I have a model Survey with a column installer_id which is related to hasOne another model Installation which is related to hasMany another model Assignment.
I want to write a query to fetch all Survey where the installer_id is not null, and where IF an Assignment exists check all the assignments if any status is != 2 ie status = 0 or 1 return the survey.
I tried this query but it does not capture the "if an assignment exists then check the status" part
$surveys = Survey::whereNotNull('installer_id')
->orWhereHas('installation',function ($query) {
return $query->whereHas('assignments',function ($q){
return $q->where('status','!=', 2 );
});
})->get();
I also tried to define a hasManyThrough relationship in the model.
public function assignments()
{
return $this->hasManyThrough(Assignment::class,Installation::class);
}
and then using this query
$schedulables = Survey::whereNotNull('installer_id')
->orWherehas('assignments',function ($query){
return $query->where('assignments.status','!=', 2 );
})->get()
Please any suggestions and help would be appreciated
I think you had the correct approach, however whereNotNull is not necessary if you're already going to check with whereHas, so this way is sufficient I think:
$surveys = Survey::whereHas('installation',function ($query) {
return $query->whereHas('assignments',function ($q){
return $q->where('status','!=', 2 );
});
})->get();
and I think you're missing the ->get(); in your code, thats why you were not getting the results
Original answer
What i needed was the whereDoesntHave method.
$surveys = Survey::whereNotNull('installer_id')
->whereDoesntHave('installation.assignments', fn ($query) => $query->where('status', 2))
->get();
Related
I am new to laravel,
I need to create a query for the db,
$query = Deal::query();
I want to use the wherehas operator.
this is my code that is worked.
else if ($group_by == 'precedence') {
if($get_deals_for == 'noprecedence'){
$get_deals_for = 0;
}
$precedenceStatus = $get_deals_for;
$query-> where('precedence', '=', $precedenceStatus);
// \Log::info('The request precedence: '.$precedenceStatus);
}
I want to add this code also to the query
if($person) {
$query->whereHas('personnel', function ($subQuery) use ($person) {
$subQuery->where('id', '=', $person);
});
}
So I need to change the first code?
how I can convert the first code to wherehas?
the first code is from table called deal, the second section is from realtionship called personnel.
the second section worked in other places in the code, I just need to fix the first section and not understand what to write in the use
I try this and get error on the last }
else if ($group_by == 'precedence') {
if($get_deals_for == 'noprecedence'){
$get_deals_for = 0;
}
$precedenceStatus = $get_deals_for;
$query-> where('precedence', '=', $precedenceStatus)
-> when ($person, function($query) use($person) {
$query->whereHas('personnel', function ($query) use ($person) {
$query->where('id', '=', $person);
});
})
}
There is a method you can use called when(, so that you can have cleaner code. The first parameter if true will execute your conditional statement.
https://laravel.com/docs/9.x/queries#conditional-clauses
$result = $query
->where('precedence', '=', $precedenceStatus)
->when($person, function ($query) use ($person) {
$query->whereHas('personnel', fn ($q) => $q->where('id', '=', $person));
})
->get();
You should also be able to clean up your precedence code prior to that using when( to make the entire thing a bit cleaner.
Querying to DB is so easy in laravel you just need to what you want what query you want execute after that you just have to replace it with laravel helpers.Or you can write the raw query if you cant understand which function to use.
using,DB::raw('write your sql query').
Now Most of the time whereHad is used to filter the data of the particular model.
Prefer this link,[Laravel official doc for queries][1] like if you have 1 to m relation ship so u can retrive many object from one part or one part from many object.like i want to filter many comments done by a user,then i will right like this.
$comments = Comment::whereHas('user', function (Builder $query) {
$query->where('content', 'like', 'title%');
})->get();
$comments = Here will be the model which you want to retrive::whereHas('relationship name', function (Builder $query) {
$query->where('content', 'like', 'title%');
})->get();
you can also write whereHas inside whereHas.
[1]: https://laravel.com/docs/9.x/eloquent-relationships#querying-relationship-existence
i need to search in last record of an relationship in Laravel 7. Here is my code, hope u understand my question :)
$Collection = ServiceRequest::whereHas('ServiceRequestSignatureFlows', function ($query) use ($ou_id) {
return $query->latest()->where('user_id',666);
})
->orderBy('name', 'ASC')
->get();
a ServiceRequest has many SignatureFlows, but i need only search on last flow inserted. I think that when i make ->latest(), my search could search 666 only in last rows, but doesnt happens.
Thanks
you can create the new relation HasOne and filter by it.
public function ServiceRequestSignatureLastFlow()
{
return $this->hasOne(ServiceRequestSignatureFlows::class)->orderByDesc('id');
}
and than
$collection = ServiceRequest::whereHas('ServiceRequestSignatureLastFlow', function ($query) use ($ou_id) {
$query->where('user_id', $ou_id);
})->orderBy('name', 'ASC')->get();
Remove the return inside the whereHas
I am trying to write a query where all items are returned (products) and if a relationship exists for that particular item (many to many) then that information is included too. When I include the relationship at the moment on the query it only returns items that have that relationship rather thatn every single item, regardless of whether that relationship exists or not.
Here is my query at the moment:
public static function filterProduct($vars) {
$query = Product::query();
if((array_key_exists('order_by', $vars)) && (array_key_exists('order', $vars))) {
$query = $query->orderBy($vars['order_by'], $vars['order']);
}
if(array_key_exists('category_id', $vars) && $vars['category_id'] != 0) {
$query = $query->whereHas('categories', function($q) use ($vars) {
return $q->where('id', $vars['category_id']);
});
}
if(array_key_exists('manufacturer_id', $vars)) {
$query = $query->whereHas('manufacturer', function($q) use ($vars) {
return $q->where('id', $vars['manufacturer_id']);
});
}
$query = $query->whereHas('options', function($q) use ($vars) {
});
As you can see, when an item has the 'options' relationship I need to have that particular row include details of that relationship in the returned date. With the code as it is though it is only returning items that have this relationship rather than every single item.
Can someone advise me as to how this is achieved please?
Thanks!
I feel a bit stupid as it was so simple but it was solved by adding this:
$query = $query->with('options');
I have the following relationship functions in my Job model:
public function resourceTypes(){
return $this->belongsToMany('ResourceType', 'job_requests');
}
public function resources(){
return $this->belongsToMany('Resource', 'jobs_resources')->withPivot('flow_type', 'resource_type_id');
}
I am able to get an object with data from both of the above relationships using:
$job = Job::findorfail($projectId);
$result = $job->with('resources.resourceTypes')->get();
I would like to put a where clause on the jobs_resources pivot table - specifically on the column flow_type.
How would I do this?
Try something like this:
$job = Job::with('resources' => function($q) {
$q->with('resourceTypes')->where('flow_type',2);
})->findorfail($projectId);
In above you will get only those resources with flow_type = 2
I ended up using the following statement:
Job::with(['resources' => function ($query){
$query->wherePivot('flow_type', '=', '1' );
}, 'resources.resourceTypes'])->where('id', $projectId)->firstOrFail();
$result = DB::table('job')
->join('job_resources', 'job.id', '=', 'job_resources.job_id')
->join('job_requests', 'job_resources.request_id', '=', 'job_requests.id')
->where('job_resources.flow_type', '=', CONDITION)
->get();
Your table data is not clear from your input, but this method (query builder) should work
here is link to my database schema:
How can I get all topics from the blogs to which the user is subscribed using his id? I use Eloquent ORM.
I have added the following lines to my User model:
public function blogs()
{
return $this->belongsToMany('Blog', 'blog_subscriptions');
}
And then requested in the controller
User::find(1)->blogs; // User id is hardcoded
With that I got all blogs to which the user is subscribed.
And now I am stuck on how to get the topics of those blogs.
Assuming relations:
// User
belongsToMany('Blog', 'user_subscriptions')
// Blog
belongsToMany('User', 'user_subscriptions')
hasMany('Topic')
// Topic
belongsTo('Blog')
1 My way, that will work with any relation, no matter how deeply nested:
User::with(['blogs.topics' => function ($q) use (&$topics) {
$topics = $q->get()->unique();
}])->find($userId);
2 Eloquent standard methods:
$topics = Topic::whereHas('blog', function ($q) use ($userId) {
$q->whereHas('users', function ($q) use ($userId) {
$q->where('users.id', $userId);
});
})->get();
// or
$user = User::find($userId);
foreach ($user->blogs as $blog)
{
$blog->topics; // collection of topics for every single blog
}
3 Joins:
$topics = Topic::join('blogs', 'topics.blog_id', '=', 'blogs.id')
->join('user_subscriptions as us', function ($j) use ($userId) {
$j->on('us.blog_id', '=', 'blogs.id')
->where('us.user_id', '=', $userId);
})->get(['topics.*']);
Mind that last solution will rely on your pivot data consistency. That said, if you can't be sure, that there are no redundant entries in user_subscriptions (eg. blog or user has been deleted but the pivot entry remains), then you need to further join users as well.
I am new to laravel and I don't have the possibility of test this, but I had a similar need and solved it with something like this:
DB::Query('topics')->join('blogs', 'blogs.id', '=', 'topics.blog_id')
->join('blog_subscriptions', 'blogs.id', '=', 'blog_subscriptions.blog_id')
->select('name.id','table.email')
->where('blog_subscriptions.user_id', '=', $user_id);