I have 3 services to be started in the system reboot in a sequnece
Tried blow in crontab -e but no use
#reboot sleep 10 && bash /myfolder/hazelcast-x.x/bin/start.sh
#reboot sleep 20 && /myfolder/apache-activemq-x.x/bin/activemq start
#reboot sleep 30 && bash /myfolder/apache-tomcat-x.x/bin/startup.sh
in your cron command you can use && so if the command on the left hand side fails, the command on the right hand side will not run. for example,
command 1 && command 2 && command 3
Also be aware that the unmodified version of bash /myfolder/hazelcast-x.x/bin/start.sh looks for a pid file if found it will not start. So you may want to clean up the pid file prior to running start.sh after a reboot. We do this to prevent more than one node from starting on a given server since without partition groups that could lead to data loss.
Related
Due to some issues I wont elaborate here to not waste time, I made a bash script which will ping google every 10 minutes and if there is a response it will keep the loop running and if not then the PC will restart. After a lot of hurdle I have been able to make the script and also make it start on bootup. However the issue is that i want to see the results on the terminal, meaning I want to keep monitoring it but the terminal does not open on bootup. But it does open if I run it as ./net.sh.
The script is running on startup, that much I know because I use another script to open an application and it works flawlessly.
My system information
NAME="Linux Mint"
VERSION="18.3 (Sylvia)"
ID=linuxmint
ID_LIKE=ubuntu
PRETTY_NAME="Linux Mint 18.3"
VERSION_ID="18.3"
HOME_URL="http://www.linuxmint.com/"
SUPPORT_URL="http://forums.linuxmint.com/"
BUG_REPORT_URL="http://bugs.launchpad.net/linuxmint/"
VERSION_CODENAME=sylvia
UBUNTU_CODENAME=xenial
The contents of my net.sh bash script are
#! /bin/bash
xfce4-terminal &
sleep 30
while true
do
ping -c1 google.com
if [ $? == 0 ]; then
echo "Ping Sucessful. The Device will Continue Operating"
sleep 600
else
systemctl reboot
fi
done
I have put the scripts in /usr/bin and inserted the scripts for startup at boot in /etc/rc.local
So I did some further research and with help from reddit I realized that the reason I couldnt get it to show on terminal was because the script was starting on bootup but I needed it to start after user login. So I added the script on startup application (which can be found searching on start menu if thats whats it called). But it was still giving issues so I divided the script in two parts.
I put the net.sh script on startup and directed that script to open my main script which i named net_loop.sh
This is how the net.sh script looks
#! /bin/bash
sleep 20
xfce4-terminal -e usr/bin/net_loop.sh
And the net_loop.sh
#! /bin/bash
while true
do
ping -c1 google.com
if [ $? == 0 ]; then
echo "Ping Sucessful. The Device will Continue Operating"
sleep 600
else
systemctl reboot
fi
done
The results are the results of the net_loop.sh script are open in another terminal.
Note: I used help from this thread
If minute interval is usable why not use "cron" to start your?
$> crontab –e
or
$> sudo crontab –e
I'm on Freebsd9.2.(I have to use this operating system) I want to run multiple scripts with at command but I want to ignore running a script in a same time.
For example: I have 3 script files: 1.sh, 2.sh, 3.sh
I have a job to execute 1.sh at today 16:20, when I run the at command with the same time and script, the number of the jobs in /var/at/jobs changed to 2 jobs. I want to ignore this, but the script 2.sh can run with thw same time. Do you have any idea what should I do?
I don't know if I understood correctly the problem, but maybe the command lockf could help.
For example try this in one terminal:
$ lockf -t 0 /tmp/a.lock sleep 5
In another terminal run:
$ lockf -t 0 /tmp/a.lock echo "sleep finished"
In this example until the command sleep 5 doesn't exit, if you try to run another command you will get something like:
lockf: /tmp/a.lock: already locked
A cron example:
15 4 * * * lockf -t 0 /tmp/poudriere.lock /usr/local/etc/poudriere.d/cron 12amd64 default
This prevents running the script/app if the lock exists, so probably you can get an idea of how you could use it with at
I am trying to run several roslaunch files, one after the other, from a bash script. However, when the nodes complete execution, they hang with the message:
[grem_node-1] process has finished cleanly
log file: /home/user/.ros/log/956b5e54-75f5-11e9-94f8-a08cfdc04927/grem_node-1*.log
Then I need to Ctrl-C to get killing on exit for all of the nodes launched from the launch file. Is there some way of causing nodes to automatically kill themselves on exit? Because at the moment I need to Ctrl-C every time a node terminates.
My bash script looks like this, by the way:
python /home/user/git/segmentation_plots/scripts/generate_grem_launch.py /home/user/Data2/Coco 0 /home/user/git/Async_CNN/config.txt
source ~/setupgremsim.sh
roslaunch grem_ros grem.launch config:=/home/user/git/Async_CNN/config.txt
source /home/user/catkin_ws/devel/setup.bash
roslaunch rpg_async_cnn_generator conf_coco.launch
The script setupgremsim.sh sources another catkin workspace.
Many thanks!
Thanks all for your advice. What I ended up doing was this; I launched my ROS Nodes from separate python scripts, which I then called from the bash script. In python you are able to terminate child processes with shutdown. So to provide an example for anyone else with this issue:
bash script:
#!/bin/bash
for i in {0..100}
do
echo "========================================================\n"
echo "This is the $i th run\n"
echo "========================================================\n"
source /home/timo/catkin_ws/devel/setup.bash
python planar_launch_generator.py
done
and then inside planar_launch_generator.py:
import roslaunch
import rospy
process_generate_running = True
class ProcessListener(roslaunch.pmon.ProcessListener):
global process_generate_running
def process_died(self, name, exit_code):
global process_generate_running
process_generate_running = False
rospy.logwarn("%s died with code %s", name, exit_code)
def init_launch(launchfile, process_listener):
uuid = roslaunch.rlutil.get_or_generate_uuid(None, False)
roslaunch.configure_logging(uuid)
launch = roslaunch.parent.ROSLaunchParent(
uuid,
[launchfile],
process_listeners=[process_listener],
)
return launch
rospy.init_node("async_cnn_generator")
launch_file = "/home/user/catkin_ws/src/async_cnn_generator/launch/conf_coco.launch"
launch = init_launch(launch_file, ProcessListener())
launch.start()
while process_generate_running:
rospy.sleep(0.05)
launch.shutdown()
Using this method you could source any number of different catkin workspaces and launch any number of launchfiles.
Try to do this
(1) For each launch you put in a separate shell script. So you have N script
In each script, call the launch file in xterm. xterm -e "roslaunch yourfacnylauncher"
(2) Prepare a master script which calling all N child script in the sequence you want it to be and delay you want it to have.
Once it is done, xterm should kill itself.
Edit. You can manually kill one if you know its gonna hang. Eg below
#!/bin/sh
source /opt/ros/kinetic/setup.bash
source ~/catkin_ws/devel/setup.bash
start ROScore using systemd or rc.local using lxtermal or other terminals to avoid accident kill. Then run the part which you think gonna hang or create a problem. Echo->action if necessary
xterm -geometry 80x36+0+0 -e "echo 'uav' | sudo -S dnsmasq -C /dev/null -kd -F 10.5.5.50,10.5.5.100 -i enp59s0 --bind-dynamic" & sleep 15
Stupid OUSTER LIDAR cant auto config like Veloydne and will hang here. other code cant run
killall xterm & sleep 1
Lets just kill it and continuous run other launches
xterm -e "roslaunch '/home/uav/catkin_ws/src/ouster_driver_1.12.0/ouster_ros/os1.launch' os1_hostname:=os1-991907000715.local os1_udp_dest:=10.5.5.1"
I'm trying to write a bash script.
The script should check if the MC server is running. If it crashed or stopped it will start the server automatically.
I'll use crontab to run the script every minute. I think I can run it every second it won't stress the CPU too much. I also would like to know when was the server restarted. So I'm going to print the date to the "RestartLog" file.
This is what I have so far:
#!/bin/sh
ps auxw | grep start.sh | grep -v grep > /dev/null
if [ $? != 0 ]
then
cd /home/minecraft/minecraft/ && ./start.sh && echo "Server restarted on: $(date)" >> /home/minecraft/minecraft/RestartLog.txt > /dev/null
fi
I'm just started learning Bash and I'm not sure if this is the right way to do it.
The use of cron is possible, there are other (better) solutions (monit, supervisord etc.). But that is not the question; you asked for "the right way". The right way is difficult to define, but understanding the limits and problems in your code may help you.
Executing with normal cron will happen at most once per minute. That means that you minecraft server may be down 59 seconds before it is restarted.
#!/bin/sh
You should have the #! at the beginning of the line. Don't know if this is a cut/paste problem, but it is rather important. Also, you might want to use #!/bin/bash instead of #!/bin/sh to actually use bash.
ps auxw | grep start.sh | grep -v grep > /dev/null
Some may suggest to use ps -ef but that is a question of taste. You may even use ps -ef | grep [s]tart.sh to prevent using the second grep. The main problem however with this line is that that you are parsing the process-list for a fairly generic start.sh. This may be OK if you have a dedicated server for this, but if there are more users on the server, you run the risk that someone else runs a start.sh for something completely different.
if [ $? != 0 ]
then
There was already a comment about the use of $? and clean code.
cd /home/minecraft/minecraft/ && ./start.sh && echo "Server restarted on: $(date)" >> /home/minecraft/minecraft/RestartLog.txt > /dev/null
It is a good idea to keep a log of the restarts. In this line, you make the execution of the ./start.sh dependent on the fact that the cd succeeds. Also, the echo only gets executed after the ./start.sh exists.
So that leaves me with a question: does start.sh keep on running as long as the server runs (in that case: the ps-test is ok, but the && echo makes no sense, or does start.sh exit while leaving the minecraft-server in the background (in that case the ps-grep won't work correctly, but it makes sense to echo the log record only if start.sh exits correctly).
fi
(no remarks for the fi)
If start.sh blocks until the server exists/crashes, you'd be better off to simply restart it in an infinite loop without the involvement of cron. Simply type in a console (or put into another script):
#!/bin/bash
cd /home/minecraft/minecraft/
while sleep 3; do
echo "$(date) server (re)start" >> restart.log
./start.sh # blocks until server crashes
done
But if it doesn't block (i.e. if start.sh starts the server and then returns, but the server keeps running), you would need to implement a different check to verify if the server is actually still running, other than ps|grep start.sh
PS: To kill the infinite loop you have to Ctrl+C twice: Once to stop ./start.sh and once to exit from the immediate sleep.
You can use monit for this task. See docu. It is available on most linux distributions and has a straightforward config. Find some examples in this post
For your app it will look something like
check process minecraftserver
matching "start.sh"
start program = "/home/minecraft/minecraft/start.sh"
stop program = "/home/minecraft/minecraft/stop.sh"
I wrote this answer because sometimes the most efficient solution is already there and you don't have to code anything. Also follow the suggestions of William Pursell and use the init system of your OS (systemd,upstart,system-v,etc.) to host your scripts.
Find more:
Shell Script For Process Monitoring
I'm running two tests on a remote server, here is the command I used several hours ago:
% ./test1.sh; ./test2.sh
The two tests are supposed to run one by one.If the second runs before the first completes, everything will be in ruin, and I'll have to restart the whole procedure.
The dilemma is, these two tasks cost too many hours to complete, and when I prepare to logout the server and wait for the result. I don't know how to switch both of them to background... If I use Ctrl+Z, only the first task will be suspended, while the second starts doing nothing useful while wiping out current data.
Is it possible to switch both of them to background, preserving their orders? Actually I should make these two tasks in the same process group like (./test1.sh; ./test2.sh) &, but sadly, the first test have run several hours, and it's quite a pity to restart the tests.
An option is to kill the second test before it starts, but is there any mechanism to cope with this?
First rename the ./test2.sh to ./test3.sh. Then do [CTRL+Z], followed by bg and disown -h. Then save this script (test4.sh):
while :; do
sleep 5;
pgrep -f test1.sh &> /dev/null
if [ $? -ne 0 ]; then
nohup ./test3.sh &
break
fi
done
then do: nohup ./test4.sh &.
and you can logout.
First, screen or tmux are your friends here, if you don't already work with them (they make remote machine work an order of magnitude easier).
To use conditional consecutive execution you can write:
./test1.sh && ./test2.sh
which will only execute test2.sh if test1.sh returns with 0 (conventionally meaning: no error). Example:
$ true && echo "first command was successful"
first command was successful
$ ! true && echo "ain't gonna happen"
More on control operators: http://www.humbug.in/docs/the-linux-training-book/ch08s01.html