I am trying to get count of all rows from views in oracle schema and my code is working fine. But when i try to add a condition like where actv_ind = 'Y', i am unable to get it working. Any suggestions on how to modify the code to make it working?
SELECT view_name,
TO_NUMBER(extractvalue(xmltype(dbms_xmlgen.getxml('select count(*) cnt from '||owner||'.'||view_name||
'where'||view_name||'.'||'actv_ind= Y')),'/ROWSET/ROW/CNT')) as VIEW_CNT
FROM all_views
WHERE owner = 'ABC' AND view_name not in ('LINK$')
I am getting the error ACTV_IND : Invalid Identifier.
The error messages from DBMS_XMLGEN are not very helpful so you need to be very careful with the syntax of the SQL statement. Add a space before and after the where, and add quotation marks around the Y:
SELECT view_name,
TO_NUMBER(extractvalue(xmltype(dbms_xmlgen.getxml('select count(*) cnt from '||owner||'.'||view_name||
' where '||view_name||'.'||'actv_ind= ''Y''')),'/ROWSET/ROW/CNT')) as VIEW_CNT
FROM all_views
WHERE owner = 'ABC' AND view_name not in ('LINK$');
The query still assumes that every view contains the column ACTV_IND. If that is not true, you might want to base the query off of DBA_TAB_COLUMNS WHERE COLUMN_NAME = 'ACTV_IND'.
Here's a simple sample schema I used for testing:
create user abc identified by abc;
create or replace view abc.view1 as select 1 id, 'Y' actv_ind from dual;
create or replace view abc.view2 as select 2 id, 'N' actv_ind from dual;
Can you help me find the error here? I do not understand why it is not working..
CREATE TABLE Commande2 AS (SELECT * FROM Commande#lienBD_S1 WHERE numF NOT IN (SELECT numF FROM Fournisseur1#lienBD_S1));
When I execute the query without the CREATE TABLE like this
SELECT * FROM Commande#lienBD_S1 WHERE numF NOT IN (SELECT numF FROM Fournisseur1#lienBD_S1);
it works.
I found an other way to make it work !
I created a table Fournisseur2 That contain the the lines that are NOT IN Fournisseur1 and used it to create my table Commande2 like this :
CREATE TABLE Fournisseur2 AS (SELECT * FROM Fournisseur#lienBD_S1 WHERE ville <> 'Paris');
CREATE TABLE Commande2 AS (SELECT * FROM Commande#lienBD_S1 WHERE numF IN (SELECT numF FROM Fournisseur2));
I'm having an "Invalid Identifier" in Oracle because of the "B.username" (username column does exist in USER table). When i remove this, it's working fine. How to resolve this issue? I came from a MySQL background.
SELECT * FROM (SELECT qNA.assignment, qNA.regDate, B.username, (
SELECT DISTINCT NVL(idx, 0)
FROM EK_USERGRADE
WHERE year = (SELECT DISTINCT userGradeNo FROM EK_USER WHERE ID = qNA.userIdx)
) AS userGradeIdx
FROM EK_NEWTESTAPPLICANT qNA
WHERE IDX = :idx ) A
INNER JOIN EK_USER B ON (A.userIdx = B.ID)
Let's try this with a simplified version of your query:
-- test tables
create table NEWTESTAPPLICANT as select 1 useridx from dual ;
create table B as select 1 id, 'name1' username from dual ;
-- query
select *
from (
select B.username
from NEWTESTAPPLICANT qNA
) A join B on A.useridx = B.id ;
-- ORA-00904: "B"."USERNAME": invalid identifier
There's no "username" column in the NEWTESTAPPLICANT table, which causes the error. A LATERAL inline view (examples see here) may do the trick ...
-- query
select
*
from B, lateral (
select B.username
from NEWTESTAPPLICANT qNA
) A ;
-- result
ID USERNAME USERNAME
1 name1 name1
This works with Oracle 12c.
The problem is, that both your virtual table A and users B have the same column name "username". Specify alias in the main select, like "Select A.* , B.* from(...".
Is it ORA-00903?
User is a reserved word are you sure you created this table? Table name cannot be a reserved word.
I am new in oracle and I want to update multiple row value where the column id = 1 , 2.
I tried this :
update Tester
set employee_phone_number = ( 0789456123,0789456321)
where employee_id in (1,2);
but it gives me "missing right parenthesis"
any help please and thanks in advance.
Another approach:
merge into
tester
using (
select 1 id,'0123456785' employee_phone_number from dual union all
select 2 id,'0123456786' employee_phone_number from dual) new_values
on (
tester.id = new_values.id)
when matched then update
set employee_phone_number = new_values.employee_phone_number;
More words, but allows the values to be specified in only one place and extends to allow inserts where the id does not already exist.
http://sqlfiddle.com/#!4/8fc86/3
Try this instead:
update Tester
set employee_phone_number = CASE WHEN employee_id = 1 THEN 0789456123
WHEN employee_id = 2 THEN 0789456321
END
where employee_id in (1,2);
I've inherited a schema so don't have complete knowledge/confidence in what is there.
I have a project table with a projectId. There are a whole bunch of other tables that reference this table by project id. What I want to do is run a query to establish:
Which tables have foreign key references to the project table on
the project id
Which tables have a column called project id (in
case foreign keys are not set up).
If it was SQL Server I know how to query the metadata but how do I do this in Oracle?
1)
select table_name
from all_constraints
where r_constraint_name = [your pk/uk constraint on PROJECTS(id)]
2)
select table_name
from all_tab_columns
where column_name = 'PROJECT_ID'
You may want to add an extra predicate containing the OWNER column.
Regards,
Rob.
Ok. Here a request that give you the referenced table and column :
SELECT
c_list.CONSTRAINT_NAME as NAME,
substr(c_src.COLUMN_NAME, 1, 20) as SRC_COLUMN,
c_dest.TABLE_NAME as DEST_TABLE,
substr(c_dest.COLUMN_NAME, 1, 20) as DEST_COLUMN
FROM ALL_CONSTRAINTS c_list, ALL_CONS_COLUMNS c_src, ALL_CONS_COLUMNS c_dest
WHERE c_list.CONSTRAINT_NAME = c_src.CONSTRAINT_NAME
AND c_list.OWNER = c_src.OWNER
AND c_list.R_CONSTRAINT_NAME = c_dest.CONSTRAINT_NAME
AND c_list.OWNER = c_dest.OWNER
AND c_list.CONSTRAINT_TYPE = 'R'
AND c_src.OWNER = '<your-schema-here>'
AND c_src.TABLE_NAME = '<your-table-here>'
GROUP BY c_list.CONSTRAINT_NAME, c_src.TABLE_NAME,
c_src.COLUMN_NAME, c_dest.TABLE_NAME, c_dest.COLUMN_NAME;
Which give you something like this:
NAME |SRC_COLUMN |DEST_TABLE | DEST_COLUMN
----------------------|----------------|----------------------|-----------
CFK_RUB_FOR |FOR_URN |T03_FORMAT |FOR_URN
CFK_RUB_RUB |RUB_RUB_URN |T01_RUBRIQUE |RUB_URN
CFK_RUB_SUP |SUP_URN |T01_SUPPORT |SUP_URN
CFK_RUB_PRD |PRD_URN |T05_PRODUIT |PRD_URN
You can forget the substr() function if the result is usable without. This is not my case.
1): SELECT * FROM USER_CONSTRAINTS WHERE CONSTRAINT_NAME='R' and R_CONSTRAINT_NAME='xxx'
where xxx is the name of the primary key constraint on the project table
2): SELECT * FROM USER_TAB_COLUMNS WHERE COLUMN_NAME='PROJECT_ID'
The r_constraint_name answers here didn't seem to work for me, not sure why as I'm new to Oracle myself, but this worked:
SELECT * FROM ALL_CONSTRAINTS WHERE CONSTRAINT_NAME = '<constraint>';
My problem was slightly different. I have a table and I wanted to programatically know which other tables/columns it references.
I started with Stan's response above but this didn't give me exactly what I needed, so I came up with this, which I post here in case anyone else has my problem:
WITH src as
(SELECT ac.table_name, ac.constraint_name, accs.column_name, accs.position, ac.r_constraint_name
FROM ALL_CONSTRAINTS ac, all_cons_columns accs
WHERE ac.owner = '<owner>'
AND ac.constraint_type = 'R'
AND ac.table_name = '<src_table>'
AND accs.owner = ac.owner
AND accs.table_name = ac.table_name
AND accs.constraint_name = ac.constraint_name
ORDER BY ac.table_name, ac.constraint_name, accs.position),
dst as
(SELECT ac.table_name, ac.constraint_name, accs.column_name, accs.position
FROM ALL_CONSTRAINTS ac, all_cons_columns accs
WHERE ac.owner = '<owner>'
AND accs.owner = ac.owner
AND accs.table_name = ac.table_name
AND accs.constraint_name = ac.constraint_name
ORDER BY ac.table_name, ac.constraint_name, accs.position)
SELECT src.table_name as src_table,
dst.table_name as dst_table,
src.constraint_name as src_constraint,
src.column_name as src_column,
dst.column_name as dst_column,
src.position as position
FROM src,dst
WHERE src.r_constraint_name = dst.constraint_name
AND src.position = dst.position
Use this query.
select b.TABLE_NAME,b.CONSTRAINT_NAME ,a.COLUMN_NAME
from all_constraints b, all_cons_columns a
where r_constraint_name = 'Constraint_Name' and a.CONSTRAINT_NAME=b.CONSTRAINT_NAME;