I am new to exploring the capability of Google Query and am seeking some assistance with structuring my query. I am esentially seeking to generate a table similar to the below, that summarises my income + expenses by month, whilst calculating the amount saved each month and the assoicated savings rate.
={query(Expense_Data, "SELECT C, SUM(Q) where T is not null GROUP BY C PIVOT T ORDER BY C desc limit 3",1),query(Expense_Data, "Select Sum(Q) where T is not null Group by C limit 3 label Sum(Q) 'Savings'")}
Month (Date)
Expense
Income
Savings
Savings Rate (NEED ASSISTANCE) %
01/05/2021
-1000.00
1500.00
500.00
33.33%
01/04/2021
-1000.00
1500.00
500.00
33.33%
01/03/2021
-1000.00
1500.00
500.00
33.33%
My dual query below so far does the job for the first 3 columns, however I am unsure how to generate the 'Savings Rate' considering this query would requre (I'm guessing) an arthimetic operator except these would contain different 'where' conditions. (ie SELECT SUM(Q) / SUM(Q) where T = 'Income')??
Any help would be greatly appreciated.
Cheers
You can use the result of your query inside another query
=query(query(Expense_Data, "SELECT C, SUM(Q) where T is not null GROUP BY C PIVOT T ORDER BY C desc limit 3",1),"select Col1,Col2,Col3, Col2+Col3, (Col2+Col3)/Col3 label Col2+Col3'Savings', (Col2+Col3)/Col3'Savings Rate %'")
Related
I have 2 Tables
table a mempur
memberno = member number
purdt = purchase date
amount = purchase amount
table b meminfo
memberno = member number
fname = first name
age = age
select a.memberno,b.fname,sum(a.amount),a.purdt,b.age from mempur a,(select max(purdt) as maxdate,memberno from mempur group by memberno) maxresult,meminfo b
where a.memberno=b.memberno
and a.purdt between '01-JAN-22' and '28-FEB-22'
and a.memberno=maxresult.memberno
and a.purdt=maxresult.maxdate
group by a.memberno,b.fname,a.purdt,b.age
order by a.memberno;
How to get my result with total purchase amount and highest date purchase from table mempur?
I use this query able to show the result but the total amount incorrect between the range.
Anyone help is much appreciated.
my sample data
MEMBERNO PURDT AMOUNT
--------------- --------------- ---------
BBMY0004580 12-AUG-21 823.65
BBMY0004580 12-AUG-21 1709.1
BBMY0004580 26-AUG-21 1015.1
BBMY0004580 28-AUG-21 1105.1
my result only show total amount 1105.1
You can aggregate in mempur and then join to meminfo:
SELECT i.*, p.total_amount, p.maxdate
FROM meminfo i
INNER JOIN (
SELECT memberno, SUM(amount) total_amount, MAX(purdt) maxdate
FROM mempur
WHERE purdt BETWEEN '01-JAN-22' AND '28-FEB-22'
GROUP BY memberno
) p ON p.memberno = i.memberno;
You may use a LEFT join if there are members with no purchases which you want in the results.
Your query gets the maximum purdt and adds up the amount for this date. It also checks whether the maximum purdt is in January or February 2022. If it is, the result gets show, if it is not, you don't show the result. This is not the query you want.
Apart from that, the query looks rather ugly. You are using an ancient join syntax that is hard to read and prone to errors. We used that in the 1980s, but in 1992 explicit joins made it into the SQL standard. You should no longer use this old comma syntax. It is strange to see it still being used. Feels like going to a museum. Then, you are using table aliases. The idea of these is to get a query more readable, but yours even lessen readability, because your alias names a and b are arbitrary. Use mnemonic names instead, e.g. mp for mempur and mi for meminfo. Then, you are comparing the date (I do hope purdt is a date!) with strings. Don't. Use date literals instead.
As to your tables: Are you really storing the age? You will have to update it daily to keep it up-to-date. Better store the date of birth and calculate the age from it in your queries.
Here is a query that gets you the maximum date and the total amount for the given date range:
select memberno, m.name, p.sum_amount, p.max_purdt, m.age
from meminfo m
left outer join
(
select memberno, sum(amount) as sum_amount, max(purdt) as max_purdt
from mempur
where purdt >= date '2022-01-01' and purdt < date '2022-03-01'
group by memberno
) p using (memberno)
order by memberno;
And here is a query that gets you the maximum overall date along with the total amount for the given date range:
select memberno, m.name, p.sum_amount, p.max_purdt, m.age
from meminfo m
left outer join
(
select
memberno,
sum(case when where purdt >= date '2022-01-01' and purdt < date '2022-03-01'
then amount
end) as sum_amount,
max(purdt) as max_purdt
from mempur
group by memberno
) p using (memberno)
order by memberno;
I have problem with the task which looks like that I have a table Warehouse containing a list of items that a company has on stock. This
table contains the columns ItemID, ItemTypeID, InTime and OutTime, where InTime (OutTime)
specifies the point in time where a respective item has entered (left) the warehouse. I have to calculate the longest period that the company has gone without an item entering or leaving the warehouse. I am trying to resolve it this way:
select MAX(OutTime-InTime) from Warehouse where OutTime is not null
Is my understanding correct? Because I believe that it is not ;)
You want the greatest gap between any two consecutive actions (item entering or leaving the warehouse). One method is to unpivot the in and out times to rows, then use lag() to get the date of the "previous" action. The final step is aggregation:
select max(x_time - lag_x_time) max_time_diff
from warehouse w
cross apply (
select x_time, lag(x.x_time) over(order by x.x_time) lag_x_time
from (
select w.in_time as x_time from dual
union all select w.out_time from dual
) x
) x
You can directly perform date calculation in oracle.
The result is calculated in days.
If you want to do it in hours, multiply the result by 24.
To calculate the duration in [day], and check all the information in the table:
SELECT round((OutTime - InTime)) as periodDay, Warehouse .*
FROM Warehouse
WHERE OutTime is not null
ORDER BY periodDay DESC
To calculate the duration in [hour]:
SELECT round((OutTime - InTime)*24) AS periodHour, Warehouse .*
FROM Warehouse
WHERE OutTime is not null
ORDER periodHour DESC
round() is used to remove the digits.
Select only the record with maximum period.
SELECT *
FROM Warehouse
WHERE (OutTime - InTime) =
( SELECT MAX(OutTime - InTime) FROM Warehouse)
Select only the record with maximum period, with the period indicated.
SELECT (OutTime - InTime) AS period, Warehouse.*
FROM Warehouse
WHERE (OutTime - InTime) =
( SELECT MAX(OutTime - InTime) FROM Warehouse)
When finding the longest period, the condition where OutTime is null is not needed.
SQL Server has DateDiff, Oracle you can just take one date away from the other.
The code looks ok. Oracle has a live SQL tool where you can test out queries in your browser that should help you.
https://livesql.oracle.com/
My Query is
SELECT unnest(array [repgroupname,repgroupname||'-'
||masteritemname,repgroupname||'-' ||masteritemname||'-'||itemname]) AS grp
,unnest(array [repgroupname,masteritemname,itemname]) AS disp
,groupname1
,groupname2
,groupname3
,sum(qty) AS qty
,sum(freeqty) AS freeqty
,sum(altqty) AS altqty
,sum(discount) AS discount
,sum(amount) AS amount
,sum(stockvalue) AS stockvalue
,sum(itemprofit) AS itemprofit
FROM (
SELECT repgroupname
,masteritemname
,itemname
,groupname1
,groupname2
,groupname3
,units
,unit1
,unit2
,altunits
,altunit1
,altunit2
,sum(s2.totalqty) AS qty
,sum(s2.totalfreeqty) AS freeqty
,sum(s2.totalaltqty) AS altqty
,sum(s2.totaltradis + s2.totaladnldis) AS discount
,sum(amount) AS amount
,sum(itemstockvalue) AS stockvalue
,sum(itemprofit1) AS itemprofit
FROM sales1 s1
INNER JOIN sales2 s2 ON s1.txno = s2.txno
INNER JOIN items i ON i.itemno = s2.itemno
GROUP BY repgroupname
,masteritemname
,itemname
,groupname1
,groupname2
,groupname3
,units
,unit1
,unit2
,altunits
,altunit1
,altunit2
ORDER BY itemname
) AS tt
GROUP BY grp
,disp
,groupname1
,groupname2
,groupname3
Here
Sales1 table have 144513 Records
Sales2 Table have 438915 Records
items Table have 78512 Records
This Query take 6 seconds to produce result.
How to Optimize this query?
am using postgresql 9.3
That is a truly horrible query.
You should start by losing the ORDER BY in the sub-select - the ordering is discarded by the outer query.
Beyond that, ask yourself why you need to look to see a summary of every songle row in th DBMS - does this serve any useful purpose (if the query is returning more than 20 rows, then the answer is no).
You might be able to make it go faster by ensuring that the foreign keys in the tables are indexed (indexes are THE most important bit of information to look at whenever you're talking about performance and you've told us nothing about them).
Maintaining the query as a regular snapshot will mitigate the performance impact.
I have a table created. With one column named states and another column called land area. I am using oracle 11g. I have looked at various questions on here and cannot find a solution. Here is what I have tried so far:
SELECT LandAreas, State
FROM ( SELECT LandAreas, State, DENSE_RANK() OVER (ORDER BY State DESC) sal_dense_rank
FROM Map )
WHERE sal_dense_rank >= 5;
This does not provide the top 5 land areas as far as number wise.
I have also tried this one but no go either:
SELECT * FROM Map order by State desc)
where rownum < 5;
Anyone have any suggestions to get me on the right track??
Here is a samle of the table
states land areas
michagan 15000
florida 25000
tennessee 10000
alabama 80000
new york 150000
california 20000
oregon 5000
texas 6000
utah 3000
nebraska 1000
Desired output from query:
States land area
new york 150000
alabama 80000
florida 25000
california 20000
Try:
Select * from
(SELECT State, LandAreas FROM Map ORDER BY LandAreas DESC)
where rownum < 6
Link to Fiddle
Use a HAVING clause and count the number state states larger:
SELECT m.state, m.landArea
FROM Map m
LEFT JOIN Map m2 on m2.landArea > m.landArea
GROUP BY m.state, m.landArea
HAVING count(*) < 5
ORDER BY m.landArea DESC
See SQLFiddle
This joins each state to every state whose area is greater, then uses a HAVING clause to return only those states where the number of larger states was less than 5.
Ties are all returned, leading to more than 5 rows in the case of a tie for 5th.
The left join is needed for the case of the largest state, which has no other larger state to join to.
The ORDER BY is optional.
Try something like this
select m.states,m.landarea
from map m
where (select count(‘x’) from map m2 where m2.landarea > m.landarea)<=5
order by m.landarea
There are two bloomers in your posted code.
You need to use landarea in the DENSE_RANK() call. At the moment you're ordering the states in reverse alphabetical order.
Your filter in the outer query is the wrong way around: you're excluding the top four results.
Here is what you need ...
SELECT LandArea, State
FROM ( SELECT LandArea
, State
, DENSE_RANK() OVER (ORDER BY landarea DESC) as area_dr
FROM Maps )
WHERE area_dr <= 5
order by area_dr;
... and here is the SQL Fiddle to prove it. (I'm going with the statement in the question that you want the top 5 biggest states and ignoring the fact that your desired result set has only four rows. But adjust the outer filter as you will).
There are three different functions for deriving top-N result sets: DENSE_RANK, RANK and ROW_NUMBER.
Using ROW_NUMBER will always guarantee you 5 rows in the result set, but you may get the wrong result if there are several states with the same land area (unlikely in this case, but other data sets will produce such clashes). So: 1,2,3,4,5
The difference between RANK and DENSE_RANK is how they handle ties. DENSE_RANK always produces a series of consecutive numbers, regardless of how many rows there are in each rank. So: 1,2,2,3,3,3,4,5
RANK on the other hand will produce a sparse series if a given rank has more than one hit. So: 1,2,2,4,4,4.
Note that each of the example result sets has a different number of rows. Which one is correct? It depends on the precise question you want to ask.
Using a sorted sub-query with the ROWNUM pseudo-column will work like the ROW_NUMBER function, but I prefer using ROW_NUMBER because it is more powerful and more error-proof.
I have a table that stores student results for different exams and different exam types say main exam, continuous assessment, course work etc, I need to query the table such that I get only one row for one particular exam unit with the percentage averaged depending on the number of exams the students sat for. Here is my attempted query:
select stu_reg_no, unit_code,
exam_unit, exam_semester,
student_year,
sum(per_centage_score)/count(per_centage_score) percentage
from student_results_master
group by unit_code, exam_unit,
per_centage_score, stu_reg_no,
exam_semester, student_year;
Here is my resultset:
I have two rows for the same exam unit since one is main exam and the other course work I need my output like this:
E35/1000/2013 TFT001 COMPLEX ANALYSIS 1 1 71.04
E35/1000/2013 TFT002 LINEAR ALGEBRA 1 1 56.25
The percentage for that particular unit is added and divided by the number of exams for that particular unit.
How can I achieve this?
Oracle provides a built-in function for calculating average value for an expression over a set of rows - AVG(). To get the desired output you need to do the following two things:
Replace sum(per_centage_score)/count(per_centage_score) with avg(per_centage_score)
Remove per_centage_score column from the group by clause.
To that end, your query might look like this:
select stu_reg_no
, unit_code
, exam_unit
, exam_semester
, student_year
, avg(percentage) percentage
from student_results_master
group by unit_code
, exam_unit
, stu_reg_no
, exam_semester
, student_year;
Result:
STU_REG_NO UNIT_CODE EXAM_UNIT EXAM_SEMESTER STUDENT_YEAR PERCENTAGE
------------- --------- ---------------- ------------- ------------ ----------
E35/1000/2013 TFT001 COMPLEX ANALYSIS 1 1 71.04
E35/1000/2013 TFT002 LINEAR ALGEBRA 1 1 56.25
try this:
select stu_reg_no, unit_code, exam_unit, exam_semester, student_year,
(select sum(per_centage_score) from student_results_master t2 where t2.exam_unit = t1.exam_unit)
/(select count(per_centage_score) from student_results_master t2 where t2.exam_unit = t1.exam_unit)
from student_results_master t1
group by unit_code, exam_unit, stu_reg_no, exam_semester, student_year;