GORM converts query text into lowercase - go

response := db.Where("createdAt BETWEEN ? AND ?", today, tomorrow).Find(&orders)
I want to make a query with GORM. The column in my table is named "createdAt" but GORM converts it to. "createdat"
ERROR: column "createdat" does not exist (SQLSTATE 42703)
[172.521ms] [rows:0] SELECT * FROM "Orders" WHERE `createdAt` BETWEEN '2021-04-21 04:00:00' AND '2021-04-22 04:00:00'
How can I prevent GORM from converting the query text to lowercase?

Its not gorm's issue its database issue means in database column is created with name created_at just check there and try replacing your code with this
response := db.Where("created_at BETWEEN ? AND ?", today, tomorrow).Find(&orders)

If you use case sensitive column name, use \",ex: \"createdAt\", No modern database cannot handle upper or lower case text.

Related

How to update table from JSON flowfile

I have a flow-files with the below structure
{
"PN" : "U0-WH",
"INPUT_DATE" : "44252.699895833335",
"LABEL" : "Marker",
"STATUS" : "Approved",
}
and I need to execute an update statement using some fields
update table1 set column1 = 'value' where pn=${PN}
I found convertJsonToSQL but am not sure how to use it in this case
You can use a processor namely ConvertjSONToSQL. Using this you can convert your json into an update query.
ConvertjSONToSQL Description
It takes the following parameters :
1. JDBC Connection Pool : Create a JDBC pool which takes DB connection information as input.
2. Statement Type : Here you need to provide type of statement you want to create. In your case its 'UPDATE'.
3. Table Name : Name of the table for which update query needed to be created
4. Schema Name : Name of the schema of your database.
5. Translate Field Names : If true, the Processor will attempt to translate JSON field names into the appropriate column names for the table specified. If false, the JSON field names must match the column names exactly, or the column will not be updated
6. Unmatched Field Behaviour : if an incoming JSON element has a field that does not map to any of the database table's columns, this property specifies how to handle the situation
7. Unmatched Column Behaviour : If an incoming JSON element does not have a field mapping for all of the database table's columns, this property specifies how to handle the situation
8. Update Keys : A comma-separated list of column names that uniquely identifies a row in the database for UPDATE statements. If the Statement Type is UPDATE and this property is not set, the table's Primary Keys are used. In this case, if no Primary Key exists, the conversion to SQL will fail if Unmatched Column Behaviour is set to FAIL. This property is ignored if the Statement Type is INSERT
Supports Expression Language: true (will be evaluated using flow file attributes and variable registry)
Read the description above and try to use the properties given. Detailed description of the processor is given in the link.
ConvertjSONToSQL Description

How to match exact Id within Comma seperated database column using LINQ and Lambda

Hi I have SQL Table where I am storing values like this:
Column Name: Registration_ID
180,1801,1803,18011,220
180,1801,
180,1801,1803
No I want to match exact Registration_ID and get records based on the Registration_ID. I have tried Contains but is not matching exact values.
Here is my query:
var Result=db.Entity_StudentRepository.Get(x =>
x.Registration_ID.Contains(Used_For_Id.ToString())).Select(x => x.Registration_ID).ToArray();
Could you please try the following query and let know if it works-
db.Entity_StudentRepository.AsEnumerable().Where(t=> Registration_ID.Split(',').Select(int.Parse).Contains(Used_For_Id));

Laravel query builder - Select elements unique or null on specific column

I have a model Form for table forms. There is a column called guid which can be null, or contain some sort of grouping random hash.
I need to select all forms that have column guid either null or unique in current search. In other words, for repeating guid values in current search I select only first occurence of every guid hash.
I tried:
$results = App\Form::where(... some where clauses .. ).groupBy('guid')
and it's almost ok, but for all rows, where guid == NULL it groups them and selects only one (and I need all of them).
How can I get the unique or null rows either by building proper SQL query or filtering the results in PHP?
Note: I need my $results to be an Illuminate\Database\Eloquent\Builder instance
EDIT:
I fount out that SQL version of query I need is:
SELECT * FROM `forms` WHERE .... GROUP BY IFNULL(guid, id)
What would be equivallent query for Laravel's database query builder?
UPDATE: Using DB::raw
App\Form::where(... conditions ...)
->groupBy(DB::raw("IFNULL('guid', 'id')"));
Or the another way could be:
You can also use whereNotNull, whereNull & at last merge both the collections using merge() like this:
First get the results where guid is grouped by (excluding null guid's here):
$unique_guid_without_null = App\Form::whereNotNull('guid')->groupBy('guid')->get();
Now, get the results where guid is null:
$all_guid_with_null = App\Form::whereNull('guid')->get();
and at last merge both the collections using merge() method:
$filtered_collection = $unique_guid_without_null->merge($all_guid_with_null);
Hope this helps!
For your edited question, you can use raw() as;
->groupBy(DB::raw("IFNULL('guid', 'id')"))
So your final query will be as:
$results = App\Form::where(... some where clauses .. )
->groupBy(DB::raw("IFNULL('guid', 'id')"));
By above query, your $results will be an instance of Illuminate\Database\Eloquent\Builder.

Set a data to a specific name with spring & mongodb

My json data
[{"cameraid":"000000001","timestamp":"2016-06-17 23:08","filename":"7e3800fbd0557c683874ed2f41ed7057"},
{"cameraid":"000000002","timestamp":"2016-06-17 23:08","filename":"b260cc730da88a6af4e5038d6e1e32db"}]
How can i have cameraid to link to a specific name?
Like example my cameraid "000000001" to be call as bedok.
Anybody got any idea on how to do it?
Create another collection with names(lets call it db_name) and link the cameraid to the _id of db_name collection. This way you can fetch the names using cameraid. This is more like primary key and foreign key concept in relational database(RDBMS).
More on this with code here: Primary Key and Foreign Key Concept in MongoDB
Assuming you want to add a name field for specific cameraid,
Try following query:-
db.collname.update({"cameraid":"000000001"},{$set : {name : 'bedok'}});
EDIT:-
The above query will update only one record which matches the query {"cameraid":"000000001"}.
Add multi:true to the query, to multiple records.
db.collname.update({"cameraid":"000000001"},{$set : {name : 'bedok'}},{multi : true});
Now it will update all the records that matches the query {"cameraid":"000000001"}.

error using regexp_extract to extract a particular part of the string from Hive

I have a table with a column that has urls. I want to query out a particular url param value from each record. the url param can occur in any position in the url data and the url can contain hashbangs and this param can contain special chars like -, _ and |.
data table column:
url
http://www.url.com?like=hobby&name=tom-_green
http://www.url.com?name=bob|ghost&like=hobby
and I want the query results to be
name
srini
tom-_green
bob|ghost
I tried a query like
Select regexp_extract(url, '(?<=name=)[^&?]*(?:|$&)',2) as name
From table_name
I see java exceptions when I run this query. the exceptions are pretty vague and checking if someone can help.
I found another Hive implementation for handling URLs specifically..
Select parse_url(url, 'QUERY', 'name') as name From table_name and this worked :)
ref: parse_url(string urlString, string partToExtract [, string keyToExtract])
https://cwiki.apache.org/confluence/display/Hive/LanguageManual+UDF

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