Binding Listview Items to multiple Models - xamarin

Question

I have a List view with a label and an entry. I set the item source of ListView to SQL table in codebehind. My label will have its text from this SQL, but I want to save my Entry.Text to a new model (binding to another model that is not related to listview itemsource)...
HOW TO DO IT??
The SQL stores names.
Here is my xaml:
<ListView x:Name="Mlist" Grid.Row="3" >
<ListView.ItemTemplate>
<DataTemplate>
<ViewCell>
<Grid Padding="5" BackgroundColor="White" RowSpacing="40">
<Label x:Name="label" HorizontalOptions="Center" Text="{Binding name}" />
<Entry x:Name="money" Placeholder="type the income" Text={ *** Binding to another model that is not related to listview itemsource}
</Grid>
</ViewCell>
</DataTemplate>
</ListView.ItemTemplate>
</ListView>
Code behind:
Mlist.itemsource = conn.Table<peaople>().ToList();

Answer 1

Move the code which manipulate data into the viewmodel ,make ViewModel implement INotifyPropertyChanged , and set the viewmodel as the BindingContext in code behind.
ViewModel
public class ViewModel : INotifyPropertyChanged
{
public event PropertyChangedEventHandler PropertyChanged;
public void NotifyPropertyChanged([CallerMemberName] String propertyName = "")
{
PropertyChanged?.Invoke(this, new PropertyChangedEventArgs(propertyName));
}
List<People> list;
public List<People> List {
get
{
return list;
}
set
{
list = value;
NotifyPropertyChanged();
}
}
private string money;
public string Money //add Money property directly in viewmodel
{
get { return money; }
set
{
money = value;
NotifyPropertyChanged();
}
}
public ViewModel()
{
List = conn.Table<People>().ToList();
}
}
Page(code behind)
viewModel = new ViewModel();
this.BindingContext = viewModel;
Xaml
Name current page as Self , and redirect the binding path on Entry.Text.
x:Class="FormsApp.Views.Page1"
x:Name="Self"
>
<ListView x:Name="Mlist" ItemsSource="{Binding List}" RowHeight="100" HasUnevenRows="True">
<ListView.ItemTemplate>
<DataTemplate>
<ViewCell>
<StackLayout >
<Label x:Name="label" TextColor="Red" HorizontalOptions="Center" Text="{Binding Name}" />
<Entry x:Name="money" Placeholder="type the income" Text="{Binding Source={x:Reference Self}, Path=BindingContext.Money}"/>
</StackLayout>
</ViewCell>
</DataTemplate>
</ListView.ItemTemplate>
</ListView>
Screen shot
All the Entry share the data Money .