I developed one API(displayBlogs) which is responsible for getting data from database ,i want to apply pagination for displayBlogs api,for that i installed require package but i am unable to apply a pagination on that query(if i don't use get() method then pagination working) ,please help me to fix this issue..
UserController.php
public function displayBlogs(){
$user = new BlogModel();
$token = JWTAuth::getToken();
$id = JWTAuth::getPayload($token)->toArray();
$user->user_id = $id["sub"];
return DB::table('blogs_table')->where('user_id', $user->user_id)->get()->paginate(3);
}
just use paginate only
public function displayBlogs(){
$user = new BlogModel();
$token = JWTAuth::getToken();
$id = JWTAuth::getPayload($token)->toArray();
$user->user_id = $id["sub"];
return DB::table('blogs_table')->where('user_id', $user->user_id)->paginate(3);
}
Related
When I use without paginate, the Voyager Translatable trait works fine.
$data = Post::where('status', 1)->get()->translate();
But, when I change it to paginate:
$data = Post::where('status', 1)->paginate(15)->translate();
in view:
$data->links()
then it gives an error in blade view:
Method TCG\Voyager\Translator\Collection::links does not exist
How can I solve this issue?
i did it that:
public function getTranslated(Builder $query, string $lang) : array {
$data = $query->paginate();
$dataArray = $data->toArray();
$translatedData = $data->translate($lang);
$dataArray['data'] = $translatedData->toArray();
return $dataArray;
}
I am trying put paginate(10) to add a pagination later, but when I added it it gives me this error:
Undefined property: Illuminate\Pagination\LengthAwarePaginator::$product
Here is my controller where I want add the pagination(10):
public function index()
{
$user_id = auth()->user()->id;
$user = User::find($user_id);
return view('your')->with('product', $user->product);
}
I did try this:
public function index()
{
$user_id = auth()->user()->id;
$user = User::find($user_id)->paginate(10);
return view('your')->with('product', $user->product);
}
How can I avoid the undefined property error?
Actually find function is used for getting only 1 result and you are applying pagination on that which is resulting into an error.
You might be wanting the products data to be paginated, For that do like this
public function index()
{
$user_id = auth()->user()->id;
$user = User::find($user_id)->product()->paginate(10);
return view('your')->with('product', $user);
}
I want a number of posts that logged in user to have
I tried but I don't know how it will work
public function limitation()
{
$limit = 3;
$ads = User::WithCount('ads')->get();
}
Any help will appericiate
it works!!
$limit = 3;
$userId = auth()->user()->id;
$userPostCountId = User::where('id', $userId);
$posts=User::withCount('ads')->first(); //Suggest:- it will return post counts
along with user details
if ($userId>0) {
# code...
if(isset($posts->ads))
{
$count = sizeof($posts->ads);
if ($count>=$limit) {
return redirect()->route('ad.index');
}
}
If you have set up your user-posts relationship correctly like so:
class User {
public function posts(){
return $this->hasMany('App\Posts')
}
}
then you can get the users posts like so
$user = Auth::user();
$numPosts = $user->posts()->count();
Read more about relationships and how to query them here: https://laravel.com/docs/6.x/eloquent-relationships#one-to-many
Make sure you defined proper model naming
Also, you have to define a relationship between users and posts
User Model
public function posts()
{
return $this->hasMany(Posts::class);
}
In your controller
public function userPosts()
{
$userId = auth()->user()->id;
$userPostCount = User::where('id', $userId)->withCount('posts')->first(); //Suggest:- it will return post counts along with user details
//or auth()->user()->posts()->count() //it will return only post count
// or if you want to count with post also
// $userPosts = User::where('id', $userId)->with('posts')->withCount('posts')->first(); // it will return user posts and post counts along with user data
return $userPostCount; // or $userPosts
}
For more information please read: Laravel eloquent relationship
use skip and take functions
$limit = 3;
$ads = User::WithCount('ads')->skip(0)->take($limit)->get();
I'm trying to attach the currently logged in user to this request, so that I can save it in the database. Can someone point me in the right direction, please?
public function store(CreateLeadStatusRequest $request)
{
$input = $request->all();
$leadStatus = $this->leadStatusRepository->create($input);
Flash::success('Lead Status saved successfully.');
return redirect(route('lead-statuses.index'));
}
So, I have come up with the following using array_merge, but there must be a better way, surely?
public function store(CreateLeadStatusRequest $request)
{
$input = $request->all();
$userDetails = array('created_by' => Auth::user()->id, 'modified_by' => Auth::user()->id);
$merged_array = array_merge($input, $userDetails);
$leadStatus = $this->leadStatusRepository->create($merged_array);
Flash::success('Lead Status saved successfully.');
return redirect(route('lead-statuses.index'));
}
So you can use Auth Facade to get information of currently logged user.
For Laravel 5 - 5.1
\Auth::user() \\It will give you nice json of current authenticated user
For Laravel 5.2 to latest
\Auth::guard('guard_name')->user() \\Result is same
In laravel 5.2, there is new feature called Multi-Authentication which can help you to use multiple tables for multiple authentication out of the box that is why the guard('guard_name') function is use to get authenticated user.
This is the best approach to handle these type of scenario instead of attaching or joining.
public function store(CreateLeadStatusRequest $request)
{
$input = $request->all();
$userDetails = \Auth::user(); //Or \Auth::guard('guard_name')->user()
$leadStatus = $this->leadStatusRepository->create($input);
Flash::success('Lead Status saved successfully.');
return redirect(route('lead-statuses.index'));
}
Hope this helps.
How to use ActiveRecotd cache for Yii 2? I did't find any examples in official docs. In Google I found 2 examples, first is:
$db = self::getDb();
$object = $db->cache(function ($db) use($id) {
return self::findOne($id);
});
But it doesn't work for Model, I tested with updated framework. Other example is:
$data = \Yii::$app->cache->get('some_var_' . $id);
if ($data === false)
{
$data = self::findOne($id);
\Yii::$app->cache->set('some_var_' . $id, $data, 60);
}
It's working fine, but it's not ActiveRecord caching it's data caching, So we haven't got ActiveRecord caching in Yii 2?
1) Use cache like that:
$db = Yii::$app->db;// or Category::getDb()
$result = $db->cache(function ($db) use ($id) {
return Category::find()->where(['id' => $id])->all();
}, CACHE_TIMEOUT);
2) If you may use query dependency, use like that:
$db = Yii::$app->db;// or Category::getDb()
$dep = new DbDependency();
$dep->sql = 'SELECT count(*) FROM category';
$result = $db->cache(function ($db) use ($id) {
return Category::find()->where(['id' => $id])->all();
}, CACHE_TIMEOUT, $dep);
I too am having trouble with this. Here's my workaround for the time being for a hasOne() relationship.
public function getGroup()
{
if(isset(static::$_getGroup[$this->id])) {
return static::$_getGroup[$this->id];
}
$Group = $this->hasOne(BillChargesGroup::className(), ['id' => 'group_id'])->one();
static::$_getGroup[$this->id] = $Group;
return $Group;
}
I only want to cache data for the current request, so this works. However because I'm using ->one(); it does not return the ActiveQuery object if we call $model->getGroup() (which I found is good for extending queries)
Unfortunately if I do return the ActiveQuery object, Yii2 does some "magic" on it and always does a SELECT * which I can't control.
Since 2.0.14 you can use the following shortcuts:
(new Query())->cache(7200)->all();
// and
User::find()->cache(7200)->all();
Source: https://www.yiiframework.com/doc/guide/2.0/en/caching-data