I have a text file which contains the following lines:
"user","password_last_changed","expires_in"
"jeffrey","2021-09-21 12:54:26","90 days"
"root","2021-09-21 11:06:57","0 days"
How can I grab two fields jeffrey and 90 days from inverted commas and save in a variable.
If awk is an option, you could save an array and then save the elements as individual variables.
$ IFS="\"" read -ra var <<< $(awk -F, '/jeffrey/{ print $1, $NF }' input_file)
$ $ var2="${var[3]}"
$ echo "$var2"
90 days
$ var1="${var[1]}"
$ echo "$var1"
jeffrey
while read -r line; do # read in line by line
name=$(echo $line | awk -F, ' { print $1} ' | sed 's/"//g') # grap first col and strip "
expire=$(echo $line | awk -F, ' { print $3} '| sed 's/"//g') # grap third col and strip "
echo "$name" "$expire" # do your business
done < yourfile.txt
IFS=","
arr=( $(cat txt | head -2 | tail -1 | cut -d, -f 1,3 | tr -d '"') )
echo "${arr[0]}"
echo "${arr[1]}"
The result is into an array, you can access to the elements by index.
May be this below method will help you using
sed and awk command
#!/bin/sh
username=$(sed -n '/jeffrey/p' demo.txt | awk -F',' '{print $1}')
echo "$username"
expires_in=$(sed -n '/jeffrey/p' demo.txt | awk -F',' '{print $3}')
echo "$expires_in"
Output :
jeffrey
90 days
Note :
This above method will work if their is only distinct username
As far i know username are not duplicate
Related
I am new to shell scripting and I found following line of code in a given script.
Could someone explain me with an example what the following line of code means
Path=`echo $line | awk -F '|' '{print $1}'`
echo $line will print the value of the variable $line, the | symbol means that the output of this will be passed (or piped) to another program/command/script. I will not attempt to explain awk here, but what is done above is that the output from the echo $line is taken and processed with it.
the option -FS as per awk man page means
-F fs Use fs for the input field separator
so the string after it will be used to split the input string given to awk into different fields. Example, you variable $line has a value of a|b it will be split into two fields a and b. What is to be done with this is specified within the '{}' expression.
Again, what can be done in there is next to infinite, here the only thing that is done is to print the first field which can be accessed with $1, or a in the above example ($2 would be b as can be guessed).
Finally, the output of this whole operation is then stored in the variable Path.
to summarize:
line="a|b"
echo $line | awk -F '|' '{print $1}'
> a
Path=`echo $line | awk -F '|' '{print $1}'`
echo $Path
> a
echo $line | awk -F '|' '{print $1}'
Explanation:
echo -> display a line of text
$line -> parameter expansion read the line
| -> A pipeline is a sequence of one or more commands separated by one of the control operators |
awk -> Invoke awk program
-F '|' -> Field separator as | for the data feed
'{print $1}' -> Print the first field
Example
echo 'a|b|c' | awk -F '|' '{print $1}'
will print a
I think this is just a complicated way to express
echo ${line%%|*}
i.e. write to stdout the part of the content of the variable line which goes up to - but not including - the first vertical bar.
Path=`echo $line | awk -F '|' '{print $1}'`
^ ^ ^ ^
| | | |
| | | print 1st column
| | |
| | input field separator
| |
| echo variable line
|
variable Path
-F'|' - by default awk splits record/line/row into columns by single space, but with |, awk splits by pipe
Above one can be written as
Path=$( awk -F '|' '{ print $1 }' <<< "$line" )
Suppose say
$ line="1|2|3"
$ Path=$( awk -F '|' '{ print $1 }' <<< "$line" )
$ echo $Path; # you get first column
1
Same as
$ Path=$( cut -d'|' -f1 <<< "$line" )
$ echo $Path;
1
the default field separator is ' ', if you have -F , means change default separator to '|'
help with shell script to read pattern in comma separated line and end result output should again be in comma separated. In below eg, read line separated by commas and output only puppet strings again separated by commas.
echo "docker-one,puppet-one,puppet-two,docker-three,puppet-four" | script
output required:
docker-one,docker-three
awk to the rescue!
echo "docker-one,puppet-one,puppet-two,docker-three,puppet-four" |
awk 'BEGIN{RS=ORS=","} /puppet/'
puppet-one,puppet-two,puppet-four
for docker, and replacing the last comma
echo "docker-one,puppet-one,puppet-two,docker-three,puppet-four" |
awk 'BEGIN{RS=ORS=","} /docker/' |
sed 's/,$/\n/'
docker-one,docker-three
or, if you meant non puppet
echo "docker-one,puppet-one,puppet-two,docker-three,puppet-four" |
awk 'BEGIN{RS=ORS=","} !/puppet/' |
sed 's/,$/\n/'
docker-one,docker-three
It sounds like one of these might be what you're looking for:
$ echo "docker-one,puppet-one,puppet-two,docker-three,puppet-four" |
awk -F, '{for (i=1;i<=NF;i++) if ($i ~ /puppet/) printf "%s%s", (c++?FS:""), $i; print ""}'
puppet-one,puppet-two,puppet-four
$ echo "docker-one,puppet-one,puppet-two,docker-three,puppet-four" |
awk -F, '{for (i=1;i<=NF;i++) if ($i !~ /puppet/) printf "%s%s", (c++?FS:""), $i; print ""}'
docker-one,docker-three
$ echo "docker-one,puppet-one,puppet-two,docker-three,puppet-four" |
awk -F, '{for (i=1;i<=NF;i++) if ($i ~ /docker/) printf "%s%s", (c++?FS:""), $i; print ""}'
docker-one,docker-three
Using native bash regEx operator ~ and using GNU paste for csv formatting alone,
IFS="," read -ra myArray <<<"docker-one,puppet-one,puppet-two,docker-three,puppet-four"
for i in "${myArray[#]}";do [[ $i =~ ^puppet ]] && echo "$i" ; done | paste -sd ','
produces an output as
puppet-one,puppet-two,puppet-four
and for the other strings than the ones starting with puppet, do a negative regex match,
for i in "${myArray[#]}";do [[ ! $i =~ ^puppet ]] && echo "$i" ; done | paste -sd ','
docker-one,docker-three
Using tr, grep, and paste:
$ echo "docker-one,puppet-one,puppet-two,docker-three,puppet-four" \
| tr , '\n' | grep -v puppet | paste -s -d , -
docker-one,docker-three
I have this shell script variable, var. It keeps 3 entries separated by new line. From this variable var, I want to extract 2, and 0.078688. Just these two numbers.
var="USER_ID=2
# 0.078688
Suhas"
These are the code I tried:
echo "$var" | grep -o -P '(?<=\=).*(?=\n)' # For extracting 2
echo "$var" | awk -v FS="(# |\n)" '{print $2}' # For extracting 0.078688
None of the above working. What is the problem here? How to fix this ?
Just use tr alone for retaining the numerical digits, the dot (.) and the white-space and remove everything else.
tr -cd '0-9. ' <<<"$var"
2 0.078688
From the man page, of tr for usage of -c, -d flags,
tr [OPTION]... SET1 [SET2]
-c, -C, --complement
use the complement of SET1
-d, --delete
delete characters in SET1, do not translate
To store it in variables,
IFS=' ' read -r var1 var2 < <(tr -cd '0-9. ' <<<"$var")
printf "%s\n" "$var1"
2
printf "%s\n" "$var2"
2
0.078688
Or in an array as
IFS=' ' read -ra numArray < <(tr -cd '0-9. ' <<<"$var")
printf "%s\n" "${numArray[#]}"
2
0.078688
Note:- The -cd flags in tr are POSIX compliant and will work on any systems that has tr installed.
echo "$var" |grep -oP 'USER_ID=\K.*'
2
echo "$var" |grep -oP '# \K.*'
0.078688
Your solution is near to perfect, you need to chance \n to $ which represent end of line.
echo "$var" |awk -F'# ' '/#/{print $2}'
0.078688
echo "$var" |awk -F'=' '/USER_ID/{print $2}'
2
You can do it with pure bash using a regex:
#!/bin/bash
var="USER_ID=2
# 0.078688
Suhas"
[[ ${var} =~ =([0-9]+).*#[[:space:]]([0-9\.]+) ]] && result1="${BASH_REMATCH[1]}" && result2="${BASH_REMATCH[2]}"
echo "${result1}"
echo "${result2}"
With awk:
First value:
echo "$var" | grep 'USER_ID' | awk -F "=" '{print $2}'
Second value:
echo "$var" | grep '#' | awk '{print $2}'
Assuming this is the format of data as your sample
# For extracting 2
echo "$var" | sed -e '/.*=/!d' -e 's///'
echo "$var" | awk -F '=' 'NR==1{ print $2}'
# For extracting 0.078688
echo "$var" | sed -e '/.*#[[:blank:]]*/!d' -e 's///'
echo "$var" | awk -F '#' 'NR==2{ print $2}'
I'm doing a script shell and I want to read data inside a file. In the file, I have something like :
/path/to/file1 something 0
/path/to/file2 something2 1
/path/to/file3 something3 2
What I want is to get the third element of the line but I don't know how to do it.
In my code, I have:
while read line;
do
//must echo the third element of the line
done < file | sort -n -k 2 -t " "
I already tried with awk but it didn't work.
How should I do please ?
This works if fields are separated by space:
$ echo 'foo bar baz' | cut --delimiter=' ' --fields=3
baz
This works for most whitespace separators:
$ echo 'foo bar baz' | awk '{print $3}'
baz
you can try something like this;
while read line;
do
path=$(echo $line | awk '{print $1}')
secondColumn=$(echo $line | awk '{print $2}')
thirdColumn=$(echo $line | awk '{print $3}')
echo $path
echo $secondColumn
echo $thirdColumn
done < test
I am storing date inside a variable and using that in the sed as below.
DateTime=`date "+%m/%d/%Y"`
Plc_hldr1=`head -$i place_holder.txt | tail -1 | awk -F ' ' '{ print $1 }'`
Plc_hldr2=`head -$i place_holder.txt | tail -1 | awk -F ' ' '{ print $2 }'`
sed "s/$Plc_hldr1/$DateTime/;s/$Plc_hldr2/$Total/" html_format.htm >> /u/raskar/test/html_final.htm
While running the sed command I am getting the below error.
sed: 0602-404 Function s/%%DDMS1RT%%/01/02/2014/;s/%%DDMS1C%%/1235/ cannot be parsed.
I suppose this is happening as the date contains the following output which includes slashes '/'
01/02/2014
I tried with different quotes around the date. How do I make it run?
Change the separator to something else that won't appear in your patterns, for example:
sed "s?$Plc_hldr1?$DateTime?;s?$Plc_hldr2?$Total?"
Not the direct quertion but replace
Plc_hldr1=`head -$i place_holder.txt | tail -1 | awk -F ' ' '{ print $1 }'`
Plc_hldr2=`head -$i place_holder.txt | tail -1 | awk -F ' ' '{ print $2 }'`
by
Plc_hldr1=`sed -n "$i {s/ .*//p;q}"`
Plc_hldr2=`sed -n "$i {s/[^ ]\{1,\} \{1,\}\([^ ]\{1,\}\) .*/\1/p;q}"`
and with aix/ksh
sed -n "$i {s/\([^ ]\{1,\} \{1,\}[^ ]\{1,\}\) .*/\1/p;q}" | read Plc_hldr1 Plc_hldr2