I have 2 tables :
Table_A
USERCODE|USERMOBILE|USERACCOUNT
001 |0123236556|ACC001
002 |0222222222|ACC002
Table_B
USERCODE|USERMOBILE
001 |0123236556
001 |0444444444
002 |0555555555
I want following output, which filter by Table_A.ACCOUNT
For example USERACCOUNT = ACC001
USERCODE|USERMOBILE
001 |0123236556
001 |0123236556
001 |0444444444
I try with following query but not work :
with tbl as
(select USERCODE,USERMOBILE from Table_A WHERE USERACCOUNT='ACC001' )
select * from tbl
union
select USERCODE,USERMOBILE from Table_B WHERE Table_B.USERCODE = tbl.USERCODE
Error : Invalid identifier : tbl.USERCODE
Are there any way to achive my expected result?
When you use UNION ALL can't refer to the 1st query from the 2nd query.
Use the CTE:
WITH cte(USERCODE, USERMOBILE) AS
(SELECT USERCODE, USERMOBILE FROM Table_A WHERE USERACCOUNT = 'ACC001')
SELECT USERCODE, USERMOBILE FROM cte
UNION ALL
SELECT USERCODE, USERMOBILE
FROM Table_B
WHERE USERCODE = (SELECT USERCODE FROM cte)
If the CTE may return more than 1 rows, change to:
WHERE USERCODE IN (SELECT USERCODE FROM cte)
There is no way to achieve the desired result you have to use Join -
SELECT USERCODE, USERMOBILE
FROM Table_A
WHERE USERACCOUNT='ACC001'
UNION
SELECT USERCODE, USERMOBILE
FROM Table_B B
JOIN Table_A A ON B.USERCODE = A.USERCODE
Related
Just wondering why the following select isn't working:
SELECT
A.FIELD1
, (SELECT PCN FROM (select B.PRIORITY, B.PCN
from
TABLE2 B
WHERE B.CUST= A.CUST
ORDER BY B.PRIORITY)
WHERE ROWNUM = 1) AS PCN
FROM TABLE1 A;
ERROR at line 2: ORA-00904: "A"."CUST": invalid identifier
Important to mention:
TABLE1 has as fields FIELD1, CUST.
TABLE2 has as fields PCN, PRIORITY, CUST.
Thanks in advance.
Your query shouldn't give you that error message, on when you remove the outer qiery this would happen
CREATE tABLE TABLE1 (FIELD1 int, CUST int)
INSERT INTO TABLE1 VALUES(1,1)
1 rows affected
CREATE TABLE TABLE2 (PCN int, PRIORITY int, CUST int)
INSERT INTO TABLE2 VALUES (1,1,1)
1 rows affected
SELECT
A.FIELD1
, (SELECT PCN FROM (select B.PRIORITY, B.PCN
from
TABLE2 B
WHERE B.CUST= A.CUST
ORDER BY B.PRIORITY)
WHERE ROWNUM = 1) AS PCN
FROM TABLE1 A;
FIELD1
PCN
1
1
fiddle
You can't nest inline selects (more than one level) without losing the ability of the inner nested selects being able to reference the parent block. So your query on TABLE2 cannot see the columns from TABLE1 because of this nesting.
Try this:
SELECT a.field1,
pcn.pcn
FROM table1 a,
(SELECT b.cust,
b.priority,
b.pcn,
ROW_NUMBER() OVER (PARTITION BY b.cust ORDER BY b.priority DESC) seq
FROM table2 b) pcn
WHERE a.cust = pcn.cust(+)
AND pcn.seq(+) = 1
That will work well for report queries. If you end up adding a filter on a specific customer, then you would be better off using OUTER APPLY if you have a recent-enough version of Oracle that supports that.
You could try this:
SELECT
A.FIELD1
, (SELECT B.PCN
from
TABLE2 B
WHERE B.CUST= A.CUST
ORDER BY B.PRIORITY
FETCH FIRST 1 ROWS ONLY) AS PCN
FROM TABLE1 A;
FETCH FIRST 1 ROWS ONLY gets you the first ordered record. Works on 12c and up and supports nesting, and no 2nd subquery needed.
Yet another option might be a CTE.
Sample data:
SQL> with
2 table1 (field1, cust) as
3 (select 1, 100 from dual union all
4 select 2, 200 from dual
5 ),
6 table2 (pcn, priority, cust) as
7 (select 10, 1, 100 from dual union all
8 select 20, 2, 100 from dual union all
9 select 30, 1, 200 from dual
10 ),
Query begins here. Rank rows by priority, and then fetch the ones that rank as the highest (line #20):
11 temp as
12 (select a.field1,
13 b.pcn,
14 rank() over (partition by a.field1 order by b.priority desc) rnk
15 from table1 a join table2 b on a.cust = b.cust
16 )
17 select field1,
18 pcn
19 from temp
20 where rnk = 1;
FIELD1 PCN
---------- ----------
1 20
2 30
SQL>
You may use first aggregate function to achieve the same (assuming that you have completely deterministic order by) functionality without nested subquery:
select
a.field1
, (
select max(b.pcn) keep(dense_rank first order by b.priority)
from table2 b
where b.cust = a.cust
) as pcn
from table1 a
which for this sample data
insert into table1 values(1,1);
insert into table1 values(2,2);
insert into table2 values(1,1,1);
insert into table2 values(2,2,1)
returns
FIELD1
PCN
1
1
2
(null)
SQL fiddle
I have a query two tables - TableA , TableB
Query :
select a.name, count(b.code)
from tableA a
join tableA b on b.id = a.id
where a.name = ('AA','BB','WWW')
group by a.name;
The data is available only for AA so it displays the result as
AA 5
But i want to display the data as :
AA 5
BB 0
WWW 0
You can collect expected names into separate table/subquery and then perform a left join with your data tables like
with exp_names as (
select 'AA' name from dual
union all
select 'BB' from dual
union all
select 'WWW' from dual
)
select en.name, count(b.code)
from exp_names en
left join tableA a on en.name = a.name
left join tableB b on b.id = a.id
group by en.name;
fiddle
My query result is a union of several queries. I am facing the below error when I use WITH clause within a union. Any ideas why?
select column1 from TABLE_A
union
with abcd as (select * from TABLE_B)
select column2 from TABLE_A A, abcd
where abcd.m_reference = A.m_reference
ORA-32034: unsupported use of WITH clause
32034. 00000 - "unsupported use of WITH clause"
*Cause: Inproper use of WITH clause because one of the following two reasons
1. nesting of WITH clause within WITH clause not supported yet
2. For a set query, WITH clause can't be specified for a branch.
3. WITH clause can't sepecified within parentheses.
*Action: correct query and retry
Encapsulate your WITH statement in a dummy select.
select column1 from TABLE_A
union
select * from (
with abcd as (select * from TABLE_B)
select column2 from TABLE_A A, abcd
where abcd.m_reference = A.m_reference
)
Just define the CTE first, before the actual UNION query. Then use it as you would a regular table:
with abcd as (select * from TABLE_B)
select column1 from TABLE_A
union
select column2
from TABLE_A A
inner join abcd
on abcd.m_reference = A.m_reference
You can use multiple CTE as follows:
with cte1 AS (...),
cte2 AS (...)
select * from ...
Encapsulating it is the way to go if you have multiple WITHs; for example I just had to do this monstrosity to quickly pull in data from ID numbers from an Excel sheet
select * from (
with childvendor as (
select vendornumber, name From vendor where vendornumber = '0000800727'
)
select
v.vendornumber as parentvendor,
v.name as parentname,
cv.vendornumber as childvendor,
cv.name as childname
From
vendor v, childvendor cv
where
v.vendornumber = '0000800004'
)
UNION ALL
select * from (
with childvendor as (
select vendornumber, name From vendor where vendornumber = '0000800042'
)
select
v.vendornumber as parentvendor,
v.name as parentname,
cv.vendornumber as childvendor,
cv.name as childname
From
vendor v, childvendor cv
where
v.vendornumber = '0000800035'
)
And so on
I am trying to write oracle subquery in Hibernate criteria but unable to do it. Can anyone help me to achieve this. Below is my oracle query.
SELECT a.id,
b.address
FROM tableA a
INNER JOIN TABLE b
ON a.id = b.id
WHERE mainId IN
(SELECT bp.ptyID
FROM bpTable bp,
busHeaderbh bh
WHERE bh.aid = bp.aid
AND bh.parentBID IN
(SELECT bp.ptyID
FROM bpTable bp,
busHeaderbh bh
WHERE bh.aid = bp.aid
AND bh.parentBID = 123
UNION
SELECT 123 FROM dual
)
UNION
SELECT 123 FROM dual
)
AND
GROUP BY a.id,
b.credttm
ORDER BY a.id DESC;
Thanks in Advance.
I have written one example for one to many relationship table
you can get reference from it
Criteria person = session.getCurrentSession().createCriteria(Person.class).createAlias("personId", "personId");
person.add(Restrictions.disjunction().add(Restrictions.ilike("PersonFirstname",Search,MatchMode.ANYWHERE))
.add(Restrictions.ilike("personId.prop1",Search,MatchMode.ANYWHERE))
.add(Restrictions.ilike("personId.col1",Search,MatchMode.ANYWHERE))
.addOrder(Property.forName("colName").desc()
.addOrder(Property.forName("colName").asc());
The Table_B contains duplicate records as seen below. What I am trying to do is lookup Table_A using Table_B.SERIAL_NUM and update Table_A .COVERAGE_END coloumn with the most recent Date value in COVERAGE_TO coloumn in Table_B.
Table_B
SERIAL_NUM ,COVERAGE_FROM ,COVERAGE_TO
123456 ,26/12/2014 ,13/12/2015
123456 ,14/12/2015 ,13/12/2016
23456 ,18/12/2014 ,13/12/2015
23456 ,14/12/2015 ,13/12/2016
Following is the update statement I am using.
update Table_A J
set ( J.COVERAGE_END_DATE)
=(select COVERAGE_TO from
(
select SERIAL_NUM, COVERAGE_TO, row_number() over(partition by SERIAL_NUM order by COVERAGE_TO desc) as rn from TABLE_B B
)where rn = 1
)
where exists
(
select * from TABLE_B Q where Q.SERIAL_NUM = J.SERIAL_NUMBER
)
;
However I get the following error
ORA-01427: single-row subquery returns more than one row
Can Some one please help me with this Query?
You have to compare J's SERIAL_NUMBER with B's to get the only proper value.
where rn = 1 and J.SERIAL_NUMBER = SERIAL_NUM
If not, subquery will return max values for every SERIAL_NUM.
I'm not sure why partitioning is needed here.
Would a simple MAX() not produce the needed result?
update table_a
set coverage_end_date = (
select max(coverage_to)
from table_b b inner join table_a a on b.serial_num = a.serial_num
)
;