await ctx.send('Enter the channel name you want to be set as default welcome channel: ')
else:
await ctx.send('Only server moderators and owner can use this command')
the code is giving me error:
IndentationError: expected an indented block
The error isn't a DiscordError subclass.
It's only an IndentationError.
It means that your code isn't indented well.
Example
>>> if (True):
print('True')
IndentationError raised
You have to indent the statement block:
>>> if (True):
print('True')
'True'
And nothing goes wrong.
In conclusion
If your error was simply because of a wrong indentation, please fix it and accept my answer.
Related
This is first time i am touching ruby, so no sure about correct terminology. I have tried searching for mulitple things, but couldn't find a solution.
I have this code block
domain_response = MyDomain::Api::MyApi::Api.new(parameters: message.to_domain_object, timeout: 1000)
# :nocov:
case (response = domain_response.response)
when MyDomain::Api::MyApi::SuccessResponse
## do something
when Domain::ErrorResponses::TimeoutResponse
## do something.
now i am trying to testing TimeoutResponse, I have written(tried) this
it "when api call timesout" do
expect(MyDomain::Api::MyApi::Api).to{
receive(:new)
} raise_error(MyDomain::ErrorResponses::TimeoutResponse)
end
this gave me error that unexpected identifier.
I have also tried by not providing receive, and it gave me error that block is expected.
Whats the proper way to raise an error that i can test?
Update:
Here is where i am stuck now
it "when api call timesout" do
# 1
expect(MyDomain::Api::MyApi::Api).to(
receive(:new),
).and_return(domain_api_instance)
# 2
expect(domain_api_instance.response).to receive(:response).and_raise(Domain::ErrorResponses::TimeoutResponse)
expect(domain_api_instance.response).to eq(ApiError::Timeout)
end
But with this code i am getting this error
1) Rpc::Package::SubPackage::V1::PackageService#first_test testing when api call timesout
Failure/Error: expect(domain_api_instance.response).to receive(:response).and_raise(Domain::ErrorResponses::TimeoutResponse)
#<InstanceDouble(MyDomain::Api::MyApi::Api) (anonymous)> received unexpected message :response with (no args)
I can not understand what is wrong in this line, could you explain it for me :)?
Code:
log.debug(F"Create Error with receive_date={self.receive_date} data={data}")
Pylint:
ErrorService/Error.py:24:8: W1202: Use % formatting in logging functions and pass the % parameters as arguments (logging-format-interpolation)
The code i wrote in time series forecasting is as follows.
It keeps getting the error.
for param in pdq:
for param_seasonal in seasonal_pdq:
try:
mod = sm.tsa.statespace.SARIMAX(indexedDataset,order=param,seasonal_order=param_seasonal,enforce_stationarity=False,enforce_invertibility=False)
results = mod.fit()
print('ARIMA{}x{}12 - AIC:{}'.format(param,param_seasonal,results.aic))
except: continue
File "<ipython-input-211-c755485ed830>", line 7
except: continue
^
IndentationError: unexpected unindent
for param in pdq:
for param_seasonal in seasonal_pdq:
try:
mod = sm.tsa.statespace.SARIMAX(indexedDataset,order=param,seasonal_order=param_seasonal,enforce_stationarity=False,enforce_invertibility=False)
results = mod.fit()
print('ARIMA{}x{}12 - AIC:{}'.format(param,param_seasonal,results.aic))
except:
continue
except needs to be at the same level of indent with try.
Please be more careful with indentation when you write python scripts.
I am trying to increment the value and use in another resource dynamically in recipe but still failing to do that.
Chef::Log.info("I am in #{cookbook_name}::#{recipe_name} and current disk count #{node[:oracle][:asm][:test]}")
bash "beforeTest" do
code lazy{ echo #{node[:oracle][:asm][:test]} }
end
ruby_block "test current disk count" do
block do
node.set[:oracle][:asm][:test] = "#{node[:oracle][:asm][:test]}".to_i+1
end
end
bash "test" do
code lazy{ echo #{node[:oracle][:asm][:test]} }
end
However I'm still getting the error bellow:
NoMethodError ------------- undefined method echo' for Chef::Resource::Bash
Cookbook Trace: ---------------
/var/chef/cache/cookbooks/Oracle11G/recipes/testSplit.rb:3:in block (2 levels) in from_file'
Resource Declaration: ---------------------
# In /var/chef/cache/cookbooks/Oracle11G/recipes/testSplit.rb
1: bash "beforeTest" do
2: code lazy{
3: echo "#{node[:oracle][:asm][:test]}"
4: }
5: end
Please can you help how lazy should be used in bash? If not lazy is there any other option?
bash "beforeTest" do
code lazy { "echo #{node[:oracle][:asm][:test]}" }
end
You should quote the command for the interpolation to work; if not, ruby would search for an echo command, which is unknown in ruby context (thus the error you get in log).
Warning: lazy has to be for the whole resource attribute; something like this WON'T work:
bash "beforeTest" do
code "echo node asm test is: #{lazy { node[:oracle][:asm][:test]} }"
end
The lazy evaluation takes a block of ruby code, as decribed here
You may have a better result with the log resource like this:
log "print before" do
message lazy { "node asm test is #{node[:oracle][:asm][:test]}" }
end
I've been drilling my head solving this problem until I came up with lambda expressions. But yet just using lambda didn't help me at all. So I thought of using both lambda and lazy evaluation. Though lambda is already lazy loading, when compiling chef recipe's, the resource where you call the lambda expression is still being evaluated. So to prevent it to being evaluated (somehow), I've put it inside a lazy evaluation string.
The lambda expression
app_version = lambda{`cat version`}
then the resource block
file 'tmp/validate.version' do
user 'user'
group 'user_group'
content lazy { app_version.call }
mode '0755'
end
Hope this can help others too :) or if you have some better solution please do let me know :)
I'm trying out the unidecoder gem and it's giving me problems with some strings:
require 'unidecoder'
str = "\u00A3"
str.to_ascii
#: (C:/Ruby193/lib/ruby/gems/1.9.1/gems/unidecoder-1.1.1/lib/unidecoder/data/x00.yml):
found unknown escape character while parsing a quote d scalar at line
2 column 3
from C:/Ruby193/lib/ruby/1.9.1/psych.rb:203:in parse'
from C:/Ruby193/lib/ruby/1.9.1/psych.rb:203:inparse_stream'
from C:/Ruby193/lib/ruby/1.9.1/psych.rb:151:in parse'
from C:/Ruby193/lib/ruby/1.9.1/psych.rb:127:inload'
from C:/Ruby193/lib/ruby/1.9.1/psych.rb:297:in block in load_file'
from C:/Ruby193/lib/ruby/1.9.1/psych.rb:297:inopen'
from C:/Ruby193/lib/ruby/1.9.1/psych.rb:297:in load_file'
from C:/Ruby193/lib/ruby/gems/1.9.1/gems/unidecoder-1.1.1/lib/unidecoder.rb:8:in
block in '
from C:/Ruby193/lib/ruby/gems/1.9.1/gems/unidecoder-1.1.1/lib/unidecoder.rb:78:in
yield'
from C:/Ruby193/lib/ruby/gems/1.9.1/gems/unidecoder-1.1.1/lib/unidecoder.rb:78:in
default'
from C:/Ruby193/lib/ruby/gems/1.9.1/gems/unidecoder-1.1.1/lib/unidecoder.rb:78:in
decode_char'
from C:/Ruby193/lib/ruby/gems/1.9.1/gems/unidecoder-1.1.1/lib/unidecoder.rb:39:in
block in decode'
from C:/Ruby193/lib/ruby/gems/1.9.1/gems/unidecoder-1.1.1/lib/unidecoder.rb:37:in
gsub'
from C:/Ruby193/lib/ruby/gems/1.9.1/gems/unidecoder-1.1.1/lib/unidecoder.rb:37:in
decode'
from C:/Ruby193/lib/ruby/gems/1.9.1/gems/unidecoder-1.1.1/lib/unidecoder.rb:16:in
to_ascii'
from (irb):21
from C:/Ruby193/bin/irb:12:in'>>
What's worse, I can't catch the error by doing:
foo = str.to_ascii rescue 'x'
Does anyone know what's happening here?
rescue clause with no parameter list, the parameter defaults to StandardError; it looks like unidecoder raises kinda other exception, but the stacktrace seems to be incomplete (it should show the exception type.)
Take a look at "C:/Ruby193/lib/ruby/gems/1.9.1/gems/unidecoder-1.1.1/lib/unidecoder/data/x00.yml". Line 2 is an YAML entry - "\z"，which is not a valid escape sequence in Ruby(but a Regexp anchor to mark the end of string). This might be a bug. You can edit this line to - "\x00".
However, "\u00A3"(£) is not a valid ASCII character, I didn't find the point of encoding it to ASCII.
The exception raised is Psych::SyntaxError, you can catch that specific exception, as #mudasobwa commented.