I'm trying to get values from nexus and assign it to a variable using curl command
The curl command i use
curl -u user_name:password --request GET "http://host_name:portnumber/URL
This works as expected in postman
when i try assigning this curl command to a variable and print it with this command
var=$(curl -u user_name:password --request GET "http://host_name:portnumber/URL)
echo $var
I couldn't see the value i get when i use the curl command in postman .
Please help to on this issue . thanks in advance .
Related
I am executing the below curl command in shell script. But I am getting command not found error. So wanted to check if I am making any mistake while executing it.
return = $(curl -s --location --request GET --url 'https://testurl.mywebsite.com/api/accts?Id=trst_id&var=test_var' --header 'type: app/test')
echo "data is: ${return}"
I am getting the error:
return: command not found
Kindly let me know if there is a problem with the way I am trying to execute the curl command.
Thank you.
Like dan pointed out in comments, the extra whotespaces between the variable and command caused the issue. After removing extra whitespaces it worked.
return=$(curl -s --location --request GET --url 'https://testurl.mywebsite.com/api/accts?Id=trst_id&var=test_var' --header 'type: app/test')
echo "data is: ${return}"
I want to pass multiple arguments through to curl. Some of these arguments are quoted and contain spaces.
I have tried like this:
ARGS="http://example.org -H 'My-Header: Foo'"
curl -vvv $ARGS
But my header is not set and I get an error at the end curl: (6) Could not resolve host: Foo'.
I have also tried quoting ARGS like this:
ARGS="http://example.org -H 'My-Header: Foo'"
curl -vvv "$ARGS"
But I get curl: (3) URL using bad/illegal format or missing URL.
If I just run curl with the arguments directly, then it works fine:
curl -vvv http://example.org -H 'My-Header: Foo'
How can I pass these arguments through to curl correctly?
There is a command called eval which evaluates all the arguments into one string and then runs it as a one big command.
Try eval curl $ARGS
I recommend you to checkout eval's man page ;)
When i run the command
curl -d "param1=value1¶m2=value2" -X POST https://xxx.xxxx.de/xx/xx.php 2>/dev/null on the normal command line i get the requested result {"success":false,"cause":"Token needed"}.
I need this result on a bash script but when i try to run it
curl = "$(curl -d "param1=value1¶m2=value2" -X POST https://xxx.xxxx.de/xx/xx.php 2>/dev/null)"
echo $curl
I don't recieve the requested result i recieve this
[1/2]: "success":false --> <stdout>
--_curl_--"success":false
curl: (3) URL using bad/illegal format or missing URL
[2/2]: "cause":"Token needed" --> <stdout>
--_curl_--"cause":"Token needed"
curl: (3) URL using bad/illegal format or missing URL
How i can use the correct result in my bash script ?
Your command is not a variable assignment, it tries to executes curl with arguments = and the output of the command substitution. Remove the space characters before and after = and you may omit the quotes around the command substitution (this is one of the few occasions where quotes are not needed).
curl=$(curl -d "param1=value1¶m2=value2" -X POST https://xxx.xxxx.de/xx/xx.php 2>/dev/null)
echo "$curl"
Have 2 different execute shells in jenkins and need to pass a variable from one to another
Code below shows what i have tried
Shell script #1
export storedBanner=$(curl http://my.network:8080/boardmessage | jq -r .[0].message|sed 's/<[^>]*>//g')
echo $storedBanner > ~/stored.txt
curl -i -X POST -H "Content-Type: application/json" -d "{\"message\":\"<h3>Test message<h3>\"}" http://my.network:8080/boardmessage
Shell script #2
export storedBanner= $(cat ~/stored.txt)
curl -X POST -H "Content-Type: application/json" -d "{\"message\":\"<h4>${storedBanner}<h4>\"}" http://my.network:8080/boardmessage
I want that the exported message to be stored and passed down to 2nd shell script however this doesnt seem to work.
you can use a global variable to do that
Thanks for help, I figured it out with the file and it turns out i used the wrong syntax
Putting this in the shell script #2 worked :)
storedBanner=$(<banner.txt)
I set a command line argument as below:
$TOKENARG='Authorization: Bearer 9042f9a3caacc63419be489aefec02a5eae338c33'
curl -v -X DELETE -H $(echo $TOKENARG) http://localhost:3001/api/v1/articles/3
And desired result is:
curl -v -X DELETE -H 'Authorization: Bearer 9042f9a3caacc63419be489aefec02a5eae338c33' http://localhost:3001/api/v1/articles/3
But when I run the above one it doesn't work as expected and returns the following messages:
curl: (6) Could not resolve host: Bearer
* Rebuilt URL to: 9042f9a3caacc63419be489aefec02a5eae338c33
Could not resolve host: 9042f9a3caacc63419be489aefec02a5eae338c33
How should I pass argument using a variable?
Because you don't quote your command substitution, the string is split up into three words, Authorization:, Bearer and 9042f9a3caacc63419be489aefec02a5eae338c33. To prevent that, you could quote it:
curl -v -X DELETE -H "$(echo $TOKENARG)" http://localhost:3001/api/v1/articles/3
But you don't need echo and the command substitution at all: $(command) has the same output as command, so you can use
curl -v -X DELETE -H "$TOKENARG" http://localhost:3001/api/v1/articles/3
Side note: all uppercase variable names should be used for environment variables only, see for example the POSIX spec (fourth paragraph), so better would be
$tokenarg='Authorization: Bearer 9042f9a3caacc63419be489aefec02a5eae338c33'
curl -v -X DELETE -H "$tokenarg" http://localhost:3001/api/v1/articles/3