I'm trying to overload << to print the protected members of a class as a string, but when I try to use it in another class doing std::cout << player2; I get "0x7f60b0100" as output.
"player2" is an Actor*, so I'm not sure what's happening.
class Actor {
private:
string type;
protected:
int health;
int damage;
vector<MoveType> moves;
public:
Actor(string type, int health): type{ type }, health{ health }{damage=0;}
virtual void Hit(int damage){health = health-damage;}
virtual void Heal(int amount){health=+amount;}
const vector<MoveType>& GetMoves() const {return moves;}
bool IsDead() { return health <= 0; }
friend ostream& operator<<(ostream& out, const Actor& actor){
return (out << "DAMAGE DONE: " << actor.damage << "HEALTH: "<< actor.health);
}
};
As you've said it's a pointer to an Actor instance, so that's what you get printed, the value of this pointer.
You need to derefernce the pointer:
std::cout << *player2;
Related
I have implemented a custom container (same vein as std::vector) and I am trying to make it so that its 'push_back' function would use leverage on move semantics to avoid creating a copy of whatever is being pushed back - specially when the object to be pushed into the container is returned by an external function.
After reading quite a bit about move semantics and custom containers, I still can't find why my approach is still generating a copy instead of just moving the passed object into the container's inner dynamic array.
Here is a simplified version of my container looks like:
template<class T>
class Constructor
{
private:
size_t size = 0;
size_t cap = 0;
T *data = nullptr;
public:
Constructor()
{
cap = 1;
size = 0;
data = static_cast<T*>(malloc(cap * sizeof(T)));
}
~Constructor()
{ delete[] data; }
template<typename U>
void push_back(U &&value)
{
if (size + 1 >= cap)
{
size_t new_cap = (cap * 2);
T* new_data = static_cast<T*>(malloc(new_cap * sizeof(T)));
memmove(new_data, data, (size) * sizeof(T));
for (size_t i = 0; i<cap; i++)
{
data[i].~T();
}
delete[] data;
cap = new_cap;
data = new_data;
new(data + size) T(std::forward<U>(value));
}
else
{
new(data + size) T(std::forward<U>(value));
}
++size;
}
const T& operator[](const size_t index) const //access [] overloading
{
return data[index];
}
};
Here is a custom class that will print messages when its instances are created, copied or moved, in order to help debugging:
class MyClass
{
size_t id;
public:
MyClass(const size_t new_id)
{
id = new_id;
std::cout << "new instance with id " << id << std::endl;
}
MyClass(const MyClass &passedEntity)
{
id = passedEntity.id;
std::cout << "copied instance" << std::endl;
}
MyClass(MyClass &&passedEntity)
{
id = passedEntity.id;
std::cout << "moved instance" << std::endl;
}
void printID() const
{
std::cout << "this instance's id is " << id << std::endl;
}
};
And here is the external function:
MyClass &foo(MyClass &passed)
{
return passed;
}
Lastly, here is the main function that runs a test case using the above function and classes to show the problem:
int main()
{
MyClass a(33);
std::cout << std::endl;
std::cout << "Using my custom container: " << std::endl;
Constructor<MyClass> myContainer;
myContainer.push_back(foo(a));
myContainer[0].printID();
std::cout << std::endl;
std::cout << "Using dinamic array: " << std::endl;
MyClass *dinArray = static_cast<MyClass*>(malloc(1 * sizeof(MyClass)));
dinArray = new(dinArray + 1) MyClass(std::forward<MyClass>(foo(a)));
dinArray[0].printID();
std::cout << std::endl;
system("Pause");
return 0;
}
The output is:
new instance with id 33
Using my custom container:
copied instance
this instance's id is 33
Using dinamic array:
moved instance
this instance's id is 33
As it can be seen, if the instance of MyClass is put directly into a dynamic array, then just the move conmstructor is called and not the copy constructor. However, if I push_back the yClass instance into an instance of Container, a copy constructor is still being called.
Could someone help me understand what exactly am I doing wrong here? How could I make it so that elements are pushed into the container without generating a copy?
When you call this line
myContainer.push_back(foo(a));
L-value is passed into push_back method, and now read about using std::forward - http://www.cplusplus.com/reference/utility/forward/,
Returns an rvalue reference to arg if arg is not an lvalue reference.
If arg is an lvalue reference, the function returns arg without modifying its type.
and in your push_back you call
new(data + size) T(std::forward<U>(value));
but value was passed as L-value, and only constructor MyClass(const MyClass &passedEntity) can be invoked.
If you want a object to be moved, you can write
myContainer.push_back(std::move(a)); // cast to R-reference
EDIT
You should not use move in your push_back function, below is simple example.
Suppose you have class like this:
struct Foo {
int i;
Foo (int i = 0) : i(i) {
}
~Foo () {
}
Foo (const Foo& ) {
}
Foo& operator=(const Foo&) {
return *this;
}
Foo (Foo&& f)
{
i = f.i;
f.i = 0; // this is important
}
Foo& operator=(Foo&& f)
{
i = f.i;
f.i = 0; // this is important
return *this;
}
};
we have also 2 functions
template<class T>
void process1 (const T& ) {
cout << "process1" << endl;
}
template<class T>
void process (T&& obj) {
cout << "process2" << endl;
T newObj = forward<T>(obj);
}
and bars functions are counterparts of your push_back method.
template <typename T>
void bar1 (T&& value) {
process (move(value)); // you use move in your push_back method
}
template <typename T>
void bar2 (T&& value) {
process (forward<T>(value));
}
now we must consider 4 cases:
[1] pass L-value, version with forward
Foo f(20);
bar2 (f);
cout << (f.i) << endl; // 20
[2] pass R-value, version with forward
Foo f(20);
bar2 (move(f));
cout << (f.i) << endl; // 0, it is OK bacuse we wanted to move 'f' object
[3] pass R-value, version with move
Foo f(20);
bar1 (move(f));
cout << (f.i) << endl; // 0, ok, we wanted to move 'f' object
[4] pass L-value, version with move in your push_back method
Foo f(20);
bar1 (f);
cout << (f.i) << endl; // 0 !!! is it OK ? WRONG
in last case, we passed f as L-value, but this object was moved in bar1 function, for me this is strange behavior and is incorrect.
It is not safe to perform a memmove with objects in C++.
You can find more information here Will memcpy or memmove cause problems copying classes?
If this is C++11 onwards, then what you want to use is placement new and the move constructor. (you could probably just bin the placement new though unless you really want to keep allocating memory yourself)
If this is any other version of C++ then you'll have to just accept that that either you're going to have to copy the object (like the rest of the stl) or that your object will have to implement a function like void moveTo(T& other)
So simple question is, if I have such situation:
class FooA{
public:
int getID(){
return ID;
}
private:
int generateID(){
//some code that generate unique ID
}
int ID = generateID();
};
class FooB : public FooA{
};
Will the ID initialized in the FooA goes also to the FooB? So for FooB I can use getID and for example get value from FooA::generateID.
Every instance of both classes will run generateID anew, producing unique value for every instance.
No, ID generated for an instance of parent class won't be same as ID generated for an instance of descendant, because they would have different instances.
Yes, descendant can use or expose parent's methods.
class FooA{
public:
int getID(){
return ID;
}
private:
int generateID(){
static int i = 0;
return i++;
}
int ID = generateID();
};
class FooB : public FooA{
};
int main() {
// your code goes here
cout << (FooA()).getID() << endl; // 0
cout << (FooA()).getID() << endl; // 1
cout << (FooB()).getID() << endl; // 2
return 0;
}
https://ideone.com/5Klf3d
After many trials I still do not understand how to properly take advantage of the move semantics in order to not copy the result of the operation and just use the pointer, or std::move, to "exchange" the data pointed to. This will be very usefull to speed-up more complicated functions like f(g(),h(i(l,m),n(),p(q()))
The objective is to have:
t3={2,4,6};
t1={}; // empty
While executing the code below the output is:
t3={2,4,6};
t1={1,2,3};
Code:
namespace MTensor {
typedef std::vector<double> Tensor1DType;
class Tensor1D {
private:
//std::shared_ptr<Tensor1DType> data = std::make_shared<Tensor1DType>();
Tensor1DType * data = new Tensor1DType;
public:
Tensor1D() {
};
Tensor1D(const Tensor1D& other) {
for(int i=0;i<other.data->size();i++) {
data->push_back(other.data->at(i));
}
}
Tensor1D(Tensor1D&& other) : data(std::move(other.data)) {
other.data = nullptr;
}
~Tensor1D() {
delete data;
};
int size() {
return data->size();
};
void insert(double value) {
data->push_back(value);
}
void insert(const std::initializer_list<double>& valuesList) {
for(auto value : valuesList) {
data->push_back(value);
}
}
double operator() (int i) {
if(i>data->size()) {
std::cout << "index must be within vector dimension" << std::endl;
exit(1);
}
return data->at(i);
}
Tensor1D& operator=(Tensor1D&& other) {
if (this == &other){
return *this;
}
data = other.data;
other.data = nullptr;
return *this;
}
void printTensor(Tensor1DType info) {
for(int i=0;i<info.size();i++) {
std::cout << info.at(i) << "," << std::endl;
}
}
void printTensor() {
for(int i=0;i<data->size();i++) {
std::cout << data->at(i) << "," << std::endl;
}
}
};
} // end of namespace MTensor
In file main.cpp:
MTensor::Tensor1D scalarProduct1D(MTensor::Tensor1D t1, double scalar) {
MTensor::Tensor1D tensor;
for(int i=0;i<t1.size();++i) {
tensor.insert(t1(i) * scalar);
}
//return std::move(tensor);
return tensor;
}
int main() {
MTensor::Tensor1D t1;
t1.insert({1,2,3});
std::cout << "t1:" << std::endl;
t1.printTensor();
MTensor::Tensor1D t3(scalarProduct1D(t1,2));
std::cout << "t3:" << std::endl;
t3.printTensor();
std::cout << "t1:" << std::endl;
t1.printTensor();
return 0;
}
Your use of new is a red flag, especially on a std::vector.
std::vectors support move semantics natively. They are a memory management class. Manual memory management of a memory management class is a BIG red flag.
Follow the rule of 0. =default your move constructor, move assignment, copy constructor, destructor and copy assignment. Remove the * from the vector. Don't allocate it. Replace data-> with data.
The second thing you should do is change:
MTensor::Tensor1D scalarProduct1D(MTensor::Tensor1D t1, double scalar) {
As it stands you take the first argument by value. That is great.
But once you take it by value, you should reuse it! Return t1 instead of creating a new temporary and returning it.
For that to be efficient, you will want to have a way to modify a tensor in-place.
void set(int i, double v) {
if(i>data->size()) {
std::cout << "index must be within vector dimension" << std::endl;
exit(1);
}
data.at(i) = v;
}
which gives us:
MTensor::Tensor1D scalarProduct1D(MTensor::Tensor1D t1, double scalar) {
for(int i=0;i<t1.size();++i) {
ts.set(i, t1(i) * scalar);
}
return t1; // implicitly moved
}
We are now getting close.
The final thing you have to do is this:
MTensor::Tensor1D t3(scalarProduct1D(std::move(t1),2));
to move the t1 into the scalarProduct1D.
A final problem with your code is that you use at and you check bounds. at's purpose is to check bounds. If you use at, don't check bounds (do so with a try/catch). If you check bounds, use [].
End result:
typedef std::vector<double> Tensor1DType;
class Tensor1D {
private:
//std::shared_ptr<Tensor1DType> data = std::make_shared<Tensor1DType>();
Tensor1DType data;
public:
Tensor1D() {};
Tensor1D(const Tensor1D& other)=default;
Tensor1D(Tensor1D&& other)=default;
~Tensor1D()=default;
Tensor1D& operator=(Tensor1D&& other)=default;
Tensor1D& operator=(Tensor1D const& other)=default;
Tensor1D(const std::initializer_list<double>& valuesList) {
insert(valuesList);
}
int size() const {
return data.size();
};
void insert(double value) {
data.push_back(value);
}
void insert(const std::initializer_list<double>& valuesList) {
data.insert( data.end(), valuesList.begin(), valuesList.end() );
}
double operator() (int i) const {
if(i>data.size()) {
std::cout << "index must be within vector dimension" << std::endl;
exit(1);
}
return data[i];
}
void set(int i, double v) {
if(i>data->size()) {
std::cout << "index must be within vector dimension" << std::endl;
exit(1);
}
data.at(i) = v;
}
static void printTensor(Tensor1DType const& info) {
for(double e : info) {
std::cout << e << "," << std::endl;
}
}
void printTensor() const {
printTensor(data);
}
};
MTensor::Tensor1D scalarProduct1D(MTensor::Tensor1D t1, double scalar) {
for(int i=0;i<t1.size();++i) {
t1.set(i, t1(i) * scalar);
}
return t1;
}
int main() {
MTensor::Tensor1D t1 = {1,2,3};
std::cout << "t1:" << std::endl;
t1.printTensor();
MTensor::Tensor1D t3(scalarProduct1D(std::move(t1),2));
std::cout << "t3:" << std::endl;
t3.printTensor();
std::cout << "t1:" << std::endl;
t1.printTensor();
return 0;
}
with a few other minor fixes (like using range-for, DRY, etc).
You need to move t1 when calling scalarProduct1D, otherwise you'll make a copy:
MTensor::Tensor1D t3(scalarProduct1D(std::move(t1),2));
You need to explicitly use std::move because t1 is an lvalue expression.
Note that you'll have to fix your printing functions to avoid dereferencing nullptr if you want accessing the moved-from object to be a valid operation. I instead suggest to avoid making method invocation on moved-from objects valid as it requires additional checks and doesn't follow the idea of "this object has been moved, now it's in an invalid state".
live wandbox example
This is my header :
class my_router_client : public FIX8::my::mine_Router {
private:
mine_session_client& _session;
mutable std::vector<std::string> vSymbolList;
public:
my_router_client(mine_session_client& session) : _session(session) {}
virtual bool operator() (const FIX8::my::SecurityList *msg) const;
void sendToServer(FIX8::Message *);
void logout();
void itertool() const;
};
I am trying to save the data obtained from security list response to the vSymbolList vector. After handling security response I am trying to iterate through the vector by itertool method. But every time I end up with an empty vector. I tried printing the contents of the vector inside securitylist response function
virtual bool operator() (const FIX8::CX::SecurityList *msg) const;
and I am able to print the contents. Is it some kind of race condition inside threads?
this is the security list response handler
bool cx_router_client::operator() (const CX::SecurityList *msg) const
{
GroupBase *dad(msg->find_group< CX::SecurityList::NoRelatedSym >());
if (dad) {
for (size_t cnt(0); cnt < dad->size(); ++cnt) {
CX::Symbol symbol;
MessageBase *details(dad->get_element(cnt));
details->get(symbol);
string ss;
ss = symbol();
vSymbolList.push_back(ss);
// cout << "at :: :: " << vSymbolList[cnt] << endl;
}
cout << "no of symbol : " << vSymbolList.size() << endl;
hypersleep<h_seconds>(1);
}
return true;
}
This is the itertool method :
void my_router_client::itertool() const
{
cout << "symbol list vector size inside itertool:: " << vSymbolList.size() << endl;
stringstream ss;
ss << this_thread::get_id();
uint64_t id = stoull(ss.str());
cout << "Thread ID #### " << id << endl;
vector<string>::iterator it = this->vSymbolList.begin();
while (it != vSymbolList.end()) {
cout << *it << endl;
it++;
}
}
This is how I use the them in main :
int main()
{
const string conf_file("myfix_client.xml");
unique_ptr<ClientSessionBase> mc(new ClientSession<mine_session_client>(my::ctx(), conf_file, "DLD1"));
mc->start(false, next_send, next_receive, mc->session_ptr()->get_login_parameters()._davi());
hypersleep<h_seconds>(1);
my_router_client *test = new my_router_client(static_cast< mine_session_client& > (*mc->session_ptr()));
hypersleep<h_seconds>(1);
test->sendToServer(makeSecurityListRequest());
hypersleep<h_seconds>(1);
test->itertool();
while(1);
}
With some code left out, elsewhere on SOF there is code that looks like this:
// CRTP Abstract Base class for implementing static subject.
// Example Subclass Usage -- Printing Observer:
class Printer : public Observer<Printer> {
public:
Printer() : timesTriggered_(0) {}
template <typename... Args>
void OnNotify(Pressure<Args...> &subject, EventType event) {
std::cout << "Observer ID: " << this->GetID() << std::endl;
switch (event) {
case EventType::UNKNOWN: {
std::cout << "Unknown Event -- Event #" << timesTriggered_++
<< std::endl;
std::cout << "Pressure: " << subject.GetPressure() << std::endl;
break;
}
default: { break; }
}
}
private:
int timesTriggered_;
};
// CRTP Abstract Base class for implementing static subject.
// Example Subclass Usage -- Pressure Sensor:
template <typename... Obs>
class Pressure : public Subject<Pressure<Obs...>, Obs...> {
public:
typedef Subject<Pressure<Obs...>, Obs...> BaseType;
Pressure(std::tuple<Obs &...> &&observers, int pressure)
: BaseType(std::move(observers)), pressure_(pressure) {}
void Change(int value) {
pressure_ = value;
this->NotifyAll(EventType::UNKNOWN);
}
int GetPressure() const { return pressure_; }
private:
int pressure_;
};
// Binding function for use with MakeSubject
// Arguments: observer objects to observe subject notifications
// Return: tuple of references to observers
template <typename... Obs> std::tuple<Obs &...> BindObservers(Obs &... obs) {
return std::tuple<Obs &...>(obs...);
}
// Creator to ease subject creation
// Template Arguments: Subject subclass type
// Arguments: Result from BindObservers
// Any constructor arguments for Subject subclass
// Return: Subject subclass
// Example Usage:
// auto pressure = MakeSubject<Pressure>(BindObservers(printerObs), initialPressure);
template <template <typename...> class T, typename... Args, typename... Obs>
T<Obs...> MakeSubject(std::tuple<Obs &...> &&obs, Args &&... args) {
return T<Obs...>(std::move(obs), args...);
}
In main.cpp
int main() {
Printer printerObs1;
Printer printerObs2;
const int initialPressure = 1;
auto pressure = MakeSubject<Pressure>(
BindObservers(printerObs1, printerObs2), initialPressure);
pressure.Change(12);
}
I need to break out the BindObservers and the return type of MakeSubject, but I can't correctly figure out what to replace both **auto in the pseudo-code below:**
auto obs = BindObservers(printerObs1, printerObs2);
auto pressure = MakeSubject<Pressure>(obs, initialPressure);
What is the exapanded version return types of both auto above? I need to store the return values in std::vector and AFAIK, I can't say
std::vector<auto> vec
[Although I don't see why not since the compiler can probably figure it out]
You can use std::vector<decltype(pressure)>.
But the type should be Pressure<Printer, Printer>.