I have many files in a folder with different extensions (.txt, .ascii, .mat). I want to move them to the destination folder which would be same as file names.
For example:
I have files like a.txt, a.ascii, b.txt, b.ascii, b.mat.
I want to make folder first in the name of a and b, then I want to move files a.txt,a.ascii to folder a and b.txt,b.ascii,b.mat to folder b.
I tried the code as follows. However I need an automatic way to make folder and move the files to it.
#!/bin/sh
mkdir a b
for file in $(<list.txt)
do
cp "$file" a
done
Seems that this Bash script can do the job
#!/usr/bin/env bash
for file in $(<list.txt); do
dirn="${file%.*}"
mkdir -p "$dirn"
cp "$file" "$dirn"
done
Related
I have a text file called "list.txt" that contain all the directories of the files that need to be copied to a new folder (dir_newfolder). I wrote the code like below:
for file in $(cat list.txt); do cp ${file} dir_newfolder; done
I got list of errors: cp:"file_name":No such file or directory. The file_names are the lines pulled out from the "list.txt". But when I copy each file_names from the error message and use cp to copy to the new folder. There is no error.
I am using mac os terminal.
Thanks in advance.
Copy a file or folder locally
In the Terminal app on your Mac, use the cp command to make a copy of a file.
For example, to copy a folder named Expenses in your Documents folder to another volume named Data:
% cp -R ~/Documents/Expenses /Volumes/Data/Expenses
The -R flag causes cp to copy the folder and its contents. Note that the folder name does not end with a slash, which would change how cp copies the folder.
in your case:
make sure you are providing correct path list.txt and the correct path for destiny folder, also i mentioned how to access file variable in double quotes , try this code it's working for me
for file in $(cat ~/Documents/list.txt); do cp "$file" ~/dir_newfolder; done
I need to rename files in multiple directories to the name of the parent directory and move them up one directory and the delete the empty directories.
Sample structure:
/export
exp_20210101
3747-46473-328383-5555
exp_20210102
4533-45323-354345-5366
Desired result:
/export
exp_20210101
exp_20210102
3747-46473-328383-5555 renamed to exp_20210101
No extensions (Linux)
I prefere to do it with a bash script.
Already tried several samples (similar questions), but they're not working for my case.
I need to rename files in multiple directories to the name of the parent directory and move them up one directory and the delete the empty directories.
I don't think that's possible, you can't have a regular file and a directory with the same name in the same directory.
You should move each file to the same level as its parent without changing its name instead (assuming a file with the same name may not exist there). Then you can remove the parent and rename the file to its name.
for f in /export/*/*; do
echo mv "$f" "${f%/*/*}"
echo rmdir "${f%/*}"
echo mv "${f%/*/*}/${f##*/}" "${f%/*}"
done
Drop echos if the output looks good.
I have two folder xyz and Bin. I want to move xyz directory and it's sub directory as well to Bin folder.
I want output like this:
Bin/xyz/q.html
/images/0.gif
How can do move files and subdirectory and I will get that type of output.
Move (mv) can be thought of as rename. If mv is used to move a file from one drive to another, then a copy will be made and the original will be deleted.
If the file is a directory (folder), then all of the contents of that directory are also moved.
$ mv -v xyz Bin
moves the file called xyz, no matter what kind of file it is, even if it is a directory, into the existing directory called Bin. If Bin does not exist, then the move command will rename xyz to Bin.
If you only want to move a few files, for example, Bin/1.html is to be moved to Bin/xyz/1.html, then file being moved is a file called 1.html (not a directory called bin or xyz).
$ mv -v Bin/1.html Bin/xyz/1.html
will perform the move if the Bin/xyz exists and is a directory. If directory Bin/xyz does not exist, then this mv command will error because mv does not create parent destination directories.
$ mkdir -v Bin/xyz
will create an empty directory called xyz in an existing directory called Bin. Then files can be moved into the existing Bin/xyz directory.
The -v (--verbose) tells mv and mkdir to report what happened. The output that they produce given a success is what -v does. The most common way to list the content of a directory is ls, but the indentation that you desire will require some programming.
$ man mv
$ man mkdir
will show all the features of the mv an mkdir commands.
The title not might be the best, I apologize, I'm rather new to scripting.
I'm trying to copy 2 files from each directory and place these compounds in a separate directory that only shares directory names.
for clarity;
/path/to/directory/all/variable_directories/
Inside this directory will be multiple files, I need 2 files which will have the same name in every individual variable directory.
I am trying to copy these 2 files from each individual variable directory and put them in variable directories based on the basename of /variable_directory/
the copy destination will be;
/path/to/magical/shit/subset/set_with_variable_name/variable_directories/
Only some of the destination directories are located in each /set_with_variable_name/
The script will need to be able to go through each /set_with_variable_name/ until it finds the directory that shares the basename of the directory that these files are originally being cp'd from
There's about 100 directories
to cp from and to and about 200 files total that need to be copied and sorted appropriately.
I can get it to cp ALL the files to the SAME directory using;
#! /usr/bin/env bash
for i in */;
do cd $i;
cp filename /path/to/destination/;
cp other_filename /path/to/destination/;
cd ..;
done;
It's the sorting the files to the correct destinations that I am completely lost at.
I appreciate any help, I'm a novice to this type of scripting
Looks like you need something like that.
# looping through all the variable directories
for var_dir in <path1>/all/*; do
# creating the destination directory if not exists
mkdir -p "<path2>/set_with_variable_name/$(basename ${var_dir})"
# copying the first file
cp "${var_dir}/filename1" "<path2>/set_with_variable_name/$(basename ${var_dir})/filename1"
# and the second
cp "${var_dir}/filename2" "<path2>/set_with_variable_name/$(basename ${var_dir})/filename2"
done
i have downloaded several pdf files(with various names) and stored them in a specific directory (for example, Downloads/directory1).
i would like to create folders to store these files under the same directory, using the names of the original files, but without the extension pdf.
for example, for a file named maths.pdf, i want to create the folder maths and store the pdf in it.
i made several attempts creating a script using commands as basename and for, but i didn't have any luck.
You can do:
Assuming you're getting:
filename='Downloads/directory1/math.pdf'
f="${filename##*/}"
dir="${f%.*}"
mkdir -p "$dir"
will create mathdirectory
try with:
cd Downloads/directory1
for f in *.pdf; do
fname=${echo $f | sed "s/.pdf//" }
echo "Creating directory [$fname]"
mkdir "$fname"
done