXISTS (
SELECT
NULL
FROM
exclude_dates
WHERE
no_work = trunc(to_date('&2') + rnum - 1)
);
I have a table called
TICKETS
that contains columns named
ID, UPDATED_AT
I want to create a view that uses the above script to return
ID, AGE
where age is the output of the script above.
You code has a few weaknesses.
There is no need for CAST(current_timestamp AS DATE).
If you need the current DATE then simply use TRUNC(SYSDATE)
You don't need to select from all_objects. Better use hierarchical query
SELECT LEVEL as rnum FROM dual CONNECT BY LEVEL <= ...
Using to_date('&2') without a format is usually bad. Either your input value is a string, then you should include the format, e.g. to_date('&2', 'YYYY-MM-DD') or your input value is a DATE, then simply use &2 - never use TO_DATE() on a value which is already a DATE!
Final query could be this one - assuming input parameter is a DATE value:
WITH t AS (
SELECT LEVEL as d
FROM dual
CONNECT BY LEVEL <= TRUNC(SYSDATE) - the_day)
SELECT COUNT(*) AS buisiness_days
FROM t
WHERE TO_CHAR(the_day + d - 1, 'DY', 'NLS_DATE_LANGUAGE = american') NOT IN ('SAT', 'SUN')
AND NOT EXISTS (
SELECT 'x'
FROM exclude_dates
WHERE no_work = TRUNC(the_day + d - 1)
)
However, for me it is not clear how you want to provide this as a view! You would need to create a separate view for each input date, or at least create a new view every day.
I would suggest to create a function:
CREATE OR REPLACE FUNCTION buisiness_days(the_date IN DATE) RETURN INTEGER AS
ret INTEGER;
BEGIN
WITH t AS (
SELECT LEVEL as d
FROM dual
CONNECT BY LEVEL <= TRUNC(SYSDATE) - the_date)
SELECT COUNT(*) AS buisiness_days
INTO ret
FROM t
WHERE TO_CHAR(the_date + d - 1, 'DY', 'NLS_DATE_LANGUAGE = american') NOT IN ('SAT', 'SUN')
AND NOT EXISTS (
SELECT 'x'
FROM exclude_dates
WHERE no_work = TRUNC(the_date + d - 1)
);
RETURN ret;
END;
The function will return a list of dates between the date range you provide so the dates don't have to be stored in a table.
CREATE OR REPLACE TYPE nt_date IS TABLE OF DATE;
/
CREATE OR REPLACE FUNCTION generate_dates_pipelined(
p_from IN DATE,
p_to IN DATE
)
RETURN nt_date PIPELINED DETERMINISTIC
IS
v_start DATE := TRUNC(LEAST(p_from, p_to));
v_end DATE := TRUNC(GREATEST(p_from, p_to));
BEGIN
LOOP
PIPE ROW (v_start);
EXIT WHEN v_start >= v_end;
v_start := v_start + INTERVAL '1' DAY;
END LOOP;
RETURN;
END generate_dates_pipelined;
/
To exclude holidays you need to know what dates they fall on so there needs to be a holiday table.
create table holidays(
holiday_date DATE not null,
holiday_name VARCHAR2(20),
constraint holidays_pk primary key (holiday_date),
constraint is_midnight check ( holiday_date = trunc ( holiday_date ) )
);
INSERT into holidays (HOLIDAY_DATE,HOLIDAY_NAME)
WITH dts as (
select to_date('25-NOV-2021 00:00:00','DD-MON-YYYY HH24:MI:SS'), 'Thanksgiving 2021' from dual union all
select to_date('29-NOV-2021 00:00:00','DD-MON-YYYY HH24:MI:SS'), 'Hanukkah 2021' from dual
)
SELECT * from dts;
This query will provide the count of days between the range, number of working days and number of holidays in the range.
SELECT COUNT (*) AS total_days
, COUNT ( CASE
WHEN h.holiday_date IS NULL
AND d.column_value - TRUNC (d.column_value, 'IW') < 5
THEN 'Business Day'
END
) AS business_days
, COUNT (h.holiday_date) AS holidays
FROM generate_dates_pipelined (DATE '2021-11-01', DATE '2021-11-30') d
LEFT JOIN holidays h ON h.holiday_date = d.column_value;
This query will provide a list of dates excluding sat, sun and holidays that fall between the range.
SELECT
COLUMN_VALUE
FROM
TABLE(generate_dates_pipelined(DATE '2021-11-01',
DATE '2021-11-30')) c
where
to_char(COLUMN_VALUE, 'DY') NOT IN ('SAT', 'SUN')
AND NOT EXISTS (
SELECT 1
FROM holidays h
WHERE c.COLUMN_VALUE = h.holiday_date
);
You don't need a function or to use a row generator function and can calculate the number of business days:
CREATE VIEW business_day_ages (ID, AGE) AS
SELECT id,
( TRUNC( SYSDATE, 'IW' ) - TRUNC( updated_at, 'IW' ) ) * 5 / 7
-- Number of full weeks.
+ LEAST( SYSDATE - TRUNC( SYSDATE, 'IW' ), 5 )
-- Add part weeks at the end.
- LEAST( updated_at - TRUNC( updated_at, 'IW' ), 5 )
-- Subtract part weeks at the start.
- COALESCE(
( SELECT SUM(
LEAST(no_work + INTERVAL '1' DAY, SYSDATE)
- GREATEST(no_work, updated_at)
)
FROM exclude_dates
WHERE no_work BETWEEN TRUNC(updated_at) AND SYSDATE
),
0
)
-- Subtract the holiday days.
FROM tickets;
Or, if you are not calculating using part days then you can simplify it to:
CREATE OR REPLACE VIEW business_day_ages (ID, AGE) AS
SELECT id,
( TRUNC( SYSDATE, 'IW' ) - TRUNC( updated_at, 'IW' ) ) * 5 / 7
-- Number of full weeks.
+ LEAST( TRUNC(SYSDATE) - TRUNC( SYSDATE, 'IW' ), 5 )
-- Add part weeks at the end.
- LEAST( updated_at - TRUNC( updated_at, 'IW' ), 5 )
-- Subtract part weeks at the start.
- COALESCE(
( SELECT 1
FROM exclude_dates
WHERE no_work BETWEEN TRUNC(updated_at) AND TRUNC(SYSDATE)
),
0
)
-- Subtract the holiday days.
FROM tickets;
db<>fiddle here
This question already has answers here:
How to get the previous working day from Oracle?
(4 answers)
Closed 1 year ago.
need help for some oracle stuff ..
I need to get Day-1 from sysdate, holiday and weekend will be excluded .
And for holiday, we need to get the range to get the last workday before holiday.
The start date and end date will coming from my holiday table.
ex :
Holiday Table
HolidayName
Start_date
End_Date
holiday1
5th Aug'21
6th Aug'21
condition :
this query run on 9th Aug 2021
expected result :
4th Aug'21
I've tried some query and function but I just can't get what I need.
Thanks a lot for help!
Here's one way to do it.
select max(d) as last_workday
from (select trunc(sysdate)-level as d from dual connect by level < 30) prior_month
where to_char(d, 'DY') not in ('SAT','SUN')
and not exists (select holidayname from holiday_table
where prior_month.d between start_date and end_date)
;
Without seeing your Holiday table, it's hard to say how many days back you would need to look to find the last workday. If you have a holiday that lasts for more than 30 days, you'll need to change the 30 to a larger number.
You can use a simple case expression to determine what day of the week the start of your holiday is, then subtract a number of days based on that.
WITH
holiday (holidayname, start_date, end_date)
AS
(SELECT 'holiday1', DATE '2021-8-5', DATE '2021-8-6' FROM DUAL
UNION ALL
SELECT 'Christmas', DATE '2021-12-25', DATE '2021-12-26' FROM DUAL
UNION ALL
SELECT 'July 4th', DATE '2021-7-4', DATE '2021-7-5' FROM DUAL)
SELECT holidayname,
start_date,
end_date,
start_date - CASE TO_CHAR (start_date, 'Dy') WHEN 'Mon' THEN 3 WHEN 'Sun' THEN 2 ELSE 1 END AS prior_business_day
FROM holiday;
HOLIDAYNAME START_DATE END_DATE PRIOR_BUSINESS_DAY
______________ _____________ ____________ _____________________
holiday1 05-AUG-21 06-AUG-21 04-AUG-21
Christmas 25-DEC-21 26-DEC-21 24-DEC-21
July 4th 04-JUL-21 05-JUL-21 02-JUL-21
You can use a recursive sub-query factoring clause from this answer:
WITH start_date (dt) AS (
SELECT DATE '2021-05-02' FROM DUAL
),
days ( dt, day, found ) AS (
SELECT dt,
TRUNC(dt) - TRUNC(dt, 'IW'),
0
FROM start_date
UNION ALL
SELECT dt - CASE day WHEN 0 THEN 3 WHEN 6 THEN 2 ELSE 1 END,
CASE WHEN day IN (0, 6, 5) THEN 4 ELSE day - 1 END,
CASE WHEN h.start_date IS NULL THEN 1 ELSE 0 END
FROM days d
LEFT OUTER JOIN holidays h
ON ( dt - CASE day WHEN 0 THEN 3 WHEN 6 THEN 2 ELSE 1 END
BETWEEN h.start_date AND h.end_date )
WHERE found = 0
)
SELECT dt
FROM days
WHERE found = 1;
Which, for the sample data:
CREATE TABLE holidays (HolidayName, Start_date, End_Date) AS
SELECT 'holiday1', DATE '2021-08-05', DATE '2021-08-06' FROM DUAL;
Outputs:
DT
2021-08-04 00:00:00
db<>fiddle here
Don't know if it's very efficient. Did it just for fun
create table holidays (
holiday_name varchar2(100) primary key,
start_date date not null,
end_date date not null
)
/
Table created
insert into holidays (holiday_name, start_date, end_date)
values ('holiday1', date '2021-08-05', date '2021-08-06');
1 row inserted
with days_before(day, wrk_day) as
(select trunc(sysdate - 1) d,
case
when h.holiday_name is not null then 0
when to_char(trunc(sysdate - 1), 'D') in ('6', '7') then 0
else 1
end work_day
from dual
left join holidays h
on trunc(sysdate - 1) between h.start_date and h.end_date
union all
select db.day - 1,
case
when h.holiday_name is not null then 0
when to_char(db.day - 1, 'D') in ('6', '7') then 0
else 1
end work_day
from days_before db
left join holidays h
on db.day - 1 between h.start_date and h.end_date
where db.wrk_day = 0) search depth first by day set order_no
select day from days_before where wrk_day = 1;
DAY
-----------
04.08.2021
I have two date columns and trying to measure days between the two dates excluding weekends. I'm getting a negative number and need help solving.
Table
CalendarDate DayNumber FirstAssgn FirstCnt DayNumber2 Id BusinessDays
5/21/2017 Sunday 5/21/17 5/21/17 Sunday 1 -1
Query:
TRUNC(TO_DATE(A.FIRST_CONTACT_DT, 'DD/MM/YYYY')) - TRUNC(TO_DATE(A.FIRST_ASSGN_DT, 'DD/MM/YYYY'))
- ((((TRUNC(A.FIRST_CONTACT_DT,'D'))-(TRUNC(A.FIRST_ASSGN_DT,'D')))/7)*2)
- (CASE WHEN TO_CHAR(A.FIRST_ASSGN_DT,'DY','nls_date_language=english') ='SUN' THEN 1 ELSE 0 END)
- (CASE WHEN TO_CHAR(A.FIRST_CONTACT_DT,'DY','nls_date_language=english')='SAT' THEN 1 ELSE 0 END)
- (SELECT COUNT(1) FROM HUM.CALENDAR CAL
WHERE 1=1
AND CAL.CALENDAR_DATE >= A.FIRST_ASSGN_DT
AND CAL.CALENDAR_DATE < A.FIRST_CONTACT_DT
--BETWEEN A.FIRST_ASSGN_DT AND A.FIRST_CONTACT_DT
AND CAL.GRH_HOLIDAY_IND = 'Y'
) AS Business_Days
Looks like below piece needs editing...
- (CASE WHEN TO_CHAR(A.FIRST_ASSGN_DT,'DY','nls_date_language=english')='SUN' THEN 1 ELSE 0 END)
Adapted from my answer here:
Get the number of days between the Mondays of both weeks (using TRUNC( datevalue, 'IW' ) as an NLS_LANGUAGE independent method of finding the Monday of the week) then add the day of the week (Monday = 1, Tuesday = 2, etc., to a maximum of 5 to ignore weekends) for the end date and subtract the day of the week for the start date. Like this:
SELECT ( TRUNC( end_date, 'IW' ) - TRUNC( start_date, 'IW' ) ) * 5 / 7
+ LEAST( end_date - TRUNC( end_date, 'IW' ) + 1, 5 )
- LEAST( start_date - TRUNC( start_date, 'IW' ) + 1, 5 )
AS WeekDaysDifference
FROM your_table
With RANGE_TEMP as (
SELECT
STARTPERIOD start_date,
ENDPERIOD end_date
FROM
TABLE_DATA -- YOUR TABLE WITH ALL DATA DATE
), DATE_TEMP AS (
SELECT
(start_date + LEVEL) DATE_ALL
FROM
RANGE_TEMP
CONNECT BY LEVEL <= (end_date - start_date)
), WORK_TMP as (
SELECT
COUNT(DATE_ALL) WORK_DATE
FROM
DATE_TEMP
WHERE
TO_CHAR(DATE_ALL,'D', 'NLS_DATE_LANGUAGE=ENGLISH') NOT IN ('1','7')
), BUSINESS_TMP as (
SELECT
COUNT(DATE_ALL) BUSINESS_DATE
FROM
DATE_TEMP
WHERE
TO_CHAR(DATE_ALL,'D', 'NLS_DATE_LANGUAGE=ENGLISH') IN ('1','7')
)
SELECT
L.WORK_DATE,
H.BUSINESS_DATE
FROM
BUSINESS_TMP H,
WORK_TMP L
;
I found this query for finding the number of Sundays in a month.
I have been tinkering with it but cannot figure out how to change it to get, say, the number of Wednesdays in a month, for example. Can you show me how?
with
months as (
select add_months(trunc(sysdate,'YEAR'),level-13) month
from dual
connect by level <= 36
)
select to_char(month,'YYYY') year,
to_char(month,'Month') month,
to_char(month,'Day') first_day,
to_char(last_day(month),'Day DD') last_day,
4+
case
when to_char(last_day(month),'DD') - decode(to_char(month,'D'),1,0,8 -to_char(month,'D')) >= 29
then 1
else 0
end nb_sunday
from months
Here's the game: You give me a year (like 2015) and a day of the week, in the form of a three-letter string (like 'Wed'). I will return a table with each month of that year and with the count of days-of-week equal to your input in each month.
Simply implementing here the suggestion from my Comment to MT0's Answer. I am hard-coding the year and the day-of-week (in a CTE) since "how to pass parameters to a query" (through bind variables and such) is not the focus in this thread.
with
inputs ( yr, day_of_week ) as (
select 2015, 'Wed' from dual
),
prep ( dec31 ) as (
select to_date(to_char(yr - 1) || '-12-31', 'yyyy-mm-dd') from inputs
)
select to_char(add_months(dec31, level), 'Mon-yyyy') as mth,
( next_day(add_months(dec31, level) , day_of_week) -
next_day(add_months(dec31, level - 1), day_of_week) ) / 7 as cnt
from inputs cross join prep
connect by level <= 12;
MTH CNT
-------- ----
Jan-2015 4
Feb-2015 4
Mar-2015 4
Apr-2015 5
May-2015 4
Jun-2015 4
Jul-2015 5
Aug-2015 4
Sep-2015 5
Oct-2015 4
Nov-2015 4
Dec-2015 5
12 rows selected.
The last wednesday of the month is given by:
TRUNC( NEXT_DAY( LAST_DAY( :month ) - INTERVAL '7' DAY, 'WEDNESDAY' ) )
The first wednesday of the month is given by:
NEXT_DAY( TRUNC( :month, 'MM' ) - INTERVAL '1' DAY, 'WEDNESDAY' )
Subtracting gives the number of days between them. Divide by 7 and add 1 and you get the number of Wednesdays:
SELECT ( TRUNC( NEXT_DAY( LAST_DAY( :month ) - INTERVAL '7' DAY, 'WEDNESDAY' ) )
- NEXT_DAY( TRUNC( :month, 'MM' ) - INTERVAL '1' DAY, 'WEDNESDAY' )
) / 7 + 1
AS number_of_wednesdays
FROM DUAL;
Or you can just use the difference between the first Wednesday of the month and of the next month as suggested by #mathguy
SELECT ( NEXT_DAY(
ADD_MONTHS( TRUNC( :month, 'MM' ), 1 ) - INTERVAL '1' DAY,
'WEDNESDAY'
)
- NEXT_DAY(
TRUNC( :month, 'MM' ) - INTERVAL '1' DAY,
'WEDNESDAY'
)
) / 7
AS number_of_wednesdays
FROM DUAL;
I have a table storing information about customers which includes a column "dateofbirth". I need to fetch those customers whose birthday has passed for the ongoing year (2015). How can I extract both date and month and compare it with system date and month?
You can use EXTRACT:
SELECT *
FROM CUSTOMERS
WHERE EXTRACT( MONTH FROM dateofbirth ) < EXTRACT( MONTH FROM SYSDATE )
OR ( EXTRACT( MONTH FROM dateofbirth ) = EXTRACT( MONTH FROM SYSDATE )
AND EXTRACT( DAY FROM dateofbirth ) <= EXTRACT( DAY FROM SYSDATE ) )
or you can use TO_CHAR with the MMDD day of year format
SELECT *
FROM CUSTOMERS
WHERE TO_CHAR( dateofbirth, 'MMDD' ) <= TO_CHAR( SYSDATE, 'MMDD' )
select to_char(to_date('27-01-1966','DD-MM-YYYY'),'MMDD'),to_char(sysdate,'MMDD'),
CASE WHEN to_char(to_date('27-01-1966','DD-MM-YYYY'),'MMDD') > to_char(sysdate,'MMDD')
THEN 'No'
ELSE 'Yes'
END
from dual;
So
WHERE to_char(dateofbirth,'MMDD') < to_char(sysdate,'MMDD')
I suggested the following solution
SELECT
name,
TO_CHAR(dob,'mm') MONTH,
TO_CHAR(dob,'dd') DAY
FROM
target_table
WHERE
TO_CHAR(sysdate,'yyyy') =2015
AND
(
to_number(TO_CHAR(dob,'mm'))<to_number(TO_CHAR(sysdate,'mm'))
OR
(
TO_CHAR(dob,'mm') =TO_CHAR(sysdate,'mm')
AND TO_CHAR(dob,'dd')<=TO_CHAR(sysdate,'dd')
)
);
i had written code based on my table data......
dob=date of birth
tartget_table= required table