I need to check if inside a relationships there is a given value but i got an error when i try to fetch the variable i need inside the loop. I get "message": "Undefined variable: cat".
Here is my code
$cate = $request->input('category');
foreach ($cate as $key => $cat) {
$restaurants->with(['categories' => function ($query) {
$query->where('name', '==', $cat);
}]);
}
can someone help me figure out?
you must use "whereHas" instead of "with" to check if relationship have pass condition:
$cate = $request->input('category');
foreach ($cate as $key => $cat) {
$restaurants->whereHas(['categories', function ($query) use ($cat) {
$query->where('name', '==', $cat);
}]);
}
and for your questions: import variable to the current scope (the use keyword)
what is inside your $cate variable ?
and what do you want to do ?
If you want to search your Restaurants matching your given categories in your input, then you should do this :
// assuming your $request->input('category') look like this :
$categories = ['foo', 'bar'];
$restaurants = Restaurant::whereHas('categories', function($query) use ($categories){
$query->whereIn('name', $categories);
})->get();
(just for explaining your error, you have to pass you $cat variable to your closure :
$restaurants->with(['categories' => function ($query) use ($cat) {
$query->where('name', '==', $cat);
}]);
you need to just pass the $cat variable to your closure => function ($query) use ($cat)
$cate = $request->input('category');
foreach ($cate as $key => $cat) {
$restaurants->whereHas(['categories' => function ($query) use ($cat) {
$query->where('name', $cat);
}]);
}
use whereHas() to specify additional filters in the relationship.
Show More => https://laravel.com/docs/8.x/eloquent-relationships
Related
How to filter by relation column
tried this
->whereHas('customer',function ($query) use ($order){
$query->orderBy('first_name', $order);
})
and this
->with(['customer' => function ($query) use ($order) {
$query->orderBy('first_name', $order);
}])
Both did not work
with() are using eager loading, which turns this into two queries.
You need to use join() instead of with()
$orders = Order
::join('customers', 'order.customer_id', '=', 'customers.id')
->orderBy('customers.first_name')
->get();
OR
You may use sortBy() or sortByDesc() methods of Collection.
For example:
$orders = Order
::with('customer')
->get()
->sortBy('customer.first_name');
request {{host}}/admin/showcases?filterBy=companies:name it order by relation column companies
if simple {{host}}/admin/showcases?filterBy=name
it will be only orderBy("name")
->when(str_contains($filterBy, ':'),
function (Builder $query) use ($filterBy, $order, $columns) {
$table = explode(':', $filterBy)[0];
$key = Str::singular($table) . "_id";
$column = explode(':', $filterBy)[1];
$selfTable = $this->getTable();
$query->leftJoin($table, "$selfTable.$key", "$table.id")
->when($columns !== ['*'],
function ($query) use ($columns, $selfTable) {
$columns = array_map(function ($column) use ($selfTable) {
return "$selfTable.$column";
}, $columns);
$query->select($columns);
},
fn($query) => $query->select(["$selfTable.*"]))
->orderBy("$table.$column", $order);
},
function ($query) use ($filterBy, $order) {
$query->orderBy($filterBy, $order);
})
hello friends can you help me to get the contents of $filter? I want to run where which is where the target column is in the relation array
$filter = $request->get('Biogear');
$data = DetailBarang::with(['barang' => function ($q) use ($filter) {
$q->where('brand', '=', $filter);
}])->get();
return response()->json($data);
you can try this
$filter = $request->get('Biogear');
$data = DetailBarang::with('barang')->whereHas('barang',function (Illuminate\Database\Eloquent\Builder $q) use ($filter) {
$q->where('brand', '=', $filter);
})->get();
return response()->json($data);
Wondering if there is a way to use closure on a relationship in order to filter the whole line if there isn't a value which corresponds?
Example code:
foreach ($paiementMethods as $value) {
$giftCards = GiftCard::with(['userEntered', 'userEmployee', 'client', 'payement', 'payement.payementMethods' => function($query) use ($value)
{
$query->where('id', $value);
}])
->where('date','>=', $dateStart)
->where('date','<=', $dateEnd)
->orderBy('updated_at', 'desc')->get();
$giftCardsCollection = $giftCardsCollection->merge($giftCards);
}
}
In this example, if $query->where doesn't find a row for the payement.payementMethods which matches the $value, I want the giftCard to return null. The result I get is the giftCard with only the relation on payement.payementMethods being empty.
My other solution would be to query the giftCard and after that checking the $value to see if I have to include the giftCard in the collection or not.
Best regards
I think using whereHas, it can be solved
$giftCards = GiftCard::with(['userEntered', 'userEmployee', 'client', 'payement', 'payement.payementMethods'])
->whereHas( 'payement.payementMethods', function($query) use ($paiementMethods) {
$query->whereIn('id', $paiementMethods);
})
->where('date','>=', $dateStart)
->where('date','<=', $dateEnd)
->orderBy('updated_at', 'desc')
->get();
I have a model with a related collection
now im doing this query
$data = DeliveryPartner::when($filter, function ($q) use ($request) {
})
->with(['orders' => function ($query) {
$query
->where('delivery_partner_invoice_id', '=', '')
->orWhereNull('delivery_partner_invoice_id')
->whereIn('status', ['payment-accepted', 'completed', 'full-refund', 'partial-refund']);
}])->get();
Now i am wondering. If the orders returns empty is it posible to remove this parent from the collection?
I Know i can do this after the eloquent query with a loop. But is it possible to do this in the query?
we cant completely remove that parent ( with index ) BUT you can set those to null using transform() like this;
$data = DeliveryPartner::when($filter, function ($q) use ($request) {
})
->with(['orders' => function ($query) {
$query
->where('delivery_partner_invoice_id', '=', '')
->orWhereNull('delivery_partner_invoice_id')
->whereIn('status', ['payment-accepted', 'completed', 'full-refund', 'partial-refund']);
}])->get()->transform(function($item){
if(!$item->orders->count() ){
return;
}
return $item;
});
Note: this will not completely remove those parents but it will set them to empty.
I have the following relations in my Laravel application
class Item extends Model
{
public function category()
{
return $this->belongsTo('App\Category');
}
}
and
class Category extends Model
{
public function item()
{
return $this->hasMany('App\Item');
}
}
I want to implement search functionality so I have created the following Eloquent query:
$items = Item::where('item_type', '=', 'type1')
->where(function($query) use ($q) {
$query->where('item_name','LIKE','%'.$q.'%')
->orWhere('item_description','LIKE','%'.$q.'%');
})
->paginate(10);
This is working as expected and returns the search results for 'q' based on the name and the description of the item.
As a next step, I would like to also search for the category_name. Because of the relation, I have the category_id stored in the Items table, but I would like to use the category_name in my Eloquent query.
Anyone could provide some help?
Based on feedback received, I tried:
Suggestion 1:
$items = Item::where('item_type', '=', 'type1')
->where(function($query) use ($q) {
$query
->where('item_name', 'LIKE' ,'%'.$q.'%')
->orWhere('item_description', 'LIKE' ,'%'.$q.'%');
})
->whereHas('category', function (Category $query) use ($q) {
$query->where('category_name', $q);
})
=> this gives following error message:
Argument 1 passed to
App\Http\Controllers\ItemController::App\Http\Controllers{closure}()
must be an instance of App\Http\Controllers\App\Category, instance of
Illuminate\Database\Eloquent\Builder given
Suggestion 2:
$items = Item::where('item_type', '=', 'type1')
->where(function($query) use ($q) {
$query
->where('item_name', 'LIKE' ,'%'.$q.'%')
->orWhere('item_description', 'LIKE' ,'%'.$q.'%');
})
->whereHas('category', function ($query) use ($q) {
$query->where('category_name', $q);
})
=> this does not result any search result anymore (also not for item_name and item_description).
Solution
$items = Item::where('item_type', '=', 'type1')
->where(function($query) use ($q) {
$query
->where('item_name', 'LIKE' ,'%'.$q.'%')
->orWhere('item_description', 'LIKE' ,'%'.$q.'%');
})
->orWhereHas('category', function ($query) use ($q) {
$query->where('category_name', $q);
})
->sortable(['id' => 'desc'])
->paginate(10);
As you already described relation to Category in your Item model, you have to use just whereHas method:
$items = Item::where('item_type', '=', 'type1')
->where(function($query) use ($q) {
$query->where('item_name','LIKE','%'.$q.'%')
->orWhere('item_description','LIKE','%'.$q.'%');
})
->orWhereHas('category', function ($query) use ($q) {
$query->where('category_name', 'LIKE', "%$q%");
})
->paginate(10);
You could add a whereHas and constrain it. For example:
$items = Item::where('item_type', '=', 'type1')
->where(function($query) use ($q) {
$query->where('item_name','LIKE','%'.$q.'%')
->orWhere('item_description','LIKE','%'.$q.'%');
})
->whereHas('category', function($query) {
$query->where('category_name', 'name');
})
->paginate(10);