I have a table with the following columns: model_id, starts and end
I'm looking to run a query tath finds all the rows that matches the provided model_id and have a start bigger and end lower that the provided code. Example: if the provided code is 15 and the model_id is 5 I should get all the rows that have model_id = 5 and start >= 15 and end <= 15.
This is th query I'm working with:
DB::table('generations')->where([['model_id', '=', 1],['starts', '>=', '1998'], ['end', '<=', '1998']])->get();
I transformed this to the raw sql but the returned sql query does not get any results too.
I'm using Laravel 5.7
Rows with model_id = 1;
your logic's order is the problem.
DB::table('generations')->where('model_id', '=', 1)->where('start', '<=', 1995)->where('end' , '>=', 1995)->get();
Learn more in the documentation.
Related
I want to fetch data from database which has booking year is 2022, and the column I have is tanggal_take whose value format is 'Y-m-d', so I want to use SELECT * FROM table_name WHERE YEAR(tanggal_take) = "2022"; How to write it in laravel controller using Eloquent?
here is my code now
$data = Booking::join('users', 'users.id', '=', 'bookings.id_member')
->join('packages', 'packages.kode_paket', '=', 'bookings.kode_paket')
->where( DB::raw('YEAR(bookings.tanggal_take)'), '=', $request->range )
->get(['bookings.*', 'packages.*', 'users.*']);
The result is 0 but in database i have 4 datas with year 2022. I also already change ->where( DB::raw('YEAR(bookings.tanggal_take)'), '=', $request->range ) to ->whereYear('bookings.tanggal_take', '=', $request->range ) but still 0 result. Any hint? I will also looking for documentation by my self rn. Thanks
When querying a product code table I have the following
$results = Stock::orderBy('stk_physical', 'desc')->paginate(10);
This works fine on the initial load of 10 records but when a subsequent call is made for page 2 I get the following error
Incorrect syntax near 'offset'. (SQL: select * from [stock_records] order by [stk_physical] desc offset 10 rows fetch next 10 rows only)
I'm using Laravel 8.0 with SQL
You should append query string to the pagination like this
$results = Stock::orderBy('stk_physical', 'desc')->paginate(10);
$results->appends(["order_by" => "stk_physical"]);
This will append the &order_by=stk_physical to each link in the view and you can also use withQueryString() to take in consideration query string in future pagination like this
$results = Stock::orderBy('stk_physical', 'desc')->paginate(10)->withQueryString();
I want to run
SELECT count(DISTINCT `ASIN`) as results FROM crawl_results WHERE user_id = 1 and website_id = 1
and expect to get 136 results
However
`select('ASIN')->where('user_id', Auth::id())->where('website_id', $scanID)->distinct()->count();`
returns all rows in the table of 814
and
`select('ASIN')->where('user_id', Auth::id())->where('website_id', $scanID)->groupby('ASIN')->count();`
returns 8 results
First create model and use the below code where you require it
use App\CrawlResult;
CrawlResult::where('user_id',1)->where('website_id',1)->distinct('ASIN')->count('ASIN');
You should write query like this:
DB::table('crawl_results')
->select(DB::raw('COUNT(DISTINCT(ASIN)) as results')
->where('user_id', 1)
->where('website_id',1)
->get();
I want to retrieve data from 4 different table using laravel eloquent with multiple criteria.
an Overview of my table;
table 1
id
name
table 2
id
name
year
table1_id
table 3
id
name
description
table2_id
table 4
id
name
quarter
table3_id
below are their relations
table 1
hasMany -> table 2
table 2
belongsTo ->table1
HasMany->table2
table 3
belongsTo ->table2
HasMany->table3
table 4
belongsTo ->table3
I'd like to fetch the data by resource show with two parameters
and i tried this
$Report = Table1::whereHas('tabke1', function($query){
$query->where('year', 'like','%'.$year.'%');
})
->with('table2')->whereHas('table3', function($query){
$query->where('quarter', 'like', '%'.$quarters.'%');
})
->get();
but im receiving syntax error.
How can I retrieve the data from multiple table with multiple filter?
i tried this table query to understand more what i expect
SELECT `table1`.*, `table2`.*, `table3`.*, `table4`.*
FROM `table1`, `table2`, `table3`, `table4`
WHERE ((`table2`.* year = 2019) AND (`table4`.* quarter = 1))
I reckon there are two queries to achieve the results.
The first query is something like:
Table1::whereHas('table2', function ($query) {
$query->where('year', 2019);
})
->whereHas('table2.table3.table4', function ($query) {
$query->where('quarter', 1);
})
->get();
The second query is something like:
Table1::select('table1.*')
->join('table2', 'table1.id', '=', 'table2.table1_id')
->join('table3', 'table2.id', '=', 'table3.table2_id')
->join('table4', 'table3.id', '=', 'table4.table3_id')
->where('table2.year', 2019)
->where('table4.quarter', 1)
->distinct()
->get();
Regarding performance, I prefer the second query.
From Laravel 4 and Eloquent ORM - How to select the last 5 rows of a table, but my question is a little different.
How do I return last N records ordered in the way they were created (ASC).
So for example the following records are inserted in order:
first
second
third
fourth
fifth
I want a query to return last 2 records
fourth
fifth
Laravel Offset
DB::table('users')->skip(<NUMBER Calulation>)->take(5)->get();
You can calculate N by getting the count of the current query and skipping $query->count() - 5 to get the last 5 records or whatever you wanted.
Ex
$query = User::all();
$count = ($query->count()) - 5;
$query = $query->skip($count)->get();
In pure SQL this is done by using a subquery. Something like this:
SELECT * FROM (
SELECT * FROM foo
ORDER BY created_at DES
LIMIT 2
) as sub
ORDER BY created_at ASC
So the limiting happens in the subquery and then in the main query the order by is reversed. Laravel doesn't really have native support for subqueries. However you can still do it:
$sub = DB::table('foo')->latest()->take(2);
$result = DB::table(DB::raw('(' . $sub->toSql() . ') as sub'))
->oldest()
->get();
And if you use Eloquent:
$sub = Foo::latest()->take(2);
$result = Foo::from(DB::raw('(' . $sub->toSql() . ') as sub'))
->oldest()
->get();
Note the latest and oldest just add an orderBy('created_at) with desc and asc respectively.