I used withinput() function to return back with form values but it's not working for ckeditor, that's why I tried getting value with Ckeditor getdata() function but it's also didn't work.
Ckeditor Form is like:
<?php echo Form::text("PageLanguage[description][$language>id]",
old("PageLanguage[description][$language->id]"),
array('id' =>"description-$language->id",'class' => 'form-control'));
?>
Any ideas?
I used textarea and it worked in my code
If you use Form::text it can't get value that's why it will save null value, you must change Form::text to Form::textarea like that:
<?php echo Form::textarea("PageLanguage[description][$language->id]",
old("PageLanguage[description][$language->id]"),
array('id' =>"description-$language->id",'class' => 'form-control'));?>
Related
view.php code part:
View Picture
viewgood.php
<?php
echo 'hello';
GoodsController.php
public function viewgood($id = null) {
}
After clicking on button View Picture my page just refreshing instead of going to viewgood.php
What am I doing incorrectly?
I am a begginer in Yii2
Try use
View Picture
in a anchor tag html your need use the complete route, for use shortcut you try use
<?= Html::a('View Picture', ['/goods/viewgood/', 'id' => $good['GoodGallery'][0]['id']], ['class' => 'btn btn-primary']) ?>
view.php
You can use Html:a(), or in your example use Url helper to() function to generate the proper route for your anchor tag.
View Picture
GoodsController.php
public function actionViewgood($id=null){
//fetch the data e.g.
$model = Good::findOne(id);
//Do some extra code checking when no record is found like throw an exception or set a flash error message, etc.
//render the viewgood and pass the data (if needed)
return $this->render('viewgood', [
'model' => $model
]);
}
viewgood.php
<?php
//do what you want with the data passed by the controller. E.g. print the name of the good (if applicable)
echo $model->name;
//your other code ...
?>
How can I clear form input on form submit?
After URL is saved I return the view for creating a form so I can add new URL.
The problem is that this time URL is populated from previous save.
How can I empty it after save?
Isn't that the point of second parameter which is set to null?
Using laravel version 5.4.36.
In the "create" iew I have a form with URL input:
{!! Form::open(['route' => 'urls.store']) !!}
{{ Form::url('url', null, array('class' => 'form-control')) }}
{{ Form::submit('Add domain', array('class' => 'btn' )) }}
Store method saves URL to database and returns the same view:
public function store(Request $request)
{
// URL Validation
$this->validate($request, array(
'url' => 'required|url|unique:urls'
));
// Save
$url = new Url;
$url->url = $request->url;
$url->save()
return view('urls.create');
}
Your form view should be handled by a get request on Route and submitting form is a post request .So after submitting the form you should redirect the same page not just returning the view . Check the web.php is the Routes are ok or not . Try to
add it to the store method ,I think it may help you
return redirect()->back();
or with flash message
return redirect('urls.create')->with('success', 'URL has been added');
you can make value = some values come from the controller with empty values when it's the parameters is set i.e use isset function
or
you can make a flag in the view when it sends to controller check it if it is true means you submit the form, in this case, make the values with empty
I am using a jui autocomplete widget in my form. Model validation is not working properly in here.
This is my view
<?php $form = ActiveForm::begin();?>
<div class="members-form">
<div class="col-md-5">
<?php
$data = FamilyName::find()
->select(['name as value', 'name as label','id as id'])
->asArray()
->all();
echo 'Family Name' .'<br>';
echo AutoComplete::widget([
'name' => 'family',
'id' => 'family_name',
'clientOptions' => [
'source' => $data,
// 'minLength'=>'3',
'autoFill'=>true,
'select' => new JsExpression("function( event, ui ) {
$('#members-family_name_id').val(ui.item.id);//#City-state_name is the id of hiddenInput.
}")],
]);
?>
<?= Html::activeHiddenInput($model, 'family_name_id')?>
<?= $form->field($model, 'remarks')->textInput() ?>
<?php ActiveForm::end(); ?>
</div>
</div>
my model code
public function rules()
{
return [
[['family_name_id', 'first_name',
'date_of_birth', 'relation_id', 'is_head','marital_status','remarks',
'gender','address_id'], 'required'],
];
}
Now if i try to create a new member with no data selected in any of the fields, then required fields will show like " ... cannot be blank" in red. But the family_name_id is not showing such validation. The data is not getting saved if leave the auto complete field empty but no validation message is being displayed. How can i show validation messages with jui auto complete ?
I believe you faced the same problem as I had few weeks ago. I experienced similar behavior: I saw autocomplete suggestions and could interact with them, but when I left the input field the client-site validation kept silent.
If you look at the html produced by your view, at the bottom you can see some javascript code, which is responsible for the client-side validation. It looks like:
jQuery(document).ready(function () {
....
jQuery('#app-new-form').yiiActiveForm(
[
{
"id":"application-familyname",
"name":" familyname ",
"container":".field-application-familyname",
"input":"#application-familyname",
"enableAjaxValidation":true,
"validate":function (attribute, value, messages, deferred, $form) {
yii.validation.required(value, messages, {"message":"Field cannot be empty"});
}
}
], []);
.....
});
This code assigns an event handler to your autocomplete field to start the client-side validation. But you have to pay attention, which id is used for the field. Unfortunately, yii2 takes the id provided by you only to construct the <input> element in html. When it produces javascript code the id is always generated from few permanent parts. The most important two are the name of the model and the name of the attribute. In your case id should be something like 'your_modelname -family_name_id'.
Because your explanation is not complete, this is only a guess. So, look at your html source and be sure you have the same id for the input you try to validate and the id in the JavaScript (see above).
You are using Html Hidden Input .. You have to use ActiveForm HiddenInput to show error validation..
use
<?= $form->field($model, 'family_name_id')->hiddenInput()->label(false);>
Why don't you use the family_name_id instead of creating a new select?
<?= $form->field($model, "family_name_id")->dropDownList(
ArrayHelper::map(FamilyName::find()->all(), 'id', 'name'),
['prompt' => 'Select']
) ?>
And you can change the label by using ->label('Family Name'), but i would recommend changing in model (unless you need "Family Name Id" as a label elsewhere).
I know you didn't said anything about that, but can i recommend you to see this answer about using methods that perform sql queries inside your view?
How can I rerender the main menu in Drupal after an Ajax Login?
I already tried the following (generating the return value in my PHP Ajax Controller):
$tree = menu_tree_all_data('main-menu');
$returnValue = drupal_render(menu_tree_output($tree));
However this will not include the Bootstrap specific class names. It basically just returns a minimalistic menu structure without anything added by the theme.
In the Bootstrap theme, the menu is rendered like this:
<?php if (!empty($primary_nav)): ?>
<?php print render($primary_nav); ?>
<?php endif; ?>
<?php if (!empty($secondary_nav)): ?>
<?php print render($secondary_nav); ?>
<?php endif; ?>
How can I enforce this type of rendering from my module?
Since I am working on an ajax one pager site, I need to update the menu based on a user's role after login. A page reload would destroy the desired look and feel, and is therefore no option.
Currently I am using the following code to process the login:
function wr_pages_form_alter(&$form, $form_state, $form_id) {
if ($form_id == 'user_login_block' || $form_id == 'user_login') {
$form['actions']['submit']['#ajax'] = array(
'callback' => 'wr_login_form_callback',
'wrapper' => 'user-login',
'method' => 'replace',
'effect' => 'fade',
'event' => 'click'
);
}
}
function wr_login_form_callback($form, $form_state) {
if (!form_get_errors()) {
return "<script>adjustViewsAndMenu();</script>";
}
else {
return $form;
}
}
adjustViewsAndMenu() makes changes to the menu, and adds extra parts to the one pager, depending on a user's role, however this function does not use any Drupal rendering, which is most likely not the best way to deal with this problem. Still haven't found out how to rerender a menu with AJAX while using the theme's rendering.
I'm using CakePHP 1.3, and trying to make a simple message posting board with ajax. I'm trying to use the Js helper to submit a form on the index page, then refresh the message board's div to include the new message. This is all on a single page.
I have previously posted on this, but I wanted to rephrase the question and include some updates. The previous question can be seen here How to use Js->submit() in CakePHP?
When I came back to this project after a couple days, I immediately tested and the form worked (sort of). Submitting the form added a message to the database (it didn't display the message, but I haven't attacked that part yet). It worked 2 times, adding 2 messages. Then I opened the controller file and commented out some debug code, and it stopped working. It appears the action is not being called.
Here is my messages_controller.php:
<?php
class MessagesController extends AppController {
function index() {
$messages = $this->Message->find('all');
$this->set('messages',$messages);
}
function add() {
$this->autoRender = false;
$this->Session->setFlash('Add action called');
if($this->RequestHandler->isAjax()) {
$this->Session->setFlash('Ajax request made');
$this->layout = 'ajax';
if(!empty($this->data)) {
if($this->Message->save($this->data)) {
$this->Session->setFlash('Your Message has been posted');
}
}
}
}
}
?>
Here is the index.ctp for my Message class
<div id="guestbook" class="section_box">
<h3 id="toggle_guestbook"><div class="toggle_arrow"></div>Sign our Guestbook</h3>
<?php
echo $this->Form->create('Message');
echo $this->Form->input('name', array('label' => 'From:'));
echo $this->Form->input('text', array('label' => 'Message:'));
echo $this->Js->submit('Post Your Message', array(
'url' => array(
'controller' => 'messages',
'action' => 'add'
),
'update' => '#message_board'
));
echo $this->Form->end();
echo $this->Js->writeBuffer(array('inline' => 'true'));
?>
<div id="message_board">
<?php foreach($messages as $message) { ?>
<div class="message">
<p class="message_txt">
<?php echo $message['Message']['text']; ?>
</p>
<div>
<div class="message_name">
<?php echo $message['Message']['name']; ?>
</div>
<div class="message_date">
<small>
<?php echo $message['Message']['date']; ?>
</small>
</div>
</div>
</div>
<?php } ?>
</div>
</div>
When the submit button is clicked, I can see in the console that a POST is made to http://localhost/messages/add with the correct data. But there doesn't appear to be a response. The flash message "Add action called" is NOT set from the controller (or any of the flash messages, for that matter) and the contents of #message_board are emptied.
If I refresh the page at this point, the SECOND flash message appears ("Ajax request made"), and the contents of the #message_board are restored. However the new message was not saved, its the same 2 messages from before.
I'm stumped. I have a feeling maybe there are bigger issues causing my problem, but I can't see it. Any help would be appreciated.
But there doesn't appear to be a
response ... and the
contents of #message_board are
emptied.
That is because you haven't set what action/view to render. You have to do this manually since you have $this->autoRender set to false. You could use render() to do this. More info can be found at its respective cookbook page.
If you have $this->autoRender set to true, then it'll replace the contents of #message_board with the contents of add.ctp
The flash message "Add action called"
is NOT set from the controller (or any
of the flash messages, for that matter)
I think you have to refresh the page or the part which contains the $this->Session->flash() bit for flash messages to appear.
The fact that the flash message appeared when you refreshed the page means that it did call and run the action.
AFAIK, you can only put/print one message from the flash key in the Messages array. The flash key is where the flash messages are stored by default. Each call to setFlash() will overwrite the flash message set by older calls.
Since only the second flash message was displayed, we could say that it failed at passing at least one of the conditions following the second call to setFlash() in the controller. You might want to put debug($this->data) statements near the conditions related to $this->data to help yourself in debugging your problem.
You could also use debug() to know if your application went through a certain action or path since it will almost always be displayed.
So you could do the following to check if it passed this condition:
if(!empty($this->data)) {
debug('Passed!');
If 'Passed!' will be printed after submitting the form, we would know that it passed that condition.
However the new message was not saved
It might be because $data is empty or it failed at validation. If your $data is not empty, it might have failed at validation and since your form doesn't display the validation errors; you might never have noticed them. One way to know if it passed validation is to do the following:
$this->Message->set($this->data);
if ($this->Message->validates()) {
debug('it validated logic');
} else {
debug('didn't validate logic');
}
Ramon's solutions worked for me. Here's the updated code.
Controller add function
function add() {
$this->autoRender = false;
if($this->RequestHandler->isAjax()) {
$this->layout = 'ajax';
if(!empty($this->data)) {
if ($this->Message->validates()) {
if($this->Message->save($this->data)) {
$this->render('/elements/message_board');
} else {
debug('didn\'t validate logic');
}
}
}
}
}
Heres the add form view:
<?php
echo $this->Form->create('Message');
echo $this->Form->input('name', array('label' => 'From:'));
echo $this->Form->input('text', array('label' => 'Message:'));
echo $this->Js->submit('Post Your Message', array(
'url' => array(
'controller' => 'messages',
'action' => 'add'
),
'update' => '#message_board'
));
echo $this->Form->end();
echo $this->Js->writeBuffer(array('inline' => 'true'));
?>
<?php pr($this->validationErrors); ?>
<div id="message_board">
<?php echo $this->element('message_board'); ?>
</div>
I tried to use the same solution as you used but it's not working. Ajax is ok when I access it directly in the URL, and I have the impression that the click is doing nothing. When I use
<fieldset><legend><?php __(' Run 1');?></legend>
<div id="formUpdateID"><div id="#error-message"></div>
<?php
$orders=array_merge($emptyarray,$orders['r1']['Order']);
echo $this->Form->create('Order');
echo $this->Form->input('id', array('value'=>$orders['id'],'type' =>'hidden'));
echo $this->Form->input('race_id', array('value'=> $orders['race_id'],'type' =>'hidden'));
echo $this->Form->input('driver_id', array('value'=>$session->read('Auth.User.driver_id'),'type' =>'hidden'));
echo $this->Form->input('run', array('value'=>$run,'type' =>'hidden'));
echo $this->Form->input('pm', array('value'=>$orders['pm'],'error'=>$err[$run]));
echo $this->Form->input('pr', array('value'=>$orders['pr'],'error'=>$err[$run]));
echo $this->Form->input('fuel', array('value'=>$orders['fuel'],'error'=>$err[$run]));
echo $this->Form->input('pit', array('value'=>$orders['pit'],'label' => __('Pit on lap '),'error'=>$err[$run]));
echo $this->Form->input('tyre_type', array('value'=>$orders['tyre_type'],'error'=>$err[$run]));
echo $this->Js->submit('Modify', array(
'url' => array(
'controller' => 'orders',
'action' => 'ajax_edit'
),
'update' => '#error_message'
));
echo $this->Form->end();
?>
<?php pr($this->validationErrors); ?>
</div></fieldset>
in view and in controller "orders":
function ajax_edit($id=null){
$this->autoRender = false;
if($this->RequestHandler->isAjax()) {
die(debug('In Ajax'));
$this->layout = 'ajax';
debug('didn\'t validate logic');
}
echo 'hi';
}
None of the messages are displayed.
I have some hard coded JS/ajax before which is not targeting this code part.
I did copy ajax layout in th webroot/view folder.
I can see the AJAX code displayed in formatted source code
<div class="submit"><input id="submit-1697561504" type="submit" value="Modify" /></div> </form><script type="text/javascript">
//<![CDATA[
$(document).ready(function () {$("#submit-1697561504").bind("click", function (event) {$.ajax({data:$("#submit-1697561504").closest("form").serialize(), dataType:"html", success:function (data, textStatus) {$("#error_message").html(data);}, type:"post", url:"\/Webmastering\/form1C\/frame\/orders\/ajax_edit\/1"});
return false;});});
//]]>
</script>
BTW, I start getting bored of the lack of doc in cakephp and its non efficacity to realize task more complicated than just posting a post in a blog. So thank you for your help before I start destroying my computer ;)
I know it's an old topic, but I stumbled acros the same problem in my application, so now I think what Thrax was doing wrong, namely he didn't put echo $this->Js->writeBuffer(array('inline' => 'true')); in the view (or in the layout) file, like Logic Artist did, so the scripts for handling the submit button's click weren't generated.