Find matching numbers - oracle

Question

I'm trying to write a PLSQL query that will in two separate columns print random integers.
It will print 1000 numbers total (random 1 - 50 in each row).
What I need to figure out is how I after this has been done, replace the second column with either "yes" or "no" if it matches the first column
Such as:
Col A Col B
10 NO(42)
32 NO(12)
25 YES(25)
And so on.
This is my code:
CREATE TABLE table
(random_num INTEGER NOT NULL,
match INTEGER NOT NULL);
Declare
CURSOR cur_ IS
(Select
random_num,
match
from table);
Begin
FOR rec_ IN 1..1000
LOOP
INSERT INTO "table" (random_num,match) VALUES (DBMS_RANDOM.VALUE(1,50),DBMS_RANDOM.VALUE(1,50));
END LOOP;
END;
Now this works as I get two 1000 rows of each column with random numbers, but I need to implement this select:
SELECT random_num, CASE WHEN random_num = match THEN 'yes' ELSE 'no' END as match
FROM table
Into the loop so. Any takers on how I can do?

Answer 1

There's something wrong in what you said. You can't put yes (string) into an INTEGER datatype column.
This makes more sense:
Sample table:
SQL> CREATE TABLE test
2 (
3 random_num_1 INTEGER NOT NULL,
4 random_num_2 INTEGER NOT NULL,
5 match VARCHAR2 (3) NOT NULL
6 );
Table created.
Procedure: use local variables to store random numbers; then it is easy to compare them.
SQL> DECLARE
2 val1 NUMBER;
3 val2 NUMBER;
4 BEGIN
5 FOR i IN 1 .. 10 --> change it to 1000
6 LOOP
7 val1 := DBMS_RANDOM.VALUE (1, 50);
8 val2 := DBMS_RANDOM.VALUE (1, 50);
9
10 INSERT INTO test (random_num_1, random_num_2, match)
11 VALUES (val1,
12 val2,
13 CASE WHEN val1 = val2 THEN 'yes' ELSE 'no' END);
14 END LOOP;
15 END;
16 /
PL/SQL procedure successfully completed.
Result:
SQL> SELECT * FROM test;
RANDOM_NUM_1 RANDOM_NUM_2 MAT
------------ ------------ ---
45 31 no
40 48 no
43 27 no
49 41 no
6 38 no
5 18 no
18 35 no
15 34 no
11 19 no
37 39 no
10 rows selected.
SQL>

Answer 2

First if you want to produce random integers from 1 to 50 that are equaly distributed, you must be carefull.
[DBMS_RANDOM.VALUE (1, 50)][1] returns a decimal number greater than or equal than 1 and less than 50.
example
select DBMS_RANDOM.VALUE (1, 50) col from dual;
COL
----------
30,4901593
You cast the result in INTEGER type that performs rounding, so you will see all numbers, but the 1 and 50 will appear only half frequenty as other numbers.
So a better way to get random integers 1 .. 50 is 1 + trunc(50*DBMS_RANDOM.VALUE)
VALUE without parameters returns [0,1)
Also typically if you do not need to use PL/SQL do not use it
create table tab1 as
select 1 + trunc(50*DBMS_RANDOM.VALUE) col1, 1 + trunc(50*DBMS_RANDOM.VALUE) col2
from dual connect by level <= 10 /* increase as much rows are needed */
and add the MATCH column as virtual
alter table tab1
add (match varchar2(3) generated always as (
case when col1 = col2 then 'YES' else 'NO' end ) virtual);
COL1 COL2 MAT
---------- ---------- ---
33 6 NO
26 28 NO
35 22 NO
30 27 NO
17 45 NO
31 4 NO
11 21 NO
2 48 NO
35 25 NO
39 15 NO