I have an issue with crudRepository (Spring boot-hibernate-postgres) and cascade when I try to save some related entities with a specific id (not autogenerated).
I spent some time googling without success.
This is the method:
private String importSourceInfo() {
SourceCompany sourceCompany= new SourceCompany();
sourceCompany.setName("companyName");
sourceCompany.setId(UUID.fromString("2bf05cbc-d530-11eb-b8bc-0242ac130003"));
Set<SourceUser> sourceUsers = new HashSet<>();
SourceUser sourceUser= new SourceUser();
sourceUser.setName("dev-team");
sourceUser.setId(UUID.fromString("4bede7a0-d530-11eb-b8bc-0242ac130003"));
sourceUser.setCompany(sourceCompany);
sourceUsers.add(sourceUser);
sourceCompany.setUsers(sourceUsers);
SourceInfo sourceInfo= new SourceInfo();
sourceInfo.setSourceUser(sourceUser);
sourceInfo.setSourceCompany(sourceCompany);
sourceInfo.setId(UUID.fromString("74a52aa0-d530-11eb-b8bc-0242ac130003"));
sourceInfo.setVersion("v1");
sourceInfo.setDescription("company v1");
sourceInfoRepository.save(sourceInfo);
return "SourceInfo has been imported!";
}
and these are the models:
SourceInfo:
#Data
#Entity
#EqualsAndHashCode(onlyExplicitlyIncluded = true)
#Table(name = "source_info")
public class SourceInfo {
#Id
#EqualsAndHashCode.Include
private UUID id;
#ManyToOne(cascade=CascadeType.PERSIST)
#JoinColumn(name = "fk_source_user", referencedColumnName = "id")
private SourceUser sourceUser;
#ManyToOne(cascade=CascadeType.PERSIST)
#JoinColumn(name = "fk_source_company", referencedColumnName = "id")
private SourceCompany sourceCompany;
#Column(columnDefinition = "text")
private String description;
private String version;
}
SourceCompany:
#Data
#Entity
#EqualsAndHashCode(onlyExplicitlyIncluded = true)
#Table(name = "source_company")
public class SourceCompany {
#Id
#EqualsAndHashCode.Include
private UUID id;
private String name;
#OneToMany(cascade = CascadeType.PERSIST, mappedBy = "company")
private Set<SourceUser> users;
}
SourceUser:
#Data
#Entity
#EqualsAndHashCode(onlyExplicitlyIncluded = true)
#Table(name = "source_user")
public class SourceUser {
#Id
#EqualsAndHashCode.Include
private UUID id;
private String name;
//ref
#ManyToOne
#JoinColumn(name = "fk_source_company")
private SourceCompany company;
}
And this is the error:
javax.persistence.EntityNotFoundException: Unable to find xxx.sp_model.sustainability.model.utils.SourceCompany with id 2bf05cbc-d530-11eb-b8bc-0242ac130003
at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl$JpaEntityNotFoundDelegate.handleEntityNotFound(EntityManagerFactoryBuilderImpl.java:163) ~[hibernate-core-5.4.27.Final.jar!/:5.4.27.Final]
at org.hibernate.event.internal.DefaultLoadEventListener.load(DefaultLoadEventListener.java:216) ~[hibernate-core-5.4.27.Final.jar!/:5.4.27.Final]
at org.hibernate.event.internal.DefaultLoadEventListener.proxyOrLoad(DefaultLoadEventListener.java:332) ~[hibernate-core-5.4.27.Final.jar!/:5.4.27.Final]
at org.hibernate.event.internal.DefaultLoadEventListener.doOnLoad(DefaultLoadEventListener.java:108) ~[hibernate-core-5.4.27.Final.jar!/:5.4.27.Final]
at org.hibernate.event.internal.DefaultLoadEventListener.onLoad(DefaultLoadEventListener.java:74) ~[hibernate-core-5.4.27.Final.jar!/:5.4.27.Final]
at org.hibernate.event.service.internal.EventListenerGroupImpl.fireEventOnEachListener(EventListenerGroupImpl.java:113) ~[hibernate-core-5.4.27.Final.jar!/:5.4.27.Final]
at org.hibernate.internal.SessionImpl.fireLoadNoChecks(SessionImpl.java:1186) ~[hibernate-core-5.4.27.Final.jar!/:5.4.27.Final]
at org.hibernate.internal.SessionImpl.internalLoad(SessionImpl.java:1051) ~[hibernate-core-5.4.27.Final.jar!/:5.4.27.Final]
at org.hibernate.type.EntityType.resolveIdentifier(EntityType.java:697) ~[hibernate-core-5.4.27.Final.jar!/:5.4.27.Final]
I think that hibernate want to update the child sourceCompany instead of saving it if new. But I don't know how to solve it.
(I need also to extend the eventual solution in a more complex structure so I need a general solution, because at principle the id of the application are autogenerated and all works, now the need is to set these IDs in the backend and so to save specific IDs.)
I think you are running into a limitation of Spring Data JPA repositories not being able to detect whether to call EntityManager.persist vs EntityManager.merge. You need to call EntityManager.persist to make this work.
Related
i want to implement a many to many association with quantity information in it . like this :
#Entity
#Table(name = "reserves")
#Getter #Setter #NoArgsConstructor
public class Reserve {
#Id
#ManyToOne(cascade = CascadeType.ALL,fetch = FetchType.EAGER)
#JoinColumn(name = "groupe_id")
private GroupeSanguin bloodGroup;
#Id
#ManyToOne(cascade = CascadeType.ALL,fetch = FetchType.EAGER)
private Banque banque;
private int quantity;
}
the GroupSanguin and the Banque are two class stored in the database two . here is the code for the two if you need :
#Entity
#Table(name = "groupe_sanguins")
public class GroupeSanguin {
#Id
private String groupe;
#OneToMany(mappedBy = "groupeSanguin")
private List<Donneur> donneurs;
}
#Entity #Getter #Setter #NoArgsConstructor
public class Banque {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
#Column(unique = true,nullable = false)
private String nom;
private String adresse;
#Column(unique = true)
private String telephone;
private String localisation;
}
so my i want to know how to annotate the JpaRepository to take the two as primary key like this and is my annotation good for it to work ?
public interface ReserveRepository extends JpaRepository<
Reserve,
//what to put here ?
>
This isn't a JPA question in fact, it's a relationnal database conception.
If Reserve has is own data and links with other entity it has it own Id
You can add unicity constraint
#Entity
#Table(name = "reserves", uniqueConstraints={
#UniqueConstraint(columnNames = {"banque_id", "groupe_id"})
#Getter #Setter #NoArgsConstructor
public class Reserve {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
#ManyToOne(cascade = CascadeType.ALL,fetch = FetchType.EAGER)
#JoinColumn(name = "groupe_id")
private GroupeSanguin bloodGroup;
#ManyToOne(cascade = CascadeType.ALL,fetch = FetchType.EAGER)
#JoinColumn(name = "banque_id")
private Banque banque;
private int quantity;
}
i've found this solutions too.
#Entity
#Table(name = "reserves")
#Getter #Setter #NoArgsConstructor
#IdClass(ReserveId.class) //this annotation will tell that id that the
// the id will be represented by a class
public class Reserve {
#Id
#ManyToOne(cascade = CascadeType.ALL,fetch = FetchType.EAGER)
#JoinColumn(name = "groupe_id")
private GroupeSanguin groupeSanguin;
#Id
#ManyToOne(cascade = CascadeType.ALL,fetch = FetchType.EAGER)
#JoinColumn(name = "banque_id")
private Banque banque;
private int quantity;
}
and the id class should implements Serializable like this :
#Getter #Setter
public class ReserveId implements Serializable {
private Banque banque;
private GroupeSanguin groupeSanguin;
}
and finally the repository will be like that :
#Repository
public interface ReserveRepo extends JpaRepository<Reserve, ReserveId>{}
See your Reserve class has nowhere mentioned composite primary key. First you need to fix the model, You can refer to the solution here How to create and handle composite primary key in JPA
I have the following Post class:
#Entity
#Table(name = "posts")
#Getter
#Setter
#JsonIdentityInfo( generator = ObjectIdGenerators.PropertyGenerator.class,
property = "id",
scope = Long.class)
public class Post {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
private String title;
private String subtitle;
private String content;
private String img_url;
#CreationTimestamp
private Timestamp created_on;
#UpdateTimestamp
private Timestamp last_updated_on;
#ManyToOne(fetch = FetchType.EAGER)
#JoinColumn(name = "owner_id", nullable=false)
#JsonIgnoreProperties({"hibernateLazyInitializer", "handler"})
private User creator;
}
And the following repository that extends JpaRepository
#Repository
public interface PostRepository extends JpaRepository<Post, Long> {
Optional<Post> findById(Long id);
List<Post> findAll();
}
When returning the result of findAll() inside the following controller, only the first creator item is sent completely and the rest just contain the id:
#GetMapping("/news")
public List<Post> getNews() {
return postRepository.findAll();
}
This is the JSON I get as result:
[
{"id":15,"title":"Title example #1","subtitle":"Subtitle example #1","content":"Lorem #1 ipsum dolor sit amet","img_url":null,"created_on":"2021-12-01T00:00:00.000+00:00","last_updated_on":"2021-12-01T00:00:00.000+00:00","creator":{"id":1,"username":"user-example","email":"blablabla#gmail.com","roles":[{"id":1,"name":"ROLE_USER"}]}}
,{"id":25,"title":"Title example #2","subtitle":"Subtitle example #2","content":"Lorem #2 ipsum dolor sit amet","img_url":null,"created_on":"2021-12-01T00:00:00.000+00:00","last_updated_on":"2021-12-01T00:00:00.000+00:00","creator":1}
]
Why is this happening? Is there a way I can get the whole child object for every element in the JSON array?
Thanks
EDIT: added the User class
#Entity
#Table( name = "users",
uniqueConstraints = {
#UniqueConstraint(columnNames = "username"),
#UniqueConstraint(columnNames = "email")
})
#DiscriminatorValue(value="USER")
public class User extends OwnerEntity {
#NotBlank
#NotNull
#Size(max = 20)
private String username;
#NotBlank
#NotNull
#Size(max = 50)
#Email
private String email;
#NotBlank
#Size(max = 120)
#JsonIgnore
private String password;
#CreationTimestamp
private Timestamp created_on;
#UpdateTimestamp
private Timestamp last_updated_on;
#ManyToMany(fetch = FetchType.LAZY)
#JoinTable( name = "user_roles",
joinColumns = #JoinColumn(name = "user_id"),
inverseJoinColumns = #JoinColumn(name = "role_id"))
private Set<Role> roles = new HashSet<>();
#ManyToMany(fetch = FetchType.LAZY)
private Set<Institution> institutions;
#OneToMany(mappedBy="creator", fetch = FetchType.LAZY, cascade = CascadeType.ALL)
protected Set<Post> posts;
#ManyToMany(fetch = FetchType.LAZY)
private Set<Institution> following;
}
EDIT 2: Added the OwnerEntity class
#Entity
#Table(name = "entities")
#Inheritance(strategy = InheritanceType.JOINED)
#DiscriminatorColumn
#Getter
#Setter
#JsonIdentityInfo( generator = ObjectIdGenerators.PropertyGenerator.class,
property = "id",
scope = Long.class)
public class OwnerEntity {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
protected Long id;
}
Your OwnerEntity also has #JsonIdentityInfo. In its reference documentation we can read the following:
Annotation used for indicating that values of annotated type or
property should be serializing so that instances either contain
additional object identifier (in addition actual object properties),
or as a reference that consists of an object id that refers to a full
serialization. In practice this is done by serializing the first
instance as full object and object identity, and other references to
the object as reference values.
This perfectly explains why you are getting the JSON like that. If you don't want this, just remove #JsonIdentityInfo but it might be there to fix an infinite recursion while serializing bidirectional relationships (you can read more about this in the following online resource https://www.baeldung.com/jackson-bidirectional-relationships-and-infinite-recursion).
I'm trying to have Spring Data JPA issue one query using joins to eagerly get a graph of entities:
#Entity
#NamedEntityGraph(name = "PositionKey.all",
attributeNodes = {#NamedAttributeNode("positionKey.account"),
#NamedAttributeNode("positionKey.product")
})
#Data
public class Position {
#EmbeddedId
private PositionKey positionKey;
}
#Embeddable
#Data
public class PositionKey implements Serializable {
#ManyToOne
#JoinColumn(name = "accountId")
private Account account;
#ManyToOne
#JoinColumn(name = "productId")
private Product product;
}
Here's my Spring Data repo:
public interface PositionRepository extends JpaRepository<Position, PositionKey> {
#EntityGraph(value = "PositionKey.all", type = EntityGraphType.LOAD)
List<Position> findByPositionKeyAccountIn(Set<Account> accounts);
}
This produces the following exception:
java.lang.IllegalArgumentException: Unable to locate Attribute with the the given name [positionKey.account] on this ManagedType
I want all of the accounts and products to be retrieved in one join statement with the positions. How can I do this / reference the embedded ID properties?
I would suggest refactoring the entity this way if it possible
#Entity
#NamedEntityGraph(name = "PositionKey.all",
attributeNodes = {#NamedAttributeNode("account"),
#NamedAttributeNode("product")
})
#Data
public class Position {
#EmbeddedId
private PositionKey positionKey;
#MapsId("accountId")
#ManyToOne
#JoinColumn(name = "accountId")
private Account account;
#MapsId("productId")
#ManyToOne
#JoinColumn(name = "productId")
private Product product;
}
#Embeddable
#Data
public class PositionKey implements Serializable {
#Column(name = "accountId")
private Long accountId;
#Column(name = "productId")
private Long productId;
}
Such an EmbeddedId is much easier to use. For instance, when you are trying to get an entity by id, you do not need to create a complex key containing two entities.
I have a problem with the historization of objects in the database.
the expected behavior of the save JpaRepository method is : Insert in the two tables idt_h and abo_h
But the current behavior is Insert in the idt_h table and update in the abo_h table.
#Data
#Entity
#Table(name = "ABO_H")
#AllArgsConstructor
#NoArgsConstructor
public class AboOP {
#Id
#Column(name = "ABO_ID")
private String id;
#Column(name = "ABO_STATUT")
private String statut;
#Column(name = "ABO_DATE_STATUT")
private Instant date;
#Column(name = "ABO_CoDE")
private String code;
#ManyToOne(cascade = CascadeType.ALL)
#JoinColumns({
#JoinColumn(name = "IDC_ID", referencedColumnName = "IDC_ID"),
#JoinColumn(name = "DATE_HISTO", referencedColumnName = "DATE_HISTO")
})
private IdtOP idtOP;
}
#Data
#Entity
#Table(name = "IDT_H")
#AllArgsConstructor
#NoArgsConstructor
public class IdtOP {
#AttributeOverrides({
#AttributeOverride(name = "id",
column = #Column(name = "IDC_ID")),
#AttributeOverride(name = "dateHisto",
column = #Column(name = "DATE_HISTO"))
})
#EmbeddedId
private IdGenerique idtId = new IdGenerique();
//Other fields
}
#Data
#AllArgsConstructor
#NoArgsConstructor
#Embeddable
public class IdGenerique implements Serializable {
private String id;
private Instant dateHisto;
}
I think that the class IdGenerique which groups the id and dateHisto is not well invoked for the table abo_h ??
thanks in advance
When you use the save() method, entityManager checks if the entity is new or not. If yes, the entity will be saved, if not, it'll be merged
If you implement your Entity Class with the inteface Persistable, you can override the method isNew() and make it returns True. In that case the save() method will persist, and not merge, your entity.
I have a class called Tag:
#Entity
#Table(name = "tags")
public class Tag {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
private String name;
#ManyToMany(fetch = FetchType.LAZY,
cascade = {
CascadeType.PERSIST,
CascadeType.MERGE
},
mappedBy = "tags")
private Set<Post> posts = new HashSet<>();
...
}
And a class called Post
#Entity
#Table(name = "posts")
public class Post {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
#ManyToMany(fetch = FetchType.LAZY,
cascade = {
CascadeType.PERSIST,
CascadeType.MERGE
})
#JoinTable(name = "post_tags",
joinColumns = { #JoinColumn(name = "post_id") },
inverseJoinColumns = { #JoinColumn(name = "tag_id") })
private Set<Tag> tags = new HashSet<>();
...
}
It creates another table named post_tags.
How can I write a Controller to access that table as it is not similar a repository?
Is there more easy and convenient way to implement ManyToMany relationship ?
My pom.xml
You don't need to access that relation table manually. You can load load all Tag entities, and then load all the referenced Post entities.
The relation table is enterily managed by your ORM frameork.
But, if you still want to access the relation table, you can use native queries in your Spring Data JPA repository, e.g.
#Query(value="select post_id, tag_id from post_tags", nativeQuery=true)
List<PostTag> loadPostTags();
PostTag class is not a jpa-managed entity and must match the structue of the returned table:
public class PostTag {
private long postId;
private long tagId;
// getter, setter
}
Use this way
#Entity
#Table(name = "tags")
public class Tag {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
private String name;
#ManyToMany(cascade = CascadeType.ALL)
#JoinTable(name = "post_tags",
joinColumns = { #JoinColumn(name = "id") },
inverseJoinColumns = { #JoinColumn(name = "post_id") })
private Set<Post> posts = new HashSet<>();
...
}
#Entity
#Table(name = "posts")
public class Post {
#Id
#Column(name = "post_id")
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long postId;
...
}