Create trigger that updates row depending on column value from other table - oracle

Question

I would like to create a trigger that updates a row in a table (TABLE2) depending on column value from other table (TABLE1).
Which line must be updated depends on the ID of TBL1.
CREATE OR REPLACE TRIGGER INSERT_PAGE
BEFORE UPDATE OR INSERT
ON TABLE1
FOR EACH ROW
BEGIN
IF INSERTING THEN
INSERT INTO TABLE2 (TBL1ID,STEP,PAGE) VALUES
(:NEW.TBL1ID,:NEW.STEP,15);
ELSIF UPDATING and :NEW.STATE='APPROVED' THEN
UPDATE TABLE2
SET PAGE=16 AND STEP1='TEXT123'
WHERE TBL1ID =TABLE1.TBL1ID;
END IF;
END;
Can someone help me in creating a trigger with an update statement?
Would this be as well a good way to go?
So I have two tables, the column state in table1 is changing throughtout the process.
Depending on the change of the column state from table1, I want to change or better say update the row in table 2 and set some columns like PAGE and STATE in Table 2 depending on column value STATE in Table 1.
I do not want that a new row being created each time TABLE 1 gets updated, only the corresponding row should be updated.

Answer 1

As far as I understood is you want to update table2 only when the state in table1 changed to 'approved' for a row and if a row is inserted in table1 trigger will insert the row in table2.
I have made some corrections to your code. Let me know if it is not what you wanted.
CREATE OR REPLACE TRIGGER INSERT_PAGE
BEFORE UPDATE OR INSERT
ON TABLE1
FOR EACH ROW
DECLARE
BEGIN
IF INSERTING THEN
INSERT INTO TABLE2 (TBL1ID,STEP,PAGE) VALUES
(:NEW.TBL1ID,:NEW.STEP,15);
ELSIF UPDATING THEN
IF :NEW.STATE = 'APPROVED' THEN
UPDATE table2 t2 SET
STATE = :NEW.STATE, PAGE=16, STEP1='TEXT123'
WHERE t2.TBL1ID = :OLD.TBL1ID;
END IF;
END IF;
END;