I want to add AM/PM in 12hour time using ALTER SESSION.
ALTER SESSION SET nls_date_format='mm/dd/yyyy hh:mi:ss ';
Here's sample output dates
Date Modified
Closed Date
Date Assigned
5/17/2018 9:18:18 AM
5/17/2018 9:18:18 AM
5/16/2018 3:54:39 PM
Add the AM or PM format model and change YY to YYYY (you can also use HH12 to be explicit that you want a 12-hour clock):
ALTER SESSION SET nls_date_format='MM/DD/YYYY HH12:MI:SS AM';
If you do not want leading zeroes in then add the FM format model:
ALTER SESSION SET nls_date_format='FMMM/DD/YYYY HH12:MI:SS AM';
Related
I need to convert below timezone format in the following format:
Input:
2020-10-28T20:12:20.986Z
Output:
28-OCT-20 8:12 PM
I tried below query but I am unable to get timestamp with it. Please help.
select TO_TIMESTAMP(SUBSTR('2020-04-21T13:02:31.259Z',1,(INSTR('2020-04-21T13:02:31.259Z', 'T') - 1)),'YYYY-MM-DD HH24:MI:SS') from dual;
One option might be this
SQL> alter session set nls_timestamp_format = 'dd-MON-YY hh:mi PM' ;
Session altered.
SQL> select to_timestamp('2020-10-28T20:12:20.986Z','yyyy-mm-dd"T"hh24:mi:ss.ff3"Z"') from dual ;
TO_TIMESTAMP('2020-10-28T20:12:20.986Z','YYYY-MM-DD"T"HH24:MI:SS.FF3"Z"')
---------------------------------------------------------------------------
28-OCT-20 08:12 PM
SQL>
But if you rely better in the to_timestamp function without any session setting, then it is better
SQL> select to_timestamp('2020-10-28T20:12:20.986Z','yyyy-mm-dd"T"hh24:mi:ss.ff3"Z"') from dual ;
TO_TIMESTAMP('2020-10-28T20:12:20.986Z','YYYY-MM-DD"T"HH24:MI:SS.FF3"Z"')
---------------------------------------------------------------------------
28-OCT-20 08.12.20.986000000 PM
You have a timestamp string with a time zone, use TO_TIMESTAMP_TZ rather than TO_TIMESTAMP and then use TO_CHAR to format it:
SELECT TO_CHAR(
TO_TIMESTAMP_TZ(
'2020-04-21T13:02:31.259Z',
'YYYY-MM-DD"T"HH24:MI:SS.FFTZR'
),
'DD-MON-RR HH12:MI AM',
'NLS_DATE_LANGUAGE=American'
)
FROM DUAL;
db<>fiddle here
Note: DATE, TIMESTAMP and TIMESTAMP WITH TIME ZONE are binary data types and are stored in 7-20 bytes (1 byte each for century, year-of-century, month, day, hour, minute and second then up to 6 optional bytes for fractional seconds for TIMESTAMPs and up to 7-bytes for time zone for TIMESTAMP WITH TIME ZONE). It is never stored in any particular format.
How the DATE/TIMESTAMP data types are displayed is dependent on the client application that you are using to query the database; some may use the NLS settings for the user's session but others do not use that. If you want a particular format then convert the DATE/TIMESTAMP to a string using TO_CHAR.
I am trying to convert the date for one reporting project where I've got stuck with below:
select
UPDATED_DT, to_CHAR(UPDATED_DT,'MM-DD-YYYY HH24:MI:SS'), TO_DATE(to_CHAR(UPDATED_DT,'MM-DD-YYYY HH24:MI:SS'),'MM-DD-YYYY HH24:MI:SS')
from COMPANY;
Result:
28-03-18 09:11:34.000000000 PM 03-28-2018 21:11:34 28-03-2018 21:11:34
If you observe i am getting correct format with TO_CHAR, however i want the date in date data type. how can i achieve "MM-DD-YYYY HH24:MI:SS"?
Use this to set the format you want
ALTER SESSION SET NLS_DATE_FORMAT = 'MMDDYYYY HH24:MI:SS';
I'm just trying to fetch Hour of my table from created date in Oracle 12c Database but it is showing error INVALID EXTRACT FIELD FOR EXTRACT FIELD. kindly guide me to fetch hour of my date my code is here...
SELECT
EXTRACT( HOUR FROM (TO_CHAR(CREATED_DATE,'RRRR-MM-DD HH:MI:SS')) ) HOUR
FROM
INVOICE_V;
my Date is stored as 6/1/2020 4:04:50 PM in this format and Extract function is not accept this function.
Do not store dates as strings.
But, since you have, convert it from a string to a date using TO_DATE:
SELECT EXTRACT( HOUR FROM TO_TIMESTAMP(CREATED_DATE,'DD/MM/YYYY HH12:MI:SS AM') ) AS HOUR
FROM INVOICE_V;
If, however, you meant that its just displaying in that format (and is actually a DATE data type) then CAST the date to a timestamp:
SELECT EXTRACT( HOUR FROM CAST( CREATED_DATE AS TIMESTAMP) ) AS HOUR
FROM INVOICE_V;
An hour can not be used in the EXTRACT function.
The only way to extract hour is to use TO_CHAR or subtract it from TRUNC date as follows:
TO_CHAR(created_date,'HH24') -- OR 'HH' as per your requirement
-- OR
FLOOR(24*(created_date- TRUNC(created_date)))
Please note that Oracle does not store dates in any format. It has its own binary representation. What you see while selecting from the table is based on the NLS_DATE_FORMAT parameter.
You can set it according to your requirement.
ALTER SESSION SET NLS_dATE_FORMAT = 'YYYY-MM-DD HH24:MI:SS'; -- like this
If you have a date column (or the-like), then:
select extract(hour from cast(created_date as timestamp)) as hr
from invoice_v
Alternatively:
select to_char(created_date, 'hh24') as hr
from invoice_v
The first expression returns an integer number, while the second produces a string.
Note that hour is a language keyword, hence not a good choice for an identifier (here, you used it as a column alias). I changed that.
I have a date field in a table that contains date in dd-MMM-yy format .
I want to create a function that get this date check it for not null and then change it to yyyy/mm/dd format
but the problem is that oracle doesn't accept dd-MMM-yy formate date as a input parameter and
it say : Please Use yyyy-MM-dd date format !!!
how can I first change dd-MMM-yy formate to yyyy-MM-dd so oracle accept it as input then change it to yyyy/mm/dd
: Please Use yyyy-MM-dd date format !!!
That is no way related to an Oracle error.
I have a date field in a table that contains date in dd-MMM-yy format .
No, you are confused. Oracle does not store dates in the format you see. It stores it internally in 7 bytes with each byte storing different components of the datetime value.
Byte Description
---- -------------------------------------------------
1 Century value but before storing it add 100 to it
2 Year and 100 is added to it before storing
3 Month
4 Day of the month
5 Hours but add 1 before storing it
6 Minutes but add 1 before storing it
7 Seconds but add 1 before storing it
If you want to display, use TO_CHAR with proper FORMAT MODEL.
While inserting, use TO_DATE with proper FORMAT MODEL.
What you see as a format by default, is your locale specific NLS settings.
SQL> select parameter, value from v$nls_parameters where parameter='NLS_DATE_FORMAT';
PARAMETER VALUE
--------------- ----------------------------------------------------------------
NLS_DATE_FORMAT DD-MON-RR
SQL> select sysdate from dual;
SYSDATE
---------
03-FEB-15
SQL> select to_char(sysdate, 'mm/dd/yyyy hh24:mi:ss') from dual;
TO_CHAR(SYSDATE,'MM
-------------------
02/03/2015 17:59:42
SQL>
Update Regarding MMM format.
By MMM if you mean the month name up to three characters, then use MON.
My table has two DATE format attributes, however, when i try to insert value it throws an error: date format picture ends before converting entire input string.
Here is my attempted code:
insert into visit
values(123456, '19-JUN-13', '13-AUG-13 12:56 A.M.');
I think the problem is with 12:56 but Oracle documentation says date implies both date and time.
Perhaps you should check NLS_DATE_FORMAT and use the date string conforming the format.
Or you can use to_date function within the INSERT statement, like the following:
insert into visit
values(123456,
to_date('19-JUN-13', 'dd-mon-yy'),
to_date('13-AUG-13 12:56 A.M.', 'dd-mon-yyyy hh:mi A.M.'));
Additionally, Oracle DATE stores date and time information together.
you need to alter session
you can try before insert
sql : alter session set nls_date_format = 'YYYY-MM-DD HH24:MI:SS'
What you're trying to insert is not a date, I think, but a string. You need to use to_date() function, like this:
insert into table t1 (id, date_field) values (1, to_date('20.06.2013', 'dd.mm.yyyy'));
I had this error today and discovered it was an incorrectly-formatted year...
select * from es_timeexpense where parsedate > to_date('12/3/2018', 'MM/dd/yyy')
Notice the year has only three 'y's. It should have 4.
Double-check your format.