All:
Quickly and succinctly, I have many many files named as such:
lorem(12312315).txt
ipsum(578938-12-315-13-416-4).txt
amet(ran-dom-guid).txt
And I want to rename them to what's inside the parentheses dot text, like so:
12312315.txt
578938-12-315-13-416-4.txt
randomguid.txt
I'm sure a mix of sed, awk, grep, etc will do it, but commenting out the parentheses from the shell is throwing me. I cant come up with a string that will do it.
If anyone is kind enough to share a few thought cycles and help me, it would be a lovely Karma gesture!
Thanks for reading!
-Jim
Another flavor:
find . -type f -name \*\(\*\).txt -print0 | xargs -0 sh -c '
for filename ; do
basename_core="${filename##*(}"
basename_core="${basename_core%%)*}"
mv "${filename}" "${basename_core}".txt
done' dummy
This might work for you (GNU sed and shell);
sed -n 's/.*(\(.*\)).*/mv '\''&'\'' '\''\1.txt'\''/p' *.txt
This will print out a list of move commands, after you have validated they are correct, pipe to shell:
sed -n 's/.*(\(.*\)).*/mv '\''&'\'' '\''\1.txt'\''/p' *.txt | sh
find and mv can handle this, with a bash rematch to find your names;
#!/bin/bash
touch lorem\(12312315\).txt
touch ipsum\(578938-12-315-13-416-4\).txt
touch amet\(ran-dom-guid\).txt
pat=".*\((.*)\).txt"
for f in $(find . -type f -name "*.txt" ); do
if [[ $f =~ $pat ]]; then
mv $f ${BASH_REMATCH[1]}.txt
fi
done
ls *.txt
A for loop and Parameter Expansion.
#!/usr/bin/env bash
for f in *\(*\)*.txt; do
temp=${f#*\(}
value=${temp%\)*}
case $value in
*[!0-9-]*) value="${value//-}";;
esac
echo mv -v "$f" "$value.txt"
done
Remove the echo if you're satisfied with the output, so mv can rename/move the files.
Thank you everyone for the responses! I ended up using a mishmash of your suggestions and doing something else entirely, but I'm posting here for posterity...
The files all had one thing in common, the GUID contained in the filename was also always contained in line 2 of the accompanying file, so I yank lane two, strip out the things that are NOT the guid, and rename the file to that string, for any .xml file in the directory where the script is run.
as such:
for i in ./*xml
do
GUID=`cat "$i" | sed -n '2p' | awk '{print $1}' | sed 's/<id>//g' | sed 's/<\/id>//'`
echo File "|" $i "|" is "|" $GUID
done
In the actual script, I do a MV instead of an ECHO and the files are renamed to the guid.
Hopefully this helps someone else in the future, and yes, I know it's wasteful to call sed three times. If I were better with regular expressions, I'm sure I could get that down to one! :)
Thanks!
Related
In bash, I have list of files all named the same (in different sub directories) and I want to order them by creation/modified time, something like this:
ls -1t /tmp/tmp-*/my-file.txt | xargs ...
I would like to rename those files with some sort of index or something so I can move them all into the same folder. My result would ideally be something like:
my-file0.txt
my-file1.txt
my-file2.txt
Something like that. How would I go about doing this?
You can just loop through these files and keep appending an incrementing counter to desired file name:
for f in /tmp/tmp-*/my-file.txt; do
fname="${f##*/}"
fname="${fname%.*}"$((i++)).txt
mv "$f" "/dest/dir/$fname"
done
EDIT: In order to sort listed files my modification time as is the case with ls -1t you can use this script:
while IFS= read -d '' -r f; do
f="${f#* }"
fname="${f##*/}"
fname="${fname%.*}"$((i++)).txt
mv "$f" "/dest/dir/$fname"
done < <(find /tmp/tmp-* -name 'my-file.txt' -printf "%T# %p\0" | sort -zk1nr)
This handles filenames with all special characters like white spaces, newlines, glob characters etc since we are ending each filename with NUL or \0 character in -printf option. Note that we are also using sort -z to handle NUL terminated data.
So I found an answer to my own question, thoughts on this one?
ls -1t /tmp/tmp-*/my-file.txt | awk 'BEGIN{ a=0 }{ printf "cp %s /tmp/all-the-files/my-file_%03d.txt\n", $0, a++ }' | bash;
I found this from another stack overflow question looking for something similar that my search didn't find at first. I was impressed with the awk line, thought that was pretty neat.
I have three files in a directory that has the structure like this:
file.exe.trace, file.exe.trace.functions and file.exe.trace.netlog
I want to know how can I get file.exe as file name?
In other world I need to get file name that has the .trace extension? I should note that as you can see all the files has the .trace part.
If $FILENAME has the name, the root part can be gotten from ${FILENAME%%.trace*}
for FILENAME in *.trace; do
echo ${FILENAME%%.trace*}
done
You can also use basename:
for f in *.trace; do
basename "$f" ".trace"
done
Update: The previous won't process files with extra extensions besides .trace like .trace.functions, but the following sed will do:
sed -r 's_(.*)\.trace.*_\1_' <(ls -c1)
You can also use it in a for loop instead:
for f in *.trace*; do
sed -r 's_(.*)\.trace.*_\1_' <<< "$f"
done
Try:
for each in *exe*trace* ; do echo $each | awk -F. '{print $1"."$2}' ; done | sort | uniq
The script works as far as renaming the files but it moves the renamed files out of their respective folders.
I would like it to not move them but only rename them and I have failed after a few days of trying. I know this code is a mess and there is unneeded code in it but it nearly works.
Also the renamed file isn’t getting an extension of .txt but that isn't really an issue for me. I just want to see the "Dynamic Range Value" that is taken from inside the file as the file name so I don’t have to open every file (a couple thousand albums worth) to see what the DR is. Here is the code:
#!/bin/bash
cd /media/Storage/MusicWorks/Processing
find . -name 'dr14.txt' | while IFS=$'\n' read -r i
do mv -n "$i" `egrep -m1 -e 'Official DR value:' "$i" | sed -e 's/Official DR value://'`;
echo "Done"
done
I run this script from the terminal with a bash alias.
I have reservations about the egrep | sed part of your script, but if they work for you, so be it. You need to preserve the pathname of the file, for example like this:
find . -name 'dr14.txt' |
while IFS=$'\n' read -r i
do
newname="${i%/*}"/$(egrep -m1 -e 'Official DR value:' "$i" | sed -e 's/Official DR value://');
mv -n "$i" "$newname"
echo "Done $i ($newname)"
done
The ${i%/*} notation removes anything from the last slash to the end of the name in $i. Since all the names from find will start with ./, this is secure enough; it would not work well on absolute names such as / and /unix (the output would be the empty string, but /usr/bin/sh would be fine).
Under a little prompting by tripleee in a comment, it is possible to simplify the egrep | sed part of the code to:
newname="${i%/*}"/$(sed -n -e '/Official DR value:/{s///p;q;}' "$i");
The second semicolon is needed with BSD sed but not with GNU sed.
Need help on writing a bash script that will rename files that are being outputted as file name.suffix.date I need these files to be rewritten as name.date.suffix instead.
Edited:
Changed suffix from date to ~
Here's what I have so far:
find . -type f -name "*.~" -print0 | while read -d $'\0' f
do
new=`echo "$f" | sed -e "s/~//"`
mv "$f" "$new"
done
This changes the suffix back to original but can't figure out how to get the date to be named before the extension (fname??)
You can use regular expression matching to pull apart the original file name:
find . -type f -name "*.~" -print0 | while read -d $'\0' f
do
dir=${f%/*}
fname=${f##*/}
[[ $fname =~ (.+)\.([^.]+)\.([^.]+)\.~$ ]] || continue
name=${BASH_REMATCH[1]}
suffix=${BASH_REMATCH[2]}
d=${BASH_REMATCH[3]}
mv "$f" "$dir/$name.$d.$suffix"
done
Bash-only solution:
while IFS=. read -r -u 9 -d '' name suffix date tilde
do
mv "${name}.${suffix}.${date}.~" "${name}.${date}.${suffix}"
done 9< <(find . -type f -name "*.~" -print0)
Notes:
-d '' gives you the same result as -d $'\0'
Splits file names by the dots while reading them. Of course this means it would break if there are dots anywhere else.
Should otherwise work with pretty much any filenames, including those containing space, newlines and other funny business.
create a list of the files first and redirect to a file.
ls > fileList.txt
Open the file and read line by line in Perl. Use a regex to match the parts of the files and capture them like this
my ($fileName,$suffix,$date)=($WholeFileName=~/(.*)\.(.*)\.(.*)/);
This should capture the three seperate variables for you. Now all you need to do is move the old file to the new file name. The new file name will be a concatenation of the above three variables that you have got. $newFileName=$fileName. ".".$date.".".$suffix. If you have a sample fileName post a comment and I can reply with a short script. Perl is not the only way. You could just use bash or awk and find alternate ways to do this.
cut each part of your filenames:
FIN=$(echo test.12345.ABCDEF | sed -e 's/[a-zA-Z0-9]*[\\.][a-zA-Z0-9]*[\\.]//')
DEBUT=$(echo test.12345.ABCDEF | sed -e 's/[\\.][a-zA-Z0-9]*[\\.][a-zA-Z0-9]*//')
MILIEU=$(echo test.12345.ABCDEF | sed -e 's/'${FIN}'//' -e 's/'${DEBUT}'//' -e 's/[\.]*//g')
paste each part as expected:
echo ${DEBUT}.${FIN}.${MILIEU}
rename --no-act 's/\(name-regex\).\(suffix-regex\).\(date-regex\)/\1.\3.\2' *
Tweak the three regexes to fit your file names, and remove --no-act when you're happy with the result to actually rename the files.
I am trying to create a small Bash script to remove hyphens from a filename. For example, I want to rename:
CropDamageVO-041412.mpg
to
CropDamageVO041412.mpg
I'm new to Bash, so be gentle :] Thank you for any help
Try this:
for file in $(find dirWithDashedFiles -type f -iname '*-*'); do
mv $file ${file//-/}
done
That's assuming that your directories don't have dashes in the name. That would break this.
The ${varname//regex/replacementText} syntax is explained here. Just search for substring replacement.
Also, this would break if your directories or filenames have spaces in them. If you have spaces in your filenames, you should use this:
for file in *-*; do
mv $file "${file//-/}"
done
This has the disadvantage of having to be run in every directory that contains files you want to change, but, like I said, it's a little more robust.
FN=CropDamageVO-041412.mpg
mv $FN `echo $FN | sed -e 's/-//g'`
The backticks (``) tell bash to run the command inside them and use the output of that command in the expression. The sed part applies a regular expression to remove the hyphens from the filename.
Or to do this to all files in the current directory matching a certain pattern:
for i in *VO-*.mpg
do
mv $i `echo $i | sed -e 's/-//g'`
done
A general solution for removing hyphens from any string:
$ echo "remove-all-hyphens" | tr -d '-'
removeallhyphens
$
f=CropDamageVO-041412.mpg
echo "${f//-}"
or, of course,
mv "$f" "${f//-}"