How to maintain only a small set of non-default kernel configs? - linux-kernel

I would like to be able to maintain only a small set of kernel configs and use defaults for the rest of configs.
For a minimalistic example: I would like to maintain only the config value. Like this:
CONFIG_ILLEGAL_POINTER_VALUE=0xdebb000000000000
And use this to build kernels v3.x, v4.x, and v5.x.
Because I care only about this kernel config value, it is fine for all others to be default values.
How do I do that?

You can add all the config options you want to override in a simple Bash script that exports them as environment variables before running make. For options that you want to disable (i.e. set from y to n) you will need to directly modify the .config file as simply exporting them as =n will not work.
#!/bin/bash
make defconfig
# Options you want to modify
export CONFIG_FOO=123
export CONFIG_BAR=456
# Options which you want to disable
sed -ie '/CONFIG_BAZ=y/ s/=y/=n/' .config
make all -j
Beware though that you should check for config dependencies (with make menuconfig or make gconfig) to see whether the config options you are dealing with also depend on others or have others as dependencies. In such case you also want to include those in your Bash script as needed.

Related

Accessing ~/.ssh/config aliases from bash and python

I use ~/.ssh/config to manage hosts that I need to interact with frequently. Sometimes I would like to access the aliases from that file in scripts that do not use ssh directly, ie if I have a .ssh/config with
Host host1
User user1
Hostname server1.somewhere.net
I would like to be able to say something like sshcfg['host1'].Hostname to get server1.somewhere.net in scripting languages, particularly Python and something sensible in Bash.
I would prefer to do this with standard tools/libraries if possible. I would also prefer the tools to autodetect the the current configuration from the environment rather than have to be explicitly pointed at a configuration file. I do not know if there is a way to have alternate configs in ssh but if there is I would like a way to autodetect the currently active one. Otherwise just defaulting to "~/.ssh/config" would do.
It is possible to specify an alternative configuration file on the command line, but ~/.ssh/config is always the default. For an alternative configuration file use the -F configfile option.
You can either try parsing the original config file, or have a file that is better suited for manipulation and generate an alternative configuration file or part of the default configuration file from that.
Using Paramiko
Paramiko is a pure-Python (3.6+) implementation of the SSHv2 protocol, providing both client and server functionality.
You may not need every feature Paramiko is providing, but based on their documentation, this module could do just what you need: paramiko.config.SSHConfig
Representation of config information as stored in the format used by OpenSSH. Queries can be made via lookup. The format is described in OpenSSH’s ssh_config man page. This class is provided primarily as a convenience to posix users (since the OpenSSH format is a de-facto standard on posix) but should work fine on Windows too.
You can define a non-standard config-file,the same way you would specify an alternate ssh-config file to ssh command line, as mentioned in a previous answer:
config = SSHConfig.from_file(open("some-path.config"))
# Or more directly:
config = SSHConfig.from_path("some-path.config")
# Or if you have arbitrary ssh_config text from some other source:
config = SSHConfig.from_text("Host foo\n\tUser bar")
You can then retrieve whichever configuration you need like so
For example with a configuration file like this:
Host foo.example.com
PasswordAuthentication no
Compression yes
ServerAliveInterval 60
You could access different settings using:
my_config = SSHConfig()
my_config.parse(open('~/.ssh/config'))
conf = my_config.lookup('foo.example.com')
assert conf['passwordauthentication'] == 'no'
assert conf.as_bool('passwordauthentication') is False
assert conf['compression'] == 'yes'
assert conf.as_bool('compression') is True
assert conf['serveraliveinterval'] == '60'
assert conf.as_int('serveraliveinterval') == 60
In case you only need available hostnames, you can list all available ones, and then get information about their configuration using that context (More info here)
get_hostnames()
Return the set of literal hostnames defined in the SSH config (both explicit hostnames and wildcard entries).
This might not be compliant with your request for a standard library, though the project seems to be actively maintained and widely used as well

autoconf: how do I substitute the library prefix?

CLISP's interface to PARI is configured with the configure.in containing AC_LIB_LINKFLAGS([pari]) from lib-link.m4.
The build process also requires the Makefile to know where the datadir of PARI is located. To this end, Makefile.in has
prefix = #LIBPARI_PREFIX#
DATADIR = #datadir#
and expects to find $(DATADIR)/pari/pari.desc (normally
/usr/share/pari/pari.desc or /usr/local/share/pari/pari.desc).
This seems to work on Mac OS X where PARI is installed by homebrew in /usr/local (and LIBPARI_PREFIX=/usr/local), but not on Ubuntu, where PARI is in /usr, and LIBPARI_PREFIX is empty.
How do I insert the location of the PARI's datadir into the Makefile?
PS. I also asked this on the autoconf mailing list.
PPS. In response to #BrunoHaible's suggestion, here is the meager attempt at debugging on Linux (where LIBPARI_PREFIX is empty).
$ bash -x configure 2>&1 | grep found_dir
+ found_dir=
+ eval ac_val=$found_dir
+ eval ac_val=$found_dir
You are trying to use $(prefix) in an unintended way. In an Autotools-based build system, the $(prefix) represents a prefix to the target installation location of the software you're building. By setting it in your Makefile.in, you are overriding the prefix that configure will try to assign. However, since you appear not to have any installation targets anyway, at least at that level, that's probably more an issue of poor form than a cause for malfunction.
How do I insert the location of the PARI's datadir into the Makefile?
I'd recommend computing or discovering the needed directory in your configure script, and exporting it to the generated Makefile via its own output variable. Let's take the second part first, since it's simple. In configure.in, having in some manner located the wanted data directory and assigned it to a variable
DATADIR=...
, you would make an output variable of that via the AC_SUBST macro:
AC_SUBST([DATADIR])
Since you are using only Autoconf, not Automake, you would then manually receive that into your Makefile by changing the assignment in your Makefile.in:
DATDIR = #DATADIR#
Now, as for locating the data directory in the first place, you have to know what you're trying to implement before you can implement it. From your question and followup comments, it seems to me that you want this:
Use a data directory explicitly specified by the user if there is one. Otherwise,
look for a data directory relative to the location of the shared library. If it's not found there then
(optional) look under the prefix specified to configure, or specifically in the specified datadir (both of which may come from the top-level configure). Finally, if it still has not been found then
look in some standard locations.
To create a configure option by which the user can specify a custom data directory, you would probably use the AC_ARG_WITH macro, maybe like this:
AC_ARG_WITH([pari-datadir], [AS_HELP_STRING([--with-pari-datadir],
[explicitly specifies the PARI data directory])],
[], [with_pari_datadir=''])
Thanks to #BrunoHaible, we see that although the Gnulib manual does not document it, the macro's internal documentation specifies that if AC_LIB_LINKFLAGS locates libpari then it will set LIBPARI_PREFIX to the library directory prefix. You find that that does work when the --with-libpari option is used to give it an alternative location to search, so I suggest working with that. You certainly can try to debug AC_LIB_LINKFLAGS to make it set LIBPARI_PREFIX in all cases in which the lib is found, but if you don't want to go to that effort then you can work around it (see below).
Although the default or specified installation prefix is accessible in configure as $prefix, I would suggest instead going to the specified $datadir. That is slightly tricky, however, because by default it refers to the prefix indirectly. Thus, you might do this:
eval "datadir_expanded=${datadir}"
Finally, you might hardcode a set of prefixes such as /usr and /usr/local.
Following on from all the foregoing, then, your configure.in might do something like this:
DATADIR=
for d in \
${with_pari_datadir} \
${LIBPARI_PREFIX:+${LIBPARI_PREFIX}/share/pari} \
${datadir_expanded}/pari \
/usr/local/share/pari \
/usr/share/pari
do
AS_IF([test -r "$[]d/pari.desc"], [DATADIR="$[]d"; break])
done
AS_IF([test x = "x$DATADIR"], [AC_MSG_ERROR(["Could not identify PARI data directory"])])
AC_SUBST([DATADIR])
Instead of guessing the location of datadir, why don't you ask PARI/GP where its datadir is located? Namely,
$ echo "default(datadir)" | gp -qf
"/usr/share/pari"
does the trick.

How to input a parameter in a custom target with cmake

I have a custom target:
add_custom_target(
create-po
COMMAND ${MSGINIT} --no-translator -i "${PROJECT_SOURCE_DIR}/data/${PACKAGE}.pot" - "${PROJECT_SOURCE_DIR}/po/es.po" -l es_MX.utf8
)
so, is invoked like this:
# make create-po
my idea is to change it to something like this:
# make create-po "es"
so, any user can create a custom localed po file. I don't know the word exactly for this, but I'd like to add a parameter in the target name..is it posible with cmake? Thanks
After so long time I found this question for the same reason: Can I use CMake to initialize a .po file if I want to add a new translation? I expect to use it only once in a while for my project, so make the build system do it seems more comfortable to me than find out all the required options and paths every time.
I ended up with the following CMake snippet:
set(INIT_LANG CACHE STRING "give a locale here to create a target which initializes a related .po file")
IF(INIT_LANG)
add_custom_target(
create-po-${INIT_LANG}
... # integrate INIT_LANG in your command
)
ENDIF(INIT_LANG)
Then, if you want to initialize a new translation file, call (assuming your build dir in under the project root):
# cmake -DINIT_LANG=es_MX.utf8 ..
... and you should get a corresponding make target:
# make create-po-es_MX.utf8
Yes, it's not as straight-forward as the OP's idea/expectation (and mine as well), but users can create new .po files by themselves (of course, this will be documented properly for them in the project ;) ).

Organizing asset files in a Go project

I have a project that contains a folder to manage file templates, but it doesn't look like Go provides any support for non-Go-code project files. The project itself compiles to an executable, but it needs to know where this template folder is in order to operate correctly. Right now I do a search for $GOPATH/src/<templates>/templates, but this feels like kind of a hack to me because it would break if I decided to rename the package or host it somewhere else.
I've done some searching and it looks like a number of people are interested in being able to "compile" the asset files by embedding them in the final binary, but I'm not sure how I feel about this approach.
Any ideas?
Either pick a path (or a list of paths) that users are expected to put the supporting data in (/usr/local/share/myapp, ...) or just compile it into the binary.
It depends on how you are planning to distribute the program. As a package? With an installer?
Most of my programs I enjoy just having a single file to deploy and I just have a few templates to include, so I do that.
I have an example using go-bindata where I build the html template with a Makefile, but if I build with the 'devel' flag it will read the file at runtime instead to make development easier.
I can think of two options, use a cwd flag, or infer from cwd and arg 0:
-cwd path/to/assets
path/to/exe -cwd=$(path/to/exe/assets)
Internally, the exectable would chdir to wherever cwd points to, and then it can use relative paths throughout the application. This has the added benefit that the user can change the assets without having to recompile the program.
I do this for config files. Basically the order goes:
process cmd arguments, looking for a -cwd variable (it defaults to empty)
chdir to -cwd
parse config file
reparse cmd arguments, overwriting the settings in the config file
I'm not sure how many arguments your app has, but I've found this to be very useful, especially since Go doesn't have a standard packaging tool that will compile these assets in.
infer from arg 0
Another option is to use the first argument and get the path to the executable. Something like this:
here := path.Dir(os.Args[0])
if !path.IsAbs(os.Args[0]) {
here = path.Join(os.Getwd(), here)
}
This will get you the path to where the executable is. If you're guaranteed the user won't move this without moving the rest of your assets, you can use this, but I find it much more flexible to use the above -cwd idea, because then the user can place the executable anywhere on their system and just point it to the assets.
The best option would probably be a mixture of the two. If the user doesn't supply a -cwd flag, they probably haven't moved anything, so infer from arg 0 and the cwd. The cwd flag overrides this.

Automatically generate conf file during make

I have a conf file that is of the format:
name=value
What I want to do is using a template, generate a result based on some values in another file.
So for example, say I have a file called PATHS that contains
CONF_DIR=/etc
BIN_DIR=/usr/sbin
LOG_DIR=/var/log
CACHE_DIR=/home/cache
This PATHS file gets included into a Makefile so that when I call make install the paths are created and built applications and conf files copied appropriately.
Now I also have a conf file which I want to use as a template.
Say the template contains lines like
LogFile=$(LOG_DIR)/myapp.log
...
Then generate a destination conf that would have
LogFile=/var/log/myapp.log
...
etc
I think this can be done with a sed script, but I'm not very familiar with sed and regular expression syntax. I will accept a shell script version too.
You should definitely go with autoconf here, whose very job is to do this. You'll have to write a conf.in file, wherein all substitutions are marked with #'s, e.g.
prefix=#prefix#
bindir=#bindir#
and write up a configure.ac, which is a shell script that will perform these substitutions for you and create conf. conf is subsequently included in the Makefile. I'd even recommend using a Makefile.in file, i.e. including your snippet in the Makefile.
If you keep to the standard path names, your configure.ac is a four-liner and has the added advantage of being GNU compatible (easy to understand & use).
You may want to consider using m4 as a simple template language instead.

Resources