JqGrid - updating the values in all data cells - jqgrid

My JqGrid looks like this:
Staff
Room 1
Room 2
Jim
240
120
Dave
480
240
The staff and rooms are obtained from tables and are unknown in number at runtime. The figures (data) represent the total time spent by each staff in each room and are in minutes. I have all the above working.
All I want to do now is to iterate over all the data entries and change minutes (Eg: 240) to hours and minutes (EG 4h:0m). I'm ok with doing the math for the conversion, it's the looping over the cells and the reading and updating (just the displayed value) that has defeated me.
This is my code so far for the looping:
var $grid = jQuery('#statstab1grid')
var rows = $grid[0].rows
var crows = rows.length
var irow, row, cellsofrow
for (irow = 1; irow < crows; irow++)
{
row = rows[irow];
cellsofrow = row.cells;
alert('$(cellsofrow[0]).text() is ' + $(cellsofrow[0]).text())
alert('$(cellsofrow[1]).text() is ' + $(cellsofrow[1]).text())
}
The first alert outputs Jim then Dave, the second alert outputs nothing,
just the prompt. Even if I managed to access the data values, how would I write back to the grid the modified values?

It is good to post which version of jqGrid is used. This one is the important part.
The code you posted and your comments that nothing is alerted for cell index 1, can tell me that maybe you have a hidden field in your colModel, which value is empty. In this case it would be good to post your entire grid setup.
To the problem - you have a lot of options to do this conversion.
You can use custom formatter - more about this you can find here. This method is preferred.
You can use getRowData (without parameter) to get all the data in the grid and use setRowData to update the values. Be a careful with this method if you have a lot of data in the grid - it will be slowly in this case. See docs for grid methods
If your data is local (array) you can recalculate it, before to put it into the grid

Related

HandsonTable not rendering all rows

HandsonTable is not rendering all rows - it loads only part of all rows. But when I do Ctrl+A and paste into Excel I see all the rows. Why is Handsontable not displaying all the rows?
<hot-table col-headers="true" row-headers="true" datarows="data" context-menu width="1080">
<hot-column ng-repeat="column in columns" data="{{column.data}}"></hot-column>
</hot-table>
To render all rows, just set renderAllRows: true
The current answer does not answer the original question.
Handsontable does not render all cells at once because it is designed to be efficient for very large data sets. It does this using virtual rendering, dynamically modifying the DOM to include only the cells at the scroll position.
The rows virtual rendering can be disabled by setting renderAllRows: true, as described in the docs: "If typed true then virtual rendering mechanism for handsontable will be disabled." Although it will then not be as efficient for large data sets.
You can also change the number of pre-rendered rows and columns instead of rendering them all. From the performance tips,
You can explicitly specify the number of rows and columns to be rendered outside of the visible part of the table. In some cases you can achieve better results by setting a lower number (as less elements get rendered), but sometimes setting a larger number may also work well (as less operations are being made on each scroll event). Tweaking these settings and finding the sweet spot may improve the feeling of your Handsontable implementation.
This is done by setting viewportRowRenderingOffset and viewportColumnRenderingOffset in the handsontable options. These are by default set to auto which lets handsontable try to find the best value, but may be provided an integer value (e.g. viewportRowRenderingOffset: 70, viewportColumnRenderingOffset: 70).
I had the same problem (using HandsOnTable 6.2.1 and the old AngularJS) and customers would start complaining about not being sure if they were at the end of the table or not.
I was able to create two buttons linked to the functions 'scrollToBeginning' and 'scrollToEnd'. This way the user is sure to be at the last line. Three things specific about my answer:
I expose the functions to the DOM using $scope;
I have an object 'goToLine' holding 3 properties (scrollingToEnd: boolean, row: number, col: number), it is used in other functions not posted here;
I have a list of ID referencing HandsOnTable objects stored in $scope.hots.
Here is my raw solution, feel free to adapt / enhance:
$scope.stopScrollingToEnd = function () {
$scope.goToLine.scrollingToEnd = false;
};
$scope.scrollToBeginning = function (goToLine) {
$scope.stopScrollingToEnd();
const hot = $scope.hots[goToLine.id];
hot.scrollViewportTo(0, 0);
};
/**
* Scroll to the end of the List Element.
* We need this functionality because of a bug in HandsOnTable related to its Virtualization process.
* In some cases (complex table), when manually scrolling, the max row is wrong, hence causing major confusion for the user.
* #param {*} goToLine
* #returns
*/
$scope.scrollToEnd = function (goToLine) {
// We scroll to the first line before going to the last to avoid the bug and being sure we get to the last line
$scope.scrollToBeginning(goToLine);
const hot = $scope.hots[goToLine.id];
var numberOfRows = hot.countRows();
// This variable is used to repeat the scrollViewportTo command.
// It is built using the length of `numberOfRows`.
var repeat = numberOfRows ? 1 * Math.ceil(Math.log10(numberOfRows + 1)) : 1;
// Used in other goTo function to avoid conflict.
$scope.goToLine.scrollingToEnd = true;
// FIXME : not supposed to call scrollViewportTo several times... => fixed in recent versions of HandsOnTable ?
for (let n = 0; n < repeat; n++) {
if (!$scope.goToLine.scrollingToEnd) {
return;
}
setTimeout(function () {
if (!$scope.goToLine.scrollingToEnd) {
return;
}
hot.scrollViewportTo(numberOfRows - 1, 0);
}, 500);
}
};

jqGrid: update a row AND have its formatters updated as well

Ideally I would call setRowData and have my cell formatters and rowattr function re-run, but cell formatters and rowattr functions don't re-run when calling setRowData (I don't know why but that's another question maybe), so setRowData isn't really helpful for me.
It seems the next easiest thing to do would be to remove a row and re-add a new one at the same position with the same model. To do that I need to get the rowid of the row above the selected row so that I can call addRowData and specify the ID of the row above in srcrowid and use 'after' for the position. This is what I'm thinking:
$.jgrid.extend({
updateRow: function(rowid, model){
// get index from id
var index = this.jqGrid('getInd', rowid);
// note: my first row's index is 1 (is that normal?)
if ( index == 1 ){
position = 'first';
srcrowid = 'n/a';
}
else{
position = 'after';
srcrowid = _____ how to get rowid of row above selected row _____???
}
// delete row
this.jqGrid('delRowData', rowid);
// insert at index
this.jqGrid('addRowData', rowid, model.attributes, position, srcrowid);
}
});
How can I get the rowid of the row above the selected row? (Is there an easier way? Is this a bad strategy?)
Note: I'm using backbone.js collections and models
I find the best way to change the row is to use setRowData instead of usage delRowData and addRowData. If you know rowid then you can use $("#" + rowid); (or if rowis have special characters like :, . an so on then $("#" + $.jgrid.jqID(rowid));) to get the <tr> element. Then you can use jQuery.addClass, jQuery.css, jQuery.attr to change the attributes of the row.
It's important to understand that jqGrid uses the same methods internally it it's required to modify element of the grid. The main goal of rowattr is another one. During filling of the grid data there are many scenarios. One can create DOM elements for <td> and <td> and insert there in the grid. The main problem is performance in case of working with DOM. It's much slowly as building of strings. Moreover DOM is even much more slowly if the elements are exist on the the HTML page (in opposite to disconnected elements). If one modify one element only from the grid having 500 rows then the position of elements of all other rows need be recalculated.
Because of the problem jqGrid construct the whole body of the grid first in string format and then assign all <tr> and <td> elements using one set of innerHTML. It improves dramatically the performance of filling of the grid. See the answer for additional information. The formatters and callbacks cellattr and rowattr are introduced to allow to customize cell and row attributes during building of grid body in string format. It gives you customization possibilities without reducing of performance.
On the other side if you need to modify the row which are attached already on HTML page then you will have no advantage with working with strings instead of DOM. Because of that I recommend you just use jQuery.addClass, jQuery.css, jQuery.attr directly. If you need to change multiple classes, assign multiple css rules or multiple attributes then you should use one call of above functions. You can use object form of jQuery.css, jQuery.attr for it.
The updateRow extension below works, BUT I ended up not using it. Not so much for the reasons Oleg talked about (which I assume are valid and something you should definitely consider), but because I had a filter provider that was too difficult to sync with (e.g. after soft deleting a row, I need to now determine if new deleted status agrees with current filter...and that's a pretty simple example). So I just defer to the data the filter provider gives me and repopulate the grid each time, which I'm not fond of, but I don't see other easy options.
As far as the extension below goes, here are pros/cons as I see them:
Pros:
easy to use
You just rely on the rowattr functions and cell formatters you already defined. You don't have to write those twice.
Cons:
possibly performance--see Oleg's answer
please add any you see
Unknowns:
performance? I have no idea how much worse it performs. It would be interesting to do benchmarks with different browsers. I saw no problems, but I only have maybe 20 rows. Let's say we're working with 500 rows and adding/removing classes and calling .css() took 30 ms but using the extension took 300 ms on a 'typical' machine/browser. That would be 10 times slower, but for me it would probably be worth it because I don't have to write something twice.
here's the extension:
$.jgrid.extend({
updateRow: function(rowid, data){
// get index from id
var index = this.jqGrid('getInd', rowid);
// note: my first row's index is 1 (is that normal?)
if ( index == 1 ){
position = 'first';
}
else{
position = 'after';
srcrowid = $(this).find('tr#' + rowid).prev()[0].id;
}
// delete row
this.jqGrid('delRowData', rowid);
// insert at index
this.jqGrid('addRowData', rowid, data, position, srcrowid);
}
});

Programatically updating underlying data in Slickgrid

I have 6 textboxes at the top of the screen that update an entire column(one textbox per column) based on any changes. I was selecting the columns based on their class (.l#). Here is the code (issues to follow):
function UpdateField() {
var ctrl = this;
var id = parseInt(ctrl.id.replace("item", ""), 10) - 1;
var bound = [".l1", ".l7", ".l8", ".l9"];
var fields = $(bound[id]);
for (var i = 0; i < fields.length; i++)
{
fields[i].innerHTML = $(ctrl).val();
}
};
which is bound to the keyup event for the text areas. Issues are:
1) initially fields.length was -1 as I didn't want to put data in the "add new
row" section at the bottom. However, when running it, I noticed the
final "real" record wasn't being populated. Also, when stepping through, I
noticed that the "new row" field was before the "last row" field.
2) when doing it this way, it is purely superficial: if I double click the field,
the real data hasn't been changed.
so in the grand scheme of things, I know that I was doing it wrong. I'm assuming it involves updating the data and then forcing a render, but I'm not certain.
Figured out how to do it. Modified the original code this way:
function UpdateField() {
var ctrl = this;
var id = parseInt(ctrl.id.replace("item", ""), 10) - 1;
var bound = ['title1', 'title2', 'title3', 'title4'];
var field = bound[id];
for (var i = 0; i < dataView.getLength(); i++)
{
var item = dataView.getItem(i);
item[field] = $(ctrl).val();
dataView.updateItem(i, item);
}
grid.invalidate();
};
I have 6 textboxes (item1-item6) that "bind" to fields in the sense that if I change data in a textbox, it updates all of the rows and any new rows added also have this data.
Parts where the two issues can be explained this way:
1) to work around that, though still it would be a presentational fix and not a real updating of the underlying data, one could force it to ignore if it had the active class attached. Extra work, and not in the "real" direction one is going for (masking the field).
2) It was pretty obvious with the original implementation (though it was all I could figure out via Chrome Dev Tools that I could modify at the time) that it was merely updating a div's content and not actually interacting with the data underneath. Would look nice, and perhaps one could just pull data from the item1-item6 boxes in place of the column if it is submitted, but if someone attempts to modify the cell, they'll be looking at the real data again.

How to select a row in kendo grid by data item ID?

I need to select a specific row in kendoGrid but NOT by data-uid (as data-uid is changed when the grid dataSource is loaded again) but by the row itemID. I saw posts but they only select the row by uid which is not what I needed, I actually need to restart the HTML5 application and when grid is loaded, a specific item should be selected. This is what I've been seeing
Demo: jsfiddle.net/rusev/qvKRk/3/
e.g. the object has OrderID as ID, and every time the grid is loaded, it will be the same, unlike uid, I want to know how will I be able to select a row with OrderID, instead of uid.
You cam mix row itemID and data.uid, I guess.
var grid = $("#Grid").data("kendoGrid");
var dataItem = $("#Grid").data("kendoGrid").dataSource.get(itemID);
var row = $("#Grid").data("kendoGrid").tbody.find("tr[data-uid='" + dataItem.uid + "']");
Going along with what umais has mentioned, the better approach, since there is no built in functionality for this as of yet, would be to iterate through all the records to find the one you need. The function that I built will work even if there are pages of data. The only other way that I can think of doing this would be do do a secondary ajax call; But this works well. Note that i haven't tested it with more than 2000 records.
var dataGrid = $("#GATIPS").data("kendoGrid").dataSource;
var numOfRows = dataGrid.total();
var currentPageSize = dataGrid.pageSize();
dataGrid.pageSize(numOfRows);
var dataGridData = dataGrid.data();
for (var i = 0; i < numOfRows; i++) {
if (dataGridData[i].uid == e)
return dataGridData[i];
}
dataGrid.pageSize(currentPageSize); // reset the view
e is the UID. However this can be substituted for what ever variable you need just replace the check.
a work around that I managed to have, was to go through all rows and check which row model has that ID equal to the parameter, and then get that row data-uid and select the item through data-uid. It's working fine for me, since there were no suggestion, it's the better answer for now.
Well, accordingly to what I have done (and worked for me), and even though the work around isn't the prettiest, set one more Column, with your model id and with ClientTemplate then create any html object (div in my case) inside it give it a html id of your id, so when ever you need it, you just have to go and look with something like:
grid.dataItem($("td div#id").closest("tr"));
Because remember that the dataItem method is waiting for a selector then you get your selectedItem as regular one.
EDIT:
I forgot to say, that you should (or could) use the style property
display:none
If you don't want to display that col.

jqgrid: How to format master/detail grids?

I have a jqgrid with a subgrid.
I am attempting to apply different colors to master and detail grids. I have two rules: the first one is to alternate odd and pair colors and the other one is to apply specific CSS to the row, based on values of a specific field.
Both master & details grid, contains the following gridComplete functions, where obviously childnodes index varies cause tables contains different fields:
gridComplete: function () {
var _rows = $(".jqgrow");
for (var i = 0; i < _rows.length; i++) {
_rows[i].attributes["class"].value += " " + _rows[i].childNodes[4].textContent;
_rows[i].attributes["class"].value += " " + _rows[i].childNodes[4].innerText;
}
applyZebra("jqTicketgrid");
}
applyZebra function provides to alternate odd/pair colours and has already been tested on another grid which not contains a subgrid.
For the record, I found above solutions in other solved questions of this forum, and both works with "simple" jqgrids (not master/detail).
PROBLEM
The master grid is formatted only when I click to expand the detail rows, while detail subgrid never alternate colours, neither apply format based on cell contents...
Where I am wrong? Pheraps I must intercept another event which is not gridComplete? Otherwise with grid&subgrids it's impossible to use _rows[x] & childNodes[y] attributes?
Please ask for clarifications, if needed, thx.
Thanks in advance!
I suppose the error in your code is that you use $(".jqgrow") instead of $(".jqgrow", this) where this inside of gridComplete will be either DOM element of the <table> of the grid or the subgid (I suppose you use grid as subgrid).
Additionally I would not recommend you to use you current code at all. It's much more effective and simple to to use cellattr. The rawObject parameter allow you access all other cells of the current row. In the answer you will find an example of implementation.

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