How to break pipe if stdin is empty? - bash

Question

I want to break the whole pipe if the stdin is empty. I try to combined xargs -r and tee, which means not print and write if stdin is empty, but it failed
...| upstream commands | xargs -r tee output.txt | downstream commands | ...
Any feedback appreciated.

Answer 1

There is no way you can actually terminate a bash pipe conditionally. All commands in a pipeline are started simultaneously. There is however a tool available that would assist you with creating a conditional pipeline. In moreutils you can find the tool ifne which executes a command if and only if the input /dev/stdin is not empty. So you could write something like:
$ command1 | ifne command2 | ifne command3 | ifne command4
Here all commands ifne and command1 are started simultaniously. Only if ifne receives input via /dev/stdin, it will start its respective commandx

Answer 2

Pipe'll break if command failed. You can add grep in between to achieve this. An example:
$ echo ok | awk '{print $0,"1"}' | awk '{print $0,"2"}' | awk '{print $0,"3"}'
ok 1 2 3
Now add grep:
$ echo ok | grep -Ei '^.+$' | awk '{print $0,"1"}' | awk '{print $0,"2"}' | awk '{print $0,"3"}'
ok 1 2 3
And test empty echo:
$ echo | awk '{print $0,"1"}' | awk '{print $0,"2"}' | awk '{print $0,"3"}'
1 2 3
$ echo | grep -Ei '^.+$' | awk '{print $0,"1"}' | awk '{print $0,"2"}' | awk '{print $0,"3"}'
Looks like this works but it doesn't, interesting indeed, well then obvy pipes don't fit here, try this approach:
#!/bin/bash
set -x
fun(){
data=$(echo "$1"); [[ $data ]] && data=$(awk '{print $0,1}' <<< "$data") || return 1; [[ $data ]] && data=$(awk '{print $0,2}' <<< "$data") || return 1; [[ $data ]] && data=$(awk '{print $0,3}' <<< "$data") || return 1; echo "$data"
}
fun ok
fun
Testing:
$ ./test
+ fun ok
++ echo ok
+ data=ok
+ [[ -n ok ]]
++ awk '{print $0,1}'
+ data='ok 1'
+ [[ -n ok 1 ]]
++ awk '{print $0,2}'
+ data='ok 1 2'
+ [[ -n ok 1 2 ]]
++ awk '{print $0,3}'
+ data='ok 1 2 3'
+ echo 'ok 1 2 3'
ok 1 2 3
+ fun
++ echo ''
+ data=
+ [[ -n '' ]]
+ return 1
More readable variant:
#!/bin/bash
set -x
fun(){
data=$(echo "$1")
[[ $data ]] && data=$(awk '{print $0,1}' <<< "$data") || return 1
[[ $data ]] && data=$(awk '{print $0,2}' <<< "$data") || return 1
[[ $data ]] && data=$(awk '{print $0,3}' <<< "$data") || return 1
echo "$data"
}
fun ok
fun