I want to display my data in a table and with selection to select the data I want, but there is no document about stipple. How can I do it?
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I have created a form with two textbox items and one editable datagrid in oracle apex form. Now i want to store those two items data along with this grid's records in single database table as we can do in invoice form. My items are in form region and grid is in its sub region. How to write the insert query. I have written a query but its storing only form items data but not grid's data.
my query as follow :
insert into FOREIGN_SAMPLE (REF_NO,PARTY_NAME,PRODUCT_NAME)
values (:P22_REF_NO,:P22_PARTY_NAME,:PRODUCT_NAME);
Here, PRODUCT_NAME is field of grid view and other 2 are form items.
Here's how:
interactive grid should contain those two columns (ref_no, party_name)
as their source, use form items (:P22_REF_NO and :P22_PARTY_NAME)
once you enter values into the product_name column in the interactive grid and save changes, ref_no and party_name will be saved along with product_name
In other words: don't write your own INSERT statement.
I have a JQGrid and a column chooser implemented on the grid. I want to save the user selected column settings(hidden and visible columns and column order)into a database table and so need to fire a query when the ok button in the column chooser is pressed. How can I do this?
Also, how can I get the state(what columns are hidden and visible) of the user selected JQGrid after the user has made changes using the column chooser in a format which I can use to insert into the table?
Using jqGrid - would like to drag from Table A into an arbitrary row in Table B. Would like the rows of Table B to highlight as I hover over them during a drag. Is this possible?
Even better, can I insert into arbitrary fields in the destination row upon drop?
What I am doing is populating a row field-by-field.
Thanks.
For some user interfaces it makes sense to have explicit checkboxes to allow users to select the items in a table. What's the best way to accomplish this using cocoa? In other words, how can I link the state of a checkbox in each row to whether or not the row is currently selected?
Tony,
if I get you correctly, you want to add a leading column to your NSTableView so you can select the corresponding column(s), separate from the usual selection of the tableView.
What is your datasource of the table view? A core data stuff or an array/dictionary? if you do not want to modify your data model, you could set up a distinct array (mutable), to keep track of the selection. bind it to the checkbox column (you would want to add as first column) and keep the array in sync with the number of items in the general datasource for the table that displays your valuable data.
You could also enhance your data model with a column "selected", make it BOOL and bind it to the checkboxes. This would also allow you to easily save the last selection to you database or file, whatever you are using.
Can you update your question with some more information on your data model?
sya - living.
how to develop a scrolling table with rows which will have more than one dynamic data in one row ? It should take data from web browser.
You can create the table like view as described by Matt Lacey. For dynamic data you can create data-template for your table and bind them to your data source. When you click items in a list you can modify ur data source so that it will be reflected in your table.Note: Make sure to implement INotifyPropertyChanged so the changes in your data are reflected correctly on the UI.
To create a table, simply use a list where each item is a row in the grid and then template the item to display data inside a single row grid.
IMPORTANT: Be sure to set a fixed width on each cell so that all rows look the same and aren't resized independently.