I'm trying to create a Jelastic Manifest with a cURL command inside it. When I import it, it gives me an error but unfortunately I have no access to the console (disabled by the provider).
The command is the following :
curl -X POST <my_url> -H "Content-Type: application/json" -H "Authorization: Bearer <token>" -d "{}"
Some additionnal information :
The URL is correct 100%
The token does not contain any special characters : Only upper/lowercase characters and numbers
The command is run successfully from the command line
If I remove the first -H parameter, I can import my manifest. Same if I remove the second -H parameter and keep the first one
My guess is that, somehow, having two -H is not considered as valid but I don't know why. Any ideas ?
EDIT : A screenshot of the error shown on the platform
The "two -H parameters" wasn't a root cause in your question.
The thing is that the YAML gets the data you sent as a key/value array (dictionary).
In your example it would be:
curl -s -X POST https://test.com -H "Content-Type - as a key,
and
application/json" -H "Authorization: Bearer xx" -d "{\"Key\":\"Value\"}" - as a value.
If you need an array of strings the YAML may be as this
cmd [cp]:
- 'curl -s -X POST https://test.com -H "Content-Type: application/json" -H "Authorization: Bearer xx" -d "{\"Key\":\"Value\"}"'
If you need a multi-line string it should look like this
cmd [cp]: |
curl -s -X POST https://test.com -H "Content-Type: application/json" -H "Authorization: Bearer xx" -d "{\"Key\":\"Value\"}"
Related
I looked at all previous answers on this subject but just can't get my POST request to work in cURL windows although it works perfectly in PostMan. I exported the code using </> and tried several combinations of export parameters... any help would greatly appreciated!
Here's my cURL code:
curl -L -X POST "https://timingserver.net/api/bridge/generic" -H "cache-control: no-cache" -H "connection: close" -H "content-type: application/json" --data-raw "{
\"username\":\"myusername\",
\"password\":\"mypassword\",
\"event\":\"demo\",
\"checkpoint\":12,
\"detections\":[{\"bib\":100, \"dt\":\"2022-01-12T13:09:23.045\"},
{\"bib\":101, \"dt\":\"2022-01-12T13:09:23.045\"},
{\"bib\":102, \"dt\":\"2022-01-12T13:09:23.045\"},
{\"bib\":199, \"dt\":\"2022-01-12T13:10:23.045\"}]
}"
Getting several errors in the same execution: Code 400, not recognized as an internal or external command... cannot find the path specified...
You need to remove the linebreaks:
curl -L -X POST "https://timingserver.net/api/bridge/generic" -H "cache-control: no-cache" -H "connection: close" -H "content-type: application/json" --data-raw "{ \"username\":\"myusername\", \"password\":\"mypassword\", \"event\":\"demo\", \"checkpoint\":12, \"detections\":[{\"bib\":100, \"dt\":\"2022-01-12T13:09:23.045\"}, {\"bib\":101, \"dt\":\"2022-01-12T13:09:23.045\"}, {\"bib\":102, \"dt\":\"2022-01-12T13:09:23.045\"}, {\"bib\":199, \"dt\":\"2022-01-12T13:10:23.045\"}] }"
To generate curl output for windows using postman click on settings next to curl code section and change line continuation character to ^ and quote double and shown in the image. This should generate output for windows. You can also change the output to single or multiline.
I am trying to get the response code of the curl command to a variable and output of the same curl command in a file. Another curl command within a different function will run and the output should append to the same output file.
response=$(curl -i -H "content-type: application/json" -w "%{http_code}" -u "$id:$cred" -H "Accept: application/json" -X POST http://sitename -d '{'<input>'}' >> out.txt
This is giving me neither the response nor the curl output in the file.
Below is working and gives me response as the desired http code though.
response=$(curl -i -H "content-type: application/json" -w "{http_code}" -u "$id:$cred" -H "Accept: application/json" -X POST http://sitename -d '{'<input>'}'
Echo $response
Problem:
I'm writing a script that performs several HTTP requests with curl and I want to add the headers to a variable, CURL_HEADERS, so that I don't have to type them out constantly. When I echo the CURL_HEADERS variable in the curl command, single quotations appear where I don't want them. How can I prevent this? (The code below is simplified for the sake of clarity)
Code
#!/usr/bin/env bash
AUTH_KEY='1234'
set -x
CURL_HEADERS='-H "Authorization: Basic '${AUTH_KEY}'" -H "Content-Type: application/json"'
echo "${CURL_HEADERS}"
curl -s $(echo "${CURL_HEADERS}") 'http://www.example.org' > /dev/null
set +x
Expected Output:
+ CURL_HEADERS='-H "Authorization: Basic 1234" -H "Content-Type: application/json"'
+ echo '-H "Authorization: Basic 1234" -H "Content-Type: application/json"'
-H "Authorization: Basic 1234" -H "Content-Type: application/json"
++ echo '-H "Authorization: Basic 1234" -H "Content-Type: application/json"'
+ curl -s -H "Authorization: Basic 1234" -H "Content-Type: application/json" http://www.example.org
+ set +x
Actual Output
+ CURL_HEADERS='-H "Authorization: Basic 1234" -H "Content-Type: application/json"'
+ echo '-H "Authorization: Basic 1234" -H "Content-Type: application/json"'
-H "Authorization: Basic 1234" -H "Content-Type: application/json"
++ echo '-H "Authorization: Basic 1234" -H "Content-Type: application/json"'
+ curl -s -H '"Authorization:' Basic '1234"' -H '"Content-Type:' 'application/json"' http://www.example.org
+ set +x
A reasonably straightforward solution is to use a bash array to store the four arguments you will want to pass:
CURL_HEADERS=(
'-H' "Authorization: Basic ${AUTH_KEY}"
'-H' 'Content-Type: application/json'
)
curl -s "${CURL_HEADERS[#]}" 'http://www.example.org' > /dev/null
Unlike scalar variables, which are just ordinary strings of ordinary characters no matter how many quotes they might contain, arrays are lists of strings, each one distinguished from each other one. In this sense, bash is just like almost every other programming language.
This problem, and the solution I suggest as well as several other ones, is well-described in the Bash FAQ entry 50 (I'm trying to put a command in a variable, but the complex cases always fail!), which is worth reading in detail. (Link taken from a comment by #John1024.)
The proposed array is a good design approach, but curl still adds single quotes to the array items that already contain double quotes around them, thus making invalid headers.
I am having a EmailRepository which queries for a person like follows
findByPerson(Person person);
The spring-data-rest /search resource list the following href
http://localhost:8080/emailAddresses{?person}
How to make a curl command for the above search url in GET method? Also if the person does not exists, I need to throw "PersonNotFoundException".
I am using org.springframework.boot:spring-boot-starter-data-rest:jar:1.3.3.RELEASE
Try the below curl commands -
if you are using path param -
curl -i -X GET -H "Content-Type: application/json" -H "Cache-Control: no-cache" -k "http://localhost:8080/emailAddresses/person"
if you are using query param -
curl -i -X GET -H "Content-Type: application/json" -H "Cache-Control: no-cache" -k "http://localhost:8080/emailAddresses?person=aaa"
I am trying to follow this example: http://docs.stormpath.com/rest/quickstart/
One of the steps mentions to do the following cURL request:
curl -X POST --user $YOUR_API_KEY_ID:$YOUR_API_KEY_SECRET \
-H "Accept: application/json" \
-H "Content-Type: application/json" \
-d '{
"name" : "My Awesome Application"
}' \
'https://api.stormpath.com/v1/applications?createDirectory=true'
I am using online cURL from : http://onlinecurl.com/
Here is the snapshot of the curl request:
Here is the snapshot of the Header Response:
Can anybody please tell me what is wrong?
I'm also having problems with that tool. I tried what you show in your screenshot, plus some other combinations. I actually get a different error (media type unauthorized). I suspect this tool uses some kind of proxy that is messing with the request.