Loop through table and parse multiple arguments to scripts in Bash - bash

Question

I am in a situation similar to this one and having difficulties implementing this kind of solution for my situation.
I have file.tsv formatted as follows:
x y
dog woof
CAT meow
loud_goose honk-honk
duck quack
with a fixed number of columns (but variable rows) and I need to loop those pairs of values, all but the first one, in a script like the following (pseudocode)
for elements in list; do
./script1 elements[1] elements[2]
./script2 elements[1] elements[2]
done
so that script* can take the arguments from the pair and run with it.
Is there a way to do it in Bash?
I was thinking I could do something like this:
list1={`awk 'NR > 1{print $1}' file.tsv`}
list2={`awk 'NR > 1{print $2}' file.tsv`}
and then to call them in the loop based on their position, but I am not sure on how.
Thanks!

Answer 1

Shell tables are not multi-dimensional so table element cannot store two arguments for your scripts. However since you are processing lines from file.tsv, you can iterate on each line, reading both elements at once like this:
#!/usr/bin/env sh
# Populate tab with a tab character
tab="$(printf '\t')"
# Since printf's sub-shell added a trailing newline, remove it
tab="${tab%?}"
{
# Read first line in dummy variable _ to skip header
read -r _
# Iterate reading tab delimited x and y from each line
while IFS="$tab" read -r x y || [ -n "$x" ]; do
./script1 "$x" "$y"
./script2 "$x" "$y"
done
} < file.tsv # from this file

Answer 2

You could try just a while + read loop with the -a flag and IFS.
#!/usr/bin/env bash
while IFS=$' \t' read -ra line; do
echo ./script1 "${line[0]}" "${line[1]}"
echo ./script2 "${line[0]}" "${line[1]}"
done < <(tail -n +2 file.tsv)
Or without the tail
#!/usr/bin/env bash
skip=0 start=-1
while IFS=$' \t' read -ra line; do
if ((start++ >= skip)); then
echo ./script1 "${line[0]}" "${line[1]}"
echo ./script2 "${line[0]}" "${line[1]}"
fi
done < file.tsv
Remove the echo's if you're satisfied with the output.