I have an API that can get by searching keyword(s).
I want to consume it with Laravel Blade. So, I made a ViewHadController:
public function cari(Request $request)
{
$cari = $request->cari;
$response = Http::get('http://hadits.test/api/hadall/cari?isi=$cari');
$data = $response->json();
//dd($data);
return view('hadits', compact('data'));
}
If I replace $cari with any keywords, return is okay.
Already tried build this in view.blade.php:
<div class="container">
<form action="/cari" method="GET">
<input type="text" name="cari" placeholder="Cari Hadits .." value="{{ old('cari') }}">
<input type="submit" value="CARI">
</form>
</div>
with this web.routes:
Route::get('/{cari}', 'ViewHadController#cari');
When the keyword hard-coded, the results are okay:
But no luck if using search parameter, always return blank. Is there any tutorials how to consume that API with search form in Laravel Blade?
Related
Following is my controller. Method ProjectsView is to view all the listings. The second method BackendProjectSearch is for searching of projects. The first page of search result is displayed properly, but when we click on next page it gives the error "The GET method is not supported for this route. Supported methods: POST."
What should I do ?
public function ProjectsView(){
$projects = projects::orderBy('id','ASC')->paginate(15);
return view('backend.projects.projects_view',compact('projects')); }
public function BackendProjectSearch(Request $request){
$request->validate(["search" => "required"]);
$item = $request->search;
$projects = Projects::where('project_name','LIKE',"%$item%")->paginate(15);
return view('backend.projects.projects_view',compact('projects')); }
Following are the routes for both the methods :
Route::post('/backend/project/search', [ProjectsController::class, 'BackendProjectSearch'])->name('backend.project.search');
Route::get('/view', [ProjectsController::class, 'projectsView'])->name('projects.view');
View code :
<div class="col-md-8">
<div class="header-navsearch">
<form class="form-inline mr-auto" method="post" action="{{route('backend.project.search')}}">
#csrf
<div class="nav-search">
<input type="search" name="search" class="form-control header-search" placeholder="Search projects…" aria-label="Search">
<button class="btn btn-primary" type="submit"><i class="fa fa-search"></i></button>
</div>
</form>
</div>
</div>
The route for this request should be post, not get.
Example
Route::post(-----);
Also, make sure to insert a CSRF token while making the request
it means you now cannot do something like the following.
Instead, you have to do something like...
<form action="{{ route('example') }}" method="POST">
#csrf {{-- According to the version of laravel --}}
{{-- Your other codes --}}
<button type="submit" class="">Submit</button>
</form>
You have to use the below code
return redirect()->route('projects.view')->with(['projects' => $projects]);
Your route might be little change
Route::get('/view/{projects?}', [ProjectsController::class, 'projectsView'])->name('projects.view');
and In your controller, you have to change function like this
public function ProjectsView($projects = null){
if($projects!=null){
return view('backend.projects.projects_view',compact('projects'));
}
else{
$projects = projects::orderBy('id','ASC')->paginate(15);
return view('backend.projects.projects_view',compact('projects'));
}
I am new to laravel and now i am facing an issue. I saw many related answers ,but nothing works for me. My problem is, i have a page and when i update a user i want to redirect on the same page with updated results.When i look into the db table,the updation is happening,but the page shows the above error. I tried many answers which i saw on stack , but nothing works for me.
Thank you
Here is my view:
<form method="POST" action="/updateleaduser">
#csrf
<h6 style = "font-family:Palatino" class="card-text">Assigned To: {{$us->name}}</h6>
<input type="hidden" name="idd" name="idd" value="{{$us->id}}">
<select name="select_user" class="form-control">
#foreach($testusers as $user)
<option value="{{$user->id}}">{{$user->name}}</option>
#endforeach
</select>
<button type="submit" class="form-control" style="background-color: green;color: white;">Update User</button>
Here is my route:
Route::post('/updateleaduser','RequestController#updateuserlead')->name('updateleaduser');
Here is my controller:
public function updateuserlead(Request $request){
$idd = $_POST['idd'];
$select_user = $request->input('select_user');
DB::table('leads')->where('id',$idd)->update(array(
'client_id'=>$select_user,
));
return redirect()->back();
}
Try replacing return redirect()->back(); with return redirect()->to("/updateleaduser")
public function updateuserlead(Request $request){
$idd = $_POST['idd'];
$select_user = $request->input('select_user');
DB::table('leads')->where('id',$idd)->update(array(
'client_id'=>$select_user,
));
return redirect()->to("/updateleaduser");
}
Hi I am new to Laravel and so far I made good progress. Right now my head is blocked now and I need some direction or help, please.
I am getting data from radio button but GET Data is empty. I need to fill-in this data (pay) into an exist DB and I am getting "Creating default object from empty value" and I agree with Laravel :) I guess, my lack of knowledge is blocking me here.
Thanks.
This is the GET and POST data
GET Data empty
POST Data
_token = "72nrnI7Y7xuIQJe6LZPLGLzNsAv6ZZbY29zkjcIr"
pay = "CC"`
This is the Model
namespace App;
use Illuminate\Database\Eloquent\Model;
use DB;
use Auth;
class DAddress extends Model
{
protected $table='dAddress';
protected $fillable = ['payment_method'];
public function createPay()
{
$user = Auth::user();
$order = $user->daddress()->create([
'payment_method' => paymentMethod()
]);
}
}
This is the Controller
public function paymentMethod(Request $request) {
$address->payment_method = $request->pay;
DAddress::createPay();
Cart::destroy();
return redirect('abc');
}
This is where I get the HTML data
<form action="{{url('/paymentMethod')}}" method="post">
<input type="hidden" value="{{csrf_token()}}" name="_token"/>
<div class="form-group">
<div class="col-md-6">
<!-- First name -->
<input type="radio" class="form-control" name="pay"
value="CC"><i class="fa fa-credit-card"></i> Credit Card
<br> <br>
<input type="radio" class="form-control" name="pay"
value="PP"><i class="fa fa-paypal"></i> Paypal
<br> <br>
<input type="radio" class="form-control" name="pay"
value="BT"><i class="fa fa-university"></i> Bank Transfer
</div>
</div>
<input type="submit" class="btn btn-primary" value="Move to Last Page" />
This is the User.php I added below function.
public function daddress()
{
return $this->hasMany(DAddress::class);
}
i do not understand what you are trying to do with this line $address->payment_method = $request->pay;
when you say $address->payment_method, what is the $address object holding and where is payment_method you are trying to access, why not do something like this $payment_method = $request->pay, except is you are setting $payment_method as a global variable
if you are using the laravel create method you could do something like this $payment_method= App\createPay::create(['payment_method' => $request->pay]);
else you could instantiate you model like
$pay =createPay();
$pay->payment_method=$request->pay;
$pay->save();
i would have love you logic to be in the controller, i would have done something like this in my controller
public function createPay(Request $request){
$user = Auth::user();
$id=$user->id;
$payment=createPay::find($id);
$payment->payment_method=$request->pay;
$payment->save();
return redirect('abc');
}
i used laravel eloquent here, that is if you want to update a record, i don't know if this is close to what you want.
guys. I'm a newbie of Laravel.
I'm just wondering that if I need to pass some sensitive info, which is been wrote on a form, to controller, then to another view.
How could I pass the info to the view without using URL?
I have made some small test, but the result is all the same (url would include the data).
Here is the code.
Html(a):
<form action="/data" method="GET" class="form-horizontal">
<div class="form-group">
<input type="text" class="form-control" name="Test">
</div>
<div class="form-group">
<button type="submit" class="btn btn-primary">test</button>
</div>
web.php:
Route::get('/data', 'DataController#show');
DataController.php:
public function show(Request $request) {
return view('testShow');
}
Html(b):
<div class="ShowDataHere">
#if(!empty(request()->all()))
{{ request()->Test }}
#endif
Simply change your form to use POST instead of GET.
On the form...
<form action="/data" method="POST" class="form-horizontal">
In your route ...
Route::post('/data', 'DataController#show');
This will send all of the form fields to the server in a way that is less visable (not in the URL) but to make the form secure, you'll want to ensure it's served using HTTPS as well.
In Laravel when you use Route::post('/data', 'DataController#show') the Laravel expect a GET, because of the show function.
So you can use Route::post('/data', 'DataController#someFunction') and in your laravel controller get with:
public function someFunction(Request $request)
{
$array = $request->all(); //your fields
}
In this function you can get the attributes with $array = $request->all();
I'm learning laravel 5.4 and i'm doing a sample project. In that I need to do a search from my DB. Below i have attached a screenshot of my interface.
As you can see in the searchbox i have given i need to search "malabe". And i need to get results for that. i have implemented Controller and needed views too. below i have attached my controller
class SearchController extends Controller
{
//search controller
public function search($keydown){
$searchDetails = DB::table('van_Services')
->where('vs_RouteTo','like','%'.$keydown.'%')
->orwhere('vs_RouteFrom','like','%'.$keydown.'%')
->orwhere('vs_Description','like','%'.$keydown.'%')
->orderBy('created_at', 'DESC')
->paginate(12);
return view('search.search', compact('searchDetails'));
}
}
route code
Route::get('/search/{key}','SearchController#search');
here is the div of my search box code,
<div class="col-xs-6 col-sm-2 col-md-2">
<div class="search_box pull-right">
{{--Search Button--}}
<input type="text" name="search" id="search" laceholder="Search"/>
</div>
</div>
My route and code works if i do the url manual,
my problem is how can i make my search box work? any tutorials or tips?
1. If you really need to use URL link.
JS solution is:
// q => Your search word
function redirectSearch(q) {
location.href = '/search/'+q;
}
pass search field value to this function and page redirect automatically.
.
2. You can send GET params to controller.
Front code:
<div class="col-xs-6 col-sm-2 col-md-2">
<div class="search_box pull-right">
<form action="/search" method="GET">
{{--Search Button--}}
<input type="text" name="search" id="search" placeholder="Search"/>
</form>
</div>
Controller code:
public function search(Request $request){
$search = $request->search;
... Your code ...
}
If you use method with request don`t forget about
use Illuminate\Http\Request;
Route:
Route::get('/search','SearchController#search');
My route and code works if i do the url manual,
I assume it's already working and redirection is just your problem.
Just simply use JS/jQuery.
// when ENTER is pressed
$(document).keypress(function (e) {
if (e.which == 13) {
e.preventDefault();
window.location = APP_URL + "/search/" + $('#search').val();
}
});
Goodluck.