I have a variable $svn_tag in a Jenkins job.
Its value is branches/sprint-77.
I want the output branches-sprint-77, but I didn't get any output.
I tried these two methods:
$svn_tag|tr "/" -
${svn_tag////-}
It is giving output in bash script, but it is not working in the Jenkins job.
What am I doing wrong?
Your first approach does not make sense, not the least because you try to run `$svn_tag´ as a command. Your second approach works for me:
svn_tag=branches/sprint-77
echo ${svn_tag////-}
prints branches-sprint-77.
For the safe side, you could also check your bash version, by doing a
echo bash=$BASH_VERSION
though I don't think that this feature is version-dependent. Mine is 4.4.12(3)-release.
Use code like below
${svn_tag.replaceAll('/', '-')}
Related
I encounter the issue that I have a parameterized project with several string parameters, e.g., "VARIABLE_A", and that Jenkins doesn't know them anymore when executing a shell script in the Build section, i.e., there is simply no value.
This is very bizarre and I am convinced this should work using a string parameter (variable) in these ways:
"echo $VARIABLE_A"
"python3 $PATH/abc.py $VARIABLE_A"
...
but there is no values anymore.
echo-command does not print anything and the Python script misses the value as VARIABLE_A is apparently empty.
Perhaps someone has an idea ?
Thanks
Rainer
PS
Jenkins version is "2.277.2".
I've created a bash file that queries my database and then updates some tables.
When I run it manually everything goes smoothly but when I run it with a cronjob it runs the first query and then stops before it goes into a loop.
After looking into it on the net I found a few things that may be the issue but from my side everything looks in order.
So what I did:
Checked if #!/bin/bash is included in my bash at the start and it is.
Checked that the path is correct in the cronjob. My cronjob below
0-59/5 * * * * cd /path/path2/bashLocation/; ./bash.sh
The loop is in the format of
for ID in ${IDS//,/ }
do
...do something
done
This works fine tested manually. My IDS are in string format that why I split it with //,/.(Works fine)
I log all outputs in a log file but it doesn't show any error.
Has anyone encountered this issue before or has any ideas how to fix the issue?
If the command you are running in cron has percent signs ('%'), they need to be escaped with a backslash. I've been bitten by this. From the manpage: "Percent-signs (%) in the command, unless escaped with backslash () ..."
The $PATH variable may be different when run from cron. Try putting something like this at the beginning of your script: export PATH=/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin
Try running bash explicitly, i.e. rather than ./bash.sh in crontab, try /bin/bash bash.sh
I don't know how helpful this may be to some people but I noticed when I printenv shell in my logs it printed that it was bin/sh even if I define it at the top of my script and run it as a bash file.
So what I did was changed all parts of my code that where not supported by shell and my conjob works fine.
So I assume that conjob does not support bash files. (Didn't find anything on the internet about this.)
Why it runs in /bin/sh I don't know.
Hope someone finds this helpful.
I'm calling Uncle. I'm attempting to manipulate variables that have hard coded values in a second bash script I am calling. I have no control over the script and am building a wrapper around it to adjust some build behavior before it finally kicks off a yocto build. I'm not sure what else to try after reading and trying numerous examples.
Examples of the situation:
build.sh calls build2.sh
IS_DEV=1 ./build2.sh #trying to override value
build2.sh
IS_DEV=0 # hardcoded value
echo $IS_DEV
# always results in 0.
I have also tried export IS_DEV=1 before calling build2.sh.
I'm sure this is pretty simple, but I cannot seem to get this to work. I appreciate any assistance. Is this possible? I'm using GNU bash, version 4.3.48(1)-release (x86_64-pc-linux-gnu) on Ubuntu 16.04.4 LTS.
Oh, I have also tried the sourcing technique with no luck.
IS_DEV=1 . ./build2.sh
IS_DEV=1 source ./build2.sh
Where am I getting this wrong?
Much appreciated.
If you can't modify the script, execute a modified version of it.
sed 's/^IS_DEV=0 /IS_DEV=1 /' build2.sh | sh
Obviously, pipe to bash if you need Bash semantics instead of POSIX sh semantics.
If the script really hard-codes a value with no means to override it from the command line, modifying that script is the only possible workaround. But the modification can be ephemeral; the above performs a simple substitution on the script, then passes the modified temporary copy through a pipe to a new shell instance for execution. The modification only exists in the pipeline, and doesn't affect the on-disk version of build2.sh.
I have a bash script that executes a series of commands, some involving redirection. See cyrus-mark-ham-spam.
I want the script to have a test mode, where all the commands run are printed instead of executing them. As you can see, I have tried to do that by just putting "echo" on the front of each command in test mode.
Unfortunately this doesn't deal with redirection - any redirections are still done, so the program leaves lots of temp files littered about the place when run in test mode.
I have tried various ways to get round this, like quoting the whole command and passing it to a function that either prints it or runs it, but either the redirections work in test mode, or they don't work in run mode.
I thought this must have come up before, and wonder if there is a known solution which does not involve every command being repeated with an if TEST round the pair?
Please note, this is NOT a duplicate of show commands without executing them because neither that question, nor its answers, covers redirection (which is the essence of this question).
I see that it is not a duplicate but there is not general solution to this. You need to look at each command separately.
As long as the command doesn't use arguments enclosed in spaces, like
cmd -a -b -c > filename
, you can quote it:
echo 'cmd -a -b -c > filename'
But real life code is more complex, sure.
I wrote a script that's retrieving the currently run command using $BASH_COMMAND. The script is basically doing some logic to figure out current command and file being opened for each tmux session. Everything works great, except when user runs a piped command (i.e. cat file | less), in which case $BASH_COMMAND only seems to store the first command before the pipe. As a result, instead of showing the command as less[file] (which is the actual program that has the file open), the script outputs it as cat[file].
One alternative I tried using is relying on history 1 instead of $BASH_COMMAND. There are a couple issues with this alternative as well. First, it does not auto-expand aliases, like $BASH_COMMAND does, which in some cases could cause the script to get confused (for example, if I tell it to ignore ls, but use ll instead (mapped to ls -l), the script will not ignore the command, processing it anyway), and including extra conditionals for each alias doesn't seem like a clean solution. The second problem is that I'm using HISTIGNORE to filter out some common commands, which I still want the script to be aware of, using history will just make the script ignore the last command unless it's tracked by history.
I also tried using ${#PIPESTATUS[#]} to see if the array length is 1 (no pipes) or higher (pipes used, in which case I would retrieve the history instead), but it seems to always only be aware of 1 command as well.
Is anyone aware of other alternatives that could work for me (such as another variable that would store $BASH_COMMAND for the other subcalls that are to be executed after the current subcall is complete, or some way to be aware if the pipe was used in the last command)?
i think that you will need to change a bit your implementation and use "history" command to get it to work. Also, use the command "alias" to check all of the configured alias.. the command "which" to check if the command is actually stored in any PATH dir. good luck