How to remove git bash ssh authentication on windows - windows

Whenever i go to do some operation on Windows involving my remote repository like git pull, git remote update or git push (among others) Windows keeps asking me to inform my SSH key. Is there any way to stop this?

Yes. As described at: https://docs.github.com/en/authentication/connecting-to-github-with-ssh/working-with-ssh-key-passphrases#auto-launching-ssh-agent-on-git-for-windows
You can run ssh-agent automatically when opening bash or the Git
shell. Copy the following lines and paste them into the ~/.profile
or ~/.bashrc file in Git Shell:
# Auto-launching ssh-agent on Git for Windows
env=~/.ssh/agent.env
agent_load_env () { test -f "$env" && . "$env" >| /dev/null ; }
agent_start () {
(umask 077; ssh-agent >| "$env")
. "$env" >| /dev/null ; }
agent_load_env
# agent_run_state: 0=agent running w/ key; 1=agent w/o key; 2=agent not running
agent_run_state=$(ssh-add -l >| /dev/null 2>&1; echo $?)
if [ ! "$SSH_AUTH_SOCK" ] || [ $agent_run_state = 2 ]; then
agent_start
ssh-add
elif [ "$SSH_AUTH_SOCK" ] && [ $agent_run_state = 1 ]; then
ssh-add
fi
unset env
But in my case I didn't have those files mentioned so what I did was create in my C:\Users\<username> directory a file called .bashrc and paste the code indicated.
It could be that the first time you open your git bash or try to do some operation involving the remote it will ask you for your password, but after you enter this first time it will not ask for any more.

Related

Alias command incorrectly executing

I am attempting to load my git aliases from a gist on github. For some reason, the command executes find, but when I attempt to execute any of the aliases, they are either incorrectly mapped — e.g., gsts -> git stash instead of gsts -> git status — or they are not mapped at all.
#!/bin/bash
update_git_aliases(){
GIST_URL='https://gist.githubusercontent.com/Moyoka22/ec605b0b52fee6d6d30d5f72822938f4/raw/git-aliases'
RESPONSE="$(wget --no-cache -qO- ${GIST_URL})"
if [ ${?} -ne 0 ]
then
echo 'Download failed. Exiting.'
return 1
fi
echo ${RESPONSE} > ${1}
chmod +x ${1}
}
DOWNLOAD_FAILED=0
ALIAS_FILE="${HOME}/.config/git-aliases"
if [ ! -f ${ALIAS_FILE} ]
then
echo "Git aliases not found! Downloading..."
update_git_aliases ${ALIAS_FILE}
DOWNLOAD_FAILED=${?}
fi
if [ ${DOWNLOAD_FAILED} -ne 0 ]
then
echo "Downloading aliases failed."
exit 1
fi
cat ${ALIAS_FILE} | bash
I assume you want the aliases on your interactive shell, so remove the last cat as it's useless and once ${HOME}/.config/git-aliases is created
$ source "${HOME}/.config/git-aliases"
The alias commands must be run in your current shell process to have an effect.
cat ${ALIAS_FILE} | bash executes the alias commands in ALIAS_FILE in a new child process, not your shell, and not the program's shell.
source runs the commands in the current shell. You need to source the file from your current shell, not from the program. You can do this after the file is updated. In order to make this permanent, you will need to add source "${HOME}/.config/git-aliases" to your shell config.
What many programs like this do is print out the necessary commands at the end.
echo "$ALIAS_FILE updated"
echo "Make sure `source $ALIAS_FILE` is in your $HOME/.bash_profile"
echo "Run `source $ALIAS_FILE` to use it in your current shell"

bash, script to git add one file and commit

I'm trying to create a script to do this:
git add "file"
git commit -m "Comment"
My idea is to run:
gac "file" "Comment"
I know I can do something similar but for all files, with:
echo 'alias gac="/path/to/gitaddcommit.sh"' >> ~/.bash_profile
And the .sh would be:
!/bin/bash
git add .
echo “Enter commit message: “
git commit -am “$commitMessage”
Well you need two things :
A bin folder where you can put every sh script you want to use everywhere.
More knowledge about shell scripting and how you can get argv (in your ex: 'file' 'Comment')
So first go to your /home/<username> then mkdir bin && cd bin && pwd
then copy the pwd and add it into your PATH env variable inside your .bashrc
path example: PATH='/bin/:/sbin/:/home//bin
Then source ~/.bashrc you can now use every sh script inside you bin folder everywhere.
Cool so first problem done !
you don't have to do echo alias gac="/path/to/gitaddcommit.sh"' >> ~/.bash_profile anymore.
Now second problem here a post that can help you post
And let me show you for your example :
cd ~/bin && vi gac.sh
Now the script :
#!/bin/sh
if [ "$#" -ne 2 ]; then
echo "Usage: ./gac FILENAME COMMIT_MESSAGE" >&2
exit 1
fi
git add "$1"
git commit -am "$2"
First we check the number or arg then git add and commit.
Simple and fast maybe checking if arg one is a file might be a good idea too.
PS: i'm going to re write my post ahah
Here's what I have in my .bashrc:
ga ()
{
if test "$1" != "-f" && git rev-parse HEAD > /dev/null 2>&1 && ! git diff-index --quiet HEAD; then
echo 'Repo is dirty. -f to force' 1>&2;
return 1;
fi;
git add "$#";
list=$(git diff --name-only --cached | tr \\n \ );
git commit -m "Add $list"
}
The commit message is autogenerated, but you could easily modify it to prompt the user or take it from somewhere else.

terminal title not setting within screen

Currently, I'm setting terminal title within screen command, but the bash script gives me:
Cannot exec 'source /etc/profile && title.set root#test': No such file or directory
And I can run above command successful directly from the command line, here are my scripts:
/usr/local/bin/s
#!/bin/bash
if [ $1 ]
then
screen -D -R $1 -m "source /etc/profile && title.set `whoami`#$1"
else
screen -R
fi
/etc/profile
...
# Source global bash config
if test "$PS1" && test "$BASH" && test -z ${POSIXLY_CORRECT+x} && test -r /etc/bash.bashrc; then
. /etc/bash.bashrc
fi
function title.set() {
if [[ -z "$ORIG" ]]; then
ORIG=$PS1
fi
TITLE="\[\e]2;$*\a\]"
PS1=${ORIG}${TITLE}
}
# Termcap is outdated, old, and crusty, kill it.
unset TERMCAP
# Man is much better than us at figuring this out
unset MANPATH
...
So What's going wrong here?
The keyword source is a bash built-in command, i.e., something for which there is not necessarily an actual file to exec (another built-in command). You can only exec something that is a file — like bash, e.g., something like this:
screen -D -R $1 -m bash -c "source /etc/profile && title.set `whoami`#$1"

Automatically launch command when cd into a choosen directory

I would like to launch : $ git status
when I cd into ~/work
I thought about putting an alias that would cd me into the work directory and launch the git status, but I don't find that solution to be optimal.
Add this to your .bashrc:
gitstatusinwork() {
if [[ "$PWD" != "$MYOLDPWD" ]]; then
MYOLDPWD="$PWD"
if [[ "$PWD/" = ~/work/* ]]; then
if [[ "$OLDPWD" != ~/work/* && "$INWORKDIR" == 0 ]]; then
git status
fi
INWORKDIR=1
else
INWORKDIR=0
fi
fi
}
export PROMPT_COMMAND="$PROMPT_COMMAND; gitstatusinwork"
This function executes git status as soon as your enter your ~/work directory (or any of its subdirectory), then never displays it again, unless you get out of the ~/work directory and re-enter it again.
The easiest way is:
cd ~/work && git status
I don't think you're looking for this though.
Another option would be overwriting the default cd command. You could place a bash function at the end of your .bashrc or .bash_profile file like so:
cd() {
builtin cd "$1"
# detect if the current directory is a git repository
if [ -d .git ] || git rev-parse --is-inside-work-tree 2> /dev/null > /dev/null; then
echo ""; git status
fi
}
I hope this helps.
Update:
If you just want to see the git status when you cd into the root of your repo, you can just use the first part of the conditional like so:
cd() {
builtin cd "$1"
# detect if the current directory is a git repository
if [ -d .git ]; then
echo ""; git status
fi
}

SSH into remote computer and compile/run code

I made a script (below) that goes into a remote computer and runs C code on it. This script works perfectly but asks for the password multiple times. How can I make it only ask for the password once?
#!/bin/bash
USER=myusername
COMP=remote_computer_name
OUTPUT=$1
ARGS=${#:2}
CODE_DIR="Dir_$$"
SCRIPT_NAME=$(basename $0)
LAST_CREATED_DIR=$(ls -td -- */ | head -n 1)
#Check if we are on local computer. If so, we copy the
#current directory to the remote run this script on the remote
if [ "${HOSTNAME}" != "${COMP}" ]; then
if [ "$#" -lt 1 ]; then
echo "Incorrect usage."
echo "Usage: ./${SCRIPT_NAME} <compiled_c_output_name> <arg1> <arg2> ... <argN>"
exit
fi
# Check if there is no makefile in the current directory
if [ ! -e [Mm]akefile ]; then
echo "There is no makefile in this directory"
exit
fi
echo "On local. Copying current directory to remote..."
scp -r ./ ${USER}#${COMP}:/ilab/users/${USER}/${CODE_DIR}
ssh ${USER}#${COMP} "bash -s" < ./${SCRIPT_NAME} ${OUTPUT} ${ARGS}
else
echo "On remote. Compiling code..."
cd $LAST_CREATED_DIR
make clean
make all
if [ -e $OUTPUT ]; then
echo "EXECUTING \"./${OUTPUT} ${ARGS}\" ON REMOTE ($COMP)"
./${OUTPUT} ${ARGS}
fi
fi
You can use SSH-Key authentication technique for password less login -
Here are the steps :
Generate RSA key -
ssh-keygen -t rsa
This generates two files under /home/<user>/.ssh/ id_rsa
(Private) and id_rsa.pub (Public)
The second file is your public key. You have to copy the contents of
this file over to the remote computer you want to log into and append
it to /home/<user>/.ssh/authorized_keys or use ssh-copy-id
utility if available (ssh-copy-id username#remote_host)
After this, the authentication is done by the public-private key pair
and you may not require a password henceforth.
You can use sshpass. Here is an example:
sshpass -pfoobar ssh -o StrictHostKeyChecking=no user#host command_to_run
More info, here:
https://askubuntu.com/questions/282319/how-to-use-sshpass

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