This question already has answers here:
JMeter retrieve value of value
(2 answers)
Closed 1 year ago.
''
I want to pass parameter inside parameter.
For ex. ${var1${var2}} something like this.
I am taking this variables from Test plan's user defined variables.
''
Try this one: ${__V(var1${var2})}
Jmeter documentation
You can use the __V() function. It will combine the two variables.
You can refer this for more details.
https://www.blazemeter.com/blog/here%E2%80%99s-what-do-combine-multiple-jmeter-variables
Related
This question already has answers here:
How can I pass a slice as a variadic input?
(3 answers)
Closed 4 years ago.
I need to initialize gocql with multiple ips, I want to pass the ips from a variable/constant.
How to pass some thing like
gocql.NewCluster(ipvalues)
instead of using
gocql.NewCluster("127.0.0.1", "127.0.0.2")
i want to pass the list of ips through a variable something like an array.
As you can see, gocql.NewCluser takes a variadic parameter, which means you can pass multiple values separated with commas to the function.
In go, you just need to make your ipvalues variable be a slice of strings and pass it like this:
ipvalues := []string{"127.0.0.1", "127.0.0.2"}
gocql.NewCluster(ipvalues...)
This will have the same effect as writing gocql.NewCluster("127.0.0.1", "127.0.0.2")
See the golang spec for more information on this feature
This question already has answers here:
What are the restrictions for method names in Ruby?
(5 answers)
Closed 7 years ago.
On the Chef Style Guide page appears this Ruby expression:
antarctica_hint = hint?('antarctica')
What exactly does the ? after hint and before ('antarctica') mean? Is it just part of the method name? (i.e. the method is called 'hint?' not 'hint')
It is part of method name, and people typically (not always) use it for methods that return boolean value.
An example from Ruby is Class#respond_to?
This question already has an answer here:
Does Swift have something like "ref" keyword that forces parameter to be passed by reference?
(1 answer)
Closed 8 years ago.
Swift has the inout keyword to pass a primitive argument by reference. When would I use this over just passing it by value?
Edit: I realize that you can use this to change its value, but why not just pass it by value and assign it the corresponding value in the tuple returned by the function?
You would do that if you wanted to modify the original value instead of just a copy. However, I would argue that you should just return the new value since you can return multiple values in Swift.
This seems to be a plausible reason:
"Maybe the existing body of Objective C libraries have a lot of out parameters, and they didn't want to wrap them all for Swift."
http://blog.lexspoon.org/2014/06/my-analysis-of-swift-language.html
This question already has answers here:
What does ##variable mean in Ruby?
(5 answers)
Closed 9 years ago.
I just started learning Ruby and I have been unable to find a good explanation on what is the difference between ## and # in terms of class variables. If anyone can provide a basic intuitive example, that would be really great. Also are they interchangeable?
A variable prefixed with ## is a class variable and one prefixed with # is an instance variable. A great description can be found in this answer: https://stackoverflow.com/a/5890199/1181886
# before a variable name : instance variable (one per instance)
## before a variable name : static variable (one per class)
This question already has an answer here:
naked asterisk as parameter in method definition: def f(*)
(1 answer)
Closed 10 years ago.
I was poking through the Rails 3 ActiveRecord source code today and found a method where the entire parameter list was a single asterisk.
def save(*)
I couldn't find a good description of what this does (though I have some ideas based on what I know about splat arguments).
What does it do, and why would you use it?
It means it can have any number of arguments (including zero) and it discards all those arguments.