Find Employees with same salary using Java 8 Streams - java-8

Question

Suppose we have a list of Employee objects { id, name, salary} . How to find the employees having the same salary? using Java 8 Stream API ..
What I tried:-
I guess this is indirect way of asking how to list employees "based on" salary, In that case we can groupBy Salary. But that will display all salary and the list of employees with that salary .
Question: How to list only employees with same salary from this big map?
Solution I tried ::
List<Employee> employees = new ArrayList<>();
employees.add(new Employee(1, "John" , 1000));
employees.add(new Employee(1, "Peter" , 2000));
employees.add(new Employee(1, "Ben" , 3000));
employees.add(new Employee(1, "Steve" , 2000));
employees.add(new Employee(1, "Parker" , 1000));
Map<Integer, Set<String>> map3 = employees.stream()
.collect(Collectors.groupingBy
(Employee::getSalary, Collectors.mapping
(Employee::getName, Collectors.toSet())));
OUTPUT
map3 :: {2000=[Steve, Peter], 3000=[Ben], 1000=[Parker, John]}
public class Employee {
public Employee(int id, String name, int salary) {
this.id = id;
this.name = name;
this.salary = salary;
}
private int id;
private String name;
private int salary;
public int getId() {
return id;
}
public void setId(int id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public int getSalary() {
return salary;
}
public void setSalary(int salary) {
this.salary = salary;
}
}

Answer 1

You can also use filter like this:
employees.stream().collect(Collectors.groupingBy(Employee::getSalary)).entrySet()
.stream()
.filter(entry -> entry.getValue().size() > 1)
.map(entry -> new AbstractMap.SimpleEntry<>(entry.getKey(),
entry.getValue()
.stream().map(Employee::getName).collect(Collectors.toSet())))
.collect(Collectors.toMap(Map.Entry::getKey, Map.Entry::getValue));

Answer 2

Came up with the below solution that uses the groupBy already coded and then do a condition check on size.
map3.forEach((k,v) -> {
if(v.size()>1) {
System.out.println("salary :: "+ k + " is same for " + v);
}
});
OR using a filter , avoiding a if condition check ..
map3.entrySet()
.stream().filter(e -> e.getValue().size()>1)
.forEach((e) -> System.out.println( "Salary :: " +
e.getKey() + " is same for " + e.getValue()));
OUTPUT
salary :: 2000 is same for [Steve, Peter]
salary :: 1000 is same for [Parker, John]