I am getting some invalid java object after running the following select statement.
select OBJECT_NAME, OBJECT_TYPE, STATUS from ALL_OBJECTS where status='INVALID' and owner='OWBSYS';
OBJECT_NAME OBJECT_TYPE STATUS
--------------- ------------------------------ ------------------- -------
/11d72cdd_TaskScheduler JAVA CLASS INVALID
/12b895ae_LexiComparator JAVA CLASS INVALID
/1327ed5a_LRUCacheLRUNode JAVA CLASS INVALID
/1aabcc3f_ServiceDoctor JAVA CLASS INVALID
/1dad730_NAMsgUtilComponentInf JAVA CLASS INVALID
/1ef21df6_NameAddrRes_ko JAVA CLASS INVALID
/20dd1937_ImmutableArray JAVA CLASS INVALID
/235a039f_NameAddrExceptions_e JAVA CLASS INVALID
/23c25276_UnhandledException JAVA CLASS INVALID
Alter the java class with RESOLVE clause
Connect to OWBSYS user
Then execute the following statement.
SQL> ALTER JAVA CLASS "<java class>" RESOLVE;
Related
Is it possible to use a Sequence inside a View?? I am using the following query:
CREATE VIEW < VIEW_NAME > (ID, VALUE1, VALUE2,...) AS
SELECT
SEQ1.NEXTVAL,
VAL1,
VAL2,
...
FROM
< TABLE >
But it is giving me the following error:
invalid identifier 'SEQ1.NEXTVAL'
The query works when not creating the view:
use the full qualified name for the SEQ object, because if I am in a different DB/Schema, that is the scope used to look for SEQ
basically everything in a view should be fully qualified, tables, views, functions, sequences.
CREATE DATABASE test;
create SCHEMA test.test;
use SCHEMA test.test;
create SEQUENCE seq1;
create view test_v as SELECT seq1.nextval;
select * from test.test.test_v;
gives:
NEXTVAL
2
create SCHEMA test.not_test;
use SCHEMA test.not_test;
select * from test.test.test_v;
and now you get:
SQL compilation error: error line 1 at position 29 invalid identifier 'SEQ1.NEXTVAL'
Here SEQ1 is not defined, that is the reason why you see the error. Documentation for Sequences is here:
https://docs.snowflake.com/en/sql-reference/sql/create-sequence.html
Is the Sequence existing? Looks like you accidentally missed to create it.
I am trying to execute this query ;
Grant SELECT on TYPE PPZ_C.BTS_BAUTEIL_STATION_INFO to PPZ_W;
and I get the folowing error:
Error starting at line : 3 in command - Grant SELECT on TYPE
PPZ_C.BTS_BAUTEIL_STATION_INFO to PPZ_W Error report - ORA-00905:
missing keyword
00905. 00000 - "missing keyword"
*Cause:
*Action:
Does anyone know what keyword I am missing ?
Firstly you need to remove TYPE. This will fix your first part of issue.
Try this
Grant SELECT on PPZ_C.BTS_BAUTEIL_STATION_INFO to PPZ_W
Now when you execute the above , you will further get the error:
ORA-02305: only EXECUTE, DEBUG, and UNDER privileges are valid for
types
Which means you cannot grant select on any type. Only EXECUTE, DEBUG, and UNDER privileges are valid for types.
So you can use EXECUTE when you want it to be used in select statement :
Grant EXECUTE on PPZ_C.BTS_BAUTEIL_STATION_INFO to PPZ_W;
EDIT:
Your select statement should be :
SELECT ppz_bts.na_stat_anf( PPZ_C.BTS_BAUTEIL_STATION_INFO ('','IG','12345679') ) FROM dual;
See demo:
CREATE OR REPLACE TYPE myschema.array_t is varray(2) of number ;
---Running in My schema
SQL> select * from table(array_t('1','2'));
COLUMN_VALUE
------------
1
2
--Granted from myschema to otherschema
SQL> grant execute on myschema.array_t to othersschema ;
--Running in otherschema
SQL> select * from table(myschema.array_t('1','2'));
COLUMN_VALUE
------------
1
2
When Oracle receives requests for type information, it verifies that the requestor has EXECUTE privilege on the type before supplying the requested information.
Try this :
Grant EXECUTE on PPZ_C.BTS_BAUTEIL_STATION_INFO to PPZ_W;
Then try doing :
SELECT ppz_bts.na_stat_anf( PPZ_C.bts_bauteil_station_info('','IG','12345679') )
FROM dual;
In an Oracle package I have defined a type
type setTable is table of my_sets.pkey%type;
in the package declaration (the non-body part). The pkey column referenced is a number(38). Then in a function in the package body I have
...
with d as (select column_value from table(sets)),
...
where sets is a parameter to the function of type settable. This line fails to compile with the error 'ORA-22905: cannot access rows from a non-nested table item'. What can I do to resolve this?
The select statement is SQL not PL/SQL, and the SQL engine can only work with types defined on the server like this:
create type setObj is object (<attributes>);
create type setTable is table of setObj;
I am getting below error in my application.
org.hibernate.util.JDBCExceptionReporter -- ERROR -- ORA-00980: synonym translation is no longer valid
i have checked the synonym,that is valid.
Can anyone please help.
You may have the synonym in VALID status which refers to even non-existing object:
SQL> create synonym t_syn for abrakadabra;
Synonym created.
SQL> select status from user_objects where object_name = 'T_SYN';
STATUS
-------
VALID
SQL> select * from t_syn;
select * from t_syn
*
error in line 1:
ORA-00980: synonym translation is no longer valid
SQL> select status from user_objects where object_name = 'T_SYN';
STATUS
-------
VALID
So first of all you need to check the existance of the object the synonym refers to.
I was reading this article:
Managing Oracle Synonyms
Regarding the order of preference, when it come to resolving an object name to the actual object, it says:
Local objects will always be accessed first.
If a local object does not exist, the object with a private synonym will be accessed.
If a private synonym does not exist or the object does not exist, then the public synonym will be used.
I was wondering if the public objects are missing in this order somehow?
E.g. if user BOB queries
select * from FOOBAR
and there is no BOB.FOOBAR in dba_tables/views but PUBLIC.FOOBAR.
Does Oracle resolve it to PUBLIC.FOOBAR or will it check for synonyms first?
Thank you.
In your example, FOOBAR is almost certainly a public synonym. There is no PUBLIC schema but PUBLIC is listed as the owner of a public synonym.
If I create a new public synonym
SQL> create public synonym pub_syn_emp
2 for scott.emp;
Synonym created.
the owner of that synonym ends up being PUBLIC
SQL> ed
Wrote file afiedt.buf
1 select object_name, owner, object_type
2 from dba_objects
3* where object_name = 'PUB_SYN_EMP'
SQL> /
OBJECT_NAME OWNER OBJECT_TYP
-------------------- ---------- ----------
PUB_SYN_EMP PUBLIC SYNONYM
In addition, item #3 does not appear to be correct. If there is a private synonym that points to a non-existent object and a public synonym that points to a valid object, the private synonym still takes precedence. You'll just get an error when Oracle tries to resolve the private synonym to an actual object.
SQL> create synonym syn_emp for scott.no_such_table;
Synonym created.
SQL> create public synonym syn_emp for scott.emp;
Synonym created.
SQL> select * from syn_emp;
select * from syn_emp
*
ERROR at line 1:
ORA-00980: synonym translation is no longer valid
At least up to 10g, PUBLIC is not a real user. You cannot create objects in the "Public schema":
SQL> CREATE TABLE public.foobar (id integer);
CREATE TABLE public.foobar (id integer)
ORA-00903: invalid table name
SQL> CREATE TABLE system.foobar (id integer);
Table created
SQL>
If you run this query:
SELECT object_name
FROM dba_objects
WHERE owner='PUBLIC'
AND object_type IN ('TABLE', 'VIEW');
You can answer the question about pre-defined tables/views in the PUBLIC "schema".